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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Train A leaves X for Y at 3 PM and travels at the constant speed of 100 mph. An hour later, it passes Train B, which is making the trip from Y to X at a constant speed. If Train B left Y at 3:50 PM and if the combined travel time of the two trains is 2 hours, what time did Train B arrive in X?

(1) Train B arrived in Xbefore Train A arrived in Y. (2) The distance between X and Y is greater than 140 miles.

Correct

Answer : (D) Each statement ALONE is sufficient.
Explanation-
Let x be the distance from meeting point to Y.
Speed of train A = 100 mph
Speed of train B = x/ (10 min) = 6x mph (converted min to hr)
Total time taken by both is 2 hrs. Already accounted for is 1hr + (1/6) hr
the remaining (5/6) hrs is the time needed by both together to reach their respective destinations.

Time taken by train A to reach B + time taken by train B to reach NY = 5/6
x/100 + 100/6x = 5/6
3x^2 – 250x + 5000 = 0 (Painful part of the question)
x = 50, 33.33

(1) Train B arrived in X before Train A arrived in Y.
If x = 50, time taken by train A to reach B = 1/2 hr, time taken by train B to reach NY = 1/3 hr
If x = 33.33, time taken by train A to reach B = 1/3 hr, time taken by train B to reach NY = 1/2 hr
Since train B arrived first, x must be 50 and B must have arrived at 4:20. Sufficient.

(2) The distance between X and Y is greater than 140 miles.
x must be 50 to make total distance more than 140. Time taken by train B must be 1/3 hr and it must have arrived at 4:20. Sufficient.

Incorrect

Answer : (D) Each statement ALONE is sufficient.
Explanation-
Let x be the distance from meeting point to Y.
Speed of train A = 100 mph
Speed of train B = x/ (10 min) = 6x mph (converted min to hr)
Total time taken by both is 2 hrs. Already accounted for is 1hr + (1/6) hr
the remaining (5/6) hrs is the time needed by both together to reach their respective destinations.

Time taken by train A to reach B + time taken by train B to reach NY = 5/6
x/100 + 100/6x = 5/6
3x^2 – 250x + 5000 = 0 (Painful part of the question)
x = 50, 33.33

(1) Train B arrived in X before Train A arrived in Y.
If x = 50, time taken by train A to reach B = 1/2 hr, time taken by train B to reach NY = 1/3 hr
If x = 33.33, time taken by train A to reach B = 1/3 hr, time taken by train B to reach NY = 1/2 hr
Since train B arrived first, x must be 50 and B must have arrived at 4:20. Sufficient.

(2) The distance between X and Y is greater than 140 miles.
x must be 50 to make total distance more than 140. Time taken by train B must be 1/3 hr and it must have arrived at 4:20. Sufficient.

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Boat travels 500 km upstream in 5 hours and 300 km downstream in 4 hours? Find the speed of boat in still water?

Correct

Answer : 5. None of these
Explanation:
A+b=300/4=75
a-b=500/5=100
a=87.5
b=-12.5
Not possible because boat can’t travel with more speed in upstream than downstream.

Incorrect

Answer : 5. None of these
Explanation:
A+b=300/4=75
a-b=500/5=100
a=87.5
b=-12.5
Not possible because boat can’t travel with more speed in upstream than downstream.

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

In how many days can P alone complete the work?

I. P alone takes six days less than that Q alone takes to complete the work.
II. Q and R together take 18 days to complete the work.
III. The ratio of efficiencies of P and Q is 4 : 3.

Correct

Answer : 2. I and III
Explanation:
Let time taken by P, Q, R be a,b,c respectively
From I:
A=b-6
From II:
1/B+1/C=1/18
FROM III:
1/a:1/b=4:3
B/a=4/3
From i and iii a can be found

Incorrect

Answer : 2. I and III
Explanation:
Let time taken by P, Q, R be a,b,c respectively
From I:
A=b-6
From II:
1/B+1/C=1/18
FROM III:
1/a:1/b=4:3
B/a=4/3
From i and iii a can be found

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

how many employees are there in the bank? I. The difference between the number of male employees and the number of female employees in the bank is eighteen. II.When three more female employees join the bank then the ratio of the number of male employees to the number of female employees would be 6 : 5. III.When six more male employees join the bank then the percentage of number of male employees would increase by 25%

Correct

Answer : 4. Any two of the three
Explanation:
Let total number of male employees=a
Total number of female employees=b
From I
A-b=18
From II
a/(b+3)=6/5
From III
A=24
Any two can be used be used to find out the answer.

Incorrect

Answer : 4. Any two of the three
Explanation:
Let total number of male employees=a
Total number of female employees=b
From I
A-b=18
From II
a/(b+3)=6/5
From III
A=24
Any two can be used be used to find out the answer.

