# Aptitude Questions: Data Analysis Set 2

Hello Aspirants.

Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample in Data Analysis, which is common for all the competitive exams. We have included Some questions that are repeatedly asked in exams!!!

1. Quantity 1: A spends 50% of his monthly income on household items and out of the remaining, he spends 50% on transport, 25% on entertainment, 10% on sports and remaining amount of Rs. 1000 is saved. What is A monthly income?
Quantity 2: B spends 50% of his monthly income on household items and out of the remaining, he spends 50% on transport, 20% on entertainment, 15% on sports and remaining amount of Rs. 1000 is saved. What is B monthly income?
1.Quantity 1 >Quantity 2
2.Quantity 1 <Quantity 2
3.Quantity 1 ≤Quantity 2
4.Quantity 1 ≥Quantity 2
5.Quantity 1 =Quantity 2 or No relation can be established
Answer – 5.Quantity 1 =Quantity 2 or No relation can be established
Explanation :
Let A’s monthly income be Rs. 100
Then, money spent on household’s item
=100×50/100 = Rs. 50
Remaining amount = 100 – 50 = Rs. 50
Money spent on transport
=50×50/100 = Rs. 25
Money spent on entertainment
=50×25/100 = Rs. 12.5
Money spent on sports
=50×10/100 = Rs. 5
∴ Last remaining amount
= 100 – (50 + 25 + 12.5 + 5)
100 – (92.5) = Rs. 7.5
∴ Rs. 7.5 is saved, when total income is Rs. 100
∴ Rs. 1 is saved, when total income =100/7.5
Q1: Now, Rs. 900 is saved, when total income
=100/7.5×1000
= 100 × 120
= Rs. 13333
Let B’s monthly income be Rs. 100
Then, money spent on household’s item
=100×50/100 = Rs. 50
Remaining amount = 100 – 50 = Rs. 50
Money spent on transport
=50×50/100 = Rs. 25
Money spent on entertainment
=50×20/100 = Rs. 10
Money spent on sports
=50×15/100 = Rs. 7.5
∴ Last remaining amount
= 100 – (50 + 25 + 10 + 7.5)
100 – (92.5) = Rs. 7.5
∴ Rs. 7.5 is saved, when total income is Rs. 100
Q2: =100/7.5×1000
= 100 × 120
= Rs. 13333

2. Quantity 1: A contractor undertook to do a certain piece of work in 18 days. He employed certain number of men but 12 of them being absent from the very 1st day, the rest could finish the work in 30 days. Find the number of men originally employed
Quantity 2: A contractor undertook to do a certain piece of work in 15 days. He employed certain number of men but 10 of them being absent from the very 1st day, the rest could finish the work in 20 days. Find the number of men originally employed
1.Quantity 1 >Quantity 2
2.Quantity 1 <Quantity 2
3.Quantity 1 ≤Quantity 2
4.Quantity 1 ≥Quantity 2
5.Quantity 1 =Quantity 2 or No relation can be established
Answer – 2.Quantity 1 <Quantity 2
Explanation :
Q1:
X *18 = (x-12)*30
18x = 30x – 360
12x = 360
X = 30
Q2:
X*15 = (x-10) *20
15x = 20x-200
5x=200
X = 40

3. A tank has a leak which would empty it in 6 hrs and it is now emptied in 10 hrsx
Quantity 1: A tap is turned on which admits 5 litres a minutes. How many litres does the tank hold?
Quantity 2: A tap is turned on which admits 4 litres a minutes. How many litres does the tank hold?
1.Quantity 1 >Quantity 2
2.Quantity 1 <Quantity 2
3.Quantity 1 ≤Quantity 2
4.Quantity 1 ≥Quantity 2
5.Quantity 1 =Quantity 2 or No relation can be established
Answer – 1.Quantity 1 >Quantity 2
Explanation :
10*6/10-6 = 60/4 = 15
Q1:Capacity of the tank = 15*60*5 = 4500 litres
Q2: Capacity of the tank = 15*60*4 = 3600 litres

4. Quantity 1: Ravi takes 20 seconds to reach a distance of 180 m from him when he increased his speed by 50%. Then if he travels at the original speed how much time will he take?
Quantity 2: Ravi takes 30 seconds to reach a distance of 180 m from him when he increased his speed by 20%. Then if he travels at the original speed how much time will he take?
1.Quantity 1 >Quantity 2
2.Quantity 1 <Quantity 2
3.Quantity 1 ≤Quantity 2
4.Quantity 1 ≥Quantity 2
5.Quantity 1 =Quantity 2 or No relation can be established
Answer – 2.Quantity 1 <Quantity 2
Explanation :
Q1:
180/20 = 9m/s
1.5x = 9
X = 6m/s
Time = 180/6 = 30sec
Q2:
180/30 = 6m/s
1.2 x = 6
X = 5
Time = 180/5 = 36sec

