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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Ajay can complete a given project in 20 days. Bharat takes 20% more than time than Ajay to complete the same project. Bharat started working alone for 2 days and was joined by Ajay till the completion of project. In how many days was the entire project completed?**CorrectAnswer –

**2)12**

Explanation:

Time taken by Ajay in doing work =20 days

Time taken by Bharat =(20*120)/100=24 days

Bharat’s 2 days work = 2/24=1/12

Remaining work =1-1/2=11/12

(Ajay+Bharat)’s 1 day’s work = 1/20+1/24=11/120

Time taken in doing 1 work =120/11

Time taken in doing 11/12 work =120/11 *11/20 = 10 daysIncorrectAnswer –

**2)12**

Explanation:

Time taken by Ajay in doing work =20 days

Time taken by Bharat =(20*120)/100=24 days

Bharat’s 2 days work = 2/24=1/12

Remaining work =1-1/2=11/12

(Ajay+Bharat)’s 1 day’s work = 1/20+1/24=11/120

Time taken in doing 1 work =120/11

Time taken in doing 11/12 work =120/11 *11/20 = 10 days - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Amit and Bala started a business. Bala’s investment was 2.5 times that of Amit. The respective ratio between the time period for which Amit invested and that for which Bala invested was 3: 1. If the total investment made by Amit & Bala together was Rs 28000 and the annual profit earned was Rs 2500 less than Amit’s investment, what was the difference between Amit’s dividend and Bala’s dividend in the annual profit?**CorrectAnswer –

**3)500**

Explanation:

Amit’s investments =Rs X

Bala’s investment = Rs 2.5x

X+2.5x=Rs 28000

X= 8000

Bala’s investment = Rs (2.5*8000)= 20000

Ratio of equivalent capitals of A & B for 1 month

=8000 *3 : 20000=6:5

Annual profit =8000-2500=Rs 5500

Difference of dividends = Rs [(6-5)/(6+5)]* 5500 = Rs 500IncorrectAnswer –

**3)500**

Explanation:

Amit’s investments =Rs X

Bala’s investment = Rs 2.5x

X+2.5x=Rs 28000

X= 8000

Bala’s investment = Rs (2.5*8000)= 20000

Ratio of equivalent capitals of A & B for 1 month

=8000 *3 : 20000=6:5

Annual profit =8000-2500=Rs 5500

Difference of dividends = Rs [(6-5)/(6+5)]* 5500 = Rs 500 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**In ‘x’ hours a bike covers 36 km less than the distance covered by an ambulance in the same time. The speed of the bike is 12 kmph less than the speed of the ambulance. Had the speed of the bike been 52 kmph. What would have been the distance covered in “x-1/2” hours**CorrectAnswer –

**4)130**

Explanation:

Speed of ambulance – speed of bike =12 kmph

x = 36/12= 3 hours

Speed of bike= 52 kmph

Time = x-1/2=(3-1/2)= 5/2 hours

Required distance = 52 * 5/2= 130 kmIncorrectAnswer –

**4)130**

Explanation:

Speed of ambulance – speed of bike =12 kmph

x = 36/12= 3 hours

Speed of bike= 52 kmph

Time = x-1/2=(3-1/2)= 5/2 hours

Required distance = 52 * 5/2= 130 km - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**Arun’s age 7 years ago was 10 years more than half of his present age. The respective ratio between Baskar’s age 4 years ago and Arun’s age that time was 2 :5. If Chand’s age 12 years hence will be thrice of Baskar’s age 2 years ago, what is Chand’s present age?(in years)**CorrectAnswer –

**2)30**

Explanation:

Arun’s present age = x years

x-7=x/2+10

x=34 years

Again, Baskar’s present age =y years

(y-4)/30=2/5

Y=16 years

Chand+12=3* (16-2)=42

Chand = 30 yearsIncorrectAnswer –

**2)30**

Explanation:

Arun’s present age = x years

x-7=x/2+10

x=34 years

Again, Baskar’s present age =y years

(y-4)/30=2/5

Y=16 years

Chand+12=3* (16-2)=42

Chand = 30 years - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**Anil & Bhuvan entered into a partnership and invested capital in the ratio of 4 : 5. At the end of 8 months Anil withdrawn half of his amount. If at the end of one year, they received profits in the ratio of 4 : 5, then Bhuvan’s capital was used for how many months**CorrectAnswer –

**5)10 months**

Explanation:

Anil = 4X, Bhuvan = 5X

At the end of 8 months (4x – 4x/2) : 5x

Now,

(4x*8 + 2x *4)/5x * Bhuvan’s months = 4/5

Bhuvan’s month=10 monthsIncorrectAnswer –

**5)10 months**

Explanation:

Anil = 4X, Bhuvan = 5X

At the end of 8 months (4x – 4x/2) : 5x

Now,

(4x*8 + 2x *4)/5x * Bhuvan’s months = 4/5

Bhuvan’s month=10 months - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative AptitudeDirections (6-10) Study the following information carefully and answer the questions given below.

