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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

A rectangular park has dimensions 100m × 40m. A circular lawn is in the middle of park. If the area of rectangular park leaving the circular lawn is 1536 m^{2}, what is the circumference of the circular lawn?

Correct

Explanation:
Area of park = 100*40 = 4000
So area of circular lawn = 4000-1536 = 2464
So ᴨr^{2} = 2464
Solve, r = 28
So circumference = 2ᴨr

Incorrect

Explanation:
Area of park = 100*40 = 4000
So area of circular lawn = 4000-1536 = 2464
So ᴨr^{2} = 2464
Solve, r = 28
So circumference = 2ᴨr

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

A sum of rupees is divided between three people A, B and C in such a way that after 2 years, 3 years and 4 years respectively the amount they get is equal. If the rate of interest is 5 percent, what is the ratio in which the amount is divided?

How many kg of wheat costing Rs 10 per kg must be mixed with 16 Kg of wheat costing Rs 15 per Kg, so that there may be gain of 30% by selling the mixture of Rs 15.6 per Kg?

Correct

Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2

Incorrect

Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

A starts from point P at 20 km/hr towards point Q. After 2 hours B starts from point Q at some speed towards A. They both meet when they reach half the distance between points P and Q. If A covered one-fourth of total distance in 2 hours, what is the speed of B?

Correct

Explanation:
A covered one-fourth of total distance in 2 hours, so 1/2 distance in 4 hours
Now B has covered that same distance that A covered in (4-2) = 2 hours [B started after 2 hrs]
And since distances are same
So distance by A = distance covered by B gives
20*4 = x*2
Solve, x = 40km/hr

Incorrect

Explanation:
A covered one-fourth of total distance in 2 hours, so 1/2 distance in 4 hours
Now B has covered that same distance that A covered in (4-2) = 2 hours [B started after 2 hrs]
And since distances are same
So distance by A = distance covered by B gives
20*4 = x*2
Solve, x = 40km/hr

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

The sum of money invested at compound interest amounts to Rs 4680 in 2 years and to Rs 5616 in 3 years. What was the amount of sum invested?

Correct

Explanation:
SI on 3380 for 1 yr = 5616 – 4680 = 936
So rate = (100*936/4680*1) = 20
So P (1 + 20/100)^{2} = 4680
Solve, P = 3250

Incorrect

Explanation:
SI on 3380 for 1 yr = 5616 – 4680 = 936
So rate = (100*936/4680*1) = 20
So P (1 + 20/100)^{2} = 4680
Solve, P = 3250

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): Study the pie chart below which gives the distribution of the expenditure on different items. Answer the questions that follow.

Which of the following combination of items contribute to 50% of the total expenditure?

Correct

Explanation:
A, B, F = 36^{o}+72^{o}+18^{o} = 126^{o}
B, C, F = 72^{o}+72^{o}+18^{o} = 162^{o}
A, B, C = 36^{o}+72^{o}+72^{o} = 180^{o}
C, D, E = 72^{o}+18^{o}+45^{o} = 135^{o}
180^{o} is the half of complete 360^{o}, so items A, B, and C contribute to 50% of total.

Incorrect

Explanation:
A, B, F = 36^{o}+72^{o}+18^{o} = 126^{o}
B, C, F = 72^{o}+72^{o}+18^{o} = 162^{o}
A, B, C = 36^{o}+72^{o}+72^{o} = 180^{o}
C, D, E = 72^{o}+18^{o}+45^{o} = 135^{o}
180^{o} is the half of complete 360^{o}, so items A, B, and C contribute to 50% of total.

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): Study the pie chart below which gives the distribution of the expenditure on different items. Answer the questions that follow.

If Rs 1440 is spent on item A, then what is the amount spent on item G?

Correct

Explanation:
Let total money spent is x
So (36/360) * x = 1440
This gives x = 14400
So spent on G = (99/360) * 14400 = 3960

Incorrect

Explanation:
Let total money spent is x
So (36/360) * x = 1440
This gives x = 14400
So spent on G = (99/360) * 14400 = 3960

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): Study the pie chart below which gives the distribution of the expenditure on different items. Answer the questions that follow.

If the amount spent on item B is 50% more than that spent on item A, then amount spent on A is what percent less than that spent on B?

Correct

Explanation:
There is no need to see the pie chart to answer this question
Required % = 100/(100+50) * 100

Incorrect

Explanation:
There is no need to see the pie chart to answer this question
Required % = 100/(100+50) * 100

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): Study the pie chart below which gives the distribution of the expenditure on different items. Answer the questions that follow.

Find the amount spent on items A, B and E together.

Correct

Explanation:
Amount spent on A = 36/360 * (total amount spent)
Since we are not given the total amount spent, we cannot determine the individual amounts spent.

Incorrect

Explanation:
Amount spent on A = 36/360 * (total amount spent)
Since we are not given the total amount spent, we cannot determine the individual amounts spent.

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): Study the pie chart below which gives the distribution of the expenditure on different items. Answer the questions that follow.

If the total expenditure increases by 50% and expenditure on item A increase by 20%, then what will be the angle for item A in the new pie-chart?

Correct

Explanation:
Let total expenditure is Rs ‘s’. After increase by 50%, new expenditure = 150/100 * s = 3s/2
Angle for item A is 36^{o}, so exp. on A = 36/360 * s = s/10. It increased by 20%, so new amount spent on A = 120/100 * s/10 = 6s/50
So new angle for A = [(6s/50)/(3s/2)] * 360 = 28.8^{o}

Incorrect

Explanation:
Let total expenditure is Rs ‘s’. After increase by 50%, new expenditure = 150/100 * s = 3s/2
Angle for item A is 36^{o}, so exp. on A = 36/360 * s = s/10. It increased by 20%, so new amount spent on A = 120/100 * s/10 = 6s/50
So new angle for A = [(6s/50)/(3s/2)] * 360 = 28.8^{o}