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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5).**There are three bags i.e. A, B and C in which there are four different colored balls i.e. red, blue, green and yellow.

In bag C, the number of yellow balls are 50% more than that of blue balls and number of red balls are 40% more than that of yellow balls. Also, in bag C, the number of green balls are 1 more than that of yellow balls. In bag A, number of blue balls are 50% more than that of red balls and number of green balls are half the number of yellow balls. In bag A, number of blue balls are 5 more than that of yellow balls and number of green balls are 7 less than that of red balls. In bag B, ratio of number of green balls to number of yellow balls is 3:4 respectively and the number of blue balls are 32% less than that of red balls. Total number of blue balls in bag A and number of yellow balls in bag C are 42.**If a ball is drawn at random from bag A, the probability of getting a blue ball is:**Correct**Answer- 5) 9/26**

Explanation-

Let the number of blue balls in bag C are x.

Then, number of yellow balls in bag C = 150% of x = 1.5x

Number of red balls in bag C = 140% of 1.5x = 2.1x

Number of green balls in bag C = 1.5x + 1

Let the number of red balls in bag A are m and number of green balls are n.

Then, number of blue balls in bag A = 1.5m

Number of yellow balls in bag A = 2n

We have,

1.5 m – 2n = 5

Also, m – n = 7

By solving both these equations, we have

m = 18, n = 11

Therefore,

Number of red balls in bag A = 18

Number of blue balls in bag A = 27

Number of green balls in bag A = 11

Number of yellow balls in bag A = 22

Also,

27 + 1.5x = 42

1.5x = 15, x = 10

Therefore,

Number of blue balls in bag C = 10

Number of yellow balls in bag C = 1.5 × 10 = 15

Number of red balls in bag C = 2.1 × 10 = 21

Number of green balls in bag C = 15 + 1 = 16

Required probability = 27/(18 + 27 + 11 + 22) = 27/78 = 9/26Incorrect**Answer- 5) 9/26**

Explanation-

Let the number of blue balls in bag C are x.

Then, number of yellow balls in bag C = 150% of x = 1.5x

Number of red balls in bag C = 140% of 1.5x = 2.1x

Number of green balls in bag C = 1.5x + 1

Let the number of red balls in bag A are m and number of green balls are n.

Then, number of blue balls in bag A = 1.5m

Number of yellow balls in bag A = 2n

We have,

1.5 m – 2n = 5

Also, m – n = 7

By solving both these equations, we have

m = 18, n = 11

Therefore,

Number of red balls in bag A = 18

Number of blue balls in bag A = 27

Number of green balls in bag A = 11

Number of yellow balls in bag A = 22

Also,

27 + 1.5x = 42

1.5x = 15, x = 10

Therefore,

Number of blue balls in bag C = 10

Number of yellow balls in bag C = 1.5 × 10 = 15

Number of red balls in bag C = 2.1 × 10 = 21

Number of green balls in bag C = 15 + 1 = 16

Required probability = 27/(18 + 27 + 11 + 22) = 27/78 = 9/26 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5).**There are three bags i.e. A, B and C in which there are four different colored balls i.e. red, blue, green and yellow.

In bag C, the number of yellow balls are 50% more than that of blue balls and number of red balls are 40% more than that of yellow balls. Also, in bag C, the number of green balls are 1 more than that of yellow balls. In bag A, number of blue balls are 50% more than that of red balls and number of green balls are half the number of yellow balls. In bag A, number of blue balls are 5 more than that of yellow balls and number of green balls are 7 less than that of red balls. In bag B, ratio of number of green balls to number of yellow balls is 3:4 respectively and the number of blue balls are 32% less than that of red balls. Total number of blue balls in bag A and number of yellow balls in bag C are 42.**If the number of green balls in bag C are y2, what is the value of y?**Correct**Answer- 3) 4**

Explanation-

Number of green balls in bag C = 16 (watch solution of Q1)

Therefore, y2 = 16, y = 4Incorrect**Answer- 3) 4**

Explanation-

Number of green balls in bag C = 16 (watch solution of Q1)

Therefore, y2 = 16, y = 4 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5).**There are three bags i.e. A, B and C in which there are four different colored balls i.e. red, blue, green and yellow.

