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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA boy started from point P at 60 km/hr. After 1 hour another boy started from point P at 70 km/hr in the same direction as the first boy. After how much time the second boy will meet the first one?
Correct
Explanation:
Let first boy meets after t hours when he started, so second boy took (t1) hours to reach the same distance.
So distance covered by first boy in t hours = distance covered by second boy in (t1) hours
60*t = 70*(t1)
Solve, t = 7 hours
So second boy met first after (71) = 6 hoursIncorrect
Explanation:
Let first boy meets after t hours when he started, so second boy took (t1) hours to reach the same distance.
So distance covered by first boy in t hours = distance covered by second boy in (t1) hours
60*t = 70*(t1)
Solve, t = 7 hours
So second boy met first after (71) = 6 hours 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeThe ratio of Babita’s present age and Anisha’s age 4 years hence is 9 : 8. If twice Babita’s present age is 12 more than Anisha’s age 12 years after, what is the ratio of present ages of Anisha and Babita?
Correct
Explanation:
B/(A+4) = 9/8, so 9A – 8B = 36
Also 2B = (A+12) +12, so A – 2B = 24
Solve, both equations, A = 12, B= 18
So required ratio is 12/18Incorrect
Explanation:
B/(A+4) = 9/8, so 9A – 8B = 36
Also 2B = (A+12) +12, so A – 2B = 24
Solve, both equations, A = 12, B= 18
So required ratio is 12/18 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeThe population of a town was 1.6 lakh three years ago. There is a successive increase of 10% in the population in the last 2 years. If before 2 years from now, there was a decrease of 5% in the population over the previous year, what is the present population of the town approximately?
Correct
Explanation:
The statement says that three years ago pop. was 1.6 lakhs, next yr decreased by 5%, and then increased by 10% for 2 years.
So present population = (1.6 lakh) * (95/100) * (110/100) * (110/100) = 1,83,920Incorrect
Explanation:
The statement says that three years ago pop. was 1.6 lakhs, next yr decreased by 5%, and then increased by 10% for 2 years.
So present population = (1.6 lakh) * (95/100) * (110/100) * (110/100) = 1,83,920 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA box contains 5 blue and 7 yellow balls. Two balls are drawn one by one with replacement. What is the probability that both balls are different in color?
Correct
Explanation:
Balls are drawn one by one so 2 cases:
When first ball is blue prob. = 5/12 * 7/12 = 35/144 [since replacement so 12 in both denominators]
When first ball is yellow prob. = 5/12 * 7/12 = 35/144
Add both casesIncorrect
Explanation:
Balls are drawn one by one so 2 cases:
When first ball is blue prob. = 5/12 * 7/12 = 35/144 [since replacement so 12 in both denominators]
When first ball is yellow prob. = 5/12 * 7/12 = 35/144
Add both cases 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative Aptitude21% of 450 + √2116 = 5*13.5 + ?
Correct
Explanation:
21% of 450 + √2116 = 5*13.5 + ?
94.50 + 46 = 67.5 + ?Incorrect
Explanation:
21% of 450 + √2116 = 5*13.5 + ?
94.50 + 46 = 67.5 + ? 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married.
Departments No. of Employees % of females Ratio of number of unmarried
males to married malesA 450 20% 2 7 B 290 40% 1 2 C 360 35% 4 5 D 540 25% 2 3 E 250 20% 7 3 Approximately what percentage of females in department B are less than that in department C?
Correct
Explanation:
Females in department B = (40/100)*290 = 116
In department C = (35/100)*360 = 126
Required % = (126116)/126 * 100 ≈ 8%Incorrect
Explanation:
Females in department B = (40/100)*290 = 116
In department C = (35/100)*360 = 126
Required % = (126116)/126 * 100 ≈ 8% 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married.
Departments No. of Employees % of females Ratio of number of unmarried
males to married malesA 450 20% 2 7 B 290 40% 1 2 C 360 35% 4 5 D 540 25% 2 3 E 250 20% 7 3 How many males in department D are married?
Correct
Explanation:
3/5 * (75/100)*540Incorrect
Explanation:
3/5 * (75/100)*540 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married.
Departments No. of Employees % of females Ratio of number of unmarried
males to married malesA 450 20% 2 7 B 290 40% 1 2 C 360 35% 4 5 D 540 25% 2 3 E 250 20% 7 3 What is the difference between the total number of females in department A and number of males in department B who are unmarried?
Correct
Explanation:
Females in A = (20/100)*450 = 90
Males in B who come by bus = (1/3) * (60/100)*290 = 58
Difference = 9058Incorrect
Explanation:
Females in A = (20/100)*450 = 90
Males in B who come by bus = (1/3) * (60/100)*290 = 58
Difference = 9058 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married.
Departments No. of Employees % of females Ratio of number of unmarried
males to married malesA 450 20% 2 7 B 290 40% 1 2 C 360 35% 4 5 D 540 25% 2 3 E 250 20% 7 3 What is the total number of males in departments D and E?
Correct
Explanation:
D + E
(75/100)*540 + (80/100)*250 = 405+200Incorrect
Explanation:
D + E
(75/100)*540 + (80/100)*250 = 405+200 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married.
Departments No. of Employees % of females Ratio of number of unmarried
males to married malesA 450 20% 2 7 B 290 40% 1 2 C 360 35% 4 5 D 540 25% 2 3 E 250 20% 7 3 What is the ratio of number of unmarried males in department C to number of married males in department B?
Correct
Explanation:
Unmarried males in department C = (4/9) * (65/100)*360 = 104
Married Males in department B = (2/3) * (60/100)*290 = 116
104 : 116 = 26 : 29Incorrect
Explanation:
Unmarried males in department C = (4/9) * (65/100)*360 = 104
Married Males in department B = (2/3) * (60/100)*290 = 116
104 : 116 = 26 : 29
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