Welcome to Online Quant Test in AffairsCloud.com. We are starting Cumulus Course for IBPS PO 2019 Main Exam and we are creating sample questions in Quant section, this type of Question will be asked in IBPS PO 2019!!!

Help:- Share Our Cumulus Course for IBPS PO 2019 Exam Course page to your Friends & FB Groups

________________________

Time limit: 0

Quiz-summary

0 of 10 questions completed

Questions:

1

2

3

4

5

6

7

8

9

10

Information

All the Best

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

Results

0 of 10 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

Categories

Quantitative Aptitude0%

1

2

3

4

5

6

7

8

9

10

Answered

Review

Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Directions(Q. 1 – 5): The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
I) 5, 6, 10, 33, 128, ?
II) 9,……,1125. If 1125 is n th term, then find the value of n?

Correct

Explanation:
Series I Pattern:
5 * 1 + 1 = 6
6 * 2 – 2 = 10
10 * 3 + 3 = 33
33 * 4 – 4 = 128
128 * 5 + 5 = 645
Series II Pattern:
Here, 9th is the first term
9*1+1=10
10*2-2=18
18*3+3=57
57*4-4=224
224*5+5=1125
1125 is 6th term. So, n = 6

Incorrect

Explanation:
Series I Pattern:
5 * 1 + 1 = 6
6 * 2 – 2 = 10
10 * 3 + 3 = 33
33 * 4 – 4 = 128
128 * 5 + 5 = 645
Series II Pattern:
Here, 9th is the first term
9*1+1=10
10*2-2=18
18*3+3=57
57*4-4=224
224*5+5=1125
1125 is 6th term. So, n = 6

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Directions (Q. 1 – 5): The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
I) 2, 9, 39, 161, 651, ?
II) 5,………,5685 If is nth term, then what value should come in place of (n – 3)th term?

Correct

Explanation:
Series I Pattern:
2 is the first term
2 * 4 + 1 = 9
9 * 4 + 3 = 39
39 * 4 + 5 = 161
161 * 4 + 7 = 651
651 * 4 + 9 = 2613
2613 is the 6th term
Series II Pattern:
5 is the first term
5*4+1=21
21*4+3=87= (n-3)th term
87*4+5=353= (n-2)th term
353*4+7=1419= (n-1)th term
1419*4+9=5685= nth term
Value of (n-3)th term= 87

Incorrect

Explanation:
Series I Pattern:
2 is the first term
2 * 4 + 1 = 9
9 * 4 + 3 = 39
39 * 4 + 5 = 161
161 * 4 + 7 = 651
651 * 4 + 9 = 2613
2613 is the 6th term
Series II Pattern:
5 is the first term
5*4+1=21
21*4+3=87= (n-3)th term
87*4+5=353= (n-2)th term
353*4+7=1419= (n-1)th term
1419*4+9=5685= nth term
Value of (n-3)th term= 87

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Directions (Q. 1 – 5): The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
I) 4, 5, 6, ?, 32.5, 100.5
II) 2,3,8 …….,190.75. If 190.75 is nth term, then find the value of n?

Correct

Explanation:
Series I Pattern:
4 is the first term
4 * 1 + 1 = 5
5 * 1.5 – 1.5= 6
6 * 2 + 2 = 14
14 * 2.5 – 2.5 = 32.5
32.5 * 3 + 3 = 100.5
Series II Pattern:
2 is the first term
2*1+1=3
3*1.5-1.5=3
3*2+2=8
8*2.5-2.5=17.5
17.5*3+3=55.5
55.5*3.5-3.5=190.75 = 7th term
n= 7

Incorrect

Explanation:
Series I Pattern:
4 is the first term
4 * 1 + 1 = 5
5 * 1.5 – 1.5= 6
6 * 2 + 2 = 14
14 * 2.5 – 2.5 = 32.5
32.5 * 3 + 3 = 100.5
Series II Pattern:
2 is the first term
2*1+1=3
3*1.5-1.5=3
3*2+2=8
8*2.5-2.5=17.5
17.5*3+3=55.5
55.5*3.5-3.5=190.75 = 7th term
n= 7

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Directions (Q. 1 – 5): The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
I) 6, 6, 7, ?, 91, 463
II) 4, 4 ……. 223. If 223 is nth term, then what value should come in place of (n-2)th term?

