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The average marks of 32 boys of section A of class X is 60 whereas the average marks of 40 boys of section B of class X is 33. What isthe average marks for both the sections combined together ?

Correct

Answer – 2) 45
Explanation:
The average marks of 32 boys= 32 X 60
The average marks of 40 boys= 40 X 33
Therefore, Mixed average= (32 X 60 + 40 X 33)/72
= (1920+1320)/72
= (3240)/72 = 45

Incorrect

Answer – 2) 45
Explanation:
The average marks of 32 boys= 32 X 60
The average marks of 40 boys= 40 X 33
Therefore, Mixed average= (32 X 60 + 40 X 33)/72
= (1920+1320)/72
= (3240)/72 = 45

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

A principal of Rs. 10,000 after 2 years compounded annually, the rate of interest being 10% per annum during the first year and 12% per annum during the second year (in rupees), what will be the total price after 2 years?

Correct

Answer – 2) Rs 12320
Explanation:
Principal= Rs 10,000
Time= 2 years
Rate of Interest of 1st year= 10%
Rate of interest of 2nd year= 12%

Incorrect

Answer – 2) Rs 12320
Explanation:
Principal= Rs 10,000
Time= 2 years
Rate of Interest of 1st year= 10%
Rate of interest of 2nd year= 12%

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

By melting a solid lead sphere of diameter 12cm, three small spheres are made whose diameters are in the ratio 3 : 4 : 5. What is the radius (in cm) of the smallest sphere?

Correct

Answer – 4) 3
Explanation:
Let radius of smallest sphere= 3x
Radius of sphere 2= 4x
Radius of sphere 3= 5x
Volume of Sphere=(4/3) ∏R^{3}
(4/3)∏ {(3x)^{ 3} + (4x)^{ 3} + (5x)^{ 3}} = (4/3)∏(6)^{3}
X^{3}(27 + 64 + 125) = 216
X^{3}(216) = 216
X^{3} = 1
X = 1
Radius of smallest sphere= 3x =3 * 1= 3cm

Incorrect

Answer – 4) 3
Explanation:
Let radius of smallest sphere= 3x
Radius of sphere 2= 4x
Radius of sphere 3= 5x
Volume of Sphere=(4/3) ∏R^{3}
(4/3)∏ {(3x)^{ 3} + (4x)^{ 3} + (5x)^{ 3}} = (4/3)∏(6)^{3}
X^{3}(27 + 64 + 125) = 216
X^{3}(216) = 216
X^{3} = 1
X = 1
Radius of smallest sphere= 3x =3 * 1= 3cm

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

The annual income of A and B are in the ratio 4:3 and the ratio of their expenditures is 3:2. If each of them saves Rs 600 in the year, what is the annual income of A?

Correct

Answer – 2) Rs 2400
Explanation:

Therefore, 1 unit= 600
Income of A= 600 x 4= Rs 2400
Income of B= 600 x 3= Rs 1800

Incorrect

Answer – 2) Rs 2400
Explanation:

Therefore, 1 unit= 600
Income of A= 600 x 4= Rs 2400
Income of B= 600 x 3= Rs 1800

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

In an examination A got 25% marks more than B, B got 10% less than C and C got 25% more than D. If D got 320 marks out of 500, What were the marks obtained by A?

Correct

Answer – 4) 450
Explanation:
Marks obtained by D = 320
Marks obtained by C = 320 X (125/100) = 400
Marks obtained by A = 320 X (125/100) = 450
Hence, required marks obtained by A = 450

Incorrect

Answer – 4) 450
Explanation:
Marks obtained by D = 320
Marks obtained by C = 320 X (125/100) = 400
Marks obtained by A = 320 X (125/100) = 450
Hence, required marks obtained by A = 450

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

A container contains 60 kg of milk. From this container 6kg of milk was taken out and replaced by water. This process was repeated further two times. What is the amount of milk left in the container?

Correct

Answer – 3) 43.74 Kg
Explanation:
According to the question,
Initial quantity= 60 kg
Final quantity= Initial quantity ((1-(Volume taken out/Initial Quantity)) n
Where, n= number of times volume taken out
Final Quantity = 60 (1-(6/60)) 3
= 60 X 9/10 X 9/10 X 9/10
Final Quantity of milk= 43.74 kg

Incorrect

Answer – 3) 43.74 Kg
Explanation:
According to the question,
Initial quantity= 60 kg
Final quantity= Initial quantity ((1-(Volume taken out/Initial Quantity)) n
Where, n= number of times volume taken out
Final Quantity = 60 (1-(6/60)) 3
= 60 X 9/10 X 9/10 X 9/10
Final Quantity of milk= 43.74 kg

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Two Quantities (I) and (II) are given in each question. On the basis of these equations you have to decide the relation between “X” and “Y” and given answer. Quantity I : 6x^{2} – 19x + 15=0 Quantity II: 10y^{2} – 29y + 21= 0