Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From Data Intrepretation that is important for IBPS,SBI exam,SSC exam, Railways Exam,FCI exam and other competitive exams. We have included Some questions that are repeatedly asked in exams !!
I. Study the following information to answer the given questions
- Expenditure of A in 1994 and 1995 are Rs. 12lak and Rs.14lak. What was the total income of A in 1994 and 1995 together ?
A)Rs.40.8L
B)Rs.40.4L
C)Rs.44L
D)Rs.46.4L
E)None of theseB)40.4L
Explanation :
1994 E = 12 L
% P = (I – E)*100 / E
50 = (I – 12)*100 / 12
I = 6+12 = 18 L
1995 E = 14L
60 = (I – 14)*100 / 14
I = 22.4L
Total = 18+22.4 = 40.4L - Ratio of Expenditure of Companies A and B in 1993 was 4:5. What was the ratio of their incomes in the same year ?
A)58:75
B)75:58
C)78:55
D)72:55
E) None of theseA)58:75
Explanation :
A : B = 40:50
45 = (I – 40)*100/40………….(A)
I = 58L
50 = (I – 50)*100/50
I = 75L ………………………………(B)
A:B = 58:75 - Total Expenditure of company B in all the years together was Rs.125L. What was the total income of the company in all the years together ?
A)Rs.185L
B)Rs,.520L
C)Rs.250L
D)Cannot be determined
E) None of theseD)Cannot be determined
Explanation :Over all % is not known - If the incomes of the B in 1992 and 1993 were in the ratio 3:4, Find the ratio of Expenditures of that company in these 2 years ?
A)48:55
B)42:53
C)58:45
D)45:58
E) None of theseD)45:58
Explanation :
Income => 1992:1993 = 3:4 = 30:40
45 = (30-E)*100/E
45E/100 = 30 – E
9E/20 = 30 – E
9E = 600 – 20E
29E = 600
E = 600/29……………1992
50 = (40 – E)*100 / E
50E/100 = 40 – E
E = 2(40 – E)
E = 80 – 2E
3E = 80
E = 80/3
Ratio = (600/29) / (80/3) = 600*3 / 29*80
= 1800/2320 = 180/232 = 45/58 - If the expenditure of A and B in 1991 were equal and total income of A and B was
Rs. 116L, what was the total expenditure of A and B in the same years ?
A)Rs.84L
B)Rs.83L
C)Rs.80L
D)Rs.40L
E) None of theseC)Rs.80L
Explanation :
For A
40 = (I – E)*100/E
40E = (I – E)100
2E = 5I – 5E
5I = 7E
I = 7/5 E
For B
50 = (116-I – E)*100/E
E = 2(116 – I – E)
E = 232 -2I – 2E
2I = 232 – 3E
I = (232 – 3E)/2
7/5E = (-232 – 3E)/2
14E = 1160 – 15E
29E = 1160
E = 1160/29 = 40
2E = 80
II. Study the following information to answer the given questions
- What is the average no of candidates qualified from state S over the given years ?
A)115.7
B)117.5
C)157.5
D)155.7
E) None of theseB)117.5
Explanation :(105+110+120+125+135+110)/6 = 705 / 6 = 117.5 - Percentage of candidates qualified over appeared in 1993 is the highest for which of the following state except R?
A)U
B)T
C)Q
D)R
E) None of theseA)U
Explanation :
P = 115*100/165 = 69.69
Q = 125*100/130 = 96.15
R = 140*100/140 = 100
S = 120*100/170 = 70.58
T =140*100/160 = 87.5
U = 145*100/150 = 96.67
U has highest % = 96.67 - Approximately what is the percentage of candidates qualified over appeared from all 6 states together in 1991 ?
A)85.90%
B)84.76%
C)87.03%
D)83.07%
E) None of theseD)83.07%
Explanation :
Q =125+140+110+105+175+130 = 785
A = 140+165+65+155+185+135 = 945
% = 785*100/945 = 83.07% - Which year the Percentage of candidates qualified over appeared is low in the State P ?
A)1991
B)1996
C)1994
D)1993
E) None of theseB)1996
Explanation :
1991 = 125*100/140 = 89.28
1992 = 120*100/130 = 92.30
1993 = 115*100/165 = 69.69
1994 = 120*100/145 = 82.76
1995 = 105*100/170 = 61.76
1996 = 110*100/180 = 61.11 - Total no of candidates qualified in the year 1996 ?
A)650
B)860
C)750
D)720
E) None of theseC)750
Explanation :Q = 110+175+125+110+120+110 = 750
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