Quantitative Aptitude Questions for IBPS/RRB Exam Set – 18

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1. What is the probability that when 3 cards are pulled from a pack of cards without replacement that we get 1 king, 1 queen and 1 jack?
   A. 16/35139
   B. 1/2179
   C. 16/5525
   D. 16/2179
   
   Answer

   C. 16/5525
   Explanation:
   Case 1: first chosen is king, second is queen and third jack:
   Prob = 4/52 * 4/51 * 4/50
   There will be 6 cases like this, so total prob = (4/52 * 4/51 * 4/50) * 6
   
   
   
2. In an examination consisting of 4 subjects, the marks obtained by Ram in 3 of them are 90%, 95% and 95% resp. Each subject is of equal marks. Under the given circumstances his average percentage marks for the examination cannot be
   A. 94%
   B. 90%
   C. 93%
   D. 96%
   
   Answer

   D. 96%
   Explanation:
   Let 100 be max marks of each subject. Check each option now.
   From option D, (90+95+95+x)/4 = 96, it gives x = 104 which is not possible because max marks is 100.
   
   
   
3. The radius of a sphere is 14 cm. The cost of painting the surface of sphere is Rs 25 per square cm. If the radius of sphere is increased by 10%, then the cost of painting is increased by 20%. What is the percentage increase in the total cost of painting per square cm?
   A. 45.2%
   B. 54.27%
   C. 20.3%
   D. 18.2%
   
   Answer

   A. 45.2%
   Explanation:
   Radius increases by 10%, so surface area changes by 10+10+((10*10)/100) = 21%
   Total cost of painting = Rate * Surface area of sphere
   So change in cost of painting = 21+20+((21*20)/100) = 45.2%
   
   
   
4. In an election there were only two candidates A and B, B got 50% of the votes that A got. Had A got 200 votes less, there would have been a tie. How many people casted their votes in all?
   A. 1000
   B. 1500
   C. 1200
   D. 1800
   
   Answer

   C. 1200
   Explanation:
   Let total votes casted = x
   then 50/100 * A + A = x
   when A got 200 votes less, means these 200 votes goes to B, there is tie, so
   A – 200 = 50/100 * A + 200
   A = 800
   x = 1200
   
   
5. A 3 : 2 milk and water solution is mixed with another 4 : 1 milk and water solution. If the volumes are 400 ml and 1,000 ml resp., then what is the ratio of milk to water in the resultant solution?
   A. 9 : 5
   B. 8 : 21
   C. 5 : 26
   D. 26 : 9
   
   Answer

   D. 26 : 9
   Explanation:
   In 400 lit, milk = 3/8 * 400 = 240 lit, water = 160 lit
   In 1000 lit, milk = 4/5 * 400 = 800 lit, water = 200 lit
   New ratio = (240+800)/(160+200)
   
   
   
6. In 40 litres mixture of milk and water, the ratio of milk to water is 7 : 1. In order to make the ratio of milk and water 3 : 1, the quantity of water should be added to the mixture will be
   A. 6 3/4 litres
   B. 6 2/3 litres
   C. 6 litres
   D. 6 1/3 litres
   
   Answer

   B. 6 2/3 litres
   Explanation:
   In 40 lit, milk = 7/8 * 40 = 35 lit, water = 5 lit
   Let x lit of water to be added, so
   35/(5+x) = 3/1
   
   
   
7. A man swims downstream 30 km and upstream 18 km, taking 3 hrs each time. What is the speed of current?
   A. 6 km/hr
   B. 4 km/hr
   C. 2 km/hr
   D. 10 km/hr
   
   Answer

   C. 2 km/hr
   Explanation:
   Downstream speed = 30/3 = 10, Upstream speed = 18/3 = 3
   Speed of stream = (10 – 6)/2
   
   
   
8. A man can row 7 km/hr in still water. In a stream which is flowing at 3 km/hr, it takes him 7 hrs to row to a place and come back. How far is the place?
   A. 25 km
   B. 20 km
   C. 10 hm
   D. 15 km
   
   Answer

   B. 20 km
   Explanation:
   Distance = T (B^2 – R^2)/2*B
   =7 (7^2 – 3^2)/2*7 = 20 km
   
   
   
9. If a sum of money at a certain rate of interest doubles in 5 years and at a different rate of simple interest becomes three times in 12 years, then the better rate of interest is in
   A. case-1
   B. case-2
   C. equal in both cases
   D. None of these
   
   Answer

   A. case-1
   Explanation:
   Case 1: SI = 2P – P = P, so P = P*r*5/100, so r = 20%
   Case 1: SI = 3P – P = 2P, so 2P = P*r*12/100, so r = 16.66%
   
   
   
10. The population of a town increases 10% half-yearly. What is the population after one and half years, if the initial population is 1,000?
    A. 1331
    B. 1300
    C. 1200
    D. 1210
    
    Answer

    A. 1331
    Explanation:
    Solve it by the method of compounded semi-annually.