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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

In a mixture of 160 gms which contains milk and water the proportion of water by weight was 65%. If 40 gms water was added to that mixture, then what would be the percentage of water in the new mixture?

Correct

Answer : 5. None
Solution:
In 160 gms mixture water = 104 gms and milk = 56 gms
now 40 gms water added = water = 144 gm s total = 200 gms
% = 144/200 = 72%

Incorrect

Answer : 5. None
Solution:
In 160 gms mixture water = 104 gms and milk = 56 gms
now 40 gms water added = water = 144 gm s total = 200 gms
% = 144/200 = 72%

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

B alone takes 3 hours more than A alone to fill a tank. If both taps fill together it takes 4 hours less than B alone would take to fill the tank. How long it takes if A and B together fill half of the tank?

Correct

Answer: 1. 1 hour
Solution:
1/x + 1/x+3 = 1/x-1
x =3
they fill tank in 2 hours
half tank in 1 hour

Incorrect

Answer: 1. 1 hour
Solution:
1/x + 1/x+3 = 1/x-1
x =3
they fill tank in 2 hours
half tank in 1 hour

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

A rectangular tank 100 cm long and 80 cm wide contains water to a depth of 20 cm. a metal cube of side 40 cms placed in the tank so that one face of cube rests at the bottom of the tank. Find how many litres of water must be poured into the tank so as to just cover the cube

A man sells 3 different articles, first at profit 20%, second at 25% loss and third at 10% loss. During the whole transaction he bears the loss of Rs.360, find the cost price of first article if their SP is same?

Correct

Answer :5. Rs. 1080
Solution:
x =A*120/100 = 1.2A
x=B*75/100 = 0.75B
x = C*90/100 = 0.9C
Loss = (A+B+C) – (1.2A+0.75B+0.9C) = 360
0.4A+ 0.4A/3 -0.2A =360
A =1080

Incorrect

Answer :5. Rs. 1080
Solution:
x =A*120/100 = 1.2A
x=B*75/100 = 0.75B
x = C*90/100 = 0.9C
Loss = (A+B+C) – (1.2A+0.75B+0.9C) = 360
0.4A+ 0.4A/3 -0.2A =360
A =1080

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

A and B started a business by investing in the ratio 6:7, after some months both of them withdraw half of their investments then in what ratio they will share the profits?

A person X starts from Delhi and another person Y starts from Mumbai to meet each other. Speed of X is 47 km/h, while Y is 59 km/h. If the distance between Delhi and Mumbai be 424 km and both X and Y start their journey at the same time, when they will meet?

Correct

Answer : 5. None
Solution:
424 = (47+59)*t
t =4

Incorrect

Answer : 5. None
Solution:
424 = (47+59)*t
t =4

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

A boat takes 28 hours to go from P to R, through a midpoint Q, but it takes 32 hours to go from P to Q and then return from Q to P. How long it would take to go from R to P?

Correct

Answer : 3. 36 hr
Solution:
Let distance from P to R be ‘2x’
28 = 2x/S+R
32 = x/S+R + x/S-R
32 = 14 + x/S-R
x/S-R = 18
2x/S-R = 36

Incorrect

Answer : 3. 36 hr
Solution:
Let distance from P to R be ‘2x’
28 = 2x/S+R
32 = x/S+R + x/S-R
32 = 14 + x/S-R
x/S-R = 18
2x/S-R = 36

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

A train of length of ‘x’ meters crosses a platform of length 200 m in 30 sec. With same speed it crosses a pole in 20 sec. Then what is the length of the train?

Correct

Answer : 3. 400 m
Solution:
(x+200)/30 = x/20
x =400

Incorrect

Answer : 3. 400 m
Solution:
(x+200)/30 = x/20
x =400

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Vidya is an expert in bargaining. Once she went to a nearby shop. When Vidya asked the price of watch the shopkeeper told her the price by increasing 22% of the original cost. But Vidya insisted to decrease the price by 22% so the shopkeeper sold it by decreasing the price by 22% what is the loss or profit of shopkeeper and by how much percent?

250 man-days of work can be completed by a certain number of men in some days. If the number of men is increased by 15 men, then the number of days required to complete the same work is decreased by 15. Then number of men initially present?

Correct

Answer : 1. 10
Solution:
M*D =250
(M+15)*(D-15) =250
M =10 D =25

Incorrect

Answer : 1. 10
Solution:
M*D =250
(M+15)*(D-15) =250
M =10 D =25

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