# Quantitative Aptitude Questions for IBPS/RRB Exam Set – 24

Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS and RRB exams. We have included Some questions that are repeatedly asked in exams.

1. If the price of petrol is increased by 30%, by how much percent a car owner must reduce his consumption in order to maintain the same budget?
A) 21%
B) 21 1/3%
C) 23 1/13%
D) 33%
C) 23 1/13%
Explanation:
30/(100+30) * 100

2. Rani got 30% discount on the marked price of an article and sold it for Rs 8750 with 25% profit on the price he bought. What was the marked price?
A) Rs 10,000
B) Rs 12,000
C) Rs 16,000
A) Rs 10,000
Explanation:
C.P. = 100/(100+25) * 8750 = 7000
(100-30)/100 * x = 7000;

3. A shopkeeper sold a table for Rs. 17,940 with a discount of 8% and earned a profit of 19.6%. What would have been the percentage of profit if no discount was offered?
A) 24.8%
B) 25%
C) 26.4%
D) None of these
D) None of these
Explanation:
MP=100/(100-8) * 1740 = 19500
CP= 17940*(100/100+19.6)=15000
now if no discount given then SP = MP that is 19500
so profit = 19500-15000 = 4500
so p%= (4500/15000) * 100 = 30%

4. 400 persons, working 9 hours per day complete 1/4th of the work in 10 days. The number of additional persons, working 8 hours per day, required to complete the remaining in 20 days is
A) 200
B) 225
C) 250
D) 275
D) 275
Explanation:
Remaining work = 1 – 1/4 = 3/4
400 * 9 * 10 * 3/4 = (400+x) * 8 * 20 * 1/4

5. The sum of money becomes Rs 13,380 after 3 years and Rs 20,070 after 6 years on compound interest. The sum is
A) Rs. 8,800
B) Rs. 8,890
C) Rs. 8,920
D) Rs. 9,050
C) Rs. 8,920
Explanation:
P [1 + r/100]^3 = 13380
P [1 + r/100]^6 = 20070
Divide both equations, u get
[1 + r/100]^3 = 669/446
put this value in first eq and solve for P

6. The sum was put at simple interest at a certain rate of interest for 3 years Had it been put at 2% higher rate, it would have fetched Rs 360 more. Find the sum.
A) Rs. 6,000
B) Rs. 6,200
C) Rs. 6,020
D) Rs. 7,050
A) Rs. 6,000
Explanation:
let previous rate is r%, new rate (r+2)%
P*(r+2)*3/100 – P*r*3/100 = 360

7. A man takes 5 hrs 45 min in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. The time he would take to walk both ways is
A) 3 hrs 45 min
B) 7 hrs 30 min
C) 7 hrs 45 min
D) 11 hrs 45 min
C) 7 hrs 45 min
walking both ways = (walking+riding time) + (gain in hours riding both ways)
* riding both ways = (walking+riding time) – (gain in hours walking both ways)

8. A alone can complete a work in 16 days and B alone in 12 days. Starting with A,, they work on alternate days. The total work will be completed in
A) 12 days
B) 13 days
C) 13 5/7 days
D) 13 3/4 days
D) 13 3/4 days
Explanation:
2 day’s work of A+B = 1/16 + 1/12 = 7/48
Multiply by 6 both sides,
12 day’s work of A+B = 42/48
Work left = 1 – 42/48 = 6/48 = 1/8
Now on 13th day, its A’ s turn, he does 1/16th work out of remaining 1/8th
so after 13th day, work left = 1/8 – 1/16 = 1/16
now on 14th days, B’s turn, he does 1/12th work in 1 day, so remaining 1/16th work in 3/4th day
so total days 13 3/4

9. A, B and C can do a piece of work in 36, 54 and 72 days respectively. They started the work but A left 8 days before the completion of work while B left 12 days before the completion. The number of days for which C worked is
A) 8
B) 12
C) 20
D) 24
D) 24
Explanation:
Let total number of days is x. C worked for all x days.
(1/72) * x + (1/36) * (x-8) + (1/72) * (x-12) = bb 1

10. 12 men complete a work in 9 days. After they have worked for 6 days, 6 more men join them. How many days will they take to complete the remaining work?
A) 2 days
B) 3 days
C) 4 days
D) 5 days
A) 2 days
Explanation:
After 6 days, the work that can be completed by 12 people in 3 remaining days, let that work be completed by (12+6) = 18 people in x days.
18 * x = 12 * 3

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