Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From **Mensuration** that is important for all the competitive exams. We have included Some questions that are repeatedly asked in exams !!

**The area of a square field is 4050 m**^{2}the length of its diagonal is

A)76m

B)90m

C)84m

D)80m

E)None of these

**B)90m**

Explanation :

1/2 d^{2}= 4050

d^{2}= 8100

d = 90 m

**The Surface area of cube is 216 m**^{2}. Find it’s diagonal

A)18.25m

B)10.38m

C)13.56m

D)20.67m

E)None of these

**B)10.38m**

Explanation :

6a^{2}= 216

a^{2}= 216/6 = 36

a= 6

Diagonal = a√3 = 6*1.73 = 10.38m

**The length of a rope by which a cow must be tethered in order that she may be able to graze an area of 2826 sq.m is**

A)20m

B)17m

C)27m

D)30m

E)None of these

**D)30m**

Explanation :

22/7×r^{2}=2826

r^{2}=(2826×7/22) = 899.18 = 900

r = 30 m

**The number of rounds that a wheel of diameter14m will make in going 2 km is**

A)62 rounds

B)50 rounds

C)45 rounds

D) 56 rounds

E)None of these

**C)45 rounds**

Explanation :N = 2000/(14*22/7) = 2000/44 = 45.45 = 45 rounds

**The ratio of length to breadth of a rectangle is 7:6. The perimeter of the plot is 260m. Find the area of the plot ?**

A)4800sq.m

B)5600sq.m

C)4200sq.m

D)2600sq.m

E)None of these

**C)4200sq.m**

Explanation :

2(7x+6x) = 260

26x = 260

X = 260/26 = 10

Area = 70*60 = 4200

**In a parallelogram the length of adjacent sides are 13m and 11m. If the length of one diagonal is 18m, find the length of the other diagonal ?**

A)9m

B)16m

C)12m

D)19m

E)None of these

**B)16m**

Explanation :

d1^{2}+d2^{2}= 2(a^{2}+b^{2})

324+d2^{2}= 2(169+121) = 580

d2^{2}= 580 – 324 = 256

d = 16m

**The circumference of the 2 circle is 212cm and 412cm. What is the difference between the area of the 2 circles ?**

A)10048cm^{2}

B) 10480cm^{2}

C) 10070cm^{2}

D) 10140cm^{2}

E)None of these

**A)10048cm**^{2}

Explanation :

2*3.14*r1 = 212

R1 = 212/6.28 = 33.75 = 34cm

2*3.14*r2 = 412

R1 = 412/6.28 = 65.60= 66cm

Diff = 3.14(66^{2}-34^{2})

= 3.14(4356-1156) = 3.14*3200

= 10048

**If the length of the rectangular field is increased by 10% and the breadth is reduced by 10%, now the area of rectangle will be 217 cm**^{2}.Find the area of the original rectangle ?

A)210 cm^{2}

B)219 cm^{2}

C) 215 cm^{2}

D) 221 cm^{2}

E)None of these

**B)219 cm**^{2}

Explanation :

% change = 10 – 10 – 10*10/100 = -1%

99x/100 = 217

X = 217*100/99 = 219.19 = 219

**The area of right angle triangle is 100sq cm. The ratio of base to its height is 4:5.Find the length of the hypotenuse ?**

A)20cm

B)22cm

C)28cm

D)30cm

E)None of these

**A)20cm**

Explanation :

Area = ½(4x*5x)

100 = 20x^2/2

X^2 = 100/10 =10

x = 3.16

4x:5x = 12.64:15.8

Hypotenuse = √12.64^{2}+15.8^{2}

= √409.40

= 20.23 = 20

**How many bricks, each measuring 20 cm x 8 cm x 5 cm, will be needed to build a wall of 10 m x 7 m x 20cm?**

A)16000

B)11000

C)12000

D)17500

E)None of these

**D)17500**

Explanation :

Number of bricks =Volume of the wall/Volume of brick

= 1000 x 700 x 20/20 x 8x 5

= 17500

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