The table shows the data of two trains from Monday to Friday.

**On Monday, find out the sum of Conditions (i),(ii) and (iii)**

(i) If the two trains run in opposite directions on parallel tracks then find out the sum of the time which they take to cross each other.

(ii) The time taken by train 1 if it crosses a pole.

(iii) The time taken by train 2 if it crosses a man.CorrectAnswer –

**5)18.9s**

Explanation:

(i) Total length = 105 + 90 = 195

Relative Speed = 72 + 45 = 117 kmph = 117 * 5/18 = 585/18 m/s

Time = 6s

(ii) 105/(45*5/18) = 8.4s

(iii) 90/(72*5/18) = 4.5s

Sum = 6+8.4+4.5 = 18.9sIncorrectAnswer –

**5)18.9s**

Explanation:

(i) Total length = 105 + 90 = 195

Relative Speed = 72 + 45 = 117 kmph = 117 * 5/18 = 585/18 m/s

Time = 6s

(ii) 105/(45*5/18) = 8.4s

(iii) 90/(72*5/18) = 4.5s

Sum = 6+8.4+4.5 = 18.9s - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative AptitudeDirections (6-10) Study the following information carefully and answer the questions given below.

The table shows the data of two trains from Monday to Friday.

**On Tuesday, find out the difference between Conditions (ii) and (i)**

(i) If the two trains run in opposite directions on parallel tracks then find out the sum of the time which they take to cross each other.

(ii) The sum of the time taken by train 1 and train 2 if they crosses the bridge of 70m and 60m respectively.CorrectAnswer –

**4)35.4s**

Explanation:

Condition(i)

(180 + 240) / (30 + 40)*5/18 = 21.6s

Condition(ii)

Time taken by train 1 = (180+70)/(30*5/18) = 30s

Time taken by train 2 = (240+60)/(40*5/18) = 27sIncorrectAnswer –

**4)35.4s**

Explanation:

Condition(i)

(180 + 240) / (30 + 40)*5/18 = 21.6s

Condition(ii)

Time taken by train 1 = (180+70)/(30*5/18) = 30s

Time taken by train 2 = (240+60)/(40*5/18) = 27s - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative AptitudeDirections (6-10) Study the following information carefully and answer the questions given below.

The table shows the data of two trains from Monday to Friday.

**On Wednesday find out the ratio of conditions (i) (ii) and (iii)**

(i) If the two trains run in opposite directions on parallel tracks then find out the sum of the time which they take to cross each other.

(ii) The time taken by train 1 if it crosses a signal post

(iii) The time taken by train 2 if it crosses a platform of 60mCorrectAnswer –

**3)2:3:2**

Explanation:

Condition(i)

(180 + 120) / (72 + 108)*5/18 = 6s

Condition(ii)

Time taken by train 1 =180/(72*5/18) = 9s

Condition(iii)

Time taken by train 2 =(120+60)/(108*5/18) = 6s

2:3:2IncorrectAnswer –

**3)2:3:2**

Explanation:

Condition(i)

(180 + 120) / (72 + 108)*5/18 = 6s

Condition(ii)

Time taken by train 1 =180/(72*5/18) = 9s

Condition(iii)

Time taken by train 2 =(120+60)/(108*5/18) = 6s

2:3:2 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative AptitudeDirections (6-10) Study the following information carefully and answer the questions given below.

The table shows the data of two trains from Monday to Friday.

**On Friday, the length of the two trains are same and cross each other in 6s then find out the sum of the length of two trains?**CorrectAnswer –

**2)250 m**

Explanation:

(65+85)*5/18 = (2x)/6

2x = 250IncorrectAnswer –

**2)250 m**

Explanation:

(65+85)*5/18 = (2x)/6

2x = 250 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative AptitudeDirections (6-10) Study the following information carefully and answer the questions given below.

The table shows the data of two trains from Monday to Friday.

**On Thursday the time taken by two trains which are moving in opposite directions is what percent of the time taken by two trains which are moving in same directions?**CorrectAnswer –

**5)25%**

Explanation:

Moving in opposite directions

(70+90)/(10+6) = 10

Moving in same directions

(70+90)/(10-6) = 40

10/40 * 100% = 25%IncorrectAnswer –

**5)25%**

Explanation:

Moving in opposite directions

(70+90)/(10+6) = 10

Moving in same directions

(70+90)/(10-6) = 40

10/40 * 100% = 25%

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