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Question 1 of 10
1. Question
1 points
Category: Quantitative Aptitude
How many less mobile phones of PIXEL company remains unsold in years 2014, 2015 as compared to combine unsold phones of LAVA in the same years?
Correct
Explanation
No of PIXEL mobiles remain unsold in year 2014 and 2015= 850000*20% +860500*31%= 170000+266755 =436755
No of LAVA mobiles remain unsold in year 2014 and 2015=650000*44% +794000*25% =484500
Difference =47745
Incorrect
Explanation
No of PIXEL mobiles remain unsold in year 2014 and 2015= 850000*20% +860500*31%= 170000+266755 =436755
No of LAVA mobiles remain unsold in year 2014 and 2015=650000*44% +794000*25% =484500
Difference =47745
Question 2 of 10
2. Question
1 points
Category: Quantitative Aptitude
What is the average number of mobile phones sold by OPPO in the following years?
Correct
Explanation-
total phone sold in all year by OPPO=
862000*88%+423000*55% +612000*75% +876000*80% +842000*35%=24,45,710
Average mobile sold all these years =489142
Incorrect
Explanation-
total phone sold in all year by OPPO=
862000*88%+423000*55% +612000*75% +876000*80% +842000*35%=24,45,710
Average mobile sold all these years =489142
Question 3 of 10
3. Question
1 points
Category: Quantitative Aptitude
What is the difference between the mobile phones sold in year 2013 of MI to unsold mobile phones in 2016 of NOKIA?
Correct
Explanation
Mobile phones sold in 2013 of MI=480000*72%=345600
Mobile phones unsold in 2016 of NOKIA= 850000*20%=170000
Difference=1,75600
Incorrect
Explanation
Mobile phones sold in 2013 of MI=480000*72%=345600
Mobile phones unsold in 2016 of NOKIA= 850000*20%=170000
Difference=1,75600
Question 4 of 10
4. Question
1 points
Category: Quantitative Aptitude
What is the percentage increase of sales of mobile phones of LAVA and OPPO in year 2015 with respect to previous year?
Correct
Explanation
Mobile phones sold in 2015= 876000*80%+794000*75%= 700800+595500=1296300
Mobile phones sold in 2014= 6,12000*75% +6,50000*56%= 4,59,000+3,64,000=8,23,000
Explanation
Mobile phones sold in 2015= 876000*80%+794000*75%= 700800+595500=1296300
Mobile phones sold in 2014= 6,12000*75% +6,50000*56%= 4,59,000+3,64,000=8,23,000
What is the difference between the average numbers of mobile phones manufactured in 2014 to average number of mobile phones manufactured in 2012?
Correct
Incorrect
Question 6 of 10
6. Question
1 points
Category: Quantitative Aptitude
A box contains 6 bottles of variety1 drink, 3 bottles of variety2 drink and 4 bottles of variety3 drink. Three bottles of them are drawn at random, what is the probability that the three are not of the same variety?
Correct
explanation
Total number of drink bottles = 6 + 3 + 4 = 13.
Let S be the sample space.
Then, n(S) = number of ways of taking 3 drink bottles out of 13.
Therefore, n(S) = 13C3=286
Let E be the event of taking 3 bottles of the same variety.
Then, E = event of taking (3 bottles out of 6) or (3 bottles out of 3) or (3 bottles out of 4)
n(E) = 6c3+ 3C3 +4C3=25
The probability of taking 3 bottles of the same variety = n(E)/n(S) = 25/286
Then, the probability of taking 3 bottles are not of the same variety = 1 – 25/286 = 261/286
Incorrect
explanation
Total number of drink bottles = 6 + 3 + 4 = 13.
Let S be the sample space.
Then, n(S) = number of ways of taking 3 drink bottles out of 13.
Therefore, n(S) = 13C3=286
Let E be the event of taking 3 bottles of the same variety.
Then, E = event of taking (3 bottles out of 6) or (3 bottles out of 3) or (3 bottles out of 4)
n(E) = 6c3+ 3C3 +4C3=25
The probability of taking 3 bottles of the same variety = n(E)/n(S) = 25/286
Then, the probability of taking 3 bottles are not of the same variety = 1 – 25/286 = 261/286
Question 7 of 10
7. Question
1 points
Category: Quantitative Aptitude
A train overtakes two bikes which are travelling at the speed of 25km/hr and 30km/hr in the same direction the train is moving and crosses them in 18 and 21 seconds respectively. Then the length of the train is:
Correct
Explanation-
25km/hr = 25 x 5/18 = 125/18 m/sec
and 30km/hr = 30 x 5/18 = 150/18 m/sec.
