Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS and RRB exams. We have included Some questions that are repeatedly asked in exams.

**If the price of petrol is increased by 30%, by how much percent a car owner must reduce his consumption in order to maintain the same budget?**

A) 21%

B) 21 1/3%

C) 23 1/13%

D) 33%C) 23 1/13%

Explanation:

30/(100+30) * 100**Rani got 30% discount on the marked price of an article and sold it for Rs 8750 with 25% profit on the price he bought. What was the marked price?**

A) Rs 10,000

B) Rs 12,000

C) Rs 16,000

D) Data inadequateA) Rs 10,000

Explanation:

C.P. = 100/(100+25) * 8750 = 7000

(100-30)/100 * x = 7000;**A shopkeeper sold a table for Rs. 17,940 with a discount of 8% and earned a profit of 19.6%. What would have been the percentage of profit if no discount was offered?**

A) 24.8%

B) 25%

C) 26.4%

D) None of theseD) None of these

Explanation:

MP=100/(100-8) * 1740 = 19500

CP= 17940*(100/100+19.6)=15000

now if no discount given then SP = MP that is 19500

so profit = 19500-15000 = 4500

so p%= (4500/15000) * 100 = 30%**400 persons, working 9 hours per day complete 1/4th of the work in 10 days. The number of additional persons, working 8 hours per day, required to complete the remaining in 20 days is**

A) 200

B) 225

C) 250

D) 275D) 275

Explanation:

Remaining work = 1 – 1/4 = 3/4

400 * 9 * 10 * 3/4 = (400+x) * 8 * 20 * 1/4**The sum of money becomes Rs 13,380 after 3 years and Rs 20,070 after 6 years on compound interest. The sum is**

A) Rs. 8,800

B) Rs. 8,890

C) Rs. 8,920

D) Rs. 9,050C) Rs. 8,920

Explanation:

P [1 + r/100]^3 = 13380

P [1 + r/100]^6 = 20070

Divide both equations, u get

[1 + r/100]^3 = 669/446

put this value in first eq and solve for P**The sum was put at simple interest at a certain rate of interest for 3 years Had it been put at 2% higher rate, it would have fetched Rs 360 more. Find the sum.**

A) Rs. 6,000

B) Rs. 6,200

C) Rs. 6,020

D) Rs. 7,050A) Rs. 6,000

Explanation:

let previous rate is r%, new rate (r+2)%

P*(r+2)*3/100 – P*r*3/100 = 360**A man takes 5 hrs 45 min in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. The time he would take to walk both ways is**

A) 3 hrs 45 min

B) 7 hrs 30 min

C) 7 hrs 45 min

D) 11 hrs 45 minC) 7 hrs 45 min

walking both ways = (walking+riding time) + (gain in hours riding both ways)

* riding both ways = (walking+riding time) – (gain in hours walking both ways)**A alone can complete a work in 16 days and B alone in 12 days. Starting with A,, they work on alternate days. The total work will be completed in**

A) 12 days

B) 13 days

C) 13 5/7 days

D) 13 3/4 daysD) 13 3/4 days

Explanation:

2 day’s work of A+B = 1/16 + 1/12 = 7/48

Multiply by 6 both sides,

12 day’s work of A+B = 42/48

Work left = 1 – 42/48 = 6/48 = 1/8

Now on 13th day, its A’ s turn, he does 1/16th work out of remaining 1/8th

so after 13th day, work left = 1/8 – 1/16 = 1/16

now on 14th days, B’s turn, he does 1/12th work in 1 day, so remaining 1/16th work in 3/4th day

so total days 13 3/4**A, B and C can do a piece of work in 36, 54 and 72 days respectively. They started the work but A left 8 days before the completion of work while B left 12 days before the completion. The number of days for which C worked is**

A) 8

B) 12

C) 20

D) 24D) 24

Explanation:

Let total number of days is x. C worked for all x days.

(1/72) * x + (1/36) * (x-8) + (1/72) * (x-12) = bb 1**12 men complete a work in 9 days. After they have worked for 6 days, 6 more men join them. How many days will they take to complete the remaining work?**

A) 2 days

B) 3 days

C) 4 days

D) 5 daysA) 2 days

Explanation:

After 6 days, the work that can be completed by 12 people in 3 remaining days, let that work be completed by (12+6) = 18 people in x days.

18 * x = 12 * 3

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