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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Rinku borrows an amount of money at 5% per annum and then lends it at 6% compounded half yearly. In this way he earns Rs 436 in a year. The amount of money borrowed by him is:

Correct

Answer- 2) Rs 40000
Explanation- Let the money borrowed by him be Rs x.
Since the money is lent at 6% compounded half yearly, the effective interest at the end of the year = (3 + 3 + 3 × 3/100) % = (6 + 0.09) % = 6.09%
The money earned by him = (6.09 – 5) % of x = 436
1.09% of x = 436
x = 436/1.09 × 100 = Rs 40000

Incorrect

Answer- 2) Rs 40000
Explanation- Let the money borrowed by him be Rs x.
Since the money is lent at 6% compounded half yearly, the effective interest at the end of the year = (3 + 3 + 3 × 3/100) % = (6 + 0.09) % = 6.09%
The money earned by him = (6.09 – 5) % of x = 436
1.09% of x = 436
x = 436/1.09 × 100 = Rs 40000

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Two partners Tom and Harry invest Rs 25000 and Rs 35000 in a business and agree that 40% of the profit will be divided equally and rest of the profit will be divided according to their investments. Find the total profit earned by them if Harry earns Rs 14000 more than Tom.

Correct

Answer- 1) Rs 140000
Explanation- Let the total profit earned by them is 100x
40% of the profit will be divided equally and rest 60% will be divided in the ratio 5:7 (25000:35000).
Total profit earned by Tom = 20x + 5/12 × 60x = 20x + 25x = 45x
Profit earned by Harry = 100x – 45x = 55x
Therefore, the difference between the profit earned by them = 55x – 45x = 10x
We have, 10x = 14000
100x = Rs 140000

Incorrect

Answer- 1) Rs 140000
Explanation- Let the total profit earned by them is 100x
40% of the profit will be divided equally and rest 60% will be divided in the ratio 5:7 (25000:35000).
Total profit earned by Tom = 20x + 5/12 × 60x = 20x + 25x = 45x
Profit earned by Harry = 100x – 45x = 55x
Therefore, the difference between the profit earned by them = 55x – 45x = 10x
We have, 10x = 14000
100x = Rs 140000

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

If A works for 5 days, remaining work is completed by B in 18 days. If B works for 9 days, remaining work is completed by A in 10 days. Time taken by B to complete the whole work alone is:

Correct

Answer- 4) 27 days
Explanation- Let the work done by A in a day is x and that by B is y.
Then, 5x + 18y = 9y + 10x
5x = 9y
x/y = 9/5
therefore, the work done by A and B is in the ratio 9:5. The number of days taken by them will be in the ratio 5:9 respectively.
If B works for 9 days, remaining work is completed by A in 10 days.
The work done by A in 10 days will be completed by B in = 10/5 × 9 = 18 days.
The time taken by B to complete the whole work alone = 9 + 18 = 27 days.

Incorrect

Answer- 4) 27 days
Explanation- Let the work done by A in a day is x and that by B is y.
Then, 5x + 18y = 9y + 10x
5x = 9y
x/y = 9/5
therefore, the work done by A and B is in the ratio 9:5. The number of days taken by them will be in the ratio 5:9 respectively.
If B works for 9 days, remaining work is completed by A in 10 days.
The work done by A in 10 days will be completed by B in = 10/5 × 9 = 18 days.
The time taken by B to complete the whole work alone = 9 + 18 = 27 days.

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

A person borrowed Rs 4000 at the rate of 8% per annum compounded annually. He paid Rs 500 at the end of one year and Rs 1000 at the end of second year. How much should he pay at the end 3rd year to finish his deal with the lender?

Correct

Answer- 2) Rs 3375.648
Explanation- Amount due after one year = 108% of 4000 – 500 = Rs 3820
Amount due after two years = 108% of 3820 – 1000 = Rs 3125.6
Amount due after three years = 108% of 3125.6 = Rs 3375.648

Incorrect

Answer- 2) Rs 3375.648
Explanation- Amount due after one year = 108% of 4000 – 500 = Rs 3820
Amount due after two years = 108% of 3820 – 1000 = Rs 3125.6
Amount due after three years = 108% of 3125.6 = Rs 3375.648

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

A man goes downstream in a boat to a place and then returned upstream to his original place in 12 hours. Find the total distance travelled by the boat if speed of the boat in still water and speed of the current are 6km/h and 1km/h respectively

Correct

Incorrect

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

What is the perimeter of a circle whose area is equal to the area of a rectangle of length 84cm and breadth 66cm?

