Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions inÂ **Quadratic Equations** which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

**You have to solve equation I and II ,Give answer**

**1)If X>Y**

**2)If X<Y**

**3)If Xâ‰¥ Y**

**4)If Xâ‰¤ YÂ Â Â Â Â Â Â Â Â Â Â **

**5)If X=Y or cannot be established**

**I. 4X**^{2 }Â – 19X + 12= 0

**II. 3Y**^{2 }+ 8Y + 4 = 0Answer –**1)If X>Y**

Explanation :

(x-4)(4x-3) = 0

X=4,3/4

(y+2)(3y+2) = 0

y=-2, -2/3

4,3/4,-2/3,-2

Xxyy = x>y**I. X**^{2 }= 729

**II.Â Y – âˆš324 = âˆš81**Answer –**4)If Xâ‰¤ Y**

Explanation :

X= Â±27

Y = 9+18 = 27

xâ‰¤y**I. X**^{2 }Â + X – 56= 0

**II.Â Y**^{2 }– 17Y + 72 = 0Answer –**2)If X<Y**

Explanation :

(x+8)(x-7) = 0

X=7,-8

(y-8)(y-9) = 0

Y=8, 9

9,8,7,-8

Yyxx = x<y**I. 20X**^{2 }Â – 17X + 3= 0

**II. 20Y**^{2 }– 9Y + 1 = 0Answer –**3)If Xâ‰¥ Y**

Explanation :

(4x-1)(5x-3) = 0

X=1/4, 3/5

(4y-1)(5y-1) =0

Y = 1/4, 1/5

3/5, Â¼,1/4, 1/5

Xxyy => Xâ‰¥ Y**I. 3X**^{2 }Â – 10X + 8= 0

**II. Y**^{2 +}Â 3Y – 4 = 0Answer –**1)If X>Y**

Explanation :

(x-2)(3x-4) = 0

X=2, 4/3

(y-1)(y+4) = 0

Y = 1, -4

2,4/3,1,-4

Xxyy => x>y**I. X**^{2 }Â + 5X + 6= 0

**II. Y**^{2 }+ 3Y + 2 = 0Answer –**4)If Xâ‰¤ Y**

Explanation :

(x+2)(x+3) = 0

X=-2,-3

(y+1)(y+2) = 0

Y=-1,-2

-1,-2,-2,-3

Yyxx => xâ‰¤y**I. 2X**^{2 }Â + 5X + 2= 0

**II. 4Y**^{2 }– 1 = 0Answer –**4)If Xâ‰¤ Y**

Explanation :

(2x+1)(x+2) = 0

X= – 1/2, -2

Y = Â½, -1/2

Â½, -1/2, -1/2, -2

Yyxx => xâ‰¤y**I. X**^{2 }Â + 14X -72= 0

**II. 3Y**^{2 }+ 14Y + 15 = 0Answer –**5)If X=Y or cannot be established**

Explanation :

(x-4)(x+18) = 0

X=4,-18

(y+3)(3y+5) = 0

Y= -3, -5/3

4,-5/3, -3, -18

xyyx**I. X**^{2 }Â + 8X + 15= 0

**II. Y**^{2 }– Y + 12 = 0Answer –**4)If Xâ‰¤ Y**

Explanation :

(x+5)(x+3) = 0

X=-5,-3

(y-4)(y+3) = 0

Y=4,-3

4,-3,-3,-5

Yyxx => xâ‰¤y**I. 4X**^{2 }Â – 13X – 12= 0

**II. Y**^{2 }– 7Y – 60 = 0Answer –**5)If X=Y or cannot be established**

Explanation :

(x-4)(4x+3) = 0

X=4, -3/4

(x+5)(x-12) =0

Y = 12, -5

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