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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections (15): There are 3 number series you have to find the value of a, b, c and then establish relation among a, b, c.
A) 12, 16, 7, (a), 2, 34
B) 4, 4, 8, (b), 96, 480
C) 2, 7, (c) 77, 238, 723Correct
Answer: 5) a <b=c
Explanation:
A)
12 + 2^{2} = 16
163^{2} = 7
7+4^{2} = 23 (a)
235^{2} = 2
2+6^{2} = 34
B)
4*1 = 4
4*2 = 8
8*3 = 24 (b)
24*4=96
96*5 = 480
C)
2*3+1 = 7
7*3+3 = 24 (c)
24*3+5=77
77*3+7 = 238
238*3+9 = 723Incorrect
Answer: 5) a <b=c
Explanation:
A)
12 + 2^{2} = 16
163^{2} = 7
7+4^{2} = 23 (a)
235^{2} = 2
2+6^{2} = 34
B)
4*1 = 4
4*2 = 8
8*3 = 24 (b)
24*4=96
96*5 = 480
C)
2*3+1 = 7
7*3+3 = 24 (c)
24*3+5=77
77*3+7 = 238
238*3+9 = 723 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections (15): There are 3 number series you have to find the value of a, b, c and then establish relation among a, b, c.
A) 512, 512, 256, (a), 8, 0.5
B) 1, 8, 9, (b), 25, 216
C) 6, 7, 15, 42, (c), 231Correct
Answer: 2) a =b<c
Explanation:
A)
512/1 = 512
512/2 = 256
256/4 = 64 (a)
64/8 = 8
8/16 = 0.5
B)
1^{2}=1
2^{3}=8
3^{2}=9
4^{3}=64 (b)
5^{2}=25
6^{3}=216
C)
6+1^{3}=7
7+2^{3}=15
15+3^{3}=42
42+4^{3}=106(c)
106+5^{3}=231Incorrect
Answer: 2) a =b<c
Explanation:
A)
512/1 = 512
512/2 = 256
256/4 = 64 (a)
64/8 = 8
8/16 = 0.5
B)
1^{2}=1
2^{3}=8
3^{2}=9
4^{3}=64 (b)
5^{2}=25
6^{3}=216
C)
6+1^{3}=7
7+2^{3}=15
15+3^{3}=42
42+4^{3}=106(c)
106+5^{3}=231 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections (15): There are 3 number series you have to find the value of a, b, c and then establish relation among a, b, c.
A) 5, 12, 24, 36, 52, (a)
B) 1, 6, 30, (b), 360, 720,
C) 105, 110, 100, 115, 95, (c)Correct
Answer: 4) a <b=c
Explanation:
A)
2+3 = 5
5+7 =12
11+13 = 24
17+19 = 36
23+29=52
31+37 =68 (a)
B)
1*6=6
6*5=30
30*4=120 (b)
120*3=360
360*2=720
C)
105+5 = 110
11010 = 100
100+15 = 115
11520 = 95
95+25 = 120 (c)Incorrect
Answer: 4) a <b=c
Explanation:
A)
2+3 = 5
5+7 =12
11+13 = 24
17+19 = 36
23+29=52
31+37 =68 (a)
B)
1*6=6
6*5=30
30*4=120 (b)
120*3=360
360*2=720
C)
105+5 = 110
11010 = 100
100+15 = 115
11520 = 95
95+25 = 120 (c) 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections (15): There are 3 number series you have to find the value of a, b, c and then establish relation among a, b, c.
