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SBI PO Previous Year Question Paper
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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeIf a shopkeeper sells a trouser at 20% profit and a shirt at 25% loss then there is no loss or profit. But if he sells the trouser at 40% profit and the shirt at 45% loss, there is a profit of Rs 26. Find the cost prize of the shirt.
Correct
Answer2) Rs 520
Explanation Let the cost prize of the trouser be Rs x and that of shirt be Rs y, then,
20% of x – 25% of y =0
Therefore, 20% of x = 25% of y
4x = 5y
Also, 40% of x – 45% of y = 26
40x – 45y = 2600
50y – 45y =2600 (since 4x = 5y, 40x = 50y)
5y = 2600
y = Rs 520Incorrect
Answer2) Rs 520
Explanation Let the cost prize of the trouser be Rs x and that of shirt be Rs y, then,
20% of x – 25% of y =0
Therefore, 20% of x = 25% of y
4x = 5y
Also, 40% of x – 45% of y = 26
40x – 45y = 2600
50y – 45y =2600 (since 4x = 5y, 40x = 50y)
5y = 2600
y = Rs 520 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeWhat is the rate of interest if the difference between the compound interest and simple interest for an amount of Rs 3500 in two years is Rs12.6?
Correct
Answer 3) 6%
Explanation Let the rate of interest be x%.
The difference between compound interest and simple interest after two years,
(2x + x2/100)% of 3500 – 2x % of 3500 = 12.6
x2/10000 × 3500 = 12.6
x2 = 36, x = 6
Therefore, rate of interest = 6%
Trick 12.6/3500 × 100 = 0.36 = 36/100
Since, 62 = 36, 6% will be the answer.Incorrect
Answer 3) 6%
Explanation Let the rate of interest be x%.
The difference between compound interest and simple interest after two years,
(2x + x2/100)% of 3500 – 2x % of 3500 = 12.6
x2/10000 × 3500 = 12.6
x2 = 36, x = 6
Therefore, rate of interest = 6%
Trick 12.6/3500 × 100 = 0.36 = 36/100
Since, 62 = 36, 6% will be the answer. 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeRavi invested an amount of money in two different schemes in the ratio 27:40. The lesser part of money was invested for 2 years at 9% p.a. on S.I. and the other part was invested for 3 years at 10% on C.I. The difference between the interests received from both the schemes is Rs 4190. Find the total money he invested in both the schemes.
Correct
Answer 2) Rs 33500
Explanation Let the two parts of money be 27x and 40x.
Then, 33.1% of 40x – 18% of 27x = 4190
13.24x – 4.86x = 4190
8.38x = 4190
x = 500
Total money = 27x + 40x = 67x = 67 × 500 = Rs 33500Incorrect
Answer 2) Rs 33500
Explanation Let the two parts of money be 27x and 40x.
Then, 33.1% of 40x – 18% of 27x = 4190
13.24x – 4.86x = 4190
8.38x = 4190
x = 500
Total money = 27x + 40x = 67x = 67 × 500 = Rs 33500 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative Aptitude4 men or 10 women can do a piece of work in 18 days. In how many days 14 men and 25 women can do the same piece of work?
Correct
Answer 3) 3 days
Explanation According to question, 4 men = 10 women
Therefore, 2 men = 5 women and 14 men = 35 women
Let the number of days in which 14 men and 25 women will complete the work be x, then,
(35 + 25) × x = 10 × 18
60x = 180
x = 3Incorrect
Answer 3) 3 days
Explanation According to question, 4 men = 10 women
Therefore, 2 men = 5 women and 14 men = 35 women
Let the number of days in which 14 men and 25 women will complete the work be x, then,
(35 + 25) × x = 10 × 18
60x = 180
x = 3 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA boat goes 16 km upstream and comes back in 6 hours. Find the speed of boat if the speed of current is 2 km/h.
Correct
Answer 1) 6km/h
Explanation Let the speed of boat be x km/h.
Then, according to the situation, 16/(x + 2) + 16/(x – 2) = 6
By solving, we have = 6km/h
Trick To avoid calculation, use options to solve the equation.Incorrect
Answer 1) 6km/h
Explanation Let the speed of boat be x km/h.
Then, according to the situation, 16/(x + 2) + 16/(x – 2) = 6
By solving, we have = 6km/h
Trick To avoid calculation, use options to solve the equation. 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA person divided his money into two parts to give it to his sons in such a way that 75% of the first part is Rs 950 more than the 85% of second part.
Also, 15% of the second part is Rs 30 more than the 12% of first part. Find the total amount of money he had before he divided it.Correct
Answer 4) Rs 29000
Explanation Let the two parts of the money be Rs x and Rs y.
Then, 75% of x – 85% of y = 950
15x – 17y = 19000…… (1)
Also, 15% of y – 12% of x = 30
15y – 12x = 3000……. (2)
By solving both the equations we have, x = Rs 16000, y = Rs 13000
Total money = 16000 + 13000 = Rs 29000Incorrect
Answer 4) Rs 29000
Explanation Let the two parts of the money be Rs x and Rs y.
Then, 75% of x – 85% of y = 950
15x – 17y = 19000…… (1)
Also, 15% of y – 12% of x = 30
15y – 12x = 3000……. (2)
By solving both the equations we have, x = Rs 16000, y = Rs 13000
Total money = 16000 + 13000 = Rs 29000 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThree solutions are in three different containers and contain 20%, 44% and 25% alcohol respectively. When first and second solutions are mixed together, alcohol amounts to 39.2% and when second and third solutions are mixed, it amounts to 727/23 %. If all the three solutions are put in the same container, the percentage of alcohol in this container will be:
Correct
Answer 1) 30.68%
Explanation Let the alcohols in three solutions be x, y and z.
Incorrect
Answer 1) 30.68%
Explanation Let the alcohols in three solutions be x, y and z.

Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDifference between a single discount of 25% and two successive discounts of 15% and 10% on a watch is Rs 11.4. Find the cost price of watch.
Correct
Answer 4) Rs 760
Explanation Let the cost prize of watch be Rs x
Then, 25% of x – (15 + 10 – 15 × 10/100) % of x = 11.4
25% of x – 23.5% of x = 11.4
1.5% of x = 11.4
x = Rs 760Incorrect
Answer 4) Rs 760
Explanation Let the cost prize of watch be Rs x
Then, 25% of x – (15 + 10 – 15 × 10/100) % of x = 11.4
25% of x – 23.5% of x = 11.4
1.5% of x = 11.4
x = Rs 760 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative Aptitude15 persons go for a dinner. Of them 13 persons spends Rs 50 each on the meal. Out of remaining one person spends Rs 15 more than the average expenditure of all fifteen and the other spends Rs 11 more than the average expenditure. Total money they spend on the meal is:
Correct
Answer 3) Rs 780
Explanation: Let the average money they spend on the meal be Rs x.
Then, 13 × 50 + x + 15 + x + 11 = 15x
650 + 2x + 26 = 15x
13x = 676
x = 52
Total money spent = 52 × 15 = Rs 780Incorrect
Answer 3) Rs 780
Explanation: Let the average money they spend on the meal be Rs x.
Then, 13 × 50 + x + 15 + x + 11 = 15x
650 + 2x + 26 = 15x
13x = 676
x = 52
Total money spent = 52 × 15 = Rs 780 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeAt present ratio of father to son is 3:1. 7 years hence, the sum of their ages will be 58 years. What is the present age of father?
Correct
Answer 1) 33 years
Explanation Let the present ages of father and son be 3x and x respectively.
Then, according to question, 3x + 7 + x + 7 = 58
4x = 44
x = 11
3x = 33
Therefore, the present age of father = 33 years.Incorrect
Answer 1) 33 years
Explanation Let the present ages of father and son be 3x and x respectively.
Then, according to question, 3x + 7 + x + 7 = 58
4x = 44
x = 11
3x = 33
Therefore, the present age of father = 33 years.
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