# SBI PO 2015: Quantitative Aptitude Quiz Set 1

Hello Aspirants, Welcome to SBI PO 2015 Quiz Sections. Here is a set of question with solution in Quantitative Aptitude based on Sbi po prelims exam. We hope it will helpful for exam. Kindly tell your suggestion in comment section.

1. X can work twice as fast as Y. X and Y together can finish a work in 16 days. In how many days can X alone finish the work ?
a) 16 days b) 18 days c) 24 days d) 32 days
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c) 24 daysÂ

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2. If 4A = 5B and 3A = 7C, the ratio of C : B is
a) 4 : 7 b) 15 : 28 c) 12 : 35 d) 5: 3
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b) 15 : 28 Â

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3. Ten years ago Ramesh was twice of Rajesh in age. If the ratio of their present ages is 4 : 3 , what is the difference in their present ages ?
a) 10 b) 7 c) 4 d) None of the above.
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d) None of the above. Â

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4. In the series given below only one number is wrong. Find out the number
5 , 16 ,49 , 148 , 444 ,1336.
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444Â

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5. A fair coin is tossed repeatedly. If head appears on first 5 tosses then the probability of head appearing on the 6 toss is ?
a) 1/2 b) 1/64 c) 1/32 d) 5/12
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a) 1/2Â

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6. A card is drawn at random from a well shuffled pack of cards. The probability of it is being a diamond or an Ace is
a) 4/13 b) 9/13 c) 8/13 d) 11/26
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a) 4/13Â

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7. 7. A number increased by 47.6% gives 81.18 , the number is
a) 67 b) 55 c) 48 d) 50
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b) 55Â

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8. 8. Anbu and Priyaa travel the same distance at 9 km/hr and 10 km/hr respectively. If Anbu takes 30 mins longer than Priyaa the distance travelled by each is
a) 63 b) 54 c) 35 d) 45
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d) 45 Â

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9. 9. What is the time required by a train of length 450 m to cross an electric pole with a speed 36km/hr.
a) 60 s b)50 s c) 55 s d) 45 s
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d) 45 sÂ

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10. 10. Two containers each with capacity 20 liters are filled up to exactly half level with the mixture of water and milk. The concentration of milk in each container is 50% and 40% .5 liters Water is added to each container now. What is the ratio of water in both containers after adding water?
a) 10 : 9 b) 5 : 6 c) 10 : 11 d)1 : 1
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c) 10 : 11Â

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###### Solutions

1) Â Let us simplify the problem by quantifying the work done and work rate/efficiency.
Let the work be to transfer â€˜aâ€™ number of bricks from one place to another.
Let the time taken by X to do it be â€˜tâ€™ , hence his work rate will be â€˜a/tâ€™.
The time taken by Y to do it be will be â€˜2tâ€™ , hence his work rate will be â€˜a/2tâ€™.Since X woks twice fast as Y.
When X and Y work together the work rate will be added up, hence net work rate will be equal to (a/t ) + (a/2t). The time taken to complete the work when they work together is 16 days, ence the equation is ( (a/t) +(a/2t) ) x16 = a ; (Net work rate X time taken = Net work ).
Simplifying we get t = 16x(3/2) ;
t = 24; hence X will take 24 days.

2)Â Â 4A = 5B implies A = (5/4)B
3A = 7C implies A = (7/3)C
(5/4)B = (7/3)C
15B = 28C
C : B = 15 : 28

3)Â  Let the present age of Ramesh be â€˜Xâ€™ and Rajesh be â€˜Yâ€™.
(X – 10) = (Y – 10) X 2 ;( Ten years ago age of Ramesh will be X- 10 and Rajesh will be Y-10)
3X = 4Y Since their present ages are in the ratio 3 : 4;
Multiplying first equation by 2 on both sides we get
2X â€“ 20 = 4Y â€“ 40 ; 2X â€“ 20 = 3X â€“ 40 ; (since 3X = 4Y)
X = 20; Implies Y = 15 ;
The difference between their ages is 5 years

4) Â Observing the series we can find that (5×3)+1 =16 (next number); (16×3) + 1 = 49 ; (49×3) + 1 =148 ; (148×3)+1 = 445 ; (445×3)+1 = 1336 ; Hence 444 is the wrong number in the sequence.

5) Â Since the coin is fair (equal probability to get ead and tail) and the events are independent (previous tosses does not affect the upcoming tosses) of each other the probability of head on 6 th toss is same as any other toss ie 1/2 .

6) Â Number of diamond cards in a deck is 13 and number of aces in a deck is 4. The number of ways in which we can get a diamond or ace is 13+3 ; Since diamond ace is already counted in diamond cards it is excluded from counting in ace cards. The total number of ways of selecting a card is 52.
Hence the required probability is 16/52 ; 4/13.

7) Â Let the number be a ; when increased by 47.6% the number becomes (147.6/100) x a ; ( a+ (47.6/100)xa )
The question becomes 147.6/100 x a = 81.18 ; On simplification we get a = 55

8) Â Let the distance covered by both of them be d km; Speed x Time = Distance ;
Let time taken by Priyaa to cover distance d be t hr , then time taken by anbu to cover the same distance will be t+1/2 hr .
9 (km/hr) x (t+1/2)hr = d km (Equation for Anbuâ€™s journey)
10 (km/hr) x t hr = d km (Equation for Priyaaâ€™s journey)
Equating above equations we get { (9xt) + (9x(1/2)) } = (10xt) ;
9x(1/2) = t ; t= 4.5 hrs ; d = 45 km

10) Â Amount of mixture in each Container is 10 ltrs.
Milk in container1 is 5lts and container 2 is 4 ltrs.
Water in container1 is 5 ltrs and container2 is 6 ltrs.
After adding water upto 5 ltrs the volume of water in each container is 10 and 11 ltrs respectively.
Hence the ratio is 10 :11.

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