Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in **Quadratic Equations** which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

**You have to solve equation I and II ,Give answer**

**1)If X>Y**

**2)If X<Y**

**3)If X≥ Y**

**4)If X≤ Y **

**5)If X=Y or cannot be established**

**I.4/√x + 3/√x = √x**

**II. Y**^{2}– (7^{5/2}/√y) = 0

Answer –**5)If X=Y or cannot be established**

**Explanation :**

7/√x = /√x

X =7

(Y^{35/2}– 7^{5/2 })/√y=0

Y^{5/2}=7^{5/2}

y = 7 x=y

**I. X**^{2/3 }= 49

**II.Y =(-4)**^{4 }

Answer –**1)If X>Y**

**Explanation :**

X = 7^{3}= 343

Y = -4*-4*-4*-4 = 256

x>y

**I. X**^{2 }– 18X + 72= 0

**II.Y**^{2 }– 20Y + 99 = 0

Answer –**5)If X=Y or cannot be established**

**Explanation :**

(x-12)(x-6) = 0

X=6,12

(y-11)(y-9) = 0

Y=9,11

12,11,9,6=> xyyx

**I.X = ±√441**

**II.Y = (9261)**^{1/3}

Answer –**4)If X≤ Y**

**Explanation :**

X=±21

Y = 21

**I. X**^{2 }– 698 = 326

**II.Y**^{2}+ 528 = 1552

Answer –**5)If X=Y or cannot be established**

**Explanation :**

X^{2 }= 326+698 =1024

Y^{2}=1552 – 528 = 1024

X=y = ±32

**I. 2X**^{2 }+ 11X + 12= 0

**II.2Y**^{2 }+ 19Y + 45 = 0

Answer –**1)If X>Y**

**Explanation**

(2x+8)(2x+3) = 0

X= -8/2, -3/2 = -4,-1.5

(2y+10)(2y+9) = 0

Y= -10/2, -9/2 = -5, -4.5

-1.5,-4,-4.5,-5 => xxyy

x>y

**I. 21X**^{2 }– 23X + 6= 0

**II.2Y**^{2 }– 11Y + 15 = 0

Answer –**2)If X<Y**

**Explanation :**

(7x-3)(3x-2) = 0

X=3/7, 2/3 = 0.43, 0.67

(2y-5)(y-3) = 0

Y=3,5/2=3,2.5

3,5/2,2/3,3/7 => yyxx

X<y

**I. 3X**^{2 }+ 10X + 8= 0

**II.3Y**^{2 }+ 7Y + 4 = 0

Answer –**4)If X≤ Y**

**Explanation :**

(3x+4)(x+2) = 0

X= -2,-4/3

(y+1)(3y+4) = 0

Y= -1,-4/3

-1,-1.3,-1.3,-2 => yyxx

x≤y

**I. 25X**^{2 }+ 25X + 6= 0

**II.5Y**^{2 }+ 20Y + 20 = 0

Answer –**1)If X>Y**

**Explanation :**

(5x+2)(5x+3) =0

X= -2/5, -3/5 = -0.4, -0.6

(5x+10)(x+2) = 0

X= -10/5, -2 = -2, -2

-0.4, -0.6, -2, -2 => Xxyy

X>y

**I. 2X**^{2 }+ 5X + 2= 0

**II.4Y**^{2 }– 1 = 0

Answer –**4)If X≤ Y**

**Explanation :**

(2x+1)(x+2) =0

X= -1/2, -2

Y^{2 }= ±1/2 = ½, -1/2

½,-1/2,-1/2, -2

yxxy

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