Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in** Quadratic Equations** which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

**You have to solve equation I and II ,Give answer**

**1)If X>Y**

**2)If X<Y**

**3)If X≥ Y**

**4)If X≤ Y **

**5)If X=Y or cannot be established**

**I. X**^{2 }+ 3X + 2= 0

**II. Y**^{2 }+ 5Y + 6 = 0

**3)If X≥ Y**

Explanation :

(x+1)(x+2) = 0

X = -1,-2

(y+3)(y+2) = 0

Y = -3,-2

-1,-2,-2,-3

x x y y

x≥y

**I. 6X**^{2 }– 7X + 2 = 0

**II. 12Y**^{2 }– 7Y + 1 = 0

**1)If X>Y**

Explanation :

(2x-1)(3y-2) = 0

X =1/2,2/3

(4y-1)(3y-1) = 0

Y =1/4,1/3

0.7,0.5,0.33,0.25

x x y y => x>y

**I. 8X**^{2 }– 22X – 21 = 0

**II. 4Y**^{2 }+ 9Y = 0

**5)If X=Y or cannot be established**

Explanation :

(2x-7)(4x+3) = 0

X=7/3,-3/4

Y(4y+9)=0

Y =0,-9/4

2.3,0,-0.75,-2.25,

xyxy =no relation

**I. 2X**^{2 }– 15X + 25 = 0

**II. 5Y**^{2 }– 126Y + 25 = 0

**5)If X=Y or cannot be established**

Explanation :

(2x-5)(x-5) = 0

X =5,5/2

(5y-1)(y-25)

Y=25,1/5

25,5,2.5,0.2

yxxy =no relation

**I. 6X**^{2 }– X – 2 = 0

**II. 9Y**^{2 }– 22Y + 8 = 0

**5)If X=Y or cannot be established**

Explanation :

(2x+1)(3x-2) = 0

X = 2/3,-1/2

(y-2)(9y-4) = 0

Y=2,4/9

2,0.7,0.4,-0.5

xyxy = no relation

**I. 2X**^{2 }+ 17X + 36 = 0

**II. 2Y**^{2 }+ 9Y +9 = 0

**2)If X<Y**

Explanation :

(x+4)(2x+9) = 0

X= -4,-9/2

(y+3)(2y+3) = 0

Y = -3,-3/2

-1.5,-3,-4,-4.5

Yyxx => x<y

**I. 3X**^{2 }– 28X + 65 = 0

**II. 3Y**^{2 }– 16Y + 21 = 0

**1)If X>Y**

Explanation :

(x-5)(3x-13) =0

X=5,13/3

(y-3)(3y-7) = 0

Y=3,7/3

5,4.3,3,2.3

Xxyy => x>y

**I. X**^{2 }– 7X + 12 = 0

**II. Y**^{2 }– 10Y +24 = 0

**4)If X≤ Y**

Explanation :

(X-4)(X-3) =0

X =4,3

(Y-4)(Y-6) = 0

Y=6,4

6,4,4,3

YYXX => Y≥X

**I. 4X**^{2 }– 29X + 45 = 0

**II. 3Y**^{2 }– 19Y + 28 = 0

**5)If X=Y or cannot be established**

Explanation :

(4X-9)(X-5) =0

X=5,9/4

(3Y-7)(Y-4) =0

Y=4,7/4

5,4,2.3,1.8

yxxy => no relation

**I. X**^{2 }= 100

**II. Y**^{2 }– 20Y + 100 = 0

**4)If X≤ Y**

Explanation :

X = +10,-10

(y-10)(y-10) =0

Y = 10,10

10,10,10,-10

Yyxx = y≥x

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