# Quants Questions : Mensuration Set 3

Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From Mensuration that is important for all the competitive exams. We have included Some questions that are repeatedly asked in exams !!

1. The area of a square field is 4050 m2the length of its diagonal is
A)76m
B)90m
C)84m
D)80m
E)None of these
B)90m
Explanation :
1/2 d2 = 4050
d2 = 8100
d = 90 m

2. The Surface area of cube is 216 m2. Find it’s diagonal
A)18.25m
B)10.38m
C)13.56m
D)20.67m
E)None of these
B)10.38m
Explanation :
6a2 = 216
a2 = 216/6 = 36
a= 6
Diagonal = a√3 = 6*1.73 = 10.38m

3. The length of a rope by which a cow must be tethered in order that she may be able to graze an area of 2826 sq.m is
A)20m
B)17m
C)27m
D)30m
E)None of these
D)30m
Explanation :
22/7×r2 =2826
r2 =(2826×7/22) = 899.18 = 900
r = 30 m

4. The number of rounds that a wheel of diameter14m will make in going 2 km is
A)62 rounds
B)50 rounds
C)45 rounds
D) 56 rounds
E)None of these
C)45 rounds
Explanation :N = 2000/(14*22/7) = 2000/44 = 45.45 = 45 rounds

5. The ratio of length to breadth of a rectangle is 7:6. The perimeter of the plot is 260m. Find the area of the plot ?
A)4800sq.m
B)5600sq.m
C)4200sq.m
D)2600sq.m
E)None of these
C)4200sq.m
Explanation :
2(7x+6x) = 260
26x = 260
X = 260/26 = 10
Area = 70*60 = 4200

6. In a parallelogram the length of adjacent sides are 13m and 11m. If the length of one diagonal is 18m, find the length of the other diagonal ?
A)9m
B)16m
C)12m
D)19m
E)None of these
B)16m
Explanation :
d12+d22 = 2(a2+b2)
324+d22 = 2(169+121) = 580
d22 =  580 – 324 = 256
d  = 16m

7. The circumference of the 2 circle is 212cm and 412cm. What is the difference between the area of the 2 circles ?
A)10048cm2
B) 10480cm2
C) 10070cm2
D) 10140cm2
E)None of these
A)10048cm2
Explanation :
2*3.14*r1 = 212
R1 = 212/6.28 = 33.75 = 34cm
2*3.14*r2 = 412
R1 = 412/6.28 = 65.60= 66cm
Diff = 3.14(662-342)
= 3.14(4356-1156) = 3.14*3200
= 10048

8. If the length of the rectangular field is increased by 10% and the breadth is reduced by 10%, now the area of rectangle will be 217 cm2 .Find the area of the original rectangle ?
A)210 cm2
B)219 cm2
C) 215 cm2
D) 221 cm2
E)None of these
B)219 cm2
Explanation :
% change = 10 – 10 – 10*10/100 =  -1%
99x/100 = 217
X = 217*100/99 = 219.19 = 219

9. The area of right angle triangle is 100sq cm. The ratio of base to its height is 4:5.Find the length of the hypotenuse ?
A)20cm
B)22cm
C)28cm
D)30cm
E)None of these
A)20cm
Explanation :
Area = ½(4x*5x)
100 = 20x^2/2
X^2 = 100/10 =10
x = 3.16
4x:5x = 12.64:15.8
Hypotenuse = √12.642+15.82
= √409.40
= 20.23 = 20

10. How many bricks, each measuring 20 cm x 8 cm x 5 cm, will be needed to build a wall of 10 m x 7 m x 20cm?
A)16000
B)11000
C)12000
D)17500
E)None of these
D)17500
Explanation :
Number of bricks =Volume of the wall/Volume of  brick
= 1000 x 700 x 20/20 x 8x 5
= 17500

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