Correct

Explanation:
Series I Pattern:
6 is the first term
6*1 – 1 + 1 = 6
6*2 – 2 – 3 = 7
7*3 – 1 + 5 = 25
25*4 – 2 – 7 = 91
91*5 – 1 + 9 = 463
Series II Pattern:
4 is the first term
4*1-1+1=4
4*2-2-3=3
3*3-1+5=13= (n-2)th term
13*4-2-7=43=(n-1)th term
43*5-1+9=223= nth term
Value of (n-2)th term= 13

Incorrect

Explanation:
Series I Pattern:
6 is the first term
6*1 – 1 + 1 = 6
6*2 – 2 – 3 = 7
7*3 – 1 + 5 = 25
25*4 – 2 – 7 = 91
91*5 – 1 + 9 = 463
Series II Pattern:
4 is the first term
4*1-1+1=4
4*2-2-3=3
3*3-1+5=13= (n-2)th term
13*4-2-7=43=(n-1)th term
43*5-1+9=223= nth term
Value of (n-2)th term= 13

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Directions (Q. 1 – 5): The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
I) 107, 106, 52, 16.3 , ?
II) 51, ……, .75. If .75 is nth term, then find the value of n?

Correct

Explanation:
Series I Pattern:
107 is the first term
107-1/1 = 106
106-2/2 = 52
52-3/3 = 16.3
16.3-4/4 = 3.075
Series II Pattern:
51 is the first term
(51-1)/1=50
(50-2)/2=24
(24-3)/3=7
(7-4)/4=.75= nth term
n=5

Incorrect

Explanation:
Series I Pattern:
107 is the first term
107-1/1 = 106
106-2/2 = 52
52-3/3 = 16.3
16.3-4/4 = 3.075
Series II Pattern:
51 is the first term
(51-1)/1=50
(50-2)/2=24
(24-3)/3=7
(7-4)/4=.75= nth term
n=5

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): Refer to the table and answer the given questions.

Cities

Total Population(In Lakhs)

Rural:Urban

Male : Female

Literate: Illiterate

% of Graduate out of Literates

P

_

7:3

10:11

1:3

_

Q

4.25

_

7:3

_

45

R

_

8:7

_

7:4

_

S

5.25

_

11:4

_

60

T

_

11:9

_

2:3

_

The total population of City P and R is 7,85,000. The difference between the total population of City P and R is 2.65 lakhs. If City P has more population than City R then the urban population of City P and R together is approximately what percent of the total population of these two Cities?

Correct

Explanation :
P + R = 7,85,000
(P has more population than R) P – R = 215000
P = 5,00,000 ; R = 2,85,000
Urban population of City P and R = 3/10 * 5,00,000 + 7/15 * 2,85,000 = 283000
% = (283000 / 785000)*100 = 36% (Approx)

Incorrect

Explanation :
P + R = 7,85,000
(P has more population than R) P – R = 215000
P = 5,00,000 ; R = 2,85,000
Urban population of City P and R = 3/10 * 5,00,000 + 7/15 * 2,85,000 = 283000
% = (283000 / 785000)*100 = 36% (Approx)

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): Refer to the table and answer the given questions.

Cities

Total Population(In Lakhs)

Rural:Urban

Male : Female

Literate: Illiterate

% of Graduate out of Literates

P

_

7:3

10:11

1:3

_

Q

4.25

_

7:3

_

45

R

_

8:7

_

7:4

_

S

5.25

_

11:4

_

60

T

_

11:9

_

2:3

_

The difference between the number of male and female in the City P is 10000. Approximately, by what percent of the rural population of City P more than its urban population?

Correct

Explanation :
X = Total population in City A
1/21 * X = 10000 => X = 2,10,000
Rural Population = 1,47,000
Urban Population = 63,000
% = (Difference / Urban Population)*100 = (84,000 / 63000)*100 = 133% (approx)

Incorrect

Explanation :
X = Total population in City A
1/21 * X = 10000 => X = 2,10,000
Rural Population = 1,47,000
Urban Population = 63,000
% = (Difference / Urban Population)*100 = (84,000 / 63000)*100 = 133% (approx)

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): Refer to the table and answer the given questions.