A) 48, 24, 36, (a), 315, 1417.5
B) 24, 35, 48, 65, 84, (b)
C) 101, 103, (c), 109, 113, 127Correct
Answer: 4) a <b=c
Explanation:
A)
48*0.5 = 24
24*1.5 = 36
36*2.5 = 90 (a)
90*3.5 = 315
315*4.5 = 1417.5
B)
24+11 = 35
35+13 = 48
48+17=65
65+19 = 84
84+23 = 107 (b)
C) Prime Numbers: 101, 103, 107(c), 109, 113, 127Incorrect
Answer: 4) a <b=c
Explanation:
A)
48*0.5 = 24
24*1.5 = 36
36*2.5 = 90 (a)
90*3.5 = 315
315*4.5 = 1417.5
B)
24+11 = 35
35+13 = 48
48+17=65
65+19 = 84
84+23 = 107 (b)
C) Prime Numbers: 101, 103, 107(c), 109, 113, 127 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections (15): There are 3 number series you have to find the value of a, b, c and then establish relation among a, b, c.
A) 3, 14, (a), 385, 1536, 4605
B) 1, 10, 0.5, (b), 0.375, 18.75
C) 5, 3, 2, 1.5, (c), 1.125Correct
Answer: 3) a >b>c
Explanation:
A)
3*77 = 14
14*66 = 78 (a)
78*55 = 385
385*44 = 1536
1536*33 = 4605
B) 1*10 = 10
10÷20 = 0.5
0.5*30 = 15 (b)
15÷40 = 0.375
0.375*50 = 18.75
C)
5*0.5 + 0.5 = 3
3*0.5+0.5 = 2
2*0.5+0.5 = 1.5
1.5*0.5+0.5 = 1.25 (c)
1.25*0.5+0.5 = 1.125Incorrect
Answer: 3) a >b>c
Explanation:
A)
3*77 = 14
14*66 = 78 (a)
78*55 = 385
385*44 = 1536
1536*33 = 4605
B) 1*10 = 10
10÷20 = 0.5
0.5*30 = 15 (b)
15÷40 = 0.375
0.375*50 = 18.75
C)
5*0.5 + 0.5 = 3
3*0.5+0.5 = 2
2*0.5+0.5 = 1.5
1.5*0.5+0.5 = 1.25 (c)
1.25*0.5+0.5 = 1.125 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Data below represent the number of people required for the various project to be completed in various days:
If 3 people were working for Project A, how many days did it take to complete the work?
Correct
Answer: 2) 4 days
Explanation:
Project A:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
(X+1)*X = (X1)*(X+3)
X2+X = X2+3XX3
X = 2X3
X = 3
Let the work = (3+1)*3 = 12 units
Workers*Days = 12
3*Days = 12
Days = 4Common Explanation:
Project A:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
(X+1)*X = (X1)*(X+3)
X^{2}+X = X^{2}+3XX3
X = 2X3
X = 3
Project B:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
8*(3Y+4) = (Y+3)*16
24Y+32 = 16Y+48
8Y = 16
Y = 2
Project C:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
M^{3}*27 = 8*N^{3}
3M = 2NIncorrect
Answer: 2) 4 days
Explanation:
Project A:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
(X+1)*X = (X1)*(X+3)
X2+X = X2+3XX3
X = 2X3
X = 3
Let the work = (3+1)*3 = 12 units
Workers*Days = 12
3*Days = 12
Days = 4Common Explanation:
Project A:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
(X+1)*X = (X1)*(X+3)
X^{2}+X = X^{2}+3XX3
X = 2X3
X = 3
Project B:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
8*(3Y+4) = (Y+3)*16
24Y+32 = 16Y+48
8Y = 16
Y = 2
Project C:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
M^{3}*27 = 8*N^{3}
3M = 2N 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Data below represent the number of people required for the various project to be completed in various days:
Find the number of people required to finish the project B in 8Y days.
Correct
Answer: 4) 5
Explanation:
Project B:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
8*(3Y+4) = (Y+3)*16
24Y+32 = 16Y+48
8Y = 16
Y = 2
8Y = 8*2 = 16
Let the work = (Y+3)*16 = (2+3)*16 = 80 units
People*Days = 80
People*8Y = 80
People*16 = 80
People = 5Incorrect
Answer: 4) 5
Explanation:
Project B:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
8*(3Y+4) = (Y+3)*16
24Y+32 = 16Y+48
8Y = 16
Y = 2
8Y = 8*2 = 16
Let the work = (Y+3)*16 = (2+3)*16 = 80 units
People*Days = 80
People*8Y = 80
People*16 = 80
People = 5 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Data below represent the number of people required for the various project to be completed in various days:
If M=4 then find the number of days required to complete the project C in situation 2.
