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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA certain sum of money amounts to Rs 812 in 2 yrs and to Rs 896 in 3.5 yrs. Find the sum and the rate of interest.
Correct
Explanation:
SI for 1.5 yrs = 896 – 812 = Rs 84
So, for 2 yrs SI = 84/1.5 * 2 = Rs 112
Amount for 2 yrs is 812, so P = 812 – 112 = Rs 700
This gives, r = 100*112/(700*2) = 8%Incorrect
Explanation:
SI for 1.5 yrs = 896 – 812 = Rs 84
So, for 2 yrs SI = 84/1.5 * 2 = Rs 112
Amount for 2 yrs is 812, so P = 812 – 112 = Rs 700
This gives, r = 100*112/(700*2) = 8% 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeIn an alloy weighing 10 kg, 1/4th is nickel and the rest is copper. It is mixed with an alloy weighing 7 kg in which 1/2 is nickel and the rest is copper. What is the ratio of nickel to copper in the final mixture?
Correct
Explanation:
After mixing the two, quantity of nickel = 1/4 * 10 + 1/2 * 7 = 6
Quantity of copper = 3/4 * 10 + 1/2 * 7 = 11
Ratio of nickel to copper = 6 : 11Incorrect
Explanation:
After mixing the two, quantity of nickel = 1/4 * 10 + 1/2 * 7 = 6
Quantity of copper = 3/4 * 10 + 1/2 * 7 = 11
Ratio of nickel to copper = 6 : 11 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeIn an examination it is required to get 350 marks of the aggregate marks to pass. A student gets 30.2% marks and is failed by 42 marks. Find the maximum aggregate marks a student can get.
Correct
Explanation:
He got failed by 42 marks so has received (35042) = 302 marks which is equal to 30.2% of aggregate marks
So 30.2% of aggregate marks = 302
aggregate marks = 30200/30.2 = 1000Incorrect
Explanation:
He got failed by 42 marks so has received (35042) = 302 marks which is equal to 30.2% of aggregate marks
So 30.2% of aggregate marks = 302
aggregate marks = 30200/30.2 = 1000 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeFind the wrong number in the series: 224, 220, 211, 195, 171, 134
Correct
Explanation:
224 – 2^2, 220 – 3^2, 211 – 4^2, 195 – 5^2, 170 – 6^2, 134Incorrect
Explanation:
224 – 2^2, 220 – 3^2, 211 – 4^2, 195 – 5^2, 170 – 6^2, 134 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeFind the wrong number in the series: 112, 224, 280, 308, 324, 329
Correct
Explanation:
112+(112/1), 224+(112/2), 280+(112/4), 308+(112/8), 322+(112/16), 329Incorrect
Explanation:
112+(112/1), 224+(112/2), 280+(112/4), 308+(112/8), 322+(112/16), 329 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (6–10) Study the given line graph carefully and answer the questions that follow.
The graph given below shows the number of students from different schools of city ABC taking part in painting and dancing for given period of time.
In which year is the percentage increase in the number of students over the previous year the highest for taking part in painting?
Correct
Explanation:
In 2012, 2013 the number is decreasing
For other years it can be seen that in 2011, the increase is very high, so % will also be high as compared in other years.
It is not always applicable. Since the difference between 2600 and 1800 is much high then the difference between other years.Incorrect
Explanation:
In 2012, 2013 the number is decreasing
For other years it can be seen that in 2011, the increase is very high, so % will also be high as compared in other years.
It is not always applicable. Since the difference between 2600 and 1800 is much high then the difference between other years. 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (6–10) Study the given line graph carefully and answer the questions that follow.
The graph given below shows the number of students from different schools of city ABC taking part in painting and dancing for given period of time.
Number of students who took part in dancing is approximately what percentage of the total number of students taking part in both activities in the year 2012?
Correct
Explanation:
In 2012, in dancing = 1900
In dancing + painting = 1900 + 2400 = 4300
So required % = (1900/4300)*100Incorrect
Explanation:
In 2012, in dancing = 1900
In dancing + painting = 1900 + 2400 = 4300
So required % = (1900/4300)*100 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections (6–10) Study the given line graph carefully and answer the questions that follow.
The graph given below shows the number of students from different schools of city ABC taking part in painting and dancing for given period of time.
What is the average number of students who took part in dancing over all the years?
Correct
Explanation:
1400+2700+1900+2100+1200+1500 / 6 = 1800Incorrect
Explanation:
1400+2700+1900+2100+1200+1500 / 6 = 1800 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections (6–10) Study the given line graph carefully and answer the questions that follow.
The graph given below shows the number of students from different schools of city ABC taking part in painting and dancing for given period of time.
Number of students in dancing event in 2015 is what percent less than that in painting event in the same year?
Correct
Explanation:
(22001500)/2200] * 100 = 31.81%Incorrect
Explanation:
(22001500)/2200] * 100 = 31.81% 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections (6–10) Study the given line graph carefully and answer the questions that follow.
The graph given below shows the number of students from different schools of city ABC taking part in painting and dancing for given period of time.
What is the difference between the averages of number of students in both events for the years 2010, 2011, 2012 and 2015?
Correct
Explanation:
Average in painting = (1800+2600+2400+2200)/4 = 2250
Average in dancing = 1400+2700+1900+1500 / 4 = 1875
Difference = 375Incorrect
Explanation:
Average in painting = (1800+2600+2400+2200)/4 = 2250
Average in dancing = 1400+2700+1900+1500 / 4 = 1875
Difference = 375
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