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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeQ(12) Each of the following questions below consists of a question and two statements numbered 1 and 2 are given below it. You have to decide if the data provided in the statements are sufficient to answer the question. Read both statements and mark answer.
Find the value of x^{2 }+ y^{2}.
Statement 1 Both x and y are prime positive integer numbers and their average is 15.
Statement 2 Value of x is more than 5 but less than 13.Correct
Answer – 4. If the data in both the statements 1 and 2 are not sufficient to answer the question.
Explanation:
Since average is 15, means sum of x and y is 30
The possible values are (1,29) , (7,23) (11,19), (13,17) (17,13) , (19,11), (23,7) , (29,1)
Since X between 5 and 13 can 7 or 11
Hence, exact value cannot be find.Incorrect
Answer – 4. If the data in both the statements 1 and 2 are not sufficient to answer the question.
Explanation:
Since average is 15, means sum of x and y is 30
The possible values are (1,29) , (7,23) (11,19), (13,17) (17,13) , (19,11), (23,7) , (29,1)
Since X between 5 and 13 can 7 or 11
Hence, exact value cannot be find. 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeQ(12) Each of the following questions below consists of a question and two statements numbered 1 and 2 are given below it. You have to decide if the data provided in the statements are sufficient to answer the question. Read both statements and mark answer.
There are total 30 marbles of 4 difference colours in the bag. How many red marbles are there in the bag ?
Statement 1 The number of Red marble is one fourth of the other three marbles.
Statement 2 The ratio of blue to orange marble is 2:3, orange to yellow is 2:4 and red to yellow marble is 2:3Correct
Answer – 3. If the data either in statement 1 alone or in statement 2 alone is sufficient to answer the question.
Explanation:
Let other marbles =4x
Red marbles = x
5x =30
X =6
Blue: Orange = 2 : 3
Orange: Yellow = 2 : 4
Yellow: Red = 3 : 2
Therefore, Blue:Orange:Yellow:Red = 2:3:6:4
Hence, red in this case = 8Incorrect
Answer – 3. If the data either in statement 1 alone or in statement 2 alone is sufficient to answer the question.
Explanation:
Let other marbles =4x
Red marbles = x
5x =30
X =6
Blue: Orange = 2 : 3
Orange: Yellow = 2 : 4
Yellow: Red = 3 : 2
Therefore, Blue:Orange:Yellow:Red = 2:3:6:4
Hence, red in this case = 8 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeQuantity – 1. Three taps P,Q and R can fill a tank in 6 Hrs, 10 Hrs and 12 hrs respectively. Tap P is opened at 5am, then tap Q is opened at 8am and Tap R is opened at 9 am. When will the tank be full ?
Quantity – 2. A train leaves Jaipur at 6 am and reaches Delhi at 10 am. On the same day another train leaves Delhi at 8 am and reaches Jaipur at 11:30 am on the same day. The time at which the two trains cross each other is ……..?Correct
Answer – 1. Quantity 1 > Quantity 2
Explanation:
Quantity 1 The total tank capacity is LCM of 6 , 10 and 12 = 60
Capacity of tank P = 60/6 = 10
Capacity of tank Q = 60/10 = 6
Capacity of tank R = 60/12 = 5
From 5 am to 8 am means 3 hr tank P filled 3×10 = 30
From 8 am to 9 am both P and Q filled 1 × (10+6) = 16
Hence total tank filled = 46
Total tank left = 14
Now from 9 am all three taps opened with capacity to fill (10+6+5) = 21 tank in one hour
Hence rest 14 units will be filled in 40 minutes.
Finally tank will be filled at 9:40 am.
Quantity 2 – Let the distance Between Delhi and Jaipur is x .
Train from jaipur to delhi travelled for 4 hr while train from delhi to Jaipur travelled for 3.5 hr .
But in the same time period from 8am till meeting one train travelled 2 hours more than the other.
Let the time for which they travelled simultaneously in same time period is T and (T2) hrs .
x/4 ×T + x/3.5 ×(T2) = x
T = 2 hrs 56 minutes
Hence train will meet at 6 hr + 2 Hr + 56 minutes = 8:56 am.Incorrect
Answer – 1. Quantity 1 > Quantity 2
Explanation:
Quantity 1 The total tank capacity is LCM of 6 , 10 and 12 = 60
Capacity of tank P = 60/6 = 10
Capacity of tank Q = 60/10 = 6
Capacity of tank R = 60/12 = 5
From 5 am to 8 am means 3 hr tank P filled 3×10 = 30
From 8 am to 9 am both P and Q filled 1 × (10+6) = 16
Hence total tank filled = 46
Total tank left = 14
Now from 9 am all three taps opened with capacity to fill (10+6+5) = 21 tank in one hour
Hence rest 14 units will be filled in 40 minutes.
Finally tank will be filled at 9:40 am.
Quantity 2 – Let the distance Between Delhi and Jaipur is x .
Train from jaipur to delhi travelled for 4 hr while train from delhi to Jaipur travelled for 3.5 hr .
But in the same time period from 8am till meeting one train travelled 2 hours more than the other.
Let the time for which they travelled simultaneously in same time period is T and (T2) hrs .
x/4 ×T + x/3.5 ×(T2) = x
T = 2 hrs 56 minutes
Hence train will meet at 6 hr + 2 Hr + 56 minutes = 8:56 am. 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeQuantity 1 – A sum of Rs. 400 is made up of 110 coins which are both 2 rupees coin and 5 rupees coin . The number of Rs 5 rupees coin is
Quantity 2 The price of an article is Marked Up by 80%. What should be the profit percentage if two successive discount of 10% were given.Correct
Answer – 1. Quantity 1 > Quantity 2
Explanation:
Quantity 1 let number of 2 rupees coins is a and number of 5 rupees coins is b
Therefore , a+b= 110
2a + 5b =400
b=60
Quantity 2 – let the price of article is 100
Market price will be 180
Two successive discounts of 10%
10 + 10 – (10×10)/100 = 19%
Hence selling price is 180 × 81/100 = 145.8
Profit = 45.8 %Incorrect
Answer – 1. Quantity 1 > Quantity 2
Explanation:
Quantity 1 let number of 2 rupees coins is a and number of 5 rupees coins is b
Therefore , a+b= 110
2a + 5b =400
b=60
Quantity 2 – let the price of article is 100
Market price will be 180
Two successive discounts of 10%
10 + 10 – (10×10)/100 = 19%
Hence selling price is 180 × 81/100 = 145.8
Profit = 45.8 % 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA sum of Rs.1000 was put in a Scheme A giving a simple interest of 4% per annum for one year, then the amount obtained after one year was put in Scheme B giving compound interest at 4% compounded half yearly for one year. What is the difference between the interest obtained in Scheme A and Scheme B?
Correct
Answer – 1. Rs. 2.016Explanation:Interest will be = 2 + 2 + (2×2)/100 = 4.04%1040 × 4.04/100 = 42.016Difference = 42.016 – 40 = 2.016Incorrect
Answer – 1. Rs. 2.016Explanation:Interest will be = 2 + 2 + (2×2)/100 = 4.04%1040 × 4.04/100 = 42.016Difference = 42.016 – 40 = 2.016 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeQ(610) Read the following pie chart carefully and answer the questions. The total quantity of rice and wheat purchased by a family in 4 months is given in first pie chart and in second pie chart the quantity of Pulses purchased per month is given.
If is January the quantity of wheat purchased is 25 kg and in the same month if 200gm of pulses is required per 1kg of rice for a time of meal, Then total how much quantity of rice and pulse is consumed in January if all rice is to be consumed completely.
Correct
Answer – 3. 42Kg
Explanation:
Total wheat and rice purchased = 24% of 250 = 60kg
Wheat purchased = 25kg , rice purchased = 35kg
Pulses consumed for 35kg of rice = 35 ×200 gm = 7000gm = 7kg
Total rice and pulse consumed = 35+7 = 42kgIncorrect
Answer – 3. 42Kg
Explanation:
Total wheat and rice purchased = 24% of 250 = 60kg
Wheat purchased = 25kg , rice purchased = 35kg
Pulses consumed for 35kg of rice = 35 ×200 gm = 7000gm = 7kg
Total rice and pulse consumed = 35+7 = 42kg 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeQ(610) Read the following pie chart carefully and answer the questions. The total quantity of rice and wheat purchased by a family in 4 months is given in first pie chart and in second pie chart the quantity of Pulses purchased per month is given.
In which month the ratio of purse purchased to rice and wheat purchased in maximum ?Correct
Answer – 4. April
Explanation:
January = 27/24
Feb = 25/21
Mar = 19/33
April = 29/22
Clearly April is maximum.Incorrect
Answer – 4. April
Explanation:
January = 27/24
Feb = 25/21
Mar = 19/33
April = 29/22
Clearly April is maximum. 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeQ(610) Read the following pie chart carefully and answer the questions. The total quantity of rice and wheat purchased by a family in 4 months is given in first pie chart and in second pie chart the quantity of Pulses purchased per month is given.
If the price of wheat is Rs 25 per kg, price of rice is Rs 40 per kg , and Price of Pulse in Rs 90 per kg . Then the expenditure on which is maximum, given that the purchase wheat and rice is in the ratio of 2:3.Correct
Answer –1. Rice
Explanation:
Ratio of purchase of wheat to rice is 2:3
Therefore wheat purchased = 100kg
Expenditure on wheat = 100 × 25 = 2500
Rice purchased = 150kg
Expenditure on rice = 150 × 40 = 6000
Pulse purchased = 60kg
Expenditure on pulse = 60 × 90 = 5400Incorrect
Answer –1. Rice
Explanation:
Ratio of purchase of wheat to rice is 2:3
Therefore wheat purchased = 100kg
Expenditure on wheat = 100 × 25 = 2500
Rice purchased = 150kg
Expenditure on rice = 150 × 40 = 6000
Pulse purchased = 60kg
Expenditure on pulse = 60 × 90 = 5400 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeQ(610) Read the following pie chart carefully and answer the questions. The total quantity of rice and wheat purchased by a family in 4 months is given in first pie chart and in second pie chart the quantity of Pulses purchased per month is given.
If the purchase of rice and wheat is increase by 20% in May with respect to April , then what is the purchase of wheat and rice in May ?Correct
Answer – 5. 66kg
Explanation:
22/100 ×250 ×120/100 = 66kgIncorrect
Answer – 5. 66kg
Explanation:
22/100 ×250 ×120/100 = 66kg 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeQ(610) Read the following pie chart carefully and answer the questions. The total quantity of rice and wheat purchased by a family in 4 months is given in first pie chart and in second pie chart the quantity of Pulses purchased per month is given.
The percentage of protein in pulses is 25% but for next 8 months of the year new type of pulses will be purchased whose protein is 20%. How much protein should be purchase for the next 8 month to gain the same amount of protein. ( given that the purchase of pulses is 15kg per month for next 8 months)Correct
Answer – 1. 150Kg
Explanation:
Protein in 60kg is 15kg
15kg protein is for 4 months
For eight months we need 30 kg protein.
x ×20/100 = 30kg
x = 150kgIncorrect
Answer – 1. 150Kg
Explanation:
Protein in 60kg is 15kg
15kg protein is for 4 months
For eight months we need 30 kg protein.
x ×20/100 = 30kg
x = 150kg
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