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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**B is 25% more efficient than A. B started the work & do it for x days. And then B is replaced by A. And A completed the remaining work in x+7 days. The ratio of work done by A to B is 3:2. In how many days A & B working together can complete the whole work?**Correct**Answer: 4. 100/9 days**

Explanation:

Given, the ratio of work done by A to B is 2:3.

Let the work done by A per day = 4p

Work done by B per day = 125% of 4p = 5p

Work done by B in x days = 5p*x

Work done by A in x+7 days = 4p*(x+7)

According to question,

4p*(x+7)/5p*x = 3/2

x = 8

work done by B = 5p*8 = 40p , work done by A = (3/2)*40 = 60p

Total work = 40p+60p = 100p

Combined efficiency of A and B = 4p+5p = 9p

Time taken = 100p/9p = 100/9 daysIncorrect**Answer: 4. 100/9 days**

Explanation:

Given, the ratio of work done by A to B is 2:3.

Let the work done by A per day = 4p

Work done by B per day = 125% of 4p = 5p

Work done by B in x days = 5p*x

Work done by A in x+7 days = 4p*(x+7)

According to question,

4p*(x+7)/5p*x = 3/2

x = 8

work done by B = 5p*8 = 40p , work done by A = (3/2)*40 = 60p

Total work = 40p+60p = 100p

Combined efficiency of A and B = 4p+5p = 9p

Time taken = 100p/9p = 100/9 days - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**The time taken for covering a distance of ‘X’ Km by downstream is equal to ‘X-12’ by covering upstream. Upstream speed is less than 4 km/hr than that of downstream. If the speed of the boat in still water is 12 km/hr. What is the value of ‘X’?**Correct**Answer: 1. 42**

Explanation:

Let the speed of current is “c”

Downstream speed = 12+c and upstream speed =12-c

According to question,

12+c – (12-c) = 4

C =2

Also,

X/ (12+c) = (X-12)/(12-c)

X/14 = (X-12)/10

10X = 14X-14*12

X= 42 kmIncorrect**Answer: 1. 42**

Explanation:

Let the speed of current is “c”

Downstream speed = 12+c and upstream speed =12-c

According to question,

12+c – (12-c) = 4

C =2

Also,

X/ (12+c) = (X-12)/(12-c)

X/14 = (X-12)/10

10X = 14X-14*12

X= 42 km - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**In a mixture of milk and water, the ratio of milk and water is 14:3. If 51 liters of mixture is taken out and 15 liters of water is added to it. Now in that mixture water quantity is 30%. Then find the mixture quantity in original.**Correct**Answer: 5) 136 litres**

Explanation:

Let the total quantity = 17x

Quantity of milk = 14x and quantity of water = 3x

when 51 liters is taken out, 51*(14/17) = 42 will be milk and 51*(3/17) = 9 will be water

According to question,

(14x-42) / (3x-9+15) = 7/3

(14x-42) / (3x+6) = 7/3

(14x-42) / (x+2) = 7/1

14x-42 = 7x+14

x =8

Mixture quantity in original = 17*8 = 136 litersIncorrect**Answer: 5) 136 litres**

Explanation:

Let the total quantity = 17x

Quantity of milk = 14x and quantity of water = 3x

when 51 liters is taken out, 51*(14/17) = 42 will be milk and 51*(3/17) = 9 will be water

According to question,

(14x-42) / (3x-9+15) = 7/3

(14x-42) / (3x+6) = 7/3

(14x-42) / (x+2) = 7/1

14x-42 = 7x+14

x =8

Mixture quantity in original = 17*8 = 136 liters - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**A train crosses a platform in 35 seconds and a pole in 20 seconds respectively. If the length of the train is 280m. Find the length of the platform.**Correct**Answer: 3) 210m**

Explanation:

Let the speed of train is “s”

Distance = Speed*time

280 = s*20

s = 14m/s

Let the length of platform = x

(x+280) = 14*35

X = 210Incorrect**Answer: 3) 210m**

Explanation:

Let the speed of train is “s”

Distance = Speed*time

280 = s*20

s = 14m/s

Let the length of platform = x

(x+280) = 14*35

X = 210 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**Two taps A and B can fill a tank in 6 hrs and 15 hrs respectively and a third tap C empty the tank in 45 hrs when all three are opened together then the tank will be filled in how many hrs?**Correct**Answer: 2) 90/19 hours**

Explanation:

Let the capacity of tank is LCM of 6, 15 and 45 = 90k

Tank filled per hour by A = 90/6 = 15k

Tank filled per hour by B = 90/15 =6k

Tank emptied per hour by C = 90/45 = 2k

Tank filled per hour by all three taps = 15k+6k-2k = 19k

Time taken by all to fill the tank = 90/19 hoursIncorrect**Answer: 2) 90/19 hours**

Explanation:

Let the capacity of tank is LCM of 6, 15 and 45 = 90k

Tank filled per hour by A = 90/6 = 15k

Tank filled per hour by B = 90/15 =6k

Tank emptied per hour by C = 90/45 = 2k

Tank filled per hour by all three taps = 15k+6k-2k = 19k

Time taken by all to fill the tank = 90/19 hours - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**X is 48 years old. If X’s age is 20% greater than that of Y then by how much percent is Y’s age less than X’s age?**Correct**Answer: 1) 16.66%**

Explanation:

Age of x = 120% of age of y

48 = 120% of y

y = (48*100)/120 = 40

Required %age = (48-40)/48 = 8/48 = 1/6 (16.66%)Incorrect**Answer: 1) 16.66%**

Explanation:

Age of x = 120% of age of y

48 = 120% of y

y = (48*100)/120 = 40

Required %age = (48-40)/48 = 8/48 = 1/6 (16.66%) - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**A person buys a commodity on a 15% discount on the labelled price. He sold the commodity for Rs. 4303 gaining 30% profit on its cost price. Find the (approximate) labelled price of the commodity.**Correct**Answer: Rs. 3900**

Explanation:

Let the cost price of the commodity = 100x

Selling price = 130% of 100x = 130x

130x = 4303

X =33.1

100x = 3310

CP = 85% of MP

3310 = 85/100 * MP

MP = 331000/85 =Rs. 3900Incorrect**Answer: Rs. 3900**

Explanation:

Let the cost price of the commodity = 100x

Selling price = 130% of 100x = 130x

130x = 4303

X =33.1

100x = 3310

CP = 85% of MP

3310 = 85/100 * MP

MP = 331000/85 =Rs. 3900 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**There are 240 boys and 220 girls in a class. In an examination, an equal number of boys and girls failed. If the number of boys passed is 1.2 times the number of girls passed, then find out the total number of boys and girls failed?**Correct**Answer: 4. 240**

Explanation:

Let the number of boys failed = x, no. of girls failed = x

Number of boys passed = (240-x) and number of girls passed = (220-x)

According to question,

(240-x) = 1.2(220-x)

240-x = 264 – 1.2x

X = 120

Total number of boys and girls failed = x+x = 120+120 = 240Incorrect**Answer: 4. 240**

Explanation:

Let the number of boys failed = x, no. of girls failed = x

Number of boys passed = (240-x) and number of girls passed = (220-x)

According to question,

(240-x) = 1.2(220-x)

240-x = 264 – 1.2x

X = 120

Total number of boys and girls failed = x+x = 120+120 = 240 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Cards are taken numbered from 1 to 35. Two cards are drawn one after the other without replacement. Find the probability that one card is divisible by 8 and other is divisible by 5.**Correct**Answer: 3. 4/85**

Explanation:

Cards which are divisible by 5 from number 1 to 35 are 7

Cards which are divisible by 8 from number 1 to 35 are 4

If first card is divisible by 8 and second by 5,

Probability of first card being divisible by 8 = 4/35

Probability of second card being divisible = 7/34 (without replacement)

Probability =(4/35)*(7/34) = 2/85

If first card is divisible by 5 and second card is divisible by 8,

Probability of first card being divisible by 5 = 7/35

Probability of second card being divisible by 8 = 4/34(without replacement)

Probability =(7/35)*(4/34) = 2/85

Total Probability = 2/85+2/85 = 4/85Incorrect**Answer: 3. 4/85**

Explanation:

Cards which are divisible by 5 from number 1 to 35 are 7

Cards which are divisible by 8 from number 1 to 35 are 4

If first card is divisible by 8 and second by 5,

Probability of first card being divisible by 8 = 4/35

Probability of second card being divisible = 7/34 (without replacement)

Probability =(4/35)*(7/34) = 2/85

If first card is divisible by 5 and second card is divisible by 8,

Probability of first card being divisible by 5 = 7/35

Probability of second card being divisible by 8 = 4/34(without replacement)

Probability =(7/35)*(4/34) = 2/85

Total Probability = 2/85+2/85 = 4/85 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**The ratio between the rates of travelling of A and B is 3:5 and therefore A takes 12 min. more than the time taken by B to reach a destination, if A had walked at thrice the speed, he would have covered the distance in?**Correct**Answer: 1) 10 minutes**

Explanation:

Given, the ratio of speed of A and B= 3:5, Ratio of time taken will be 5:3, Difference of time is (5-3)= 2, (here 2 = 12minutes)

Therefore, 1 =6 minutes

Therefore, time taken by A to complete the distance = 5*6 = 30 minutes

Hence, A will cover the same distance with thrice its speed in 10 minutesIncorrect**Answer: 1) 10 minutes**

Explanation:

Given, the ratio of speed of A and B= 3:5, Ratio of time taken will be 5:3, Difference of time is (5-3)= 2, (here 2 = 12minutes)

Therefore, 1 =6 minutes

Therefore, time taken by A to complete the distance = 5*6 = 30 minutes

Hence, A will cover the same distance with thrice its speed in 10 minutes

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