Hello Aspirants

Welcome to Online **Quants** **Test** in AffairsCloud.com. We are starting **Cumulus Course for IBPS PO 2018 Main Exam** and we are creating sample questions in Quants section, this type of Question will be asked in IBPS PO 2018!!!

**Click Here to View Cumulus Course: IBPS PO 2018 Mains**

**IBPS PO 2018 Mains: GA Test **– 7 PM Every Day

**IBPS PO 2018 Mains: Reasoning Test **– 8 PM Every Day

**IBPS PO 2018 Mains: Quants Test **– 9 PM Every Day

**IBPS PO 2018 Mains: English Test **– 10 PM Every Day

**Help:- **Share Our Cumulus Course for IBPS PO 2018 Exam Course page to your Friends & FB Groups

**Best Mock Test Series for IBPS PO Exam**

________________________

#### Quiz-summary

0 of 10 questions completed

Questions:

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10

#### Information

**All the Best**

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

#### Results

0 of 10 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

#### Categories

- Quantitative Aptitude 0%

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10

- Answered
- Review

- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Given below is the table which shows the ratio of Efficiency of X and Y in completing five different works and time taken by X alone to complete these five works. Line Graph shows the number of days Y actually worked on these five works.**

**After Y had worked for the given number of days on work C and work D, X completes the remaining of work C and work D. Time taken by X in completing the remaining of work C is what percent more or less than time taken by him in completing the remaining of work D.**CorrectAnswer:

**2) 500/9 %**

Explanation:

Y alone will complete work C in= (8 *1)/2= 4 days

Y alone will complete work D in= (6 * 7)/6=7 days

Part of work C and work D completed by Y in given time= 2/4, 4/7

Remaining of work C and work D is completed by X

So,

X will complete remaining work of C= (1-2/4)*8= 4 days

X will complete remaining work of D= (1-4/7)*6= 18/7 days

Required %= ((4-(18/7)/ (18/7))* 100= 500/9%IncorrectAnswer:

**2) 500/9 %**

Explanation:

Y alone will complete work C in= (8 *1)/2= 4 days

Y alone will complete work D in= (6 * 7)/6=7 days

Part of work C and work D completed by Y in given time= 2/4, 4/7

Remaining of work C and work D is completed by X

So,

X will complete remaining work of C= (1-2/4)*8= 4 days

X will complete remaining work of D= (1-4/7)*6= 18/7 days

Required %= ((4-(18/7)/ (18/7))* 100= 500/9% - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Given below is the table which shows the ratio of Efficiency of X and Y in completing five different works and time taken by X alone to complete these five works. Line Graph shows the number of days Y actually worked on these five works.**

**X and Y together started working on work D but both left after working for 2 days. Remaining work is completed by M and N together in 4 days. If ratio of efficiency of X and M in completing work D is 7 : 3, then in how much time N alone will complete the work D.**CorrectAnswer:

**5) 42 days**

Explanation:

Y can complete work D= 6*7/6= 7 days

Part of work D completed by X and Y in 2 days= 2/6 + 2/7

= 1/3 + 2/7

= 13/21

Time taken by M in completing work D= (6/3) * 7= 14 days

So,

In 4 days M will complete= 4/14

= 2/7 part

M and N together complete= (1-13/21)= 8/21days

But M completes 2/7 of work D.

Remaining (8/21-2/7) = 2/21 is completed by N in 4 days

So, N alone will complete in work D= 4÷ 2/21= 42 daysIncorrectAnswer:

**5) 42 days**

Explanation:

Y can complete work D= 6*7/6= 7 days

Part of work D completed by X and Y in 2 days= 2/6 + 2/7

= 1/3 + 2/7

= 13/21

Time taken by M in completing work D= (6/3) * 7= 14 days

So,

In 4 days M will complete= 4/14

= 2/7 part

M and N together complete= (1-13/21)= 8/21days

But M completes 2/7 of work D.

