Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample from **Mensuration** that is important for all the competitive exams. We have included Some questions that are repeatedly asked in exams !!

**A room 24cm long and 32cm broad is to be paved with equal no of tiles. Find the no of largest tiles requires so that the tiles exactly fit.**

A.15

B.12

C.17

D.19

E.None of theseAnswer –**B.12**

**Explanation :**

HCF of 24,32 = 8

No of tiles = L *B/(HCF)^{2}

= 24*32/8*8 = 12**A circular garden has a path of uniform width around it. The difference between outer and inner circumference of the circular path is 210cm.Find its width.**

A.33.44cm

B.30.34cm

C.40.24cm

D.28.64cm

E.None of theseAnswer –**A.33.44cm**

**Explanation :**

2*3.14*R – 2*3.14*r = 210

R-r = 210/2*3.14 = 33.44cm**The length of a rectangular plot is 3 folds its width. Half the area of the plot is covered by a playground whose area is 363 square meter. What is the length of the plot?**

A.18.50m

B.13.61m

C.17.21m

D.15.51m

E.None of theseAnswer –**D.15.51m**

**Explanation :**

X * 3X = 320*2

3x^{2 }= 363*2

x^{2 }= 363*2/3 = 121*2

x = 11*1.41 = 15.51**A rectangular field has its length and breadth in the ratio 6:5 respectively. A man riding bicycle complete one lap of this field along its perimeter at the speed of 12kmph in 1.5m. What is the area of the field ?**

A.5345

B.5487

C.5468

D.5460

E.None of theseAnswer –**C.5468**

**Explanation :**

Speed = 12*5/18 = 3.3 m/s

Perimeter = Distance

2(6x+5x) = 90*3.3

22x= 297

X=13.5

Area = 6*13.5 *5*13.5 = 5467.5 = 5468sq.m**One of the angles of a parallelogram is 65degree. What will be the sum of twice the largest angle and thrice the smallest angle of the parallelogram ?**

A.460degree

B.375degree

C.235degree

D.425degree

E.None of theseAnswer –**D.425degree**

**Explanation :**

180-65 = 115

2*115+ 3*65 = 230+195 = 425**The area of the square is three-fifth the area of a rectangle. The length of the rectangle is 25cm and breadth 10cm less than its length. What is the area of the square ?**

A.20cm

B.12cm

C.15cm

D.17cm

E.None of theseAnswer –**C.15cm**

**Explantion :**

Area of rectangle = 25*15 = 375sq.cm

Area of square = 3*375/5 = 225sq.cm = a*a

Side of the square = a = 15cm**What will be the cost of painting a hall whose area is 256sq m, if the rate of painting per sq m is Rs.22.**

A.Rs.1256

B.Rs.1350

C.Rs.2225

D.Can’t be determined

E.None of theseAnswer –**D.Can’t be determined**

**Explanation :**

Hall shape and it’s parameter was not given**The width of a rectangle is 10 meter and its area is 120 square meter. If length of the rectangle is increased by 6.What is the new perimeter of the rectangle?**

A.65

B.43

C.56

D.32

E.None of theseAnswer –**C.56**

**Explanation :**

Length = 120/10 = 12

(12+6) = 18

Perimeter = 2(10+18) = 56**If the sides of a triangle measure 62cm, 70cm and 18cm, what is the measure of its in radius?**

A.7cm

B.6cm

C.4cm

D.9cm

E.None of theseAnswer –**A.7cm**

**Explanation :**

Radius = product of perpendicular side/ perimeter of traingle

R = 62*18/62+70+18 = 1116/150 = 7.44 = 7cm**Four horses are tethered at 4 corners of a square field of side 60 metres so that they just cannot reach one another. The area left ungrazed by the horses is:**

A.841m

B.771m

C.612m

D.523m

E.None of theseAnswer –**B.771m**

**Explanation :**

Length of the rope = 60/2 = 30m

Total area covered by 4 horse = 22*30*30/7

Ungrazed area = Area of Square field – area covered by 4 horse

= 3600 – 2829 = 771m

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