**Hello Aspirants**. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in **Inequalities** which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

**The respective ratio between the present age of Mohan and David is 5:x. Mohan is 9 years younger than Preethi. Preethi’s age after 9 years will be 33 years. The difference between David’s and Mohan’s age is same as the present age of Preethi.**

**Quantity I: Mohan’s present age**

**Quantity II: The value of x**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relation cannot be established**A. Quantity I > Quantity II**

Explanation:

Preethi’s age after 9 years = 33 years

Preethi’s present age = 33 – 9 = 24 years

Mohan’s present age = 24 – 9 = 15 years

David’s present age = 15 + 24 = 39 years

Ratio between Mohan and David = 15 : 39 = 5 : 13

X = 13**Sri invested some amount(x) at the rate of 12% simple interest and a certain amount(y) at the rate of 10% simple interest. He received yearly interest of Rs.140. But if he had interchanged the amounts invested, he would have received Rs.4 more as interest.**

**Quantity I: The value of x**

**Quantity II: The value of y**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relation cannot be established**B. Quantity I < Quantity II**

Explanation:

Amount invested at 12% = Rs. x

Amount invested at 10% = Rs. y

140 = x*12*1/100 + y*10*1/100

12x + 10y = 14000 -(i)

144 = x*10*1/100 + y*12*1/100

10x + 12y = 14400 -(ii)

x = 545.45; y = 745.45**Ajith can do a piece of work in 10 days, Bala in 15 days. They work together for 5 days, the rest of the work is finished by Chand in two more days. They get Rs. 6000 as wages for the whole work.**

**Quantity I: What is the sum of Rs.100 and the daily wage of Bala?**

**Quantity II: What is the daily wage of Chand?**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relation cannot be established**E. Quantity I = Quantity II or relation cannot be established**

Explanation:

Ajith’s 5 days work = 50%

Bala’s 5 days work = 33.33%

Chand’s 2 days work = 16.66%[100- (50+33.33)]

Ratio of contribution of work of Ajith, Bala and Chand = 3 : 2 : 1

Ajith’s total share = Rs. 3000

Bala’s total share = Rs. 2000

Chand’s total share = Rs. 1000

Ajith’s one day’s earning = Rs.600

Bala’s one day’s earning = Rs.400

Chand’s one day’s earning = Rs.500**A Bike is available at 40% discount at showroom “A” and the same is available at only 25% discount at showroom “B”. Mr. Arun has just sufficient amount of Rs. 60,000 to purchase it at showroom “A”.**

Quantity I: Difference between Marked Price and SP at Show Room “A”

Quantity II: Difference between Marked Price and SP at Show Room “B”

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relation cannot be established**A. Quantity I > Quantity II**

Explanation:

Let the marked price be x.

Cost price (CP) = 40 % discount on MP = 0.6y = 60000

⇒ y= Rs.100000 MP

SP at Show Room “A” = Rs. 60000

SP at Show Room “B” = 100000 X 0.75 = 75000

Difference between Marked Price and SP at Show Room “A” = 40000

Difference between Marked Price and SP at Show Room “B” = 25000**Quantity I: (x – 18)² = 0**

**Quantity II: y² = 324**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relation cannot be established**C. Quantity I ≥ Quantity II**

Explanation:

x² – 36x + 324 = 0

x = 18, 18

y² = 324

y = ±18**A Cistern has an inlet pipe and outlet pipe. The inlet pipe fills the cistern completely in 1 hour 20 minutes when the outlet pipe is plugged. The outlet pipe empties the tank completely in 4 hours when the inlet pipe is plugged.**

Quantity I: Inlet pipe Efficiency

Quantity II: 3 times of Outlet pipe Efficiency

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relation cannot be established**E. Quantity I = Quantity II or relation cannot be established**

Explanation:

Inlet pipe Efficiency = 100/(8/6) = 75%

Outlet pipe Efficiency = 100/(4) = 25%

3 times of Outlet pipe Efficiency = 75%**Harish took an educational loan from a nationalized bank for his 2 years course of MBA. He took the loan of Rs.5 lakh such that he would be charged at 7% p.a. at CI during his course and at 9% CI after the completion of the course. He returned half of the amount which he had to be paid on the completion of his studies and remaining after 2 years.**

Quantity I: He returned half of the amount which he had to be paid on the completion of his studies

Quantity II: He returned remaining amount after 2 years

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relation cannot be established**B. Quantity I < Quantity II**

Explanation:

5,00,000 * (1.07)² = 572450

Returned amount = 286225

After two years = 286225 * (1.09)² = 340063**The average salary of the entire staff in an office is Rs 250 per month. The average salary of officers is Rs 520 and that of non-officers is Rs. 200.**

**Quantity I: Number of Officers = 15**

Quantity II: Number of Non-Officers

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relation cannot be established**B. Quantity I < Quantity II**

Explanation:

Let the required number of non–officers = x

200x + 520 x 15 = 250 ( 15 + x )

250x – 200x = 520 * 15 – 250 x 15

50x = 4050

x = 81**The perimeter of a rectangle and a square is 160 cm each. If the difference between their areas is 600 cm.**

**Quantity I: Area of Square**

Quantity II:Area of Rectangle

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relation cannot be established**A. Quantity I > Quantity II**

Explanation:

Perimeter of rectangle = Perimeter of Square = 160

4a = 160 => a = 40

Area of square = 1600

1600 – lb = 600

lb = 1000 cm²**Shree started traveling from a place A to B and Priya started traveling from a place B to A which are 576 km apart. They meet after 12 hours. After their meeting, Shree increased her speed by 2 km/hr and Priya reduced her speed by 2 km/hr, they arrived at B and A respectively at the same time.**

Quantity I: Initial Speed of Shree

Quantity II: Initial Speed of Priya

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relation cannot be established**B. Quantity I < Quantity II**

Explanation:

Sum of their speeds = Distance/time = 576/12 = 48 kmph

Respective Speed of Shree and Priya = (23 + 25) = 48 kmph

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