Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in **Quadratic Equations** which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Follow the link **To solve Quadratic Equations with the help of Number Line**

**You have to solve equation I and II ,Give answer
A) If X > Y
B) If X < Y
C) If X ≥ Y
D) If X ≤ Y
E) If X = Y or cannot be established**

**I. 2X**^{2 }+ 11X + 12= 0

**II.5Y**^{2 }+ 27Y + 10 = 0Answer –**5)If X=Y or cannot be established**

**Explanation :**

(2x+3)(x+4) = 0

X= -3/2, -4

(5y+2)(y+5) = 0

Y = -5, -2/5

-0.4, -1.5, -4, -5 => yxxy**I. 25X**^{2 }+ 25X + 6= 0

**II.5Y**^{2 }+ 20Y + 20 = 0Answer –**1)If X>Y**

**Explanation :**

(5x+2)(5x+3) = 0

X = -2/5, -3/5

(5y+10)(y+2) = 0

Y = -2, -10/5 = -2, -2

-2/5, -3/5, -2, -2=> xxyy

x>y**I. 3X**^{2 }+ 7X + 4= 0

**II.3Y**^{2 }+ 10Y + 8 = 0Answer –**3)If X≥ Y**

**Explanation :**

(x+1)(3x+4) = 0

X=-1, -4/3

(3y+4)(y+2) =0

Y = -4/3, -2

-1, -4/3, -4/3, -2 => xxyy

X≥ Y**I.(x+y)**^{2}= 900

**II.Y + 1689 = 1705**Answer –**2)If X<Y**

**Explanation :**

y = 1705 – 1689 = 16

(x + y)^{2}= 900

x + y = 30

x = 30 – 16 = 14

16>14

Clearly,*x < y***I.8X**^{2 }+ 3X – 38= 0

**II.6Y**^{2 }– 29Y + 34 = 0Answer –**4)If X≤ Y**

**Explanation :**

8X^{2 }+ 3X – 38= 0

(8x + 19) (x – 2) = 0

x = 2 or -19/8

6Y^{2 }– 29Y + 34 = 0

(y – 2) (6y – 17) = 0

y = 2 or 17/6

17/6, 2, 2, -19/8 => yyxx

X≤ Y**9x – 3x = 64.55 + 19.45**

**√(y *155) = 7 + 6**Answer –**5)If X=Y or cannot be established**

**Explanation :**

9x – 3x = 64.55 + 19.45

6x = 84

x = 14

√(y *155) = 7 + 6 =13

y + 155 = 169

y = 169 – 155 = 14

x=y**I.2X**^{2 }+ 19X + 44= 0

**II.2Y**^{2 }+ 3Y – 20 = 0Answer –**4)If X≤ Y**

**Explanation :**

2X^{2 }+ 19X + 44= 0

(x + 4) (2x + 11) = 0

x = -4 or -11/2

2Y^{2 }+ 3Y – 20 = 0

(y + 4) (2y – 5) = 0

y = -4 or 5/2

5/2, -4,-4,-5/2 = yyxx

X≤ Y**I.P**^{2 }+ 9P = 2P – 12

**II.4Q**^{2 }+ 8Q = 4Q + 8Answer –**2)If X<Y**

**Explanation :**

p^{2}+ 9p = 2p – 12

(p + 3) (p + 4 ) = 0

p = – 3, – 4

4q^{2}+ 8q = 4q + 8

4q2 + 4q – 8 = 0

(q + 2) (q – 1) = 0

q = -2, 1

1, -2,-3,-4 => QQPP

P<Q**I.2X**^{2 }– 7X + 6= 0

**II.4Y**^{2 }= 9Answer –**3)If X≥ Y**

**Explanation :**

2X^{2 }– 7X + 6= 0

(*x*– 2) (2*x*– 3) = 0

*x*= 2 or*x*=3/2

4Y^{2 }= 9

Y = ±3/2 = 3/2, -3/2

2,3/2,3/2,-3/2 = xxyy

x≥y**I. X**^{2 }= 1296

**II.Y = √1296**Answer –**4)If X≤ Y**

**Explanation :**

X = ±36

Y = 36

X**≤**Y

**Note :** Dear Aspirants try to post your attempts and time here

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