Hello Aspirants.

Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample in **Data Analysis**, which is common for all the competitive exams. We have included Some questions that are repeatedly asked in exams!!!

**Quantity 1:**A spends 50% of his monthly income on household items and out of the remaining, he spends 50% on transport, 25% on entertainment, 10% on sports and remaining amount of Rs. 1000 is saved. What is A monthly income?

**Quantity 2:**B spends 50% of his monthly income on household items and out of the remaining, he spends 50% on transport, 20% on entertainment, 15% on sports and remaining amount of Rs. 1000 is saved. What is B monthly income?

1.Quantity 1 >Quantity 2

2.Quantity 1 <Quantity 2

3.Quantity 1 ≤Quantity 2

4.Quantity 1 ≥Quantity 2

5.Quantity 1 =Quantity 2 or No relation can be established

Answer –**5.Quantity 1 =Quantity 2 or No relation can be established**

**Explanation :**

Let A’s monthly income be Rs. 100

Then, money spent on household’s item

=100×50/100 = Rs. 50

Remaining amount = 100 – 50 = Rs. 50

Money spent on transport

=50×50/100 = Rs. 25

Money spent on entertainment

=50×25/100 = Rs. 12.5

Money spent on sports

=50×10/100 = Rs. 5

∴ Last remaining amount

= 100 – (50 + 25 + 12.5 + 5)

100 – (92.5) = Rs. 7.5

∴ Rs. 7.5 is saved, when total income is Rs. 100

∴ Rs. 1 is saved, when total income =100/7.5

Q1: Now, Rs. 900 is saved, when total income

=100/7.5×1000

= 100 × 120

= Rs. 13333

Let B’s monthly income be Rs. 100

Then, money spent on household’s item

=100×50/100 = Rs. 50

Remaining amount = 100 – 50 = Rs. 50

Money spent on transport

=50×50/100 = Rs. 25

Money spent on entertainment

=50×20/100 = Rs. 10

Money spent on sports

=50×15/100 = Rs. 7.5

∴ Last remaining amount

= 100 – (50 + 25 + 10 + 7.5)

100 – (92.5) = Rs. 7.5

∴ Rs. 7.5 is saved, when total income is Rs. 100

Q2: =100/7.5×1000

= 100 × 120

= Rs. 13333

**Quantity 1:**A contractor undertook to do a certain piece of work in 18 days. He employed certain number of men but 12 of them being absent from the very 1st day, the rest could finish the work in 30 days. Find the number of men originally employed

**Quantity 2:**A contractor undertook to do a certain piece of work in 15 days. He employed certain number of men but 10 of them being absent from the very 1st day, the rest could finish the work in 20 days. Find the number of men originally employed

1.Quantity 1 >Quantity 2

2.Quantity 1 <Quantity 2

3.Quantity 1 ≤Quantity 2

4.Quantity 1 ≥Quantity 2

5.Quantity 1 =Quantity 2 or No relation can be established

Answer –**2.Quantity 1 <Quantity 2**

**Explanation :**

Q1:

X *18 = (x-12)*30

18x = 30x – 360

12x = 360

X = 30

Q2:

X*15 = (x-10) *20

15x = 20x-200

5x=200

X = 40

**A tank has a leak which would empty it in 6 hrs and it is now emptied in 10 hrsx**

**Quantity 1:**A tap is turned on which admits 5 litres a minutes. How many litres does the tank hold?

**Quantity 2:**A tap is turned on which admits 4 litres a minutes. How many litres does the tank hold?

1.Quantity 1 >Quantity 2

2.Quantity 1 <Quantity 2

3.Quantity 1 ≤Quantity 2

4.Quantity 1 ≥Quantity 2

5.Quantity 1 =Quantity 2 or No relation can be established

Answer –**1.Quantity 1 >Quantity 2**

**Explanation :**

10*6/10-6 = 60/4 = 15

Q1:Capacity of the tank = 15*60*5 = 4500 litres

Q2: Capacity of the tank = 15*60*4 = 3600 litres

**Quantity 1:**Ravi takes 20 seconds to reach a distance of 180 m from him when he increased his speed by 50%. Then if he travels at the original speed how much time will he take?

**Quantity 2:**Ravi takes 30 seconds to reach a distance of 180 m from him when he increased his speed by 20%. Then if he travels at the original speed how much time will he take?

