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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Ajay can complete a given project in 20 days. Bharat takes 20% more than time than Ajay to complete the same project. Bharat started working alone for 2 days and was joined by Ajay till the completion of project. In how many days was the entire project completed?

Correct

Answer – 2)12
Explanation:
Time taken by Ajay in doing work =20 days
Time taken by Bharat =(20*120)/100=24 days
Bharat’s 2 days work = 2/24=1/12
Remaining work =1-1/2=11/12
(Ajay+Bharat)’s 1 day’s work = 1/20+1/24=11/120
Time taken in doing 1 work =120/11
Time taken in doing 11/12 work =120/11 *11/20 = 10 days

Incorrect

Answer – 2)12
Explanation:
Time taken by Ajay in doing work =20 days
Time taken by Bharat =(20*120)/100=24 days
Bharat’s 2 days work = 2/24=1/12
Remaining work =1-1/2=11/12
(Ajay+Bharat)’s 1 day’s work = 1/20+1/24=11/120
Time taken in doing 1 work =120/11
Time taken in doing 11/12 work =120/11 *11/20 = 10 days

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Amit and Bala started a business. Bala’s investment was 2.5 times that of Amit. The respective ratio between the time period for which Amit invested and that for which Bala invested was 3: 1. If the total investment made by Amit & Bala together was Rs 28000 and the annual profit earned was Rs 2500 less than Amit’s investment, what was the difference between Amit’s dividend and Bala’s dividend in the annual profit?

Correct

Answer – 3)500
Explanation:
Amit’s investments =Rs X
Bala’s investment = Rs 2.5x
X+2.5x=Rs 28000
X= 8000
Bala’s investment = Rs (2.5*8000)= 20000
Ratio of equivalent capitals of A & B for 1 month
=8000 *3 : 20000=6:5
Annual profit =8000-2500=Rs 5500
Difference of dividends = Rs [(6-5)/(6+5)]* 5500 = Rs 500

Incorrect

Answer – 3)500
Explanation:
Amit’s investments =Rs X
Bala’s investment = Rs 2.5x
X+2.5x=Rs 28000
X= 8000
Bala’s investment = Rs (2.5*8000)= 20000
Ratio of equivalent capitals of A & B for 1 month
=8000 *3 : 20000=6:5
Annual profit =8000-2500=Rs 5500
Difference of dividends = Rs [(6-5)/(6+5)]* 5500 = Rs 500

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

In ‘x’ hours a bike covers 36 km less than the distance covered by an ambulance in the same time. The speed of the bike is 12 kmph less than the speed of the ambulance. Had the speed of the bike been 52 kmph. What would have been the distance covered in “x-1/2” hours

Correct

Answer – 4)130
Explanation:
Speed of ambulance – speed of bike =12 kmph
x = 36/12= 3 hours
Speed of bike= 52 kmph
Time = x-1/2=(3-1/2)= 5/2 hours
Required distance = 52 * 5/2= 130 km

Incorrect

Answer – 4)130
Explanation:
Speed of ambulance – speed of bike =12 kmph
x = 36/12= 3 hours
Speed of bike= 52 kmph
Time = x-1/2=(3-1/2)= 5/2 hours
Required distance = 52 * 5/2= 130 km

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Arun’s age 7 years ago was 10 years more than half of his present age. The respective ratio between Baskar’s age 4 years ago and Arun’s age that time was 2 :5. If Chand’s age 12 years hence will be thrice of Baskar’s age 2 years ago, what is Chand’s present age?(in years)

Correct

Answer – 2)30
Explanation:
Arun’s present age = x years
x-7=x/2+10
x=34 years
Again, Baskar’s present age =y years
(y-4)/30=2/5
Y=16 years
Chand+12=3* (16-2)=42
Chand = 30 years

Incorrect

Answer – 2)30
Explanation:
Arun’s present age = x years
x-7=x/2+10
x=34 years
Again, Baskar’s present age =y years
(y-4)/30=2/5
Y=16 years
Chand+12=3* (16-2)=42
Chand = 30 years

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Anil & Bhuvan entered into a partnership and invested capital in the ratio of 4 : 5. At the end of 8 months Anil withdrawn half of his amount. If at the end of one year, they received profits in the ratio of 4 : 5, then Bhuvan’s capital was used for how many months

Correct

Answer – 5)10 months
Explanation:
Anil = 4X, Bhuvan = 5X
At the end of 8 months (4x – 4x/2) : 5x
Now,
(4x*8 + 2x *4)/5x * Bhuvan’s months = 4/5
Bhuvan’s month=10 months

Incorrect

Answer – 5)10 months
Explanation:
Anil = 4X, Bhuvan = 5X
At the end of 8 months (4x – 4x/2) : 5x
Now,
(4x*8 + 2x *4)/5x * Bhuvan’s months = 4/5
Bhuvan’s month=10 months

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Directions (6-10) Study the following information carefully and answer the questions given below.