In bag C, the number of yellow balls are 50% more than that of blue balls and number of red balls are 40% more than that of yellow balls. Also, in bag C, the number of green balls are 1 more than that of yellow balls. In bag A, number of blue balls are 50% more than that of red balls and number of green balls are half the number of yellow balls. In bag A, number of blue balls are 5 more than that of yellow balls and number of green balls are 7 less than that of red balls. In bag B, ratio of number of green balls to number of yellow balls is 3:4 respectively and the number of blue balls are 32% less than that of red balls. Total number of blue balls in bag A and number of yellow balls in bag C are 42.**If one ball is drawn at random from bag B, the probability of getting a green ball is 1/7. What are the number of yellow balls in bag B if total number of red balls and green balls in bag B are 34?**Correct**Answer- 1) 12**

Explanation-

Let the number of green balls and yellow balls in bag B are 3x and 4x.

Let the number of red balls in bag B are y

Then, number of blue balls in bag B = 0.68y

We have,

y + 3x = 34

Also,

3x/(7x + 1.68y) = 1/7

x/y = 3/25

y = 25x/3

Therefore,

25x/3 + 3x = 34

34x/3 = 34, x = 3

Number of yellow balls in bag B = 4 × 3 = 12Incorrect**Answer- 1) 12**

Explanation-

Let the number of green balls and yellow balls in bag B are 3x and 4x.

Let the number of red balls in bag B are y

Then, number of blue balls in bag B = 0.68y

We have,

y + 3x = 34

Also,

3x/(7x + 1.68y) = 1/7

x/y = 3/25

y = 25x/3

Therefore,

25x/3 + 3x = 34

34x/3 = 34, x = 3

Number of yellow balls in bag B = 4 × 3 = 12 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5).**There are three bags i.e. A, B and C in which there are four different colored balls i.e. red, blue, green and yellow.

In bag C, the number of yellow balls are 50% more than that of blue balls and number of red balls are 40% more than that of yellow balls. Also, in bag C, the number of green balls are 1 more than that of yellow balls. In bag A, number of blue balls are 50% more than that of red balls and number of green balls are half the number of yellow balls. In bag A, number of blue balls are 5 more than that of yellow balls and number of green balls are 7 less than that of red balls. In bag B, ratio of number of green balls to number of yellow balls is 3:4 respectively and the number of blue balls are 32% less than that of red balls. Total number of blue balls in bag A and number of yellow balls in bag C are 42.**Total number of yellow balls in bag A and number of green balls in bag C are:**Correct**Answer- 2) 38**

Explanation-

Required number of balls = 22 + 16 = 38Incorrect**Answer- 2) 38**

Explanation-

Required number of balls = 22 + 16 = 38 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5).**There are three bags i.e. A, B and C in which there are four different colored balls i.e. red, blue, green and yellow.

In bag C, the number of yellow balls are 50% more than that of blue balls and number of red balls are 40% more than that of yellow balls. Also, in bag C, the number of green balls are 1 more than that of yellow balls. In bag A, number of blue balls are 50% more than that of red balls and number of green balls are half the number of yellow balls. In bag A, number of blue balls are 5 more than that of yellow balls and number of green balls are 7 less than that of red balls. In bag B, ratio of number of green balls to number of yellow balls is 3:4 respectively and the number of blue balls are 32% less than that of red balls. Total number of blue balls in bag A and number of yellow balls in bag C are 42.**By using the information given in Q3), the total number of red balls in all the three bags together are how much more than the total number of green balls in all the three bags together?**Correct**Answer- 1) 28**

Explanation-

By using information given in Q3),

Number of red balls in bag B = 25 (watch the solution of Q3)

Number of green balls in bag B = 9

Total number of red balls = 18 + 25 + 21 = 64

Total number of green balls = 11 + 9 + 16 = 36

Required difference = 64 – 36 = 28Incorrect**Answer- 1) 28**

Explanation-

By using information given in Q3),

Number of red balls in bag B = 25 (watch the solution of Q3)

Number of green balls in bag B = 9

Total number of red balls = 18 + 25 + 21 = 64

Total number of green balls = 11 + 9 + 16 = 36

Required difference = 64 – 36 = 28 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Direction (Q6-10). There are five boats i.e. A, B, C, D and E who travel different distance downstream, upstream and in still water (in different streams) as shown by radar graphs given below. The table given below shows the ratio of speed of boat in still water to the speed of current and total time taken by these boats to travel total distance.**

**Time taken by the boat B to travel the distance upstream is:**Correct**Answer- 3) 23 hrs**

Explanation-

Let the speed of boat B in still water and speed of current for him are 4x and 3x respectively.

