**Hello Aspirants.**

Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From **Data ****Interpretation** that is important for all the competitive exams. We have included Some questions that are repeatedly asked in exams.

**I. Refer to the table and answer the given questions.**

**Data related to number of candidates appeared and qualified in a competitive exam from 2 states during 5 years.**

Year | Arunachal Pradesh | Madhya Pradesh | ||
---|---|---|---|---|

Number of Appeared candidates | Percentage of Appeared candidates who qualified | Number of Appeared candidates | Percentage of Appeared candidates who qualified | |

2011 | 450 | 50% | ___ | 40% |

2012 | 600 | 24% | ___ | 35% |

2013 | ___ | 50% | 280 | 40% |

2014 | 480 | 60% | 550 | 50% |

2015 | 380 | ___ | 400 | ___ |

**Note:** Few values are missing in the table (indicated by __).

A candidate is expected to calculate the missing value, if it is required to answer the given questions on the basis of given data and information.

**Out of the number of qualified candidates from State Arunachal Pradesh in 2013, the respective ratio of male and female candidates is 11:9. If the number of female qualified candidates from State Arunachal Pradesh in 2013 is 162, what is the number of appeared candidates(both male and female) from State Arunachal Pradesh in 2013?**

A. 630

B. 510

C. 570

D. 650

E. 720Answer –**E. 720**

**Explanation :**

X — Male candidates

X = 162 * (11/9) = 198

Total Qualified Candidates = 198 + 162 = 360

Total Appeared Candidates = 360 * (100/50) = 720.**Number of Appeared Candidates from State Madhya Pradesh increased by 100% from 2011 to 2012. If the total number of qualified candidates from State Madhya Pradesh in 2011 and 2012 together is 550, what is the number of appeared candidates from State Madhya Pradesh in 2011?**

A. 480

B. 420

C. 500

D. 460

E. 400Answer –**C. 500**

**Explanation :**

x — Total number of appeared Candidates in 2011

2x — Total number of appeared Candidates in 2012

x*(40/100) + 2x*(35/100) = 550

110x/100 = 550 —> x = 500**What is the difference between number of qualified candidates from State Arunachal Pradesh in 2011 and that in 2012?**

A. 51

B. 41

C. 61

D. 81

E. 71Answer –**D. 81**

**Explanation :**

50% of 450 = 225

24% of 600 = 144

Difference – 81**If the average number of qualified candidates from State Madhya Pradesh in 2013, 2014 and 2015 is 320, what is the number of qualified candidates from state Madhya Pradesh in 2015?**

A. 591

B. 573

C. 583

D. 587

E. 579Answer –**B. 573**

**Explanation :**

Average no of qualified students in 2013,2014,2015 = 320

Total no of qualified students in 2013,2014,2015 = 960

Qualified students in 2015 = (960 – (40% Of 280 + 50% Of 550)) = 960 – 387 = 573**If the respective ratio between number of qualified candidates from State Arunachal Pradesh in 2014 and 2015 is 8:11, what is the number of qualified candidates from State Arunachal Pradesh in 2015?**

A. 396

B. 312

C. 316

D. 334

E. 398Answer –**A. 396**

**Explanation :**

x — Number of qualified candidates in 2015

x = 288*(11/8) = 396

**II. Refer to the table and answer the given questions.**

**Data related to number of employees in 5 different companies in December, 2012**

Company | Total number of Employees | Out of total number of employees | ||
---|---|---|---|---|

Percentage of Engineering Graduates | Percentage of Science Graduates | Percentage of Arts Graduates | ||

A | 1000 | 32% | ___ | ___ |

B | 600 | ___ | 42% | 30% |

C | ___ | 30% | 30% | ___ |

D | ___ | ___ | 40% | 20% |

E | ___ | 35% | 50% | ___ |

**I.** Employees of the given companies can be categorised only in three types:

Engineering Graduates, Science Graduates and Arts Graduates

**II.** Few values are missing in the table (indicated by ___). A candidate is expected to calculate the missing value, if it is required to answer the given questions, on the basis of the given data and information.

**What is the difference between the number of Arts graduate employees and Engineering Graduates employees in Company B?**

A. 17

B. 18

C. 12

D. 11

E. 16Answer –**C. 12**

**Explanation :**

Number of Arts graduate employees = 30% of 600 = 180

Number of Engineering Graduates employees = 28% of 600 = 168

Difference = 180 – 168 = 12**The Average number of Arts graduate employees and Science graduate employees in Company E was 338. what was the total number of employees in Company E?**

A. 920

B. 960

C. 1120

D. 1040

E. 1080Answer –**D. 1040**

**Explanation :**

Average no of Arts graduate employees and Science graduate employees in Company E = 338

Total no of Arts graduate employees and Science graduate employees in Company E = 676

Total number of employees in Company E = X

X = 676 * (100/65) = 1040**If the respective ratio between the number of Science graduate employees and Arts graduate employees in Company A was 10:7, what was the number of Arts graduate employees in A?**

A. 294

B. 266

C. 280

D. 308

E. 322Answer –**C. 280**

**Explanation :**

Number of Science Graduate employees = 32% of 1000 = 320

Number of Science Graduate employees and Arts graduate employees = 1000 -320 = 680

Number of Arts graduate employees in A = 680 * (7/17) = 280**Total number of employees in Company B increased by 20% from December 2012 to 2013, If 20% of the total number of employees in Company B in December, 2013 was Engineering graduates, what was the number of Engineering graduate employees in Company B in December 2013?**

A. 194

B. 166

C. 144

D. 152

E. 138Answer –**C. 144**

**Explanation :**

Total number of employees in Company B in 2013 = 720

Engineering graduate employees in Company B in December 2013 = 20% of 720 = 144**Total number of employees in Company C was 3 times the total number of employees in Company D. If the difference between number of Arts graduate employees in Company D and that of Science graduate employees in the same Company was 120, what was the total number of employees in Company C?**

A. 1200

B. 1400

C. 1720

D. 1600

E. 1800Answer –**E. 1800**

**Explanation :**

40% – 20% = 120

20% = 120; Total number of employees in Company D = 600

Total number of employees in Company C = 1800

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