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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). In an organization, there’re six departments i.e. A, B, C, D, E and F. There are total 3800 employees in the organization and different number of employees work in each department as shown by the pie chart in percentage. Ratio of number of male to female in each department is shown by the table. Few values are missing in the table.**

**Number of females in department B are how much more than the number of males in department F?**Correct**Answer-3) 12**

Explanation-

Number of females in department B = 6/13 × 13% of 3800 = 228

Number of males in department F = 27/76 × 16% of 3800 = 216

Required difference = 228 – 216 = 12Incorrect**Answer-3) 12**

Explanation-

Number of females in department B = 6/13 × 13% of 3800 = 228

Number of males in department F = 27/76 × 16% of 3800 = 216

Required difference = 228 – 216 = 12 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). In an organization, there’re six departments i.e. A, B, C, D, E and F. There are total 3800 employees in the organization and different number of employees work in each department as shown by the pie chart in percentage. Ratio of number of male to female in each department is shown by the table. Few values are missing in the table.**

**Number of females working in department D are 399 less than the number of males working in department E. Number of males working in the department D are how much more than the number of females in the same department?**Correct**Answer- 1) 38**

Explanation-

Number of males working in department E = 5/7 × 21% of 3800 = 570

Number of females working in department D = 570 – 399 = 171

Total number of employees in department D = 10% of 3800 = 380

Number of males = 380 – 171 = 209

Required difference = 209 – 171 = 38Incorrect**Answer- 1) 38**

Explanation-

Number of males working in department E = 5/7 × 21% of 3800 = 570

Number of females working in department D = 570 – 399 = 171

Total number of employees in department D = 10% of 3800 = 380

Number of males = 380 – 171 = 209

Required difference = 209 – 171 = 38 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). In an organization, there’re six departments i.e. A, B, C, D, E and F. There are total 3800 employees in the organization and different number of employees work in each department as shown by the pie chart in percentage. Ratio of number of male to female in each department is shown by the table. Few values are missing in the table.**

**In department A, the number of males are increased by 4% and number of females are increased by 49 due to which the total number of employees in department A become 904. Originally how many male employees were there in department A?**Correct**Answer- 5) 475**

Explanation-

Let the original number of males and females in department A are x and y respectively.

Original number of employees in department A = 22% of 3800 = 836

Therefore, x + y = 836

Also, 1.04x + y + 49 = 904 or 1.04x + y = 855

By solving both the equations, we have,

x = 475, y = 361Incorrect**Answer- 5) 475**

Explanation-

Let the original number of males and females in department A are x and y respectively.

Original number of employees in department A = 22% of 3800 = 836

Therefore, x + y = 836

Also, 1.04x + y + 49 = 904 or 1.04x + y = 855

By solving both the equations, we have,

x = 475, y = 361 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

**Salary of each male employee in department B is Rs 55000 and that of each female employee is Rs 48000. Amount of salary paid to all the female employees together in department B is approximately how much percent less than the amount of salary paid to all the male employees together in the same department?**Correct**Answer- 2) 25%**

Explanation-

Total number of employees in department B = 13% of 3800 = 494

Number of male employees = 494/13 × 7 = 266

Number of female employees = 494/13 × 6 = 228

Amount of salary paid to male employees together = 55000 × 266 = Rs 14630000

Amount of salary paid to female employees together = 48000 × 228 = Rs 10944000

Required percentage = (14630000 – 10944000)/14630000 × 100 = 25% (approx.)Incorrect**Answer- 2) 25%**

Explanation-

Total number of employees in department B = 13% of 3800 = 494

Number of male employees = 494/13 × 7 = 266

Number of female employees = 494/13 × 6 = 228

Amount of salary paid to male employees together = 55000 × 266 = Rs 14630000

Amount of salary paid to female employees together = 48000 × 228 = Rs 10944000

Required percentage = (14630000 – 10944000)/14630000 × 100 = 25% (approx.) - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

**Number of female employees in department C are 12 more than that of male employees. Total number of female employees in department C are:**Correct**Answer- 5) 348**

Explanation-

Total number of employees in department C = 18% of 3800 = 684

Let the number of male employees and female employees are x and y respectively in department C.

According to question,

x + y = 684

y – x = 12

by solving both equations, we have,

x = 336, y = 348Incorrect**Answer- 5) 348**

Explanation-

Total number of employees in department C = 18% of 3800 = 684

Let the number of male employees and female employees are x and y respectively in department C.

