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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeFind out the wrong number in the series given below
2 9 22 43 74 116
Correct
Answer – 5) 116
Explanation:
2 + 2^2 + 3 = 9
9 + 3^2 + 4 = 22
22 + 4^2 + 5 = 43
43 + 5^2 + 6 = 74
74 + 6^2 + 7 = 117Incorrect
Answer – 5) 116
Explanation:
2 + 2^2 + 3 = 9
9 + 3^2 + 4 = 22
22 + 4^2 + 5 = 43
43 + 5^2 + 6 = 74
74 + 6^2 + 7 = 117 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeOut of 14 applicants for a post, there are 6 females and 8 males. It is desired to select 2 persons for the post.
Quantity I: Probability of selecting no female
Quantity II: Probability of selecting at least one femaleCorrect
Answer – 2) Quantity I < Quantity II Explanation:
Man only = 8C2 = 14
Probability of selecting no female = 14/91
Probability of selecting at least one female = 1 – 14/91 = 77/91Incorrect
Answer – 2) Quantity I < Quantity II Explanation:
Man only = 8C2 = 14
Probability of selecting no female = 14/91
Probability of selecting at least one female = 1 – 14/91 = 77/91 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude12x² – 22x + 8 = 0
18y² + 18y + 4 = 0Correct
Answer – 1) X > Y
Explanation:
12x² – 22x + 8 = 0
x = 0.13, 0.5
18y² + 18y+ 4 = 0
y = 0.6, 0.3Incorrect
Answer – 1) X > Y
Explanation:
12x² – 22x + 8 = 0
x = 0.13, 0.5
18y² + 18y+ 4 = 0
y = 0.6, 0.3 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeEight years ago there were 5 members in the Arun’s family and then the average age of the family was 36 years. Meanwhile, Arun got married and gave birth to a child. Still, the average age of his family is same now. If the difference between the age of her child and herself was 26 years then what is the present age of his wife?
Correct
Answer – 3) 29 years
Explanation:
The present age of his child be x
The present age of wife be x + 26
Thus the total age = x + ( x + 26) = 32 [∵252220 = 32]
=> x = 3
Present age of his wife = 29 yearsIncorrect
Answer – 3) 29 years
Explanation:
The present age of his child be x
The present age of wife be x + 26
Thus the total age = x + ( x + 26) = 32 [∵252220 = 32]
=> x = 3
Present age of his wife = 29 years 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeWhat is the percent profit earned at 20% discount?
I) Marked Price(MP) of the book is 40% above its Cost Price(CP).
II) After 15% discount, the profit earned is 19%
III) Marked Price(MP) is Rs 120 above the Cost Price(CP).Correct
Answer – 3) Either I or II
Explanation:
From I,
Let cost price(CP) = Rs 100, MP = Rs 140
After 20% discount, SP = Rs 14028 =Rs 112
Profit % = 12 %
Hence , I alone is sufficient
From II,
85 % of MP = 119% of CP
80 % of MP = 119/85 * 80 % of CP = 112% of CP
% profit = 12%Incorrect
Answer – 3) Either I or II
Explanation:
From I,
Let cost price(CP) = Rs 100, MP = Rs 140
After 20% discount, SP = Rs 14028 =Rs 112
Profit % = 12 %
Hence , I alone is sufficient
From II,
85 % of MP = 119% of CP
80 % of MP = 119/85 * 80 % of CP = 112% of CP
% profit = 12% 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe cost of the metal varies directly with square of its weight. Metal is broken into 3 parts whose weights are in the ratio of 3:4:5. If the metal had been broken into three equal parts by weight then there would have been a further loss of Rs. 800. What is the actual cost of the original metal?
