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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeFind out the wrong number in the series
9, 8, 15, 50, 175, 874Correct
Answer – 1.50
Explanation :
9*1 – 1 = 8
8*2 – 1 = 15
15*3 – 1 = 44Incorrect
Answer – 1.50
Explanation :
9*1 – 1 = 8
8*2 – 1 = 15
15*3 – 1 = 44 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude2552 ÷ 97 + 34 * 43 – 96 + 69 = ?
Correct
Answer – 2. 1461
Explanation :
26 + (34 * 43) – 96 + 69 = 1461Incorrect
Answer – 2. 1461
Explanation :
26 + (34 * 43) – 96 + 69 = 1461 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude1/x3 + 1/x+5 = 1/3
y – √16 = √9Correct
Answer – 4. X ≤ Y
Explanation:
1/x3 + 1/x+5 = 1/3
x = 3, 7
y – √16 = √9
y = 4 + 3 = 7Incorrect
Answer – 4. X ≤ Y
Explanation:
1/x3 + 1/x+5 = 1/3
x = 3, 7
y – √16 = √9
y = 4 + 3 = 7 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeFor a certain box and pen, what is the price of the pen?
I. The combined price of the box and the pen is Rs.95
II. The price of the box is Rs.75 more than the price of the pen.Correct
Answer – 5. if the data in both the statements I and II together are necessary to answer the question.
Explanation :
From Statement II, Let the price of pen be x, then the price of the box = (x+75)
From Statement I, combined price box and pen = Rs.95
x+(x+75) = 95 => 2x + 75 = 95 => x = 10Incorrect
Answer – 5. if the data in both the statements I and II together are necessary to answer the question.
Explanation :
From Statement II, Let the price of pen be x, then the price of the box = (x+75)
From Statement I, combined price box and pen = Rs.95
x+(x+75) = 95 => 2x + 75 = 95 => x = 10 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA car started from Chennai to Bengaluru at a certain speed. The Car missed an accident at 40Km away from Chennai, then the driver decided to reduce Car speed to 4/5 of the original speed. Due to this, he reached Bengaluru by a late of 1hr 15min. Suppose if he missed an accident at 80Km away from Chennai and from then he maintained 4/5 of original speed then he would reach Bengaluru by a late of 1 hour. Then what is the original speed of the Car?
Correct
Answer – 2. 40 km/hr
Explanation :
(x+40/s) + 5/4 = 40/s + 5x/4s — — — 1
(x+40/s) + 1 = 80/s + 5(x40)/4s — — — 2
s = 40Incorrect
Answer – 2. 40 km/hr
Explanation :
(x+40/s) + 5/4 = 40/s + 5x/4s — — — 1
(x+40/s) + 1 = 80/s + 5(x40)/4s — — — 2
s = 40 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA bag contains 5 red and 7 white Pencils. Four Pencils are drawn out one by one and not replaced. What is the probability that they are alternatively of different colours?
Correct
Answer – 3. 14/99
Explanation :
Pencils are picked as RWRW or WRWR Probability = (5/12)*(7/11)*(4/10)*(6/9) + (7/12)*(5/11)*(6/10)*(4/9) = 14/99Incorrect
Answer – 3. 14/99
Explanation :
Pencils are picked as RWRW or WRWR Probability = (5/12)*(7/11)*(4/10)*(6/9) + (7/12)*(5/11)*(6/10)*(4/9) = 14/99 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeAjay will be half as old as Lavanya in 3 years. Ajay will also be onethird as old as Jennifer in 5 years. If Jennifer is 15 years older than Lavanya, how old is Ajay?
Correct
Answer – 2. 8
Explanation :
let age of Ajay =x, Lavanya =y Jennifer = z
(x+3) =1/2 *(y+3) so we have 2xy =3 (1)
(x+5) =1/3 * (z+5) ; => 3xz=10 (2)
From (1)&(2) we get, x+yz =7 (3)
we have z =15+y – (4)
from equation 3 and 4 we get x=8Incorrect
Answer – 2. 8
Explanation :
let age of Ajay =x, Lavanya =y Jennifer = z
(x+3) =1/2 *(y+3) so we have 2xy =3 (1)
(x+5) =1/3 * (z+5) ; => 3xz=10 (2)
From (1)&(2) we get, x+yz =7 (3)
we have z =15+y – (4)
from equation 3 and 4 we get x=8 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeIn a library 60% of the books are in French, 60% of the remaining books are in Japanese rest of the books are in Spanish. If there are 4800 books in Japanese, then the total number of books in Spanish are?
Correct
Answer – 4. 3200
Explanation:
Let there are X books in the library.
French books = 60% of X = 60X /100 = 0.6X
Remaining Books = X – 0.6X = 0.4X
Japanese books = 40% of reaming books = 60% of 0.4X = 0.24X.
Spanish Books = X0.6X 0.24X = 0.16X
Given,
0.24X = 4800
X = 4800/0.24 = 20000
Spanish Books = 0.16X = 0.16*20000 = 3200Incorrect
Answer – 4. 3200
Explanation:
Let there are X books in the library.
French books = 60% of X = 60X /100 = 0.6X
Remaining Books = X – 0.6X = 0.4X
Japanese books = 40% of reaming books = 60% of 0.4X = 0.24X.
Spanish Books = X0.6X 0.24X = 0.16X
Given,
0.24X = 4800
X = 4800/0.24 = 20000
Spanish Books = 0.16X = 0.16*20000 = 3200 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeThree friends started a business. Vishnu, Prakash and David invested Rs 5000, Rs 6000 and Rs 7000 respectively. After 4 months all invested the same amount as before for another 4 months. And then each of them invested Rs 1000 more. If after a year a total profit of Rs 46,500 is made, what is the profit of David?
Correct
Answer – 4. Rs 18,000
Explanation:
5000*4 +10,000*4 + 11,000*4 : 6000*4 +12,000*4 + 13,000*4 : 7000*4 +14,000*4 + 15,000*4
26 : 31 : 36
Profit of David = (36/93) * 46,500 = Rs.18000Incorrect
Answer – 4. Rs 18,000
Explanation:
5000*4 +10,000*4 + 11,000*4 : 6000*4 +12,000*4 + 13,000*4 : 7000*4 +14,000*4 + 15,000*4
26 : 31 : 36
Profit of David = (36/93) * 46,500 = Rs.18000 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeSiva started his Journey from M to N by his bike at the speed of 40 kmph and then, the same distance he travelled on his foot at the speed of 10 kmph from N to O. Then he returned from O to M via N at the speed of 24 kmph. What is the average speed of the whole Journey?
Correct
Answer – 4. 19.2 kmph
Explanation:
Average speed from M to O = 2 * 40 * 10 / (40 + 10) = 16 kmph
Average Speed = 2 * 16 * 24 / (16 + 24) = 19.2 kmphIncorrect
Answer – 4. 19.2 kmph
Explanation:
Average speed from M to O = 2 * 40 * 10 / (40 + 10) = 16 kmph
Average Speed = 2 * 16 * 24 / (16 + 24) = 19.2 kmph
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