Correct
Answer: 3) 216
Explanation:
Project C:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
M^{3}*27 = 8*N^{3}
3M = 2N
3*4 = 2N
N = 6
N^{3} = 6^{3} = 216Incorrect
Answer: 3) 216
Explanation:
Project C:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
M^{3}*27 = 8*N^{3}
3M = 2N
3*4 = 2N
N = 6
N^{3} = 6^{3} = 216 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Data below represent the number of people required for the various project to be completed in various days:
2*N*X is what percent of 3*M*Y?
Correct
Answer: 5) 150%
Explanation:
Project A:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
(X+1)*X = (X1)*(X+3)
X2+X = X2+3XX3
X = 2X3
X = 3
Project B:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
8*(3Y+4) = (Y+3)*16
24Y+32 = 16Y+48
8Y = 16
Y = 2
Project C:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
M3*27 = 8*N3
3M = 2N
2*N*X = (2N)*3 = 3M*3 = 9M
3*M*Y = 3*M*2 = 6M
Required percentage = (9M/6M)*100 = (3/2)*100 = 150%Incorrect
Answer: 5) 150%
Explanation:
Project A:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
(X+1)*X = (X1)*(X+3)
X2+X = X2+3XX3
X = 2X3
X = 3
Project B:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
8*(3Y+4) = (Y+3)*16
24Y+32 = 16Y+48
8Y = 16
Y = 2
Project C:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
M3*27 = 8*N3
3M = 2N
2*N*X = (2N)*3 = 3M*3 = 9M
3*M*Y = 3*M*2 = 6M
Required percentage = (9M/6M)*100 = (3/2)*100 = 150% 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Data below represent the number of people required for the various project to be completed in various days:
4 workers started working for project B and after 8 days they were replaced by 10 children. The efficiency of a child is 40% of the efficiency of a worker. Find the total time taken to finish the project B.
Correct
Answer: c) 20 days
Explanation:
Project B:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
8*(3Y+4) = (Y+3)*16
24Y+32 = 16Y+48
8Y = 16
Y = 2
Let the work = (Y+3)*16 = (2+3)*16 = 80 units
8 workers completed the work in [(3Y+4) = (3*2+4)] = 10 days
Work completed by 8 workers in 1 day = 80/10 = 8 units
Work done by 4 workers in 1 day will be 4 units
Work done by 1 worker in 1 day = 4/4 = 1 unit
Work done by 4 workers in 8 days will be 4*8 = 32 units
Work left = 8032 = 48units
Work done by 1 child in one day = 0.4*1 = 0.4 unit (efficiency of a child is 40% of the efficiency of worker)
Work done by 10 children in one day will be 0.4*10 = 4 units
Remaining 48 units will be completed by 10 children in 48/4 = 12 days
Total time taken = 8 +12 = 20 daysIncorrect
Answer: c) 20 days
Explanation:
Project B:
Workers*Days (Situation 1) = Workers*Days (Situation 2)
8*(3Y+4) = (Y+3)*16
24Y+32 = 16Y+48
8Y = 16
Y = 2
Let the work = (Y+3)*16 = (2+3)*16 = 80 units
8 workers completed the work in [(3Y+4) = (3*2+4)] = 10 days
Work completed by 8 workers in 1 day = 80/10 = 8 units
Work done by 4 workers in 1 day will be 4 units
Work done by 1 worker in 1 day = 4/4 = 1 unit
Work done by 4 workers in 8 days will be 4*8 = 32 units
Work left = 8032 = 48units
Work done by 1 child in one day = 0.4*1 = 0.4 unit (efficiency of a child is 40% of the efficiency of worker)
Work done by 10 children in one day will be 0.4*10 = 4 units
Remaining 48 units will be completed by 10 children in 48/4 = 12 days
Total time taken = 8 +12 = 20 days
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