**Hello Aspirants.**

Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From **Data ****Interpretation** that is important for all the competitive exams. We have included Some questions that are repeatedly asked in exams.

**Bank PO Level Questions** :-

**I. Study the following table and Pie-Chart carefully and answer the following questions given below.
Number of students studying in different streams in six engineering colleges**

Colleges | Computer Science | Electrical Engineering | Electronics | Civil | Mechanical | Others |
---|---|---|---|---|---|---|

M | 250 | 320 | 160 | 272 | 128 | 150 |

N | 120 | 210 | 200 | 150 | 180 | 220 |

O | 220 | 150 | 220 | 160 | 200 | 120 |

P | 180 | 170 | 140 | 128 | 100 | 172 |

Q | 240 | 220 | 180 | 170 | 190 | 200 |

R | 160 | 200 | 150 | 190 | 150 | 160 |

**Pie-charts show the distribution of students in different states in colleges N and Q.**

**How many students doing in civil engineering in College N, were from UP?**

A. 35

B. 60

C. 55

D. Can not be determinedAnswer –**D. Can not be determined**

**Explanation :**

Given data is not sufficient to calculate the answer.**What is the difference between the number of students from Delhi in colleges N and Q?**

A. 34

B. 50

C. 60

D. 72Answer –**D. 72**

**Explanation :**

Total number of students in college N = 1080

Number of students from Delhi in college N = 1080 * (20/100) = 216

Total number of students in college Q = 1200

Number of students from Delhi in college N = 1200 * (12/100) = 144

Difference = 216 – 144 = 72**What is the difference between the number of students pursuing computer science and those pursuing mechanical engineering in the given six colleges?**

A. 205

B. 224

C. 222

D. 220Answer –**C. 222**

**Explanation :**

Number of students pursuing computer science = 250 + 120 + 220 + 180 + 240 + 160 = 1170

Number of students pursuing mechanical engineering = 948

Difference = 1170 – 948 = 222**By what percentage is the number of students from Punjab in college N more/less than those from Maharashtra in college Q?**

A. 50%

B. 40%

C. 20%

D. 30%Answer –**B. 40%**

**Explanation :**

Number of students from Punjab in college N = 1080 * (10/100) = 108

Number of students from Maharashtra in college Q = 1200 * (15/100) = 180

Percentage = [(180 – 108)*100] = 40%**The total number of students in college R forms approximately what percentage of the total number of students in colleges M, N and P together?**

A. 25%

B. 33%

C. 31%

D. 35%Answer –**C. 31%**

**Explanation :**

Total number of students in colleges M, N and P = 1280 + 1080 + 890 = 3250

Total number of students in college R = 1010

Percentage = [(1010/3250)*100] = 31%(approximately)

**II. Study the following bar graph and table carefully and answer the following questions given below.**

** Time taken to travel (in hours) by six vehicles on two different days.**

**Distance covered by six vehicles on each day**

Vehicle | Day 1 | Day 2 |
---|---|---|

A | 832 | 864 |

B | 516 | 774 |

C | 693 | 810 |

D | 552 | 765 |

E | 935 | 546 |

F | 703 | 636 |

**Which of the following vehicles travelled at the same speed on both the days?**

A. Vehicle A

B. Vehicle B

C. Vehicle C

D. Vehicle DAnswer –**B. Vehicle B**

**Explanation :**

Speed of vehicle A on day 1 = 832/16 = 52kmph

Speed of vehicle A on day 2 = 864/16 = 54kmph

Speed of vehicle B on day 1 = 516/12 = 43kmph

Speed of vehicle B on day 2 = 774/18 = 43kmph

Speed of vehicle C on day 1 = 693/11 = 63kmph

Speed of vehicle C on day 2 = 810/18 = 45kmph

Speed of vehicle D on day 1 = 552/12 = 46kmph

Speed of vehicle D on day 2 = 765/15 = 51kmph

Vehicle B travelled at the same speed on both the days**What was the difference between the speed of vehicle A on day 1 and the speed of the vehicle on the same day?**

A. 22 kmph

B. 11 kmph

C. 10 kmph

D. 13 kmphAnswer –**B. 11 kmph**

**Explanation :**

Speed of vehicle A on day 1 = 832/16 = 52kmph

Speed of vehicle C on day 1 = 693/11 = 63kmph

Difference = 63-52 = 11kmph**What was the speed (in m/s) of vehicle C on day 2?**

A. 12.5 m/s

B. 11.5 m/s

C. 10.5 m/s

D. 9.5 m/sAnswer –**A. 12.5 m/s**

**Explanation :**

Speed of vehicle C on day 2 = 810/18 = 45kmph

Speed of vehicle C on day 2 = 45 * (5/18) = 12.5 m/s**The distance travelled by vehicle F on day 2 was approximately what % of the distance travelled by it on day 1?**

A. 90%

B. 95%

C. 94%

D. 98%Answer –**A. 90%**

**Explanation :**

Percentage = (636/703)*100 = 90%**What is the ratio of speeds of vehicle D and Vehicle E on day 2?**

A. 14:15

B. 17:13

C. 15:16

D. 13:17Answer –**B. 17:13**

**Explanation :**

Speed of vehicle D on day 2 = 51kmph

Speed of vehicle E on day 2 = 39kmph

Ratio = [Speed of vehicle D on day 2/Speed of vehicle E on day 2] = 51/39 = 17:13

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