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Q. (5-9)in a college there are total 800 students. Among them, 55.625% like Game A, 32.5% like Game B and 43.125% like Game C. 5% students like all three games. 9.375% students like only Game A and Game B, and 5.625% students like only Game B and Game C. Answer the following questions based on this information.

what percentage of students like only Game A?

Correct

Answer : 5. 35%
Explanation-

Game A = 55.625% of 800 = 445
Game B = 32.5% of 800 = 260
Game C = 43.125% of 800 = 345
All three games = 5% of 800 = 40
A + B = 9.375% of 800 = 75
B + C = 5.625% of 800 = 45
y = 260 – (75 + 40 + 45) = 100
x + k = 445 – (75 + 40) = 330
… (i)
z + k = 345 – (40 + 45) = 260
… (ii)
x + z + k = 800 – (75 + 40 + 45 + 100) = 540
… (iii)
Eqn (i) + (ii) – eqn (iii)
(x + z + 2k) – (x + z + k) = (330 + 260) – 540
Solving this, k = 590 – 540 = 50
x = 330 – 50 = 280
z = 260 – 50 = 210
Percentage of students like only Game A=
Reqd % = (280/800)×100 =35%

Incorrect

Answer : 5. 35%
Explanation-

Game A = 55.625% of 800 = 445
Game B = 32.5% of 800 = 260
Game C = 43.125% of 800 = 345
All three games = 5% of 800 = 40
A + B = 9.375% of 800 = 75
B + C = 5.625% of 800 = 45
y = 260 – (75 + 40 + 45) = 100
x + k = 445 – (75 + 40) = 330
… (i)
z + k = 345 – (40 + 45) = 260
… (ii)
x + z + k = 800 – (75 + 40 + 45 + 100) = 540
… (iii)
Eqn (i) + (ii) – eqn (iii)
(x + z + 2k) – (x + z + k) = (330 + 260) – 540
Solving this, k = 590 – 540 = 50
x = 330 – 50 = 280
z = 260 – 50 = 210
Percentage of students like only Game A=
Reqd % = (280/800)×100 =35%

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Q. (5-9)in a college there are total 800 students. Among them, 55.625% like Game A, 32.5% like Game B and 43.125% like Game C. 5% students like all three games. 9.375% students like only Game A and Game B, and 5.625% students like only Game B and Game C. Answer the following questions based on this information.

How many students are there who like Game A and Game C but do not like Game B?

Correct

Answer : 2.50
Explanation-
Check solution of question 5

Incorrect

Answer : 2.50
Explanation-
Check solution of question 5

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Q. (5-9)in a college there are total 800 students. Among them, 55.625% like Game A, 32.5% like Game B and 43.125% like Game C. 5% students like all three games. 9.375% students like only Game A and Game B, and 5.625% students like only Game B and Game C. Answer the following questions based on this information.

The number of students who like only Game B is approximately, what per cent of the number of Students who like Game B?

Q. (5-9)in a college there are total 800 students. Among them, 55.625% like Game A, 32.5% like Game B and 43.125% like Game C. 5% students like all three games. 9.375% students like only Game A and Game B, and 5.625% students like only Game B and Game C. Answer the following questions based on this information.

The number of students who like only Game C is approximately what per cent of the number of Students who like all three games?

Q. (5-9)in a college there are total 800 students. Among them, 55.625% like Game A, 32.5% like Game B and 43.125% like Game C. 5% students like all three games. 9.375% students like only Game A and Game B, and 5.625% students like only Game B and Game C. Answer the following questions based on this information.

What is the percentage of students who like at least two games among the given three types of Games?

Correct

Answer :3. 26.25%
Explanation-
The number of students who like at least
Two games = 75 + 50 + 45 + 40 = 210
Reqd% = (210/800)×100=26.25%

Incorrect

Answer :3. 26.25%
Explanation-
The number of students who like at least
Two games = 75 + 50 + 45 + 40 = 210
Reqd% = (210/800)×100=26.25%

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Three equal cubes are placed adjacently in a row. Find the ratio of total surface area of the new cuboid to that of the sum of the surface areas of the three cubes.

Correct

Answer : 1. 7 : 9
Explanation-
Let the side of the cube be = a units, Total surface area of 3 cubes = 3* 6a^{2} = 18 a^{2}. Total surface area of cuboid = 18a2 – 4a^{2} = 14 a^{2}. Hence ratio = 7 : 9

Incorrect

Answer : 1. 7 : 9
Explanation-
Let the side of the cube be = a units, Total surface area of 3 cubes = 3* 6a^{2} = 18 a^{2}. Total surface area of cuboid = 18a2 – 4a^{2} = 14 a^{2}. Hence ratio = 7 : 9

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