Cities

Total Population(In Lakhs)

Rural:Urban

Male : Female

Literate: Illiterate

% of Graduate out of Literates

P

_

7:3

10:11

1:3

_

Q

4.25

_

7:3

_

45

R

_

8:7

_

7:4

_

S

5.25

_

11:4

_

60

T

_

11:9

_

2:3

_

One–fourth of total population of City R is 2,20,000. If the total number of Literate graduates of City Q and S are 18,000 and 48,000 respectively. What % (approx) of the total population of City Q, R and S together is literate?

Correct

Explanation :
1/4 * R = 2,20,000 => R = 8,80,000
Literate population of City R = 7/11 * 8,80,000 = 5,60,000
Total number of Literate graduates of City Q = 18000 = 45%
x = Literate population of City Q
45% of x = 18000 => x = 40000
Total number of Literate graduates of City S = 48000 = 60%
y = Literate population of City S
60% of y = 48000 => x = 80000
% = (680000/1830000) * 100 = 37% (approx)

Incorrect

Explanation :
1/4 * R = 2,20,000 => R = 8,80,000
Literate population of City R = 7/11 * 8,80,000 = 5,60,000
Total number of Literate graduates of City Q = 18000 = 45%
x = Literate population of City Q
45% of x = 18000 => x = 40000
Total number of Literate graduates of City S = 48000 = 60%
y = Literate population of City S
60% of y = 48000 => x = 80000
% = (680000/1830000) * 100 = 37% (approx)

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): Refer to the table and answer the given questions.

Cities

Total Population(In Lakhs)

Rural:Urban

Male : Female

Literate: Illiterate

% of Graduate out of Literates

P

_

7:3

10:11

1:3

_

Q

4.25

_

7:3

_

45

R

_

8:7

_

7:4

_

S

5.25

_

11:4

_

60

T

_

11:9

_

2:3

_

The difference between the total population of City R and T is 60,000. The ratio of total population of City R and T is 44:41. Total % of Literate graduates of City R and T is 90%. If the % Literate graduates of City R is equalled to half of Literate graduates of City T, then what is the difference between the number of graduates from City R and City T?

Correct

Explanation:
3/85 * x = 60000 => x = 1700000
44/85*1700000 = 880000 =Population of city R
7/11*880000 = 560000
Total % of Literate graduates of City R and T is 90%
If the % Literate graduates of City R is equalled to half of Literate graduates of City T, then
% of Literate graduates of City R =30%
% Literate graduates of City T = 60%
Number of graduates from City R = 30% of 560000 = 168000
41/85*170000 = 820000 =Population of city T
2/5*820000 = 328000
Number of graduates from City T = 60% of 3,28,000 = 196800
Difference = 28800

Incorrect

Explanation:
3/85 * x = 60000 => x = 1700000
44/85*1700000 = 880000 =Population of city R
7/11*880000 = 560000
Total % of Literate graduates of City R and T is 90%
If the % Literate graduates of City R is equalled to half of Literate graduates of City T, then
% of Literate graduates of City R =30%
% Literate graduates of City T = 60%
Number of graduates from City R = 30% of 560000 = 168000
41/85*170000 = 820000 =Population of city T
2/5*820000 = 328000
Number of graduates from City T = 60% of 3,28,000 = 196800
Difference = 28800

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): Refer to the table and answer the given questions.

Cities

Total Population(In Lakhs)

Rural:Urban

Male : Female

Literate: Illiterate

% of Graduate out of Literates

P

_

7:3

10:11

1:3

_

Q

4.25

_

7:3

_

45

R

_

8:7

_

7:4

_

S

5.25

_

11:4

_

60

T

_

11:9

_

2:3

_

What is the sum of the male population in City S and the female population in City Q together?

Click view Questions button to view Explanation
Note:- We are providing unique questions for you to practice well, have a try !!
Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
If you find any mistake, please tell us in the comment section.