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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(1-5) Study the following line graph and answer the questions.**The line graph shows the ratio of income to expenditure of three bike companies over the month July-December

**If income of Royal Enfield in the month of July was 23.58 what was expenditure in that month?**CorrectAnswer –

**3) 78.60 Lakh**

Explanation:

I – Income

E – Expenditure

I/E =0.3

(E)Royal Enfield= 23.58/0.3= 78.60 lakhIncorrectAnswer –

**3) 78.60 Lakh**

Explanation:

I – Income

E – Expenditure

I/E =0.3

(E)Royal Enfield= 23.58/0.3= 78.60 lakh - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(1-5) Study the following line graph and answer the questions.**The line graph shows the ratio of income to expenditure of three bike companies over the month July-December

**The ratio of income to expenditure of Royal Enfield in the month of December is approximately what percent of the ratio of income to expenditure of Hero in the month November?**CorrectAnswer –

**3) 62.5%**

Explanation:

(I)Royal Enfield(December)/(E)Royal Enfield(December) = 0.75

(I)Hero(November)/(E)Hero(November) = 1.2

Required Percent = 0.75/1.2*100 =62.5%IncorrectAnswer –

**3) 62.5%**

Explanation:

(I)Royal Enfield(December)/(E)Royal Enfield(December) = 0.75

(I)Hero(November)/(E)Hero(November) = 1.2

Required Percent = 0.75/1.2*100 =62.5% - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(1-5) Study the following line graph and answer the questions.**The line graph shows the ratio of income to expenditure of three bike companies over the month July-December

**If the expenditure of Royal Enfield in the month of December and the income of Hero in the month of September equal to 64 lakh each then the income of Royal Enfield in the month of December was approximately what percent of the expenditure of Hero in the month of September?**CorrectAnswer –

**4) 60%**

Explanation:

(I)Royal Enfield(December)/(E)Royal Enfield(December)=0.75

(I)Royal Enfield(December) = 0.75*64 = 48 lakh

(I)Hero(September)/(E)Hero(September) = 0.8

(E)Hero = 64/0.8 = 80 lakh

Required percent = 48/80*100 = 60%IncorrectAnswer –

**4) 60%**

Explanation:

(I)Royal Enfield(December)/(E)Royal Enfield(December)=0.75

(I)Royal Enfield(December) = 0.75*64 = 48 lakh

(I)Hero(September)/(E)Hero(September) = 0.8

(E)Hero = 64/0.8 = 80 lakh

Required percent = 48/80*100 = 60% - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(1-5) Study the following line graph and answer the questions.**

**If the income of Royal Enfield and TVS in the month of September were 36 lakh and 27 lakh respectively. what was the ratio of expenditure in that month?**CorrectAnswer –

**3) 2:3**

Explanation:

(I)Royal Enfield(September)/(E)Royal Enfield(September) = 0.5

(E)Royal Enfield(December) = 36/0.5 = 72 lakh

(I)TVS(September)/(E)TVS(September) = 0.25

(E)TVS(September) = 27/0.25 = 108 lakh

Ratio = 72/108 = 2/3

= 2:3IncorrectAnswer –

**3) 2:3**

Explanation:

(I)Royal Enfield(September)/(E)Royal Enfield(September) = 0.5

(E)Royal Enfield(December) = 36/0.5 = 72 lakh

(I)TVS(September)/(E)TVS(September) = 0.25

(E)TVS(September) = 27/0.25 = 108 lakh

Ratio = 72/108 = 2/3

= 2:3 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(1-5) Study the following line graph and answer the questions.**

**If the income of Hero in the month of August and December were equal then the expenditure of Hero in the month of August was approximately what percent of its expenditure in the month of December?**CorrectAnswer –

**1) 120**

Explanation:

Let the income of Hero in August = X

E(August) = X/0.5 = 2X

E(December) = X/0.6 = 5X/3

Required percent = 2X/5X/3*100 = 120IncorrectAnswer –

**1) 120**

Explanation:

Let the income of Hero in August = X

E(August) = X/0.5 = 2X

E(December) = X/0.6 = 5X/3

Required percent = 2X/5X/3*100 = 120 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(6-10) Study the following Chart and answer the questions given below.****J and K started doing the task. After 2 days they both left, and L joined the task. He completed his part of task. Now the remaining task was completed by C in 7 days. In how many days can C complete the whole task?**CorrectAnswer –

**3) 12 days**

Explanation:

J does 20% works in 4 days.

100% task in 100*4/20 = 20 days

K can complete 100% task in 100*3/10 = 30 days

They worked for 2 days,

[1/20 + 1/30]*2 = 1/6 work

Now L completed 25% = 1/4 work

So now remaining work = 1 – (1/6 + 1/4) = 7/12

C complete 7/12 work in 7 days, so complete work in 12 daysIncorrectAnswer –

**3) 12 days**

Explanation:

J does 20% works in 4 days.

100% task in 100*4/20 = 20 days

K can complete 100% task in 100*3/10 = 30 days

They worked for 2 days,

[1/20 + 1/30]*2 = 1/6 work

Now L completed 25% = 1/4 work

So now remaining work = 1 – (1/6 + 1/4) = 7/12

C complete 7/12 work in 7 days, so complete work in 12 days - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(6-10) Study the following Chart and answer the questions given below.****H who can complete whole task in 30 days replaced J and did J’s part of task. He left and then K also worked for same number of days as H. If the remaining task was completed by O who can complete the task in one-fourth of the number of days in which N can complete the task, then in how many days was the whole task completed?**CorrectAnswer –

**4) 18 days**

Explanation:

J’s part of work = 20% = 1/5

So H did 1/5 of work,

Whole work in 30 days, 1/5 work in 1/5 * 30 = 6 days

K also worked for 6 days.