5. The annual income of A is 10% less than that of B whose income is 20% more than that of C, find the total  income of A, B and C together per month
Quantity 1: . If the monthly income of C is Rs. 1000
Quantity 2: . If the monthly income of C is Rs. 1100
1.Quantity 1 >Quantity 2
2.Quantity 1 <Quantity 2
3.Quantity 1 ≤Quantity 2
4.Quantity 1 ≥Quantity 2
5.Quantity 1 =Quantity 2 or No relation can be established
Answer – 2.Quantity 1 <Quantity 2s
Explanation :
Q1:
C = 1000
B = 1.2*1000 =1200
C= 0.9*1000 = 900
Total = 1000+1200+900=3100
Q2:
C = 1100
B = 1.2*1100 =1320
C= 0.9*1100 = 990
Total = 1100+1200+900=3200

6. A got 20% concession of the labeled price of an article and sold it with 30% profit on the price he bought. What was the labeled price?
Quantity 1:If the article was sold it for Rs.5200
Quantity 2: If the article was sold it for Rs.7800
1.Quantity 1 >Quantity 2
2.Quantity 1 <Quantity 2
3.Quantity 1 ≤Quantity 2
4.Quantity 1 ≥Quantity 2
5.Quantity 1 =Quantity 2 or No relation can be established
Answer – 2.Quantity 1 <Quantity 2
Explanation :
Q1:
CP = 100/130 * 5200 = Rs.4000
80x/100 = 4000
X = 5000
Q2:
CP = 100/130 * 7800 = Rs.6000
80x/100 = 6000
X = 7500

7. During the first four months the investments of P and Q are in the ratio 4:7. For the remaining months their investments are in the ratio 6:5.
Quantity 1:What will be the share of P in an annual profit of Rs.13600
Quantity 2:What will be the share of Q in an annual profit of Rs.12800
1.Quantity 1 >Quantity 2
2.Quantity 1 <Quantity 2
3.Quantity 1 ≤Quantity 2
4.Quantity 1 ≥Quantity 2
5.Quantity 1 =Quantity 2 or No relation can be established
Answer – 5.Quantity 1 =Quantity 2 or No relation can be established
Explanation :
4*4  + 6*8 : 7*4 +5*8
16+48 : 28+40
64:68 => 16 :17
Q1: P = 13600*16/33 =6594
Q2: Q = 12800*17/33 = 6594

8. The difference in CI(annual) and SI for a period of 2 years is Rs.71. What is P ?
Quantity 1:If the rate of Interest is.6.5% pa
Quantity 2: If the rate of Interest is.7 % pa
1.Quantity 1 >Quantity 2
2.Quantity 1 <Quantity 2
3.Quantity 1 ≤Quantity 2
4.Quantity 1 ≥Quantity 2
5.Quantity 1 =Quantity 2 or No relation can be established
Answer – 1.Quantity 1 >Quantity 2
Explanation :
Difference of Interest over the period of 2 years = P *(r/100)2
Q1: P = 71*10000/6.5*6.5 = 16804.7
Q2: P = 71*10000/7*7 = 14489.7

9. The average age of 3 family members A, B, C , 2 years ago was 14. The average age of B and C of them before 3 years was 15.The sum of present age of A and B is 18.
Quantity 1:What is the present age of B ?
Quantity 2:What is the present age of A ?
1.Quantity 1 >Quantity 2
2.Quantity 1 <Quantity 2
3.Quantity 1 ≤Quantity 2
4.Quantity 1 ≥Quantity 2
5.Quantity 1 =Quantity 2 or No relation can be established
Answer – 2.Quantity 1 <Quantity 2
Explanation :
A=12, B= 6 C = 30
(A-2)+(B-2)+(C-2)/3 = 14
A+B+C = 42 + 6
A+B+C = 48
(B-3)+(C-3)/2 = 15
B+C = 30+6 = 36
A = 12
A+B = 18
B = 18-12 = 6
C = 30

10. Quantity 1: The speed of an aircraft in still air is 7km/hr and rate of the wind is 6km/hr.what is the distance travelled by the aircraft during the journey .If it is travels along the direction of the wind for 3 hours
Quantity 2: The speed of an aircraft in still air is 5km/hr and rate of the wind is 8km/hr.what is the distance travelled by the aircraft during the journey.If it is travels along the direction of the wind for 5 hours
1.Quantity 1 >Quantity 2
2.Quantity 1 <Quantity 2
3.Quantity 1 ≤Quantity 2
4.Quantity 1 ≥Quantity 2
5.Quantity 1 =Quantity 2 or No relation can be established
Answer – 2.Quantity 1 <Quantity 2
Explanation :
The effective speed of the aircraft = 7+6 = 13 km/hr
Q1:Distance = 13*3 = 39km/hr
Q2:Distance = 13*5 = 65km/hr

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