Let the length of the train be X meters and its speed by Y m/sec
Then the relative speed of the train and the bike with speed 125/18 m/sec is (Y – 125/18)
And the relative speed of the train and the bike with speed 150/18 m/sec is (Y – 150/18).
Relative distance covered is equal which is equal to length of train=
(Y-125/18) *18= (Y-150/18) *21
Y=50/3
Distance of train (50/3-125/18) *18 =175 m
Incorrect
Explanation-
25km/hr = 25 x 5/18 = 125/18 m/sec
and 30km/hr = 30 x 5/18 = 150/18 m/sec.
Let the length of the train be X meters and its speed by Y m/sec
Then the relative speed of the train and the bike with speed 125/18 m/sec is (Y – 125/18)
And the relative speed of the train and the bike with speed 150/18 m/sec is (Y – 150/18).
Relative distance covered is equal which is equal to length of train=
(Y-125/18) *18= (Y-150/18) *21
Y=50/3
Distance of train (50/3-125/18) *18 =175 m
Question 8 of 10
8. Question
1 points
Category: Quantitative Aptitude
If a cyclist starts at 7 km/hr and he increases his speed in every 3 hours by 1 km/hr then the time taken by the cyclist to cover 113 km is:
Correct
Explanation
Initial speed of the cyclist = 7km/hr.
Distance covered in 1st 3 hours = 7 x 3 = 21 km.
After increasing, 1km/hr for every 3 hours period,
Distance covered in 2nd 3 hours period = 8 x 3 = 24 km.
Distance covered in 3rd 3 hours period = 9 x 3 = 27 km.
Distance covered in 4th 3 hours period = 10 x 3 = 30 km.
Total distance covered = 21 + 24 + 27 + 30 = 102 km.
Remaining km to cover = 113 – 102 = 11 km.
Speed in 5th 3 hours period = 11 km/hr.
Time to cover 13 km at 11km/hr = 11/11 hours = 1 hour.
Now, the total time taken by him for 113 km = (3 + 3 + 3 + 3 + 1) = 13 hours.
Incorrect
Explanation
Initial speed of the cyclist = 7km/hr.
Distance covered in 1st 3 hours = 7 x 3 = 21 km.
After increasing, 1km/hr for every 3 hours period,
Distance covered in 2nd 3 hours period = 8 x 3 = 24 km.
Distance covered in 3rd 3 hours period = 9 x 3 = 27 km.
Distance covered in 4th 3 hours period = 10 x 3 = 30 km.
Total distance covered = 21 + 24 + 27 + 30 = 102 km.
Remaining km to cover = 113 – 102 = 11 km.
Speed in 5th 3 hours period = 11 km/hr.
Time to cover 13 km at 11km/hr = 11/11 hours = 1 hour.
Now, the total time taken by him for 113 km = (3 + 3 + 3 + 3 + 1) = 13 hours.
Question 9 of 10
9. Question
1 points
Category: Quantitative Aptitude
A, B, C starts a business with investment of Rs.1,00,000. C invest Rs. 8,000 more than B and B invest Rs. 10,000 more than A. If the total profit is Rs. 70,000 then
Creceives:
Correct
explanation
Let A’s investment be X
Then, B’s = X + 10,000 and C’s = X + 10,000 + 8,000
Now the total investment = X + X + 10,000 + X + 10,000 + 8,000 = 3X + 28,000
From the given data, 3X + 28000 = 1,00,000
3X = 72,000
then X = 24,000.
A: B: C = 24000: 34000: 42,000 = 12: 17: 21
Then c’s share = (21/50) x 70,000 = Rs. 29,400
Incorrect
explanation
Let A’s investment be X
Then, B’s = X + 10,000 and C’s = X + 10,000 + 8,000
Now the total investment = X + X + 10,000 + X + 10,000 + 8,000 = 3X + 28,000
From the given data, 3X + 28000 = 1,00,000
3X = 72,000
then X = 24,000.
A: B: C = 24000: 34000: 42,000 = 12: 17: 21
Then c’s share = (21/50) x 70,000 = Rs. 29,400
Question 10 of 10
10. Question
1 points
Category: Quantitative Aptitude
Two taps P and Q fill a cistern in 2 days and 3 days respectively and another tap R empties the full cistern in 4 days. If all the taps P, Q and R switched simultaneously then the time taken to fill the cistern is:
