Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating question sample in **Time and Distance **with Explanation, which is common for all the IBPS,SBI,SSC and other competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

**A car started from Indore to Bhopal at a certain speed. The Car missed an accident at 40Kms away from Indore, then the driver decided to reduce Car speed to 4/5 of the original speed. Due to this, he reached Bhopal by a late of 1hr 15min.Suppose if he missed an accident at 80Km away from Indore and from then he maintained 4/5 of original speed then he would reach Bhopal by a late of 1hour. Then what is the original speed of the Car?**

A. 20 km/hr

B. 40 km/hr

C. 60 km/hr

D. 80 km/hr

E. Cannot be determined

Answer –**B. 40 km/hr**

**Explanation :**

(x+40/s) + 5/4 = 40/s + 5x/4s — — — 1

(x+40/s) + 1 = 80/s + 5(x-40)/4s — — — 2

s = 40**Two places A and B are at a certain distance. Ramu started from A towards B at a speed of 40 kmph. After 2 hours Raju started from B towards A at a speed of 60 kmph. If they meet at a place C then ratio of ratio of time taken by Raju to Ramu to reach Place C is 2:3. Then what is the distance between A and B?**

A. 300 Km

B. 400 Km

C. 480 Km

D. 600 Km

E. Cannot be determined

Answer –**C. 480 Km**

40t 1 +60t 2 = d

T 1 /t 2 = 3/2

T 1 – t 2 = 2

Solving d = 480 Km**Ramu started from A towards B at a speed of 20Km/hr and Raju started from B towards A. They crossed each other after one hour. Raju reached his destination 5/6 hour earlier than Ramu reached his destination.Then what is the distance between A and B?**

A. 40 Km

B. 50 Km

C. 60 Km

D. 80 Km

E. Cannot be determined

Answer –**B. 50 Km**

**Explanation :**

1 = x/20 = D-x/s 2

5/6 = D(1/20 – 1/s 2 )

D =50**Two Cars started at same time, same place and towards same direction. First Car goes at uniform speed of 12Km/hr. Second Car goes at speed of 4 Km/hr in first hour and increases it speed by 1 Km/hr for every hour. Then what is the distance traveled by car B when the both the Cars meet for the first time?**

A. 196 Km

B. 198 Km

C. 200 Km

D. 204 Km

E. None

Answer –**D. 204 Km**

**Explanation :**

12*x = x/2(2*4+(x-1)*1)

X= 17

D = 17*12 =204**A man traveled 100 km by Bike in 2 hours. He then traveled in Bus for 8 hrs and then Train in 9 hrs. Ratio of Speeds of Bus to Train is 4:5. If speed of train is 4/5 of Bike speed then the entire journey covered by him in Km is?**

A. 516 Km

B. 616 Km

C. 716 Km

D. 816 Km

E. None

Answer –**C. 716 Km**

**Explanation :**

Speed of train = 50

Bus = 32

Train = 40

Distance = 100+32*8+40*9 = 716**Car A leaves Delhi at a certain time, after 5 hours Car B leaves Delhi in the same direction as of A. Speed of Car A is 20Km/hr and Speed of Car B is 40Km/hr. In how much time Car B will be 20Km ahead of Car A?**

A. 5 Hours

B. 6 Hours

C. 8 Hours

D. 11 Hours

E. None

Answer –**B. 6 Hours**

**Explanation :**

20 =40*(t-5) – 20*t

T = 11

11-5 = 6**Two places A and B are at a distance of 480Km. Sita started from A towards B at the speed of 40Kmph. After 2 hours Gita started from B towards A at speed of 60 Kmph. They meet at a Place C then what is the difference between the time taken by them to reach their destinations from Place C?**

A. 1 hour

B. 2 hours

C. 3 hours

D. 4 hours

E. Cannot be determined

Answer –**B. 2 hours**

**Explanation :**

t*40+ (t-2)*60 = 480

t=6

From Place C to A = C to B = 240

Then time taken by Sita = 6hours and GIta = 4 hours

Difference = 6-4 = 2 hours**Two Cars started at same time, same place and towards same direction. First Car goes at a speed of 5km/hr in first and 7 Km/hr in second hour and repeats the cycle over the entire journey. Similarly second Car goes at 4km/hr in first hour and 9km/hr in second hour and repeats the cycle over the entire journey.Then these two Cars for the first time for after how many hours of journey?**

A. 3 Hours

B. 6 Hours

C. 9 Hours

D. 12 Hours

E. None

Answer –**A. 20****kmph**

**Explanation :**

First car : 5,12,17

Second Car: 4,3,17**A police saw a Thief at a distance of 2km. When Police started chasing him Thief also started running. If the ratio of Speeds of Police to Thief is 5:4. Then thief was caught at a certain distance then how many Kms did police run to catch the Thief?**

A. 5 Km

B. 6 Km

C. 8 Km

D. 10 Km

E. Cannot be determined

Answer –**D. 10 Km**

**Explanation :**2+x/5 = x/4

X = 8

Police = 8+2 = 10**If a Car runs at 45Km/hr it reaches its destination by 10 min late. If it runs at 60Km/hr it is late by 4min. Then what is the correct time for the journey?**

A. 12 min

B. 14 min

C. 16 min

D. 18 min

E. Cannot be determined

Answer –**B. 14 min**

**Explanation :**45(t+10) = 60(t+4)

T = 14

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