Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating question sample in **Time and Distance **with Explanation, which is common for all the IBPS,SBI,SSC and other competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Questions Penned by Yogit

**The distance between two cities P and Q is 300km. A train starts from station P at 10 am with speed 80 km/hr towards Q. Another train starts from Q towards P with speed 40km/hr at 11 am . At what time do they meet.**

a) 12.20pm

b) 12.40 pm

c) 12.50 pm

d) 1 pm

Answer –**c) 12.50 pm**

**Solution:**

First train starts at 10am so in one hour it covers 80 km in one hour. Now distance b/w P and Q is 220. Suppose at some’ x’ km they meet. So,

x/80 = (220-x)/40

x = 440/3.

The time after which they meet = (440/3)/80 = 11/6 i.e = 1hr 50 min.

**A car covers first 10 km with 40km/hr next 10km with 60 km and next 10 km in 20 km/hr. What is the average speed of the car.**

a) 320/11

b) 330/11

c) 350/11

d) 360/11

Answer –**d) 360/11**

**Solution:**

Average speed = (3*20*40*60)/800+2400+1200 = 360/11

**A train running with 72km/hr takes 20sec to cross a platform 200 m long. How much it take to cross a stationary train having same length**

a) 20 sec

b) 30 sec

c) 40 sec

d) 50 sec

Answer –**a) 20 sec**

**Solution:**

200+L = 72*(5/18)*20. L= 200m.

400 = 72*(5/18)*t. So, t = 20sec.

**Two cities A and B are at a distance of 60 km from each other. Two persons P and Q start from First city at a speed of 10km/hr and 5km/hr respectively. P reached the second city B and returns back and meets Q at Y. Find the distance between A and Y.**

a) 30 km

b) 40 km

c) 50 km

d) 55 km

Answer –**b) 40 km**

**Solution:**

Time taken by P to reach city B is 6hr. In 6 hr, distance covered by Q is 30km. Now at some x distance they will meet. So

x/5 = (30-x)/10. X= 10.

So distance b/w A and Y is 30+10 =40 km

**A man covers 2/3 distance at a speed of 30 km/hr and the remaining at 60 km/hr. If the total distance he covers is 300 km. Find the average speed of the man.**

a) 36 km/hr

b) 38km/hr

c) 40 km/hr

d) 42km/hr

Answer –**a) 36 km/hr**

**Solution:**Average speed = 300/[(200/30)+(100/60)] = 36

**When priya travels from home to office with a speed of 40km/hr she reaches her office late by 20 minutes and when she travels with 60km/hr, she reach 10 minutes early. Find the distance between her office and home.**

a) 50 km

b) 60 km

c) 65 km

d) 70 km

Answer –**b) 60 km**

**Solution:**

D = 40(t+20/60) and D = 60(t-10/60)

solve these two equation and get D.

**A bus running at 3/5 of its usual speed reaches its destination in 15 hrs. If the bus runs at his usual speed, how much time would be saved.**

a) 6hr

b) 7hr

c) 8hr

d) 10hr

sol = > D = (3/5)*v*15

Answer –**a) 6hr**

**Solution:**

Now running at usual speed, D = v*t = (3/5)*v*15, so time = 9hr.

Hence saved 6hrs

**Excluding stoppages the speed of bus is 60 km/hr and including stoppages it average speed becomes 48km/hr. For how much time the bus stops.**

a) 10 min

b) 12 min

c) 14 min

d) 16 min

Answer –**b) 12 min**

**Solution:**

Due to stoppages bus covers 12 km less. To cover 12km with 60km/hr speed it takes 12min.

**Rahul takes 4 hr in walking at certain place and return back. While it takes 3 hrs in walking at certain place and riding back. Find the time rahul will take to ride both sides**

a) 2hr

b) 3 hr

c) 3.5 hr

d) 1.5 hr

Answer –**a) 2hr**

**Solution:**

W + W = 4. W =2

W+ R = 3. R =1

So to ride both direction, it will take 1+1 = 2 hrs.

**P walks with a speed of 6 km/hr and after 5 hr of his start, Q starts****running towards P at a speed of 8 km/hr. At what distance from start will Q catch P.**

a) 100

b) 110

c) 120

d) 140

Answer –**c) 120**

**Solution:**

In 5hrs, P will cover 30 km. Now, at some distance ‘x’. So P will cover X distance and Q will cover 30 + X.

x/6 = (30+x)/8

x = 90. So distance from start after which Q will catch P = 90+30 =120km.

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