1.Quantity 1 >Quantity 2

2.Quantity 1 <Quantity 2

3.Quantity 1 ≤Quantity 2

4.Quantity 1 ≥Quantity 2

5.Quantity 1 =Quantity 2 or No relation can be established

Answer –**2.Quantity 1 <Quantity 2**

**Explanation :**

Q1:

180/20 = 9m/s

1.5x = 9

X = 6m/s

Time = 180/6 = 30sec

Q2:

180/30 = 6m/s

1.2 x = 6

X = 5

Time = 180/5 = 36sec

**The annual income of A is 10% less than that of B whose income is 20% more than that of C, find the total income of A, B and C together per month**

**Quantity 1:**. If the monthly income of C is Rs. 1000

**Quantity 2:**. If the monthly income of C is Rs. 1100

1.Quantity 1 >Quantity 2

2.Quantity 1 <Quantity 2

3.Quantity 1 ≤Quantity 2

4.Quantity 1 ≥Quantity 2

5.Quantity 1 =Quantity 2 or No relation can be established

Answer –**2.Quantity 1 <Quantity 2s**

**Explanation :**

Q1:

C = 1000

B = 1.2*1000 =1200

C= 0.9*1000 = 900

Total = 1000+1200+900=3100

Q2:

C = 1100

B = 1.2*1100 =1320

C= 0.9*1100 = 990

Total = 1100+1200+900=3200

**A got 20% concession of the labeled price of an article and sold it with 30% profit on the price he bought. What was the labeled price?**

**Quantity 1:**If the article was sold it for Rs.5200

**Quantity 2:**If the article was sold it for Rs.7800

1.Quantity 1 >Quantity 2

2.Quantity 1 <Quantity 2

3.Quantity 1 ≤Quantity 2

4.Quantity 1 ≥Quantity 2

5.Quantity 1 =Quantity 2 or No relation can be established

Answer –**2.Quantity 1 <Quantity 2**

**Explanation :**

Q1:

CP = 100/130 * 5200 = Rs.4000

80x/100 = 4000

X = 5000

Q2:

CP = 100/130 * 7800 = Rs.6000

80x/100 = 6000

X = 7500

**During the first four months the investments of P and Q are in the ratio 4:7. For the remaining months their investments are in the ratio 6:5.**

**Quantity 1:**What will be the share of P in an annual profit of Rs.13600

**Quantity 2:**What will be the share of Q in an annual profit of Rs.12800

1.Quantity 1 >Quantity 2

2.Quantity 1 <Quantity 2

3.Quantity 1 ≤Quantity 2

4.Quantity 1 ≥Quantity 2

5.Quantity 1 =Quantity 2 or No relation can be established

Answer –**5.Quantity 1 =Quantity 2 or No relation can be established**

**Explanation :**

4*4 + 6*8 : 7*4 +5*8

16+48 : 28+40

64:68 => 16 :17

Q1: P = 13600*16/33 =6594

Q2: Q = 12800*17/33 = 6594

**The difference in CI(annual) and SI for a period of 2 years is Rs.71. What is P ?**

**Quantity 1:**If the rate of Interest is.6.5% pa

**Quantity 2:**If the rate of Interest is.7 % pa

1.Quantity 1 >Quantity 2

2.Quantity 1 <Quantity 2

3.Quantity 1 ≤Quantity 2

4.Quantity 1 ≥Quantity 2

5.Quantity 1 =Quantity 2 or No relation can be established

Answer –**1.Quantity 1 >Quantity 2**

**Explanation :**

Difference of Interest over the period of 2 years = P *(r/100)^{2}

Q1: P = 71*10000/6.5*6.5 = 16804.7

Q2: P = 71*10000/7*7 = 14489.7

**The average age of 3 family members A, B, C , 2 years ago was 14. The average age of B and C of them before 3 years was 15.The sum of present age of A and B is 18.**

**Quantity 1:**What is the present age of B ?

**Quantity 2:**What is the present age of A ?

1.Quantity 1 >Quantity 2

2.Quantity 1 <Quantity 2

3.Quantity 1 ≤Quantity 2

4.Quantity 1 ≥Quantity 2

5.Quantity 1 =Quantity 2 or No relation can be established

Answer –**2.Quantity 1 <Quantity 2**

**Explanation :**

A=12, B= 6 C = 30

(A-2)+(B-2)+(C-2)/3 = 14

A+B+C = 42 + 6

A+B+C = 48

(B-3)+(C-3)/2 = 15

B+C = 30+6 = 36

A = 12

A+B = 18

B = 18-12 = 6

C = 30

**Quantity 1:**The speed of an aircraft in still air is 7km/hr and rate of the wind is 6km/hr.what is the distance travelled by the aircraft during the journey .If it is travels along the direction of the wind for 3 hours

**Quantity 2:**The speed of an aircraft in still air is 5km/hr and rate of the wind is 8km/hr.what is the distance travelled by the aircraft during the journey.If it is travels along the direction of the wind for 5 hours

1.Quantity 1 >Quantity 2

2.Quantity 1 <Quantity 2

3.Quantity 1 ≤Quantity 2

4.Quantity 1 ≥Quantity 2

5.Quantity 1 =Quantity 2 or No relation can be established

Answer –**2.Quantity 1 <Quantity 2**

**Explanation :**

The effective speed of the aircraft = 7+6 = 13 km/hr

Q1:Distance = 13*3 = 39km/hr

Q2:Distance = 13*5 = 65km/hr

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