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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA rectangular park has dimensions 100m × 40m. A circular lawn is in the middle of park. If the area of rectangular park leaving the circular lawn is 1536 m^{2}, what is the circumference of the circular lawn?
Correct
Explanation:
Area of park = 100*40 = 4000
So area of circular lawn = 40001536 = 2464
So ᴨr^{2} = 2464
Solve, r = 28
So circumference = 2ᴨrIncorrect
Explanation:
Area of park = 100*40 = 4000
So area of circular lawn = 40001536 = 2464
So ᴨr^{2} = 2464
Solve, r = 28
So circumference = 2ᴨr 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeA sum of rupees is divided between three people A, B and C in such a way that after 2 years, 3 years and 4 years respectively the amount they get is equal. If the rate of interest is 5 percent, what is the ratio in which the amount is divided?
Correct
Explanation:
Shortcut when amounts are equal:
1/(100+2*5) : 1/(100+3*5) : 1/(100+4*5)
1/110 : 1/115 : 1/120
23*12 : 22*12 : 11*23Incorrect
Explanation:
Shortcut when amounts are equal:
1/(100+2*5) : 1/(100+3*5) : 1/(100+4*5)
1/110 : 1/115 : 1/120
23*12 : 22*12 : 11*23 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeHow many kg of wheat costing Rs 10 per kg must be mixed with 16 Kg of wheat costing Rs 15 per Kg, so that there may be gain of 30% by selling the mixture of Rs 15.6 per Kg?
Correct
Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2Incorrect
Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA starts from point P at 20 km/hr towards point Q. After 2 hours B starts from point Q at some speed towards A. They both meet when they reach half the distance between points P and Q. If A covered onefourth of total distance in 2 hours, what is the speed of B?
Correct
Explanation:
A covered onefourth of total distance in 2 hours, so 1/2 distance in 4 hours
Now B has covered that same distance that A covered in (42) = 2 hours [B started after 2 hrs]
And since distances are same
So distance by A = distance covered by B gives
20*4 = x*2
Solve, x = 40km/hrIncorrect
Explanation:
A covered onefourth of total distance in 2 hours, so 1/2 distance in 4 hours
Now B has covered that same distance that A covered in (42) = 2 hours [B started after 2 hrs]
And since distances are same
So distance by A = distance covered by B gives
20*4 = x*2
Solve, x = 40km/hr 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeThe sum of money invested at compound interest amounts to Rs 4680 in 2 years and to Rs 5616 in 3 years. What was the amount of sum invested?
Correct
Explanation:
SI on 3380 for 1 yr = 5616 – 4680 = 936
So rate = (100*936/4680*1) = 20
So P (1 + 20/100)^{2} = 4680
Solve, P = 3250Incorrect
Explanation:
SI on 3380 for 1 yr = 5