According to question,

x + y = 684

y – x = 12

by solving both equations, we have,

x = 336, y = 348 - Question 6 of 10
##### 6. Question

1 points**Directions (Q6-10). In a city, the data was gathered about the students of class 8th, 9th and 10th of all the schools together. The line graph below shows the percentage of students who have failed in these classes from year 2014 to 2018.**

**In class 8th in 2015, the number of students who failed are 180 which is equal to 12% of the total number of students in class 9th in 2014. The number of students who failed in class 9th in 2014 are how much less than the number of students who passed in class 8th in 2015?**Correct**Answer- 2) 310**

Explanation-

Total number of students in class 8th in 2015 = 180/18 × 100 = 1000

Number of students who passed = 82% of 1000 = 820

Total number of students in class 9th in 2014 = 180/12 × 100 = 1500

Number of students who failed = 34% of 1500 = 510

Required difference = 820 – 510 = 310Incorrect**Answer- 2) 310**

Explanation-

Total number of students in class 8th in 2015 = 180/18 × 100 = 1000

Number of students who passed = 82% of 1000 = 820

Total number of students in class 9th in 2014 = 180/12 × 100 = 1500

Number of students who failed = 34% of 1500 = 510

Required difference = 820 – 510 = 310 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). In a city, the data was gathered about the students of class 8th, 9th and 10th of all the schools together. The line graph below shows the percentage of students who have failed in these classes from year 2014 to 2018.**

**In 2017, the ratio of number of students in class 8th, 9th and 10th are in the ratio 60:68:55 and the number of students who failed in class 8th are 205 less than the number of students who failed in class 10th. The number of students who passed in class 9th in 2017 are:**Correct**Answer- 1) 1105**

Explanation-

Let the number of students in class 8th, 9th and 10th in 2017 are 60x, 68x and 55x respectively.

According to question,

21% of 60x – 8% of 55x = 205

12.6x – 4.4x = 205

8.2x = 205, x = 25

Total number of students in class 9th = 25 × 68 = 1700

Number of students who passed in class 9th = 65% of 1700 = 1105Incorrect**Answer- 1) 1105**

Explanation-

Let the number of students in class 8th, 9th and 10th in 2017 are 60x, 68x and 55x respectively.

According to question,

21% of 60x – 8% of 55x = 205

12.6x – 4.4x = 205

8.2x = 205, x = 25

Total number of students in class 9th = 25 × 68 = 1700

Number of students who passed in class 9th = 65% of 1700 = 1105 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). In a city, the data was gathered about the students of class 8th, 9th and 10th of all the schools together. The line graph below shows the percentage of students who have failed in these classes from year 2014 to 2018.**

**The total number of students in class 9th in 2016 and in class 10th in 2018 are 6156. The total number of students who passed in class 10th in 2018 and the number of students who failed in class 9th in 2016 are 3049. The number of students who passed in class 9th in 2016 are how much more than the number of students who failed in class 10th in 2018:**Correct**Answer- 3) 1429**

Explanation-

Let the number of students in class 9th in 2016 and in class 10th in 2018 are x and y respectively.

According to question,

x + y = 6156

19% of x + 75% of y = 3049

0.19x + 0.75y = 3049

By solving both these equations, we have,

x = 2800, y = 3356

Number of students who passed in class 9th in 2016 = 81% of 2800 = 2268

Number of students who failed in class 10th in 2018 = 25% of 3356 = 839

Required difference = 2268 – 839 = 1429Incorrect**Answer- 3) 1429**

Explanation-

Let the number of students in class 9th in 2016 and in class 10th in 2018 are x and y respectively.

According to question,

x + y = 6156

19% of x + 75% of y = 3049

0.19x + 0.75y = 3049

By solving both these equations, we have,

x = 2800, y = 3356

Number of students who passed in class 9th in 2016 = 81% of 2800 = 2268

Number of students who failed in class 10th in 2018 = 25% of 3356 = 839

Required difference = 2268 – 839 = 1429 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude

**The number of students who failed in class 9th in 2015 are 650. The total number of students in class 10th in 2015 are 40% less than the total number of students in class 9th in same year. The number of students who passed in class 10th in 2015 are:**Correct**Answer- 2) 1248**

Explanation-

Total number of students in class 9th in 2015 = 650/25 × 100 = 2600

Total number of students in class 10th in 2015 = 2600 – 40% of 2600 = 2600 – 1040 = 1560

Number of students who passed = 80% of 1560 = 1248Incorrect**Answer- 2) 1248**

Explanation-

Total number of students in class 9th in 2015 = 650/25 × 100 = 2600

Total number of students in class 10th in 2015 = 2600 – 40% of 2600 = 2600 – 1040 = 1560

Number of students who passed = 80% of 1560 = 1248 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude

**In 2016, in class 10th, 36% of the students passed the exam with distinction and 1020 students passed the exam without distinction. Number of students who failed in class 10th in 2016 are:**Correct**Answer- 4) 612**–

Explanation

Let the total number of students in class 10th in 2016 are x.

Percentage of students who passed the exam without distinction = (100 – 24 – 36) % = 40%

According to question, we have,

40% of x = 1020

0.4x = 1020

x = 2550

Number of students who failed in class 10th in 2016 = 24% of 2550 = 612Incorrect**Answer- 4) 612**–

Explanation

Let the total number of students in class 10th in 2016 are x.

Percentage of students who passed the exam without distinction = (100 – 24 – 36) % = 40%

According to question, we have,

40% of x = 1020

0.4x = 1020

x = 2550

Number of students who failed in class 10th in 2016 = 24% of 2550 = 612

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