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Farhan’s present age is three times his daughter’s present age and nine-thirteenth of his mother’s present age. The sum of their ages after five years is 115 years. What is the difference between the present ages of Farhan’s daughter and Farhan’s mother?

Correct

Answer : 1.40 years Explanation:
Present age of F+D+M = 115-15 = 100
D = F/3; M = 13F/9
F (1+1/3+13/9) = 100
F =36; D = 12; M =52
M-D = 52-12 =40

Incorrect

Answer : 1.40 years Explanation:
Present age of F+D+M = 115-15 = 100
D = F/3; M = 13F/9
F (1+1/3+13/9) = 100
F =36; D = 12; M =52
M-D = 52-12 =40

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

The average expenditure of the hostel when there are 10 students is Rs. 60 per student and the average expenditure is Rs. 45 when there are 20 students. If it is known that there are some fixed expenses irrespective of the number of students then the average expenditure per student when there are 30 students in the hostel

Correct

Answer :4.Rs.40 Explanation:
Let fixed charges be F
F+D/10 = 60; F+D = 600
F+2D/20 = 45; F+2D = 900
D = 300; F= 300
For 30 students
F+3D/30 = (300+3*300)/30 = 40

Incorrect

Answer :4.Rs.40 Explanation:
Let fixed charges be F
F+D/10 = 60; F+D = 600
F+2D/20 = 45; F+2D = 900
D = 300; F= 300
For 30 students
F+3D/30 = (300+3*300)/30 = 40

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

A, B, C started a business with their investments in the ratio 1:2:5. After six months A invested the half amount more as before, B continued with same the amount as before, while C withdrew 3/5 th of his investment. Find the ratio of their profits at the end of year.

Correct

Answer:2.5:8:14 Explanation:
A: B: C = 1:2:5
Investments be x, 2x, and 5x
Ratio at end of the year:
x*6+1.5x*6 : 2x*6+2x*6: 5x*6+2x*6
2.5:4:7
5:8:14

Incorrect

Answer:2.5:8:14 Explanation:
A: B: C = 1:2:5
Investments be x, 2x, and 5x
Ratio at end of the year:
x*6+1.5x*6 : 2x*6+2x*6: 5x*6+2x*6
2.5:4:7
5:8:14

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

The distance between Visakhapatnam and Bhubaneswar is 713 km. Inter City express starts from Visakhapatnam to Bhubaneswar at 60 km/h. 50 minutes later Prasanthi express leaves Bhubaneswar to Visakhapatnam on the parallel tracks at 70 km/h. How far from Bhubaneswar will they cross each other?

Correct

Answer: 3.357 Explanation
713 = 60*t + 70*(t-50/60)
713 = 60t+70t-175/3
2314/3 = 130t
t = 17.8/3
from Visakhapatnam = 60*17.8/3 = 356
from Bhubaneswar = 713-356 = 357

Incorrect

Answer: 3.357 Explanation
713 = 60*t + 70*(t-50/60)
713 = 60t+70t-175/3
2314/3 = 130t
t = 17.8/3
from Visakhapatnam = 60*17.8/3 = 356
from Bhubaneswar = 713-356 = 357

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 24 minutes, then the slower pipe alone will be able to fill the tank in:

Correct

Answer :4.96min Explanation:
First pipe take x hours then second pipe takes x/3 hours
1/x+3/x = 1/24
x =96 min

Incorrect

Answer :4.96min Explanation:
First pipe take x hours then second pipe takes x/3 hours
1/x+3/x = 1/24
x =96 min

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

In a school, 37% girls and 17% boys participated in dancing. Number of students in the school is 800. How many boys are there in the school? Statement I: Number of boys are more than 300 Statement II: More than 196 students participated

Correct

Answer :5. If the data given in both statements I & II together are necessary to answer the question Explanation:
B+G = 800
Boys more than 300 possible cases 400,500,600,700
Boys =400 Girls = 400
400*37/100+400*17/100 > 196
216>196

Incorrect

Answer :5. If the data given in both statements I & II together are necessary to answer the question Explanation:
B+G = 800
Boys more than 300 possible cases 400,500,600,700
Boys =400 Girls = 400
400*37/100+400*17/100 > 196
216>196

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

I.X²-√3 (4+√6) X +4√54 = 0
II.Y² +√3 (8-√6) Y -8√54 =0

Correct

Answer:3. X ≥ Y Explanation :
X = 4√3, 3√2
Y = 3√2, -8√3

Incorrect

Answer:3. X ≥ Y Explanation :
X = 4√3, 3√2
Y = 3√2, -8√3

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

I.21X²+68X + 55 = 0
II.28Y²– 27Y -81 =0

Correct

Answer:2.X Explanation:
X = -11/7, -5/3
Y = -9/7, 9/4

Incorrect

Answer:2.X Explanation:
X = -11/7, -5/3
Y = -9/7, 9/4

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