Correct
Answer – 4) Rs. 57600
Explanation:
Cost = (3x)^2 + (4x)^2 + (5x)^2 = 50x^2
Loss = 50x^2 – 48x^2 = 2x^2
800 = 2x^2
x^2 = 400
Actual cost of original metal =(12x)^2 = 144x^2 = 144 * 400 = 57600Incorrect
Answer – 4) Rs. 57600
Explanation:
Cost = (3x)^2 + (4x)^2 + (5x)^2 = 50x^2
Loss = 50x^2 – 48x^2 = 2x^2
800 = 2x^2
x^2 = 400
Actual cost of original metal =(12x)^2 = 144x^2 = 144 * 400 = 57600 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThe rate of interest in two banks SBI and BOB are in the ratio of 7:8. If Suresh invested some amount at SI in both the banks and received equal amount from both the banks in two years. The ratio of amount invested in SBI and BOB respectively is:
Correct
Answer – 2) 8:7
Explanation:
P1*2*7x / 100 = P2*2*8x / 100
P1/P2 = 8/7Incorrect
Answer – 2) 8:7
Explanation:
P1*2*7x / 100 = P2*2*8x / 100
P1/P2 = 8/7 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative Aptitude33 children can do a work in 30 days. If 44 children started the work together and after every day of the task, one person leaves. What is the minimum number of days required to complete the whole task.
Correct
Answer – 5) 44
Explanation:
Total = 33 * 30 = 990 mandays
First day work = 1/990 * 44
Second day work = 1/990 * 43
Total work in 44 days = 1/990(44 + 43 + 42 + ….)
= 1/990 * (44*45/2)
Total work will be completed in 44 days.Incorrect
Answer – 5) 44
Explanation:
Total = 33 * 30 = 990 mandays
First day work = 1/990 * 44
Second day work = 1/990 * 43
Total work in 44 days = 1/990(44 + 43 + 42 + ….)
= 1/990 * (44*45/2)
Total work will be completed in 44 days. 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeAmit and Bala setout at the same time to walk towards each other respectively from Chennai and Vellore 144 km apart. Amit walks at the constant speed of 8 kmph, while Bala walks 4 km in the first hour, 5 km in the second hour, 6 km in the third hour and so on. Then the Amit and Bala will meet?
Correct
Answer – 3) Midway between Chennai and Vellore
Explanation:
Distance travelled by them in first hour = 12 km
Distance travelled by them in second hour = 13 km
Distance travelled by them in third hour = 14 km and so on
Thus in 9 hours they will cover exactly 144 km i.e each will cover half the total distance.Incorrect
Answer – 3) Midway between Chennai and Vellore
Explanation:
Distance travelled by them in first hour = 12 km
Distance travelled by them in second hour = 13 km
Distance travelled by them in third hour = 14 km and so on
Thus in 9 hours they will cover exactly 144 km i.e each will cover half the total distance. 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeIn a business venture Arun invests 1/6 of the capital for 1/6 of the time, Bharat invests 1/3 of the capital for 1/3 of the time and Chand, the rest of the capital for the whole time. Out of total profit of Rs. 4,600 Bharat’s share is?
Correct
Answer – 1) Rs. 800
Explanation:
Suppose Arun invests Rs. N/6 for M/ 6 months. Bharat invests Rs. N/3 for M/3 months and Chand invests Rs. [N – (N/6 + N/3)]
For M months.
Ratio of their investment = (N/6 x M/6) : (N/3 x M/3) : (N / 2NM)
= 1/36 : 1/9 : 1/2 = 1 : 4 : 18
∴ Bharat’s share = Rs. 4600 x (4/23) = Rs. 800Incorrect
Answer – 1) Rs. 800
Explanation:
Suppose Arun invests Rs. N/6 for M/ 6 months. Bharat invests Rs. N/3 for M/3 months and Chand invests Rs. [N – (N/6 + N/3)]
For M months.
Ratio of their investment = (N/6 x M/6) : (N/3 x M/3) : (N / 2NM)
= 1/36 : 1/9 : 1/2 = 1 : 4 : 18
∴ Bharat’s share = Rs. 4600 x (4/23) = Rs. 800
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