Aptitude Questions: Quadratic Equations Set 13

Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions inÂ Quadratic Equations which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Follow the link To solve Quadratic Equations with the help of Number Line

You have to solve equation I and II ,Give answer
A) If X > Y
B) If X < Y
C) If X â‰¥ Y
D) If X â‰¤ Y
E) If X = Y or cannot be established

1. I. 2X2 + 11X + 12= 0
II.5Y2 + 27Y + 10 = 0
Answer – 5)If X=Y or cannot be established
Explanation :
(2x+3)(x+4) = 0
X= -3/2, -4
(5y+2)(y+5) = 0
Y = -5, -2/5
-0.4, -1.5, -4, -5 => yxxy

2. I. 25X2 + 25X + 6= 0
II.5Y2 + Â 20Y + 20 = 0
Answer – 1)If X>Y
Explanation :
(5x+2)(5x+3) = 0
X = -2/5, -3/5
(5y+10)(y+2) = 0
Y = -2, -10/5 = -2, -2
-2/5, -3/5, -2, -2=> xxyy
x>y

3. I. 3X2 + 7X + 4= 0
II.3Y2 + Â 10Y + 8 = 0
Answer – 3)If Xâ‰¥ Y
Explanation :
(x+1)(3x+4) = 0
X=-1, -4/3
(3y+4)(y+2) =0
Y = -4/3, -2
-1, -4/3, -4/3, -2 => xxyy
Xâ‰¥ Y

4. I.(x+y)2 = 900
II.Y + 1689 = 1705
Answer – 2)If X<Y
Explanation :
y = 1705 – 1689 = 16
(x + y)2 = 900
x + y = 30
x = 30 – 16 = 14
16>14
Clearly, x < y

5. I.8X2 + 3X – 38= 0
II.6Y2 – Â 29Y + 34 = 0
Answer – 4)If Xâ‰¤ Y
Explanation :
8X2 + 3X – 38= 0
(8x + 19) (x – 2) = 0
x = 2 or -19/8
6Y2 – Â 29Y + 34 = 0
(y – 2) (6y – 17) = 0
y = 2 or 17/6
17/6, 2, 2, -19/8 => yyxx
Xâ‰¤ Y

6. 9x – 3x = 64.55 + 19.45
âˆš(y *155) = 7 + 6
Answer – 5)If X=Y or cannot be established
Explanation :
9x – 3x = 64.55 + 19.45
6x = 84
x = 14
âˆš(y *155) = 7 + 6 =13
y + 155 = 169
y = 169 – 155 = 14
x=y

7. I.2X2 + 19X + 44= 0
II.2Y2 + Â 3Y – 20 = 0
Answer – 4)If Xâ‰¤ Y
Explanation :
2X2 + 19X + 44= 0
(x + 4) (2x + 11) = 0
x = -4 or -11/2
2Y2 + Â 3Y – 20 = 0
(y + 4) (2y – 5) = 0
y = -4 or 5/2
5/2, -4,-4,-5/2 = yyxx
Xâ‰¤ Y

8. I.P2 + 9P = 2P – 12
II.4Q2 + Â 8Q = 4Q + 8
Answer – 2)If X<Y
Explanation :
p2 + 9p = 2p – 12
(p + 3) (p + 4 ) = 0
p = – 3, – 4
4q2 + 8q = 4q + 8
4q2 + 4q – 8 = 0
(q + 2) (q – 1) = 0
q = -2, 1
1, -2,-3,-4 => QQPP
P<Q

9. I.2X2 – 7X + 6= 0
II.4Y2 = 9
Answer – 3)If Xâ‰¥ Y
Explanation :
2X2 – 7X + 6= 0
(x – 2) (2x – 3) = 0
x = 2 or x =3/2
4Y2 = 9
Y = Â±3/2 = 3/2, -3/2
2,3/2,3/2,-3/2 = xxyy
xâ‰¥y

10. I. X2 Â = 1296
II.Y Â = âˆš1296
Answer – 4)If Xâ‰¤ Y
Explanation :
X = Â±36
Y = 36
Xâ‰¤Y

Note : Dear Aspirants try to post your attempts and time here

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