K can complete whole task in 30 days, in 6 days, completed 6/30 = 1/5 of task

Now remaining task = 1 – (1/5 + 1/5) = 3/5

Now N can complete whole task in 40 days [100*6/15]

So O can complete task in 10 days. So completed 3/5 task in 3/5 * 10 = 6 days

So total number of days = 6+6+6 = 18 daysIncorrectAnswer –

**4) 18 days**

Explanation:

J’s part of work = 20% = 1/5

So H did 1/5 of work,

Whole work in 30 days, 1/5 work in 1/5 * 30 = 6 days

K also worked for 6 days.

K can complete whole task in 30 days, in 6 days, completed 6/30 = 1/5 of task

Now remaining task = 1 – (1/5 + 1/5) = 3/5

Now N can complete whole task in 40 days [100*6/15]

So O can complete task in 10 days. So completed 3/5 task in 3/5 * 10 = 6 days

So total number of days = 6+6+6 = 18 days - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(6-10) Study the following Chart and answer the questions given below.****All persons decided to complete the task in less number of days. So they divided the task equally among themselves. In how many days will the task be completed this way?**CorrectAnswer –

**2) 27.8 days**

Explanation:

5 people equally divided the task so each did 1/5 work now

J = 1/5 work in 4 days

K =1/10 work in 3 days, so 1/5 work in 6 days

L =1/4 work in 6 days, so 1/5 work in 24/5 days

M = 3/10 work in 7.5 days, so 1/5 work in 5 days

N = 3/20 work in 6 days, so 1/5 work in 8 days

Complete work in = 4 + 6 + 24/5 + 5 + 8 = 27.8 daysIncorrectAnswer –

**2) 27.8 days**

Explanation:

5 people equally divided the task so each did 1/5 work now

J = 1/5 work in 4 days

K =1/10 work in 3 days, so 1/5 work in 6 days

L =1/4 work in 6 days, so 1/5 work in 24/5 days

M = 3/10 work in 7.5 days, so 1/5 work in 5 days

N = 3/20 work in 6 days, so 1/5 work in 8 days

Complete work in = 4 + 6 + 24/5 + 5 + 8 = 27.8 days - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(6-10) Study the following Chart and answer the questions given below.****A is 20% more efficient than K and B is 60% more efficient than L. They worked together for 5 days and left the task, after which the remaining task was completed by L and N together. If all worked together, in how many less days they could have completed the task?**CorrectAnswer – 2) 81/13 days

Explanation:

A and K

A = 120:100 = 6:5. Days = 5:6

6 =30, 1 =5, 5 =25.

A can complete task in 25 days

B and L

B = 160: 100 = 8: 5.Days = 5: 8

8 = 24, 1 = 3, 5 = 15.

B can complete task in 15 days

They worked for 5 days. So

[1/25 + 1/15]*5 = 8/15 work

Reaming 7/15 by L and N

So [1/24 + 1/40]*x = 7/15

x = 7 days

Total = 5+7 = 12 days

They work together

[1/25 + 1/15 + 1/24 + 1/40] = 13/75

So 75/13 days

So less days = 12 – 75/13 = 81/13IncorrectAnswer – 2) 81/13 days

Explanation:

A and K

A = 120:100 = 6:5. Days = 5:6

6 =30, 1 =5, 5 =25.

A can complete task in 25 days

B and L

B = 160: 100 = 8: 5.Days = 5: 8

8 = 24, 1 = 3, 5 = 15.

B can complete task in 15 days

They worked for 5 days. So

[1/25 + 1/15]*5 = 8/15 work

Reaming 7/15 by L and N

So [1/24 + 1/40]*x = 7/15

x = 7 days

Total = 5+7 = 12 days

They work together

[1/25 + 1/15 + 1/24 + 1/40] = 13/75

So 75/13 days

So less days = 12 – 75/13 = 81/13 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(6-10) Study the following Chart and answer the questions given below.****O can complete the whole task in number of days equal to the average of number of days in which J and K can complete the task. O, L, M, and N all started the task and after 5 days they were replaced by J and K. J and K completed the remaining task in how many days?**CorrectAnswer –

**1) 16/5 days**

Explanation:

J in 20 days, K in 30 days.

O in (20+30)/2 = 25 days

O, L, M, and N started work

[1/25 + 1/24 + 1/25 + 1/40]= 11/75.

Worked for 5 days

11/75 * 5 =11/15 of work

Remaining work = 4/15

[1/20 + 1/30]*x = 4/15

x = 48/15 days = 16/5 daysIncorrectAnswer –

**1) 16/5 days**

Explanation:

J in 20 days, K in 30 days.

O in (20+30)/2 = 25 days

O, L, M, and N started work

[1/25 + 1/24 + 1/25 + 1/40]= 11/75.

Worked for 5 days

11/75 * 5 =11/15 of work

Remaining work = 4/15

[1/20 + 1/30]*x = 4/15

x = 48/15 days = 16/5 days

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