Then,

120/4x + 252/7x + 138/x = 34

204/x = 34, x = 6

Speed of boat upstream = 4 × 6 – 3 × 6 = 6 km/h

Required time = 138/6 = 23 hrsIncorrect**Answer- 3) 23 hrs**

Explanation-

Let the speed of boat B in still water and speed of current for him are 4x and 3x respectively.

Then,

120/4x + 252/7x + 138/x = 34

204/x = 34, x = 6

Speed of boat upstream = 4 × 6 – 3 × 6 = 6 km/h

Required time = 138/6 = 23 hrs - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Direction (Q6-10). There are five boats i.e. A, B, C, D and E who travel different distance downstream, upstream and in still water (in different streams) as shown by radar graphs given below. The table given below shows the ratio of speed of boat in still water to the speed of current and total time taken by these boats to travel total distance.**

**What is the speed of boat E in still water?**Correct**Answer- 2) 63 km/h**

Explanation-

Let the speed of boat E and speed of stream for him are 9x and 4x.

Then,

315/9x + 273/13x + 385/5x = 19

35/x + 21/x + 77/x = 19

133/x = 19

x = 7

Therefore, speed of boat E = 63 km/hIncorrect**Answer- 2) 63 km/h**

Explanation-

Let the speed of boat E and speed of stream for him are 9x and 4x.

Then,

315/9x + 273/13x + 385/5x = 19

35/x + 21/x + 77/x = 19

133/x = 19

x = 7

Therefore, speed of boat E = 63 km/h - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Direction (Q6-10). There are five boats i.e. A, B, C, D and E who travel different distance downstream, upstream and in still water (in different streams) as shown by radar graphs given below. The table given below shows the ratio of speed of boat in still water to the speed of current and total time taken by these boats to travel total distance.**

**Speed of boat C downstream is how much more than the speed of boat C upstream?**Correct**Answer- 1) 70 km/h**

Explanation-

Let the speed of boat C in still water and speed of stream for him are 7x and 5x respectively.

Then,

147/7x + 336/12x + 140/2x = 17

21/x + 28/x + 70/x = 17

119/x = 17, x = 7

Speed of boat C in downstream = 12 × 7 = 84 km/h

Speed of boat C in upstream = 2 × 7 = 14 km/h

Required difference = 84 – 14 = 70 km/hIncorrect**Answer- 1) 70 km/h**

Explanation-

Let the speed of boat C in still water and speed of stream for him are 7x and 5x respectively.

Then,

147/7x + 336/12x + 140/2x = 17

21/x + 28/x + 70/x = 17

119/x = 17, x = 7

Speed of boat C in downstream = 12 × 7 = 84 km/h

Speed of boat C in upstream = 2 × 7 = 14 km/h

Required difference = 84 – 14 = 70 km/h - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude

**In how much time boat A will travel a distance of 126 km upstream in the same stream in which E was travelling?**Correct**Answer- 1) 18 hrs**

Explanation-

Speed of stream in which E was travelling = 4 × 7 = 28 km/h (watch solution of Q7)

Let the speed of boat A and speed of stream in which he was travelling are 5x and 2x respectively

210/5x + 98/7x + 168/3x = 16

42/x + 14/x + 56/x = 16

112/x = 16, x = 7

Speed of boat A in still water = 5 × 7 = 35 km/h

Required time = 126/(35 – 28) = 18 hrsIncorrect**Answer- 1) 18 hrs**

Explanation-

Speed of stream in which E was travelling = 4 × 7 = 28 km/h (watch solution of Q7)

Let the speed of boat A and speed of stream in which he was travelling are 5x and 2x respectively

210/5x + 98/7x + 168/3x = 16

42/x + 14/x + 56/x = 16

112/x = 16, x = 7

Speed of boat A in still water = 5 × 7 = 35 km/h

Required time = 126/(35 – 28) = 18 hrs - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude

**Speed of boat D in still water is how much percent more than the speed of stream in which he was travelling?**Correct**Answer- 4) 100%**

Explanation-

Required percentage = (2x – x)/x × 100 = 100%Incorrect**Answer- 4) 100%**

Explanation-

Required percentage = (2x – x)/x × 100 = 100%

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