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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections(Q. 1 – 5): The questions below are based on the given SeriesI. The seriesI satisfy a certain pattern, follow the same pattern in SeriesII and answer the questions given below.
I) 5, 6, 10, 33, 128, ?
II) 9,……,1125. If 1125 is n th term, then find the value of n?Correct
Explanation:
Series I Pattern:
5 * 1 + 1 = 6
6 * 2 – 2 = 10
10 * 3 + 3 = 33
33 * 4 – 4 = 128
128 * 5 + 5 = 645
Series II Pattern:
Here, 9th is the first term
9*1+1=10
10*22=18
18*3+3=57
57*44=224
224*5+5=1125
1125 is 6th term. So, n = 6Incorrect
Explanation:
Series I Pattern:
5 * 1 + 1 = 6
6 * 2 – 2 = 10
10 * 3 + 3 = 33
33 * 4 – 4 = 128
128 * 5 + 5 = 645
Series II Pattern:
Here, 9th is the first term
9*1+1=10
10*22=18
18*3+3=57
57*44=224
224*5+5=1125
1125 is 6th term. So, n = 6 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections (Q. 1 – 5): The questions below are based on the given SeriesI. The seriesI satisfy a certain pattern, follow the same pattern in SeriesII and answer the questions given below.
I) 2, 9, 39, 161, 651, ?
II) 5,………,5685 If is nth term, then what value should come in place of (n – 3)th term?Correct
Explanation:
Series I Pattern:
2 is the first term
2 * 4 + 1 = 9
9 * 4 + 3 = 39
39 * 4 + 5 = 161
161 * 4 + 7 = 651
651 * 4 + 9 = 2613
2613 is the 6th term
Series II Pattern:
5 is the first term
5*4+1=21
21*4+3=87= (n3)th term
87*4+5=353= (n2)th term
353*4+7=1419= (n1)th term
1419*4+9=5685= nth term
Value of (n3)th term= 87Incorrect
Explanation:
Series I Pattern:
2 is the first term
2 * 4 + 1 = 9
9 * 4 + 3 = 39
39 * 4 + 5 = 161
161 * 4 + 7 = 651
651 * 4 + 9 = 2613
2613 is the 6th term
Series II Pattern:
5 is the first term
5*4+1=21
21*4+3=87= (n3)th term
87*4+5=353= (n2)th term
353*4+7=1419= (n1)th term
1419*4+9=5685= nth term
Value of (n3)th term= 87 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections (Q. 1 – 5): The questions below are based on the given SeriesI. The seriesI satisfy a certain pattern, follow the same pattern in SeriesII and answer the questions given below.
I) 4, 5, 6, ?, 32.5, 100.5
II) 2,3,8 …….,190.75. If 190.75 is nth term, then find the value of n?Correct
Explanation:
Series I Pattern:
4 is the first term
4 * 1 + 1 = 5
5 * 1.5 – 1.5= 6
6 * 2 + 2 = 14
14 * 2.5 – 2.5 = 32.5
32.5 * 3 + 3 = 100.5
Series II Pattern:
2 is the first term
2*1+1=3
3*1.51.5=3
3*2+2=8
8*2.52.5=17.5
17.5*3+3=55.5
55.5*3.53.5=190.75 = 7th term
n= 7Incorrect
Explanation:
Series I Pattern:
4 is the first term
4 * 1 + 1 = 5
5 * 1.5 – 1.5= 6
6 * 2 + 2 = 14
14 * 2.5 – 2.5 = 32.5
32.5 * 3 + 3 = 100.5
Series II Pattern:
2 is the first term
2*1+1=3
3*1.51.5=3
3*2+2=8
8*2.52.5=17.5
17.5*3+3=55.5
55.5*3.53.5=190.75 = 7th term
n= 7 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections (Q. 1 – 5): The questions below are based on the given SeriesI. The seriesI satisfy a certain pattern, follow the same pattern in SeriesII and answer the questions given below.
