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Question 1 of 10
1. Question
1 points
Category: Quantitative Aptitude
A bag contains 25 paise, 50 paise, and Rs 2 coins in the ratio 12 : 15 : 20 respectively. If the total value of money in bag is Rs 505, what is the total number of coins in the bag?
Correct
Explanation:
Coins – 12x, 15x, 20x, so
Value of 25 paise coins = (25/100)*12x = 3x, of 50 paise coin = (50/100)*15x = 15x/2, of Rs 2 coins = 2*20x = 40x
So total value is 3x+(15x/2)+40x = 101x/2 which equals 505, so x = 10
Total coins = 12x+15x+20x = 47x = 470
Incorrect
Explanation:
Coins – 12x, 15x, 20x, so
Value of 25 paise coins = (25/100)*12x = 3x, of 50 paise coin = (50/100)*15x = 15x/2, of Rs 2 coins = 2*20x = 40x
So total value is 3x+(15x/2)+40x = 101x/2 which equals 505, so x = 10
Total coins = 12x+15x+20x = 47x = 470
Question 2 of 10
2. Question
1 points
Category: Quantitative Aptitude
36, 18, 18, 27, 54, ?
Correct
Explanation:
36*0.5, 18*1, 18*1.5, 27*2, 54*2.5,
Incorrect
Explanation:
36*0.5, 18*1, 18*1.5, 27*2, 54*2.5,
Question 3 of 10
3. Question
1 points
Category: Quantitative Aptitude
How many kg of wheat costing Rs 10 per kg must be mixed with 16 Kg of wheat costing Rs 15 per Kg, so that there may be gain of 30% by selling the mixture of Rs 15.6 per Kg?
Correct
Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2
Solve, x = 24
Incorrect
Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2
Solve, x = 24
Question 4 of 10
4. Question
1 points
Category: Quantitative Aptitude
A and B can complete a work in 40 and 60 days respectively. They started a work which is to be completed in 20 days. But it was found that they will not be able to complete work on time, so a third person C was appointed after 12 days. In how many days C can alone complete the work?
Correct
Explanation:
A and B worked for 20 days. In 1 day they could have completed work (1/40 + 1/60) = 1/24
So in 20 days, they did (1/24)*20 = 5/6
This means C did 1 – 5/6 = 1/6 of work in 8 days because he joined after 12 days and up to 20 days.
So he can do 1 work in 48 days
Incorrect
Explanation:
A and B worked for 20 days. In 1 day they could have completed work (1/40 + 1/60) = 1/24
So in 20 days, they did (1/24)*20 = 5/6
This means C did 1 – 5/6 = 1/6 of work in 8 days because he joined after 12 days and up to 20 days.
So he can do 1 work in 48 days
Question 5 of 10
5. Question
1 points
Category: Quantitative Aptitude
A train starts from station A at 7:00 AM and reaches station B at 9:00 AM. Another train starts from station B at 7:30 AM and reaches station A at 10:30 AM. At what time the two trains will meet?
Correct
Explanation:
Let the distance from A to B is ‘d’ km.
First train reaches destination in 2 hrs, so speed of first train = d/2 km/hr.
Speed of second train = d/3 km/hr
Speed of first train = d/2 km/hr, so after 1/2 hr, i.e. at 7:30 AM, the first train has covered d/4 km.
The distance left = (d – d/4) km = 3d/4 km. relative speed = d/2 + d/3.
So time they will meet at = 7:30 AM + (3d/4) / (d/2 + d/3)
= 7:30 AM + (9/10)*60 = 8:24 AM
Incorrect
Explanation:
Let the distance from A to B is ‘d’ km.
First train reaches destination in 2 hrs, so speed of first train = d/2 km/hr.
Speed of second train = d/3 km/hr
Speed of first train = d/2 km/hr, so after 1/2 hr, i.e. at 7:30 AM, the first train has covered d/4 km.
The distance left = (d – d/4) km = 3d/4 km. relative speed = d/2 + d/3.
So time they will meet at = 7:30 AM + (3d/4) / (d/2 + d/3)
= 7:30 AM + (9/10)*60 = 8:24 AM
Question 6 of 10
6. Question
1 points
Category: Quantitative Aptitude
An article is marked 25% above the cost price with marked price being Rs 150. The profit gets increased by Rs 6.9, when the selling price of this article is increased by 5%. What is the original selling price of the article?
Correct
Explanation:
5% of SP= 6.9
then 100% of SP= 6.9×100/5 =138
Incorrect
Explanation:
5% of SP= 6.9
then 100% of SP= 6.9×100/5 =138
Question 7 of 10
7. Question
1 points
Category: Quantitative Aptitude
The ratio of the areas of the circumcircle and the incircle of an equilateral triangle is
Correct
Explanation:
For equi. Triangle
Inradius = a/2√3
Circumradius = a/√3
So ratio is
ᴨ (a/√3)^2 : ᴨ (a/2√3)^2
= 4 : 1
Incorrect
Explanation:
For equi. Triangle
Inradius = a/2√3
Circumradius = a/√3
So ratio is
ᴨ (a/√3)^2 : ᴨ (a/2√3)^2
= 4 : 1
Question 8 of 10
8. Question
1 points
Category: Quantitative Aptitude
If [2x + (1/3x)] = 5, then value of 5x/(6x^2 + 20x +1) is
Correct
Explanation:
[2x + (1/3x)] = 5
So 6x^2 + 1 =15x
Add 20 x to both sides
6x^2 + 20x + 1 =15x + 20x = 35x
So 5x/(6x^2 + 20x +1) = 5x/35x = 1/7
Incorrect
Explanation:
[2x + (1/3x)] = 5
So 6x^2 + 1 =15x
Add 20 x to both sides
6x^2 + 20x + 1 =15x + 20x = 35x
So 5x/(6x^2 + 20x +1) = 5x/35x = 1/7
Question 9 of 10
9. Question
1 points
Category: Quantitative Aptitude
If A = tan 11.tan 29, B = 2 cot 61.cot79, then:
Correct
Explanation:
B = 2 cot 61.cot79
B = 2 cot (90-29). cot (90-11) = 2 tan 29.tan 11 = 2A
Incorrect
Explanation:
B = 2 cot 61.cot79
B = 2 cot (90-29). cot (90-11) = 2 tan 29.tan 11 = 2A
Question 10 of 10
10. Question
1 points
Category: Quantitative Aptitude
Consider the data set {5, 2, 3, 8, 9}. The variance of set is
