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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

In a school there are 950 students, if 60% boys know swimming but total 38% of the students don’t know swimming. Find how many girls know swimming. If number of boys are 230 more than the number of girls.

Correct

Answer-3) 235
Explanation –
Total boys = 230 + total girls
Total boys + total girls = 950
230 + total girls + Total girls = 950
2 × Total girls = 720
Total girls = 360
Total boys = 590
Total student who know swimming = 62% of 950 = 589
Total boys who know swimming = 60% of 590 = 354
Total girls who know swimming = 589-354 = 235

Incorrect

Answer-3) 235
Explanation –
Total boys = 230 + total girls
Total boys + total girls = 950
230 + total girls + Total girls = 950
2 × Total girls = 720
Total girls = 360
Total boys = 590
Total student who know swimming = 62% of 950 = 589
Total boys who know swimming = 60% of 590 = 354
Total girls who know swimming = 589-354 = 235

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

In a department the no. of males and no. of females are in the ratio of 3:2. If the no. of males are increased by 10% and no. of females are increased by 19, then the new ratio of the no. of males to females is 4:3. What is the total strength of the department after increase?

Correct

Answer -3) 231
Explanation
Let the no. males initially are 3x
After increase 3.3x
No. of females initially = 2x
After increase = 2x + 19
According to question,
3.3x / 2x + 19 = 4 / 3
x = 40
Strength = 3.3x + 2x + 19 = 5.3x + 19 = 5.3 × 40 +19 = 231

Incorrect

Answer -3) 231
Explanation
Let the no. males initially are 3x
After increase 3.3x
No. of females initially = 2x
After increase = 2x + 19
According to question,
3.3x / 2x + 19 = 4 / 3
x = 40
Strength = 3.3x + 2x + 19 = 5.3x + 19 = 5.3 × 40 +19 = 231

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Total cost of three gadgets A, B and C is Rs. 7500 and ratio of cost of A to B is 2:3 while the cost of C is Rs. 1100 more than the cost of B. If A is sold at 20% profit and B is sold at 25% loss. At what price C should be sold for overall profit of 20%.

Correct

Answer- 5) Rs. 5280
Explanation-
Let the cost price of A = 2x
Cost price of B = 3x
Cost price of C 3x + 1100
Total cost = 2x + 3x + 3x + 1100 = 8x+1100
8x +1100 = 7500
x = 800
Cost of A = 1600
Cost of B = 2400
Cost of C = 3500
Profit on selling A = 20% of 1600 = 320
Loss on selling B = 25% 0f 2400 = 600
Required overall profit = 20% of 7500 = 1500
A + B + C = 1500
320 + (-600) + C = 1500
C = 1780
Hence, C should be sold at 3500 + 1780 = 5280

Incorrect

Answer- 5) Rs. 5280
Explanation-
Let the cost price of A = 2x
Cost price of B = 3x
Cost price of C 3x + 1100
Total cost = 2x + 3x + 3x + 1100 = 8x+1100
8x +1100 = 7500
x = 800
Cost of A = 1600
Cost of B = 2400
Cost of C = 3500
Profit on selling A = 20% of 1600 = 320
Loss on selling B = 25% 0f 2400 = 600
Required overall profit = 20% of 7500 = 1500
A + B + C = 1500
320 + (-600) + C = 1500
C = 1780
Hence, C should be sold at 3500 + 1780 = 5280

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Boat “A” which sails at 9km/hr in still water starts chasing Boat “B”, from 8km behind, another one which sails at 5km/hr in the upstream direction. After how long will it catch up if the stream is flowing at 2km/hr?

Correct

Answer -4) 4hr
Explanation
Speed of boat A in upstream = 9-2=7
Relative speed of boat A with respect to boat B (in Upstream) = 7-5 = 2km/hr
Distance to cover = 8km/hr
Time taken = 8km/ relative speed = 8/2 = 4hr

Incorrect

Answer -4) 4hr
Explanation
Speed of boat A in upstream = 9-2=7
Relative speed of boat A with respect to boat B (in Upstream) = 7-5 = 2km/hr
Distance to cover = 8km/hr
Time taken = 8km/ relative speed = 8/2 = 4hr

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

To reach city B from city A, at 6am, Parag will have to travel at an average speed of 36km/hr. He will reach City B at 5am if he travels at 48km/hr. At what average speed should Parag travel to reach City B at 4am?

Correct

Answer -2) 72km/hr
Explanation
Let the taken to reach at 4am is t
Time taken to reach at 5am = t+1
Time taken to reach at 6am = t+2
Since distance is constant
36(t+2) = 48(t+1)
t = 2
putting t=2
Distance = 48(2+1) = 48 × 3
Speed = (48 × 3) / 2 = 72km/hr

Incorrect

Answer -2) 72km/hr
Explanation
Let the taken to reach at 4am is t
Time taken to reach at 5am = t+1
Time taken to reach at 6am = t+2
Since distance is constant
36(t+2) = 48(t+1)
t = 2
putting t=2
Distance = 48(2+1) = 48 × 3
Speed = (48 × 3) / 2 = 72km/hr

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Two trains cross each other in 36 seconds when they are moving in opposite direction and when they are moving in the same direction they cross each other in 540 seconds. The speed of slower train is what percent of the speed of faster train?

