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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

A completes a piece of work in 20 days, and B completes the same work in 15 days. Both A and B started the work, but B left after some days. Now A completed the remaining work in 8 1/3 days. What is the number of days after which B left?

Correct

Explanation:
Let B left after ‘x’ days. A completed remaining work in 8 1/3 days or 25/3 days. So,
(1/20 + 1/15) * x + 1/20 * 25/3 = 1
(7/60) * x = 1 – 5/12
7/60 * x = 7/12
Solve, x = 5

Incorrect

Explanation:
Let B left after ‘x’ days. A completed remaining work in 8 1/3 days or 25/3 days. So,
(1/20 + 1/15) * x + 1/20 * 25/3 = 1
(7/60) * x = 1 – 5/12
7/60 * x = 7/12
Solve, x = 5

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

A man starts from point P at 7:00 AM and reaches point Q at 9:00 AM. Another man starts from point Q at 8:00 AM and reaches point P at 12:00 Noon. At what time both men will meet?

Correct

Explanation:
Let the distance from A to B is ‘d’ km.
First train reaches destination in 2 hrs, so speed of first train = d/2 km/hr.
Speed of second train = d/4 km/hr
Speed of first train = d/2 km/hr, so after 1 hr, i.e. at 8AM, the first train has covered d/2 km.
The distance left = (d – d/2) km = d/2 km. relative speed = d/2 + d/4.
So time they will meet at = 8:00 AM + (d/2) / (d/2 + d/4)
= 8:00 AM + (2/3)*60 = 8:40 AM

Incorrect

Explanation:
Let the distance from A to B is ‘d’ km.
First train reaches destination in 2 hrs, so speed of first train = d/2 km/hr.
Speed of second train = d/4 km/hr
Speed of first train = d/2 km/hr, so after 1 hr, i.e. at 8AM, the first train has covered d/2 km.
The distance left = (d – d/2) km = d/2 km. relative speed = d/2 + d/4.
So time they will meet at = 8:00 AM + (d/2) / (d/2 + d/4)
= 8:00 AM + (2/3)*60 = 8:40 AM

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

90 litres of a mixture contains 20% water and the rest milk. What amount of water must be added so that the resulting mixture contains only 60% milk?

Correct

Explanation:
Mixture contains 20% water.
The water which will be added will be 100% water
The new mixture contains 60% milk, this gives 40% water
So by allegation rule
Mixture………………..Water
20…………………….. 100
……………..40
60……………………… 20
This gives 60 : 20 = 3 : 1
Let x litres of water to be added to 80 litres mixture.
So 90/x = 3/1
x = 30

Incorrect

Explanation:
Mixture contains 20% water.
The water which will be added will be 100% water
The new mixture contains 60% milk, this gives 40% water
So by allegation rule
Mixture………………..Water
20…………………….. 100
……………..40
60……………………… 20
This gives 60 : 20 = 3 : 1
Let x litres of water to be added to 80 litres mixture.
So 90/x = 3/1
x = 30

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

How many words can be made out of the letters of the word ADDINS such that all vowels occur together?

Correct

Explanation:
We have D D N S and AI
So 5! For these 5 letters (take AI as single letter because they are to be taken together). And since 2 Ds are there, so 5!/2
Now arrangement of AI is 2!
So total 5!/2 * 2!

Incorrect

Explanation:
We have D D N S and AI
So 5! For these 5 letters (take AI as single letter because they are to be taken together). And since 2 Ds are there, so 5!/2
Now arrangement of AI is 2!
So total 5!/2 * 2!

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

A dealer gains 10% when an article is sold at 2/5th of its actual selling price. What will be the gain% if the same article is sold at 40% less than the actual selling price?

Correct

Explanation:
Profit is 10%. So,
(2/5 S.P. – C.P.)/C.P. * 100 = 20
This gives S.P. = 11/4 C.P.
Now product sold at 40% less S.P. i.e. 60/100 or 6/10 of S.P.
Profit/loss% = (6/10 S.P. – C.P.)/C.P. * 100
Put S.P. = 11/4 C.P. and find the final answer

Incorrect

Explanation:
Profit is 10%. So,
(2/5 S.P. – C.P.)/C.P. * 100 = 20
This gives S.P. = 11/4 C.P.
Now product sold at 40% less S.P. i.e. 60/100 or 6/10 of S.P.
Profit/loss% = (6/10 S.P. – C.P.)/C.P. * 100
Put S.P. = 11/4 C.P. and find the final answer

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

25 men are employed for a work which needs to be completed in 40 days. But after 24 days, it was found that only one third of the work was completed. Now in order to complete the work 4 days earlier, how many extra men needed to be employed?

Correct

Explanation:
4 days earlier the work is to be completed, this means in (40-4) = 36 days
After 24 days, the meaning work is to be completed in (36-24) = 12 days
Remaining work = 1 – 1/3 = 2/3
Let x extra men are to be employed. So,
25 * 24 * 2/3 = (x+25) * 12 * 1/3
Solve, x = 75

Incorrect

Explanation:
4 days earlier the work is to be completed, this means in (40-4) = 36 days
After 24 days, the meaning work is to be completed in (36-24) = 12 days
Remaining work = 1 – 1/3 = 2/3
Let x extra men are to be employed. So,
25 * 24 * 2/3 = (x+25) * 12 * 1/3
Solve, x = 75

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

There are 2 pipes A and B such that A fills the cistern in 8 hrs and B empties the cistern in 2 hrs. First the pipe A was opened and after 2 hours B was also opened. In how much total time will the cistern get empty?

Correct

Explanation:
In 1 hr, cistern filled by A is 1/8 so in 2 hrs 2/8 = 1/4
After 2 hr, cistern filled by A + B is 1/4 – 1/2 = -1/4
This means after 1/4th of cistern filled, in 2 hr, 1/4 gets empty in next one hour
So 2 + 1

Incorrect

Explanation:
In 1 hr, cistern filled by A is 1/8 so in 2 hrs 2/8 = 1/4
After 2 hr, cistern filled by A + B is 1/4 – 1/2 = -1/4
This means after 1/4th of cistern filled, in 2 hr, 1/4 gets empty in next one hour
So 2 + 1

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

15 men can complete a work in 40 days. 6 men started the work and after working for 20 days it was realized that the work will not get completed on time so 10 more persons are employed. Now they will complete the remaining work in how many days?

Correct

Explanation:
Shortcut:
15*40 = 6*20 + (6+10)* x
600 = 120 + 16x
Solve, x = 30

Incorrect

Explanation:
Shortcut:
15*40 = 6*20 + (6+10)* x
600 = 120 + 16x
Solve, x = 30

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

The incomes of 2 persons A and B is in the ratio 4 : 5. Their expenditures are in the ratio 8 : 15 respectively. If both save Rs 40,000, then what is B’s income?

Correct

Explanation:
Incomes 4x and 5x
Expenditures 8y and 15y
So 4x – 8y = 40000
And 5x – 15y = 40000
Solve both equations, x = 14,000
So B’s income = 5*14000

Incorrect

Explanation:
Incomes 4x and 5x
Expenditures 8y and 15y
So 4x – 8y = 40000
And 5x – 15y = 40000
Solve both equations, x = 14,000
So B’s income = 5*14000

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

The HCF and LCM of two numbers is 6 and 462 respectively. If the first number is 42, find the second one.

Correct

Explanation:
Product of two numbers = HCF * LCM
So 2nd number = 6*462/42

Incorrect

Explanation:
Product of two numbers = HCF * LCM
So 2nd number = 6*462/42