I) 6, 6, 7, ?, 91, 463
II) 4, 4 ……. 223. If 223 is nth term, then what value should come in place of (n2)th term?Correct
Explanation:
Series I Pattern:
6 is the first term
6*1 – 1 + 1 = 6
6*2 – 2 – 3 = 7
7*3 – 1 + 5 = 25
25*4 – 2 – 7 = 91
91*5 – 1 + 9 = 463
Series II Pattern:
4 is the first term
4*11+1=4
4*223=3
3*31+5=13= (n2)th term
13*427=43=(n1)th term
43*51+9=223= nth term
Value of (n2)th term= 13Incorrect
Explanation:
Series I Pattern:
6 is the first term
6*1 – 1 + 1 = 6
6*2 – 2 – 3 = 7
7*3 – 1 + 5 = 25
25*4 – 2 – 7 = 91
91*5 – 1 + 9 = 463
Series II Pattern:
4 is the first term
4*11+1=4
4*223=3
3*31+5=13= (n2)th term
13*427=43=(n1)th term
43*51+9=223= nth term
Value of (n2)th term= 13 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections (Q. 1 – 5): The questions below are based on the given SeriesI. The seriesI satisfy a certain pattern, follow the same pattern in SeriesII and answer the questions given below.
I) 107, 106, 52, 16.3 , ?
II) 51, ……, .75. If .75 is nth term, then find the value of n?Correct
Explanation:
Series I Pattern:
107 is the first term
1071/1 = 106
1062/2 = 52
523/3 = 16.3
16.34/4 = 3.075
Series II Pattern:
51 is the first term
(511)/1=50
(502)/2=24
(243)/3=7
(74)/4=.75= nth term
n=5Incorrect
Explanation:
Series I Pattern:
107 is the first term
1071/1 = 106
1062/2 = 52
523/3 = 16.3
16.34/4 = 3.075
Series II Pattern:
51 is the first term
(511)/1=50
(502)/2=24
(243)/3=7
(74)/4=.75= nth term
n=5 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Refer to the table and answer the given questions.
Cities Total Population(In Lakhs) Rural:Urban Male : Female Literate: Illiterate % of Graduate out of Literates P _ 7:3 10:11 1:3 _ Q 4.25 _ 7:3 _ 45 R _ 8:7 _ 7:4 _ S 5.25 _ 11:4 _ 60 T _ 11:9 _ 2:3 _ The total population of City P and R is 7,85,000. The difference between the total population of City P and R is 2.65 lakhs. If City P has more population than City R then the urban population of City P and R together is approximately what percent of the total population of these two Cities?
Correct
Explanation :
P + R = 7,85,000
(P has more population than R) P – R = 215000
P = 5,00,000 ; R = 2,85,000
Urban population of City P and R = 3/10 * 5,00,000 + 7/15 * 2,85,000 = 283000
% = (283000 / 785000)*100 = 36% (Approx)Incorrect
Explanation :
P + R = 7,85,000
(P has more population than R) P – R = 215000
P = 5,00,000 ; R = 2,85,000
Urban population of City P and R = 3/10 * 5,00,000 + 7/15 * 2,85,000 = 283000
% = (283000 / 785000)*100 = 36% (Approx) 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Refer to the table and answer the given questions.
Cities Total Population(In Lakhs) Rural:Urban Male : Female Literate: Illiterate % of Graduate out of Literates P _ 7:3 10:11 1:3 _ Q 4.25 _ 7:3 _ 45 R _ 8:7 _ 7:4 _ S 5.25 _ 11:4 _ 60 T _ 11:9 _ 2:3 _ The difference between the number of male and female in the City P is 10000. Approximately, by what percent of the rural population of City P more than its urban population?
Correct
Explanation :
X = Total population in City A
1/21 * X = 10000 => X = 2,10,000
Rural Population = 1,47,000
Urban Population = 63,000
% = (Difference / Urban Population)*100 = (84,000 / 63000)*100 = 133% (approx)Incorrect
Explanation :
X = Total population in City A
1/21 * X = 10000 => X = 2,10,000
Rural Population = 1,47,000
Urban Population = 63,000
% = (Difference / Urban Population)*100 = (84,000 / 63000)*100 = 133% (approx) 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Refer to the table and answer the given questions.