Remaining (8/21-2/7) = 2/21 is completed by N in 4 days

So, N alone will complete in work D= 4÷ 2/21= 42 days - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Given below is the table which shows the ratio of Efficiency of X and Y in completing five different works and time taken by X alone to complete these five works. Line Graph shows the number of days Y actually worked on these five works.**

**If percentage of work C completed by X in 4 days is equal to the percentage of work C completed by 4 women in 5 hours and ratio of efficiency of a woman and a child in completing work C is 5 : 3, then in how much time work C will be completed by 6 children**CorrectAnswer:

**1) 100/9 hours**

Explanation:

% of work C Completed by X in 4 days

= 4/8 * 100

= 50%

This is equal to work C completed by 4 women in 4 days

So, one woman will complete= 40 days

One child will complete= (40/3) * 5

6 children will complete= ( (40*5) / (3*6))= 100/9 daysIncorrectAnswer:

**1) 100/9 hours**

Explanation:

% of work C Completed by X in 4 days

= 4/8 * 100

= 50%

This is equal to work C completed by 4 women in 4 days

So, one woman will complete= 40 days

One child will complete= (40/3) * 5

6 children will complete= ( (40*5) / (3*6))= 100/9 days - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

**If another person Z can complete work B in (Q – P) days where P and Q are the times taken by X and Y together to complete work B and C respectively, then what is the ratio of efficiency of Y and Z in completing work B?**CorrectAnswer:

**3) 1:9**

Explanation:

Y will complete in work B= (4*5) / 5= 4 days

Y will complete in work C= (8*1) / 2= 4 days

P= (5*4)/9 = 20/9days

Q= (8*4)/12= 8/3 days

Z will complete in work B= 8/3 – 20/9= (24-20)/9 = 4/9 days

Ratio of time taken by Y and Z in completing work B

= 4: 4/9

=9: 1

Ratio of efficiency= 1:9IncorrectAnswer:

**3) 1:9**

Explanation:

Y will complete in work B= (4*5) / 5= 4 days

Y will complete in work C= (8*1) / 2= 4 days

P= (5*4)/9 = 20/9days

Q= (8*4)/12= 8/3 days

Z will complete in work B= 8/3 – 20/9= (24-20)/9 = 4/9 days

Ratio of time taken by Y and Z in completing work B

= 4: 4/9

=9: 1

Ratio of efficiency= 1:9 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

**After Y had worked for the given numbers of days on work C, D and E, what is the sum of times taken by X in completing the remaining of work C, D and E?**CorrectAnswer:

**5) 60/7 days**

Explanation:

Y alone will complete work C, D and E will be 4, 7 and 9/2 days respectively.

Part of work of C, D and E done by Y = 2/4, 4/7 and 2/3 days respectively.

Remaining of work C, D and E is completed by X= (1/2) * 8, (3/7) *6, (1/3) * 6 days respectively.

Required sum= 4 + 18/7 + 2

= 6 + 18/7

= 60/7 daysIncorrectAnswer:

**5) 60/7 days**

Explanation:

Y alone will complete work C, D and E will be 4, 7 and 9/2 days respectively.

Part of work of C, D and E done by Y = 2/4, 4/7 and 2/3 days respectively.

Remaining of work C, D and E is completed by X= (1/2) * 8, (3/7) *6, (1/3) * 6 days respectively.

Required sum= 4 + 18/7 + 2

= 6 + 18/7

= 60/7 days - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**The following pie-chart shows the percentage of passed candidates in SBI exam from cities X,Y,Z,K,L and M out of the total passed candidates from all six cities together in year 2010.**

Table shows the percentage of fresher candidates who passed from each city out of the total passed from that city in year 2010.

**If in year2010, total number of freshers passed from city K was320, then how many fresher candidates passed the SBI exam from city L?**CorrectAnswer –

**1) 384**

Explanation

Let the total number of candidates passed in exam for city K be x.

25 % of x = 320

X = 320x 100/25 = 1280

Total passed candidates from all city K is1280

Total passed candidates from all city be y

10% of y =1280

Y= 12800

Total passed from city L

=25/100 x12800 = 3200

Total passed candidates from city L

=12/100 x 3200 = 384IncorrectAnswer –

**1) 384**

Explanation

Let the total number of candidates passed in exam for city K be x.

