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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeSathish invested Rs X on SI at the rate of 12% for 4 years, and he invested Rs (X+200) at 10% CI for 2 years. The total interest obtained is Rs 4320. Find the total amount (in Rs) invested by Sathish?
Correct
Answer – 4. 12600
Explanation:
Simple interest is ,
SI * 100= P *12 *4
SI = 48P/100
In compound interest , total interest will be
(P+200) * 21/100
According to the questions ,
48P/100 + (P+200)*21/100= 4320
P=6200
So P+200=6400
Total investment = 6200 + 6400= 12600Incorrect
Answer – 4. 12600
Explanation:
Simple interest is ,
SI * 100= P *12 *4
SI = 48P/100
In compound interest , total interest will be
(P+200) * 21/100
According to the questions ,
48P/100 + (P+200)*21/100= 4320
P=6200
So P+200=6400
Total investment = 6200 + 6400= 12600 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeSuresh rows to the place 80 km away and back in 20 hours. He finds that he can row 8 km downstream in the same time as 4 km upstream. The speed of the stream is
Correct
Answer – 1. 3 kmph
Explanation:
If Suresh moves 8 km downstream in X hours
Downstream speed = 8/X kmph
upstream speed = 4/X kmph
Now 80/(8/X) + 80/(4/X)=20
X=2/3
downstream Speed = 8/(2/3)= 12 kmph
upstream Speed = 4/(2/3)= 6 kmph
Rate of the stream = (126)/3= 3 kmphIncorrect
Answer – 1. 3 kmph
Explanation:
If Suresh moves 8 km downstream in X hours
Downstream speed = 8/X kmph
upstream speed = 4/X kmph
Now 80/(8/X) + 80/(4/X)=20
X=2/3
downstream Speed = 8/(2/3)= 12 kmph
upstream Speed = 4/(2/3)= 6 kmph
Rate of the stream = (126)/3= 3 kmph 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeKavin sold two watches – P and Q. Marked Price(MP) of watch P was Rs 500 more than that of watch Q. He sold watch P at Rs 1620 after giving successive discounts
of 20% and 10% on its MP. What was the selling price of watch B, if Kavin sold it at a discount of 20 % on its marked price?(in Rs)Correct
Answer – 3. 1400
Explanation:
Let MP of P = Rs X
So X * 80/100 *90/100= 1620
So X= 2250
Marked price of watch Q = Rs (2250500)=Rs 1750
SP of watch Q = (1750 *80)/100=Rs 1400Incorrect
Answer – 3. 1400
Explanation:
Let MP of P = Rs X
So X * 80/100 *90/100= 1620
So X= 2250
Marked price of watch Q = Rs (2250500)=Rs 1750
SP of watch Q = (1750 *80)/100=Rs 1400 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA tradesman mixed 7 litres of water with 20 litres of pure Juice. If the cost of pure Juice is Rs 30 per litre the percentage profit of the tradesman when he sells all the mixture at the cost price is
Correct
Answer – 1. 35%
Explanation:
Profit %= (7*100)/20= 35%Incorrect
Answer – 1. 35%
Explanation:
Profit %= (7*100)/20= 35% 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeMr.Suresh spending 20% of his monthly salary in buying Washing Machine and 10% of the monthly salary in Medicine, invested 30% of the remaining amount in fixed deposits. If he was left with Rs 18963, how much is his monthly salary?
Correct
Answer – 1. 38700
Explanation:
Let the monthly salary be Rs X
X * 70/100* 70/100=18693
X=38700Incorrect
Answer – 1. 38700
Explanation:
Let the monthly salary be Rs X
X * 70/100* 70/100=18693
X=38700 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeAt present Amit’s age is less than thrice of Bala’s age by 8 years. The respective ratio between Amit’s age 5 years ago and Bala’s age 1 year ago was 7:3, what is Catherine’s present age if Catherine is 2 years younger than Bala?
Correct
Answer – 2. 14
Explanation:
Let Bala’s present age = X years
(3X85)/(X1)=7/3
X=16
Catherine’s present age=162=14 yearsIncorrect
Answer – 2. 14
Explanation:
Let Bala’s present age = X years
(3X85)/(X1)=7/3
X=16
Catherine’s present age=162=14 years 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeIn a city, 30% of the citizens belong to upper economic class. The number of citizens who belong to middle economic class are 3/2 of the number of citizens who belong to lower economic class. If 6860 citizens belong to lower economic class, what is the population of the city?
Correct
Answer – 2. 24500
Explanation:
citizens belong to lower economic class =6860
citizens belong to middle economic class= 30/2 * 6860=10290
Let the population of city be X
(30X/100)+ 10290+6860=X
X=24500Incorrect
Answer – 2. 24500
Explanation:
citizens belong to lower economic class =6860
citizens belong to middle economic class= 30/2 * 6860=10290
Let the population of city be X
(30X/100)+ 10290+6860=X
X=24500 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeA cistern has one inlet, L and one inlet, M. L takes 5 hours to fill the empty tank, when M is not open and M takes 8 hours to empty the full tank, if the tank is three fifth full, how much time will it take to fill the tank completely when both L and M are opened simultaneously? (in hours)
Correct
Answer – 4. 16/3
Explanation:
If the tank is 3/5th full, then remaining empty tank will be = 13/5=2/5th
L and M can fill the empty tank in = (5*8)/(85)=40/3 hours
Then 2/5 th tank fill in =40/3 * 2/5= 16/3 hoursIncorrect
Answer – 4. 16/3
Explanation:
If the tank is 3/5th full, then remaining empty tank will be = 13/5=2/5th
L and M can fill the empty tank in = (5*8)/(85)=40/3 hours
Then 2/5 th tank fill in =40/3 * 2/5= 16/3 hours 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeIn an University examination Praveen scored 25 marks less than Queen. Queen scored 45 more marks than Ramya. Tamanna scored 75 marks which is 10 more than Ramya. Uma’s score is 80 less than maximum marks of the test. What is the approximate percentage of marks did Uma score in the examination if he get 55 marks more than Ramya?
Correct
Answer – 4. 60%
Explanation :
Marks of Tamanna = 75
Marks of Ramya = 65
Marks of Queen = 110
Marks of Praveen = 85
Marks of Uma = 120
Maximum marks = 200
Required percentage = 120/200 x 100 = 60%Incorrect
Answer – 4. 60%
Explanation :
Marks of Tamanna = 75
Marks of Ramya = 65
Marks of Queen = 110
Marks of Praveen = 85
Marks of Uma = 120
Maximum marks = 200
Required percentage = 120/200 x 100 = 60% 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeThe difference between the sum of four consecutive odd numbers, and three consecutive even number together is 20. The largest even number is 5 more than the largest odd number. Find the sum of the smallest odd number and the biggest even number?
Correct
Answer – 2. 81
Explanation :
Let the consecutive odd numbers be:
x, x+2, x+4 and x+6
Largest even number = x+11 and other even numbers
= x+7 and x+9
x + x + 2 + x + 4 + x + 6 (x + 7+ x + 9 + x + 11 )=20
x – 15 = 20Incorrect
Answer – 2. 81
Explanation :
Let the consecutive odd numbers be:
x, x+2, x+4 and x+6
Largest even number = x+11 and other even numbers
= x+7 and x+9
x + x + 2 + x + 4 + x + 6 (x + 7+ x + 9 + x + 11 )=20
x – 15 = 20
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