Correct

Answer- 1) 264cm Explanation- Let the radius of the circle is r. Then,
∏r^{2} = 84 × 66 (area of the rectangle = length × breadth)
r^{2} = 84 × 66 × 7/22
Therefore, r = 42cm
Perimeter of the circle = 2∏r = 2 × 22/7 × 42 = 264cm

Incorrect

Answer- 1) 264cm Explanation- Let the radius of the circle is r. Then,
∏r^{2} = 84 × 66 (area of the rectangle = length × breadth)
r^{2} = 84 × 66 × 7/22
Therefore, r = 42cm
Perimeter of the circle = 2∏r = 2 × 22/7 × 42 = 264cm

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

What sum of money at compound interest will amount to Rs 3213.1674, if the rate of interest is 3% for the first year, 6% for the second year and 9% for the third year?

Correct

Answer- 2) Rs 2700
Explanation- Percentage of interest after 2 years = 3 + 6 + 3 × 6 /100 = 9.18%
Percentage of interest after 3 years = 9.18 + 9 + 9.18 × 9 / 100 = 18.18 + 0.8262 = 19.0062 %
Let the sum of money be Rs x, then,
119.0062% of x = 3213.1674
, x = 3213.1674/119.0062 × 100 = Rs 2700

Incorrect

Answer- 2) Rs 2700
Explanation- Percentage of interest after 2 years = 3 + 6 + 3 × 6 /100 = 9.18%
Percentage of interest after 3 years = 9.18 + 9 + 9.18 × 9 / 100 = 18.18 + 0.8262 = 19.0062 %
Let the sum of money be Rs x, then,
119.0062% of x = 3213.1674
, x = 3213.1674/119.0062 × 100 = Rs 2700

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

The average age of the family of 4 members seven years ago was 20 years. A baby, having been born, the average age of family now is 22 years. What is the present age of the baby?

Correct

Answer- 2) 2 years
Explanation- total age of all the four family members seven years ago = 20 × 4 = 80 years
Total present age of the four family members = 80 + 28 = 108 years
Total age of all the five family members = 22 × 5 = 110 years
Age of the baby = 110 – 108 = 2 years

Incorrect

Answer- 2) 2 years
Explanation- total age of all the four family members seven years ago = 20 × 4 = 80 years
Total present age of the four family members = 80 + 28 = 108 years
Total age of all the five family members = 22 × 5 = 110 years
Age of the baby = 110 – 108 = 2 years

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Total number of students in a school is 840 and the ratio of number of boys to girls is 13:8. Few girls and 50 boys joined the school due to which ratio of boys to girls becomes 3:2. Number of girls who joined the school are:

Correct

Answer- 1) 60
Number of boys in the school originally = 840/21 × 13 = 520
Number of girls in the school originally = 840/21 × 8 = 320
Let the number of girls who joined the school is x
Then, according to the question, we have,
(520 + 50) / (320 + x) = 3/2
By solving, we have x = 60

Incorrect

Answer- 1) 60
Number of boys in the school originally = 840/21 × 13 = 520
Number of girls in the school originally = 840/21 × 8 = 320
Let the number of girls who joined the school is x
Then, according to the question, we have,
(520 + 50) / (320 + x) = 3/2
By solving, we have x = 60

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

The length of the rectangle is increased by 50%. By what percent should the width be decreased to maintain the same area?

Correct

Answer- 5) 100/3%
Explanation- Let the width to be decreased by x%
Then, the effective change in the area = 50 – x – 50 × x/100 = 50 – 3x/2
Then, we have, 50 – 3x/2 = 0
3x/2 = 50
x = 100/3%

Incorrect

Answer- 5) 100/3%
Explanation- Let the width to be decreased by x%
Then, the effective change in the area = 50 – x – 50 × x/100 = 50 – 3x/2
Then, we have, 50 – 3x/2 = 0
3x/2 = 50
x = 100/3%

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