25 % of x = 320

X = 320x 100/25 = 1280

Total passed candidates from all city K is1280

Total passed candidates from all city be y

10% of y =1280

Y= 12800

Total passed from city L

=25/100 x12800 = 3200

Total passed candidates from city L

=12/100 x 3200 = 384 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**The following pie-chart shows the percentage of passed candidates in SBI exam from cities X,Y,Z,K,L and M out of the total passed candidates from all six cities together in year 2010.**

Table shows the percentage of fresher candidates who passed from each city out of the total passed from that city in year 2010.

**If in year 2010, total passed candidates from all cities was 1250, then what is the number of the non-fresher candidates from cityX who passed the SBI exam in same year?**CorrectAnswer –

**4)280**

Explanation

Non fresger candidates who passed from city X

=1250 x 28/100 x 80/100

=280IncorrectAnswer –

**4)280**

Explanation

Non fresger candidates who passed from city X

=1250 x 28/100 x 80/100

=280 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**The following pie-chart shows the percentage of passed candidates in SBI exam from cities X,Y,Z,K,L and M out of the total passed candidates from all six cities together in year 2010.**

Table shows the percentage of fresher candidates who passed from each city out of the total passed from that city in year 2010.

**If the non-fresher candidates passed from city Y in year 2010 were 180, then how many total candidates passed the SBI exam from all cities together?**CorrectAnswer-

**3)1500**

Explanation

Toatl passed candidates from city Y

=180 x 100/75 = 240

A total candidates passed from all cities = 240×100/16 = 1500IncorrectAnswer-

**3)1500**

Explanation

Toatl passed candidates from city Y

=180 x 100/75 = 240

A total candidates passed from all cities = 240×100/16 = 1500 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude

**If there is an increase of 10% and 20% in the number of passed candidates in city X and Y in year 2011 respectively from year 2010 and total passed candidates from city Z in 2010 was 770. Then what would be the difference in no. of passed candidates from city X and Y in year 2011?**CorrectAnswer –

**2)812**

Explanation

Total no. of candidates passed in 2010 = 770 x 100/11 = 7000

No. of candidates passed from city X in 2010

=28/100 x 7000 = 1960

Candidates passed in 2011 from city X

=110/100 x 1960 = 2156

No. of candidates passed from city Y in 2010

=16/100 x 7000 = 1120

Candidates passed in 2011 from city Y

=120/100 x 1120 = 1344

Required difference = 2156-1344

=812IncorrectAnswer –

**2)812**

Explanation

Total no. of candidates passed in 2010 = 770 x 100/11 = 7000

No. of candidates passed from city X in 2010

=28/100 x 7000 = 1960

Candidates passed in 2011 from city X

=110/100 x 1960 = 2156

No. of candidates passed from city Y in 2010

=16/100 x 7000 = 1120

Candidates passed in 2011 from city Y

=120/100 x 1120 = 1344

Required difference = 2156-1344

=812 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude

**If total passed candidates from city Y in year 2010 was 320, then what is the ratio between the no. of fresher passed from city X and that of non-fresher passed from city Z?**CorrectAnswer –

**1)112:187**

Explanation

Total candidates passed = 320 x 100/16 = 2000

Candidates passed from city Z = 11/100 x 2000 = 220

Non-fresher candidates passed from Z

=85/100 x 220 = 187

Candidates passed from city X

=28/100 x 2000 = 560

Fresher candidates passed from X = 20/100 x 560 = 112

Required ratio = 112: 187IncorrectAnswer –

**1)112:187**

Explanation

Total candidates passed = 320 x 100/16 = 2000

Candidates passed from city Z = 11/100 x 2000 = 220

Non-fresher candidates passed from Z

=85/100 x 220 = 187

Candidates passed from city X

=28/100 x 2000 = 560

Fresher candidates passed from X = 20/100 x 560 = 112

Required ratio = 112: 187

**Click view Questions button to view Explanation****Note:-**We are providing unique questions for you to practice well, have a try !!- Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
- If you find any mistake, please tell us in the comment section.