Hello Aspirants. Welcome to Online Quantitative Aptitude Section Section with explanation in **AffairsCloud.com.** Here we are creating question samples from **Percentage** with explanation, which is common for competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

**If x is 20% more than y, then by what percent y is smaller than x.**

a) 50/3 %

b) 40/3 %

c) 46/3 %

d) 47/3 %

Answer –**a) 50/3 %**

**Solution:**

x = 120y/100 or x = 6y/5

y = 5x/6. Percentage by which y is smaller

Than x is [(x – 5x/6)/x]*100 = 50/3 %

**In an alloy, there is 15% of brass, to get 90 kg of brass, how much alloy is needed ?**

a) 400 kg

b) 500 kg

c) 600 kg

d) 700

Answer –**c) 600 kg**

**Solution:**

Let X kg of alloy is needed. So, 15/100 of X = 90. So X =600 kg

**25 litre of solution contains alcohol and water in the ratio 2:3. How much alcohol must be added to the solution to make a solution containing 60% of alcohol ?**

a) 10.5 ltr

b) 11.5 ltr

c) 12.5 ltr

d) 13.5 ltr

Answer –**c) 12.5 ltr**

**Solution:**

Initially alcohol 2/5 * 25 = 10 ltr and water is 15 ltr.

To make a solution of 60% alcohol (10+x)/25+x = 60/100. X = 12.5

**In an examination if a person get 20% of the marks then it is fail by 30 marks. Another person who gets 30% marks gets 30 marks more than the passing marks. Find out the total marks and the passing marks.**

a) 600 and 150

b) 600 and 180

c) 500 and 150

d) 500 and 180

Answer –**a) 600 and 150**

**Solution:**

20% of X = P – 30 (X = Maximum marks and P = passing marks)

30% of X = P + 30. Solve for X and P.

**A company has produced 900 pieces of transistor out of which 15% are defective and out of remaining 20 % were not sold. Find out the number of sold transistor.**

a) 610

b) 611

c) 612

d) 614

Answer –**c) 612**

**Solution:**

No of transistor sold = 900*(85/100)*(80/100) = 612

**In an election the votes between the winner and loser candidate are in the ratio 5:1. If total number of eligible voters are 1000, out of which 12% did not cast their vote and among the remaining vote 10% declared invalid. What is the number of votes the winner candidate get ?**

a) 620

b) 630

c) 640

d) 660

Answer –**d) 660**

**Solution:**

Ratio b/w winner and loser 5:1

Total no of votes casted actually = 1000*(88/100)*(90/100) = 792

5x + x = 792, X =132

Votes of winner candidate = 5*132 = 660

**If the price of a commodity is increased by 30%, by how much % a consumer must reduce his consumption so to keep the expenditure same ?**

a) 100/13

b) 200/13

c) 300/13

d) 400/13

Answer –**c) 300/13**

**Solution:**

If commodity price is increased then reduction in consumption will be

[(increase in price)/100 + increase in price]*100.

(30/130)*100 = 300/13%

**1000 sweets need to be distributed equally among the school students in such a way that each student gets sweet equal to 10% of total students. Then the number of sweets, each student gets.**

a) 10

b) 12

c) 14

d) 16

Answer –**a) 10**

**Solution:**

No of students = T. Each student gets 10% of T.

So , T students get T^2/10 sweets.

T^2/10 = 1000. So T = 100. So each student gets 10 sweets

**Rishi salary is first increased by 20% and then decreased by 25%. How much percent the salary increased/decreased ?**

a) 5%

b) 10%

c) 15%

d)20%

Answer –**b) 10%**

**Solution:**

Take 100 as rishi salary.

Increased by 20% percent = 120.

Then decreased by 25%, i.e = (75/100)*120 = 90.

So percentage decrease is 10%.

**The income of a person is 10000 and its expenditure is 6000 and thus saves 4000rs. In the next year his income is increased by 10% and its expenditure increased by 20%. Now his saving is what percent lower than the previous saving.**

a) 5%

B) 7.5%

c) 10%

d) 15%

Answer –**a) 5%**

**Solution:**

Initially I-E = S (I = Income, E = expenditure, S = saving)

10000-6000 = 4000(saving)

Now, I = 11000 and E = 7200. So saving = I – E = 3800.

[(4000-3800)/4000]*100 = 5%

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