The table shows the data of two trains from Monday to Friday.

On Monday, find out the sum of Conditions (i),(ii) and (iii)
(i) If the two trains run in opposite directions on parallel tracks then find out the sum of the time which they take to cross each other.
(ii) The time taken by train 1 if it crosses a pole.
(iii) The time taken by train 2 if it crosses a man.

Correct

Answer – 5)18.9s
Explanation:
(i) Total length = 105 + 90 = 195
Relative Speed = 72 + 45 = 117 kmph = 117 * 5/18 = 585/18 m/s
Time = 6s
(ii) 105/(45*5/18) = 8.4s
(iii) 90/(72*5/18) = 4.5s
Sum = 6+8.4+4.5 = 18.9s

Incorrect

Answer – 5)18.9s
Explanation:
(i) Total length = 105 + 90 = 195
Relative Speed = 72 + 45 = 117 kmph = 117 * 5/18 = 585/18 m/s
Time = 6s
(ii) 105/(45*5/18) = 8.4s
(iii) 90/(72*5/18) = 4.5s
Sum = 6+8.4+4.5 = 18.9s

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Directions (6-10) Study the following information carefully and answer the questions given below.

The table shows the data of two trains from Monday to Friday.

On Tuesday, find out the difference between Conditions (ii) and (i)
(i) If the two trains run in opposite directions on parallel tracks then find out the sum of the time which they take to cross each other.
(ii) The sum of the time taken by train 1 and train 2 if they crosses the bridge of 70m and 60m respectively.

Correct

Answer – 4)35.4s
Explanation:
Condition(i)
(180 + 240) / (30 + 40)*5/18 = 21.6s
Condition(ii)
Time taken by train 1 = (180+70)/(30*5/18) = 30s
Time taken by train 2 = (240+60)/(40*5/18) = 27s

Incorrect

Answer – 4)35.4s
Explanation:
Condition(i)
(180 + 240) / (30 + 40)*5/18 = 21.6s
Condition(ii)
Time taken by train 1 = (180+70)/(30*5/18) = 30s
Time taken by train 2 = (240+60)/(40*5/18) = 27s

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Directions (6-10) Study the following information carefully and answer the questions given below.

The table shows the data of two trains from Monday to Friday.

On Wednesday find out the ratio of conditions (i) (ii) and (iii)
(i) If the two trains run in opposite directions on parallel tracks then find out the sum of the time which they take to cross each other.
(ii) The time taken by train 1 if it crosses a signal post
(iii) The time taken by train 2 if it crosses a platform of 60m

Correct

Answer – 3)2:3:2
Explanation:
Condition(i)
(180 + 120) / (72 + 108)*5/18 = 6s
Condition(ii)
Time taken by train 1 =180/(72*5/18) = 9s
Condition(iii)
Time taken by train 2 =(120+60)/(108*5/18) = 6s
2:3:2

Incorrect

Answer – 3)2:3:2
Explanation:
Condition(i)
(180 + 120) / (72 + 108)*5/18 = 6s
Condition(ii)
Time taken by train 1 =180/(72*5/18) = 9s
Condition(iii)
Time taken by train 2 =(120+60)/(108*5/18) = 6s
2:3:2

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Directions (6-10) Study the following information carefully and answer the questions given below.

The table shows the data of two trains from Monday to Friday.

On Friday, the length of the two trains are same and cross each other in 6s then find out the sum of the length of two trains?

Directions (6-10) Study the following information carefully and answer the questions given below.

The table shows the data of two trains from Monday to Friday.

On Thursday the time taken by two trains which are moving in opposite directions is what percent of the time taken by two trains which are moving in same directions?

Correct

Answer – 5)25%
Explanation:
Moving in opposite directions
(70+90)/(10+6) = 10
Moving in same directions
(70+90)/(10-6) = 40
10/40 * 100% = 25%

Incorrect

Answer – 5)25%
Explanation:
Moving in opposite directions
(70+90)/(10+6) = 10
Moving in same directions
(70+90)/(10-6) = 40
10/40 * 100% = 25%

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