Cities Total Population(In Lakhs) Rural:Urban Male : Female Literate: Illiterate % of Graduate out of Literates P _ 7:3 10:11 1:3 _ Q 4.25 _ 7:3 _ 45 R _ 8:7 _ 7:4 _ S 5.25 _ 11:4 _ 60 T _ 11:9 _ 2:3 _ One–fourth of total population of City R is 2,20,000. If the total number of Literate graduates of City Q and S are 18,000 and 48,000 respectively. What % (approx) of the total population of City Q, R and S together is literate?
Correct
Explanation :
1/4 * R = 2,20,000 => R = 8,80,000
Literate population of City R = 7/11 * 8,80,000 = 5,60,000
Total number of Literate graduates of City Q = 18000 = 45%
x = Literate population of City Q
45% of x = 18000 => x = 40000
Total number of Literate graduates of City S = 48000 = 60%
y = Literate population of City S
60% of y = 48000 => x = 80000
% = (680000/1830000) * 100 = 37% (approx)Incorrect
Explanation :
1/4 * R = 2,20,000 => R = 8,80,000
Literate population of City R = 7/11 * 8,80,000 = 5,60,000
Total number of Literate graduates of City Q = 18000 = 45%
x = Literate population of City Q
45% of x = 18000 => x = 40000
Total number of Literate graduates of City S = 48000 = 60%
y = Literate population of City S
60% of y = 48000 => x = 80000
% = (680000/1830000) * 100 = 37% (approx) 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Refer to the table and answer the given questions.
Cities Total Population(In Lakhs) Rural:Urban Male : Female Literate: Illiterate % of Graduate out of Literates P _ 7:3 10:11 1:3 _ Q 4.25 _ 7:3 _ 45 R _ 8:7 _ 7:4 _ S 5.25 _ 11:4 _ 60 T _ 11:9 _ 2:3 _ The difference between the total population of City R and T is 60,000. The ratio of total population of City R and T is 44:41. Total % of Literate graduates of City R and T is 90%. If the % Literate graduates of City R is equalled to half of Literate graduates of City T, then what is the difference between the number of graduates from City R and City T?
Correct
Explanation:
3/85 * x = 60000 => x = 1700000
44/85*1700000 = 880000 =Population of city R
7/11*880000 = 560000
Total % of Literate graduates of City R and T is 90%
If the % Literate graduates of City R is equalled to half of Literate graduates of City T, then
% of Literate graduates of City R =30%
% Literate graduates of City T = 60%
Number of graduates from City R = 30% of 560000 = 168000
41/85*170000 = 820000 =Population of city T
2/5*820000 = 328000
Number of graduates from City T = 60% of 3,28,000 = 196800
Difference = 28800Incorrect
Explanation:
3/85 * x = 60000 => x = 1700000
44/85*1700000 = 880000 =Population of city R
7/11*880000 = 560000
Total % of Literate graduates of City R and T is 90%
If the % Literate graduates of City R is equalled to half of Literate graduates of City T, then
% of Literate graduates of City R =30%
% Literate graduates of City T = 60%
Number of graduates from City R = 30% of 560000 = 168000
41/85*170000 = 820000 =Population of city T
2/5*820000 = 328000
Number of graduates from City T = 60% of 3,28,000 = 196800
Difference = 28800 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Refer to the table and answer the given questions.
Cities Total Population(In Lakhs) Rural:Urban Male : Female Literate: Illiterate % of Graduate out of Literates P _ 7:3 10:11 1:3 _ Q 4.25 _ 7:3 _ 45 R _ 8:7 _ 7:4 _ S 5.25 _ 11:4 _ 60 T _ 11:9 _ 2:3 _ What is the sum of the male population in City S and the female population in City Q together?
Correct
Explanation :
Sum = 11/15 *525000 + 3/10 * 425000 = 385000 +127500 = 512500Incorrect
Explanation :
Sum = 11/15 *525000 + 3/10 * 425000 = 385000 +127500 = 512500
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