Correct

Answer -5) 87.5%
Explanation
Let the speed of slower train is s and speed of faster train is f
Ratio of time = 36 : 540 = 1 : 15
Ratio of their relative speed ,
( f+s) : (f- s) = 15 : 1
f = 8, s = 7
Percent
7 / 8 × 100 = 87.5%

Incorrect

Answer -5) 87.5%
Explanation
Let the speed of slower train is s and speed of faster train is f
Ratio of time = 36 : 540 = 1 : 15
Ratio of their relative speed ,
( f+s) : (f- s) = 15 : 1
f = 8, s = 7
Percent
7 / 8 × 100 = 87.5%

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Ratio of efficiency of A and B in completing a work is 4:3. Both started to work together but B left after 2 days. Another person C joins A and they together completed the remaining work in 7days. If A and B together can complete the work in 12 days, then in how many days C alone can complete the work?

Correct

Answer -5) 14days
Explanation –
Let the efficiency of A = 4x
Efficiency of B = 3x
Total efficiency of A and B = 7x
Time taken by A and B together to finish the work is 12days
Let total work = (combined efficiency of A and B) × 12 days
Total work = 7x × 12 days = 84x
Work done by A and B in 2 days = 7x × 2 = 14x
Work left = 84x – 14x = 70x
Time × (4x + C) = 70x
7 × (4x + C) = 70x
C = 6x
Time taken by C alone = 84x / 6x = 14days

Incorrect

Answer -5) 14days
Explanation –
Let the efficiency of A = 4x
Efficiency of B = 3x
Total efficiency of A and B = 7x
Time taken by A and B together to finish the work is 12days
Let total work = (combined efficiency of A and B) × 12 days
Total work = 7x × 12 days = 84x
Work done by A and B in 2 days = 7x × 2 = 14x
Work left = 84x – 14x = 70x
Time × (4x + C) = 70x
7 × (4x + C) = 70x
C = 6x
Time taken by C alone = 84x / 6x = 14days

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

There are 7 filling pipes, each capable of filling a cistern alone in 6 minutes and 5 empty pipes each capable of emptying the cistern alone in 8 minutes. All pipes are opened together and as a result tank gets filled by 13 litres of water per minute. Find the capacity of the tank.

Correct

Answer – 2) 24 litres
Explanation –
Tank filled per minute by filling pipe = 1/6
Tank filled per minute by 7 filling pipe = 7/6
Tank emptied per minute by emptying pipe = 1/8
Tank emptied per minute by 5 emptying pipe = 5/8
When all pipes are opened, tank filled per minute = 7/6 – 5/8
= 13/24
Tank will be fully filled in = 24/13 minutes
Capacity of tank = 24/13 × 13 = 24 litres

Incorrect

Answer – 2) 24 litres
Explanation –
Tank filled per minute by filling pipe = 1/6
Tank filled per minute by 7 filling pipe = 7/6
Tank emptied per minute by emptying pipe = 1/8
Tank emptied per minute by 5 emptying pipe = 5/8
When all pipes are opened, tank filled per minute = 7/6 – 5/8
= 13/24
Tank will be fully filled in = 24/13 minutes
Capacity of tank = 24/13 × 13 = 24 litres

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Two customers are visiting a particular shop in the same week (Monday to Friday). Each is equally likely to visit the shop on any one day as on another. What is the probability that both will visit the shop on different days?

Correct

Answer-2) 4/5
Explanation-
Total number of days to visit the shop = 5
Total number of possible outcomes = 5 × 5 = 25
Number of favourable outcomes (for visiting the shop on same day) = 5 i.e., (M,M), (Tu,Tu,) (W,W), (Th,Th, ) ( F,F)
Probability (for visiting the shop on same day) = 5/25 = 1/5
Probability (for visiting the shop on different days) = 1 – Probability (for visiting the shop on same day)
Probability (for visiting the shop on different days) = 1 – 1/ 5 = 4/5

Incorrect

Answer-2) 4/5
Explanation-
Total number of days to visit the shop = 5
Total number of possible outcomes = 5 × 5 = 25
Number of favourable outcomes (for visiting the shop on same day) = 5 i.e., (M,M), (Tu,Tu,) (W,W), (Th,Th, ) ( F,F)
Probability (for visiting the shop on same day) = 5/25 = 1/5
Probability (for visiting the shop on different days) = 1 – Probability (for visiting the shop on same day)
Probability (for visiting the shop on different days) = 1 – 1/ 5 = 4/5

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

A glass contains a mixture of apple, sugarcane and orange juices in the respective ratio of 5:6:4. 15ml of this mixture is taken out and 16ml of orange juice and 4ml of sugarcane juice are added to the glass. If the resultant quantity of orange juice is 8ml less than the resultant quantity of sugarcane juice, what was the initial quantity of mixture in the glass?

Correct

Answer- 3) 165ml
Explanation
After 15ml mixture is taken out,
Let the quantity of apple juice, sugarcane juice and orange juice in the glass is 5x, 6x and 4x respectively.
According to question,
(6x + 4) – (4x +16) = 8ml
x = 10
15x = 150
Adding 15ml which was taken in the beginning,
150+15 = 165ml

Incorrect

Answer- 3) 165ml
Explanation
After 15ml mixture is taken out,
Let the quantity of apple juice, sugarcane juice and orange juice in the glass is 5x, 6x and 4x respectively.
According to question,
(6x + 4) – (4x +16) = 8ml
x = 10
15x = 150
Adding 15ml which was taken in the beginning,
150+15 = 165ml

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