Hello Aspirants. Welcome to Online Reasoning Section in AffairsCloud.com. Here we are creating question sample in coded **Inequalities**, which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!

** Directions (1 – 10): **

** (A) **only 1st follows

** (B) **only 2nd follows

** (C) **either 1st or 2nd

** (D) **neither 1st nor 2nd

** (E) ** both 1st and 2nd

**Statements:**K > B ≤ G = A, G ≤ P ≤ Q, A ≤ M

**Conclusions:**

I. Q > M

II. Q ≤ M

**(C) either 1st or 2nd**

Explanation:

Q ≥ G = A ≤ M, this gives both Q and M less than equal to F

So either Q will be > M or Q will be ≤ M**Statements:**Q ≥ P > K, P > F < C, A > W

**Conclusions:**

I. Q > F

II. A > C

**(A) only 1st follows**

Explanation:

Q ≥ P > F, so Q > F

A > Q ≥ P > F < C, so relation cant be determined between A and C

**Statements:**Q > V < B ≤ P, A ≤ M ≤ V, G < M

**Conclusions:**

I. P > G

II. A < Q

**(E) both 1st and 2nd**

Explanation:

P > V ≥ M > G, so P > G

A ≤ V < Q, so P < Q

**Statements:**L > P, P < N, N ≥ A

**Conclusions:**

I. A < P II. L > N

**(D) neither 1st nor 2nd**

Explanation:

A ≤ N > P, so no relationship between A and P

L > P < N, both L and N less than P so no relationship between L and N**Statements:**K ≥ T ≥ J, R < L, L > O

**Conclusions:**

I. O > T

II. K > L

**(D) neither 1st nor 2nd**

Explanation:

O < L > R ≤ T, so relation cant be determined between O and T

K ≥ R < L, so relation cant be determined between K and L**Statements:**S > M ≤ A, T ≤ M, Q ≤ B = T

**Conclusions:**

I. A > Q

II. A = Q

**(C) either 1st or 2nd**

Explanation:

A ≥ M ≥ T ≥ Q

So A ≥ Q

So either or between two conclusions**Statements:**P < E ≤ S, D > S < M, E ≥ A

**Conclusions:**

I. M ≥ A

II. D > A

**(B)****only 2nd follows**

Explanation:

M > S ≥ E ≥ A, so M > A

D > S ≥ E ≥ A so L > A

**Statements:**N ≥ P ≥ T, T < O, O > E

**Conclusions:**

I. E > P

II. N > O

**(D) neither 1st nor 2nd**

Explanation:

E < O > T ≤ P, so relation cant be determined between E and P

N ≥ T < O, so relation cant be determined between N and O

**Statements:**L > A ≥ Z, P = A, S > L

**Conclusions:**

I. S > P

II. Z < S

**(E) both 1st and 2nd**

Explanation:

S > L > A = P, so S > P

Z < L < S, so Z < S

**Statements:**P ≥ L > K, L > T < Q, B > P

**Conclusions:**

I. P > T

II. B > Q

**(A) only 1st follows**

Explanation:

P ≥ L > T, so P > T

B > P ≥ L > T < Q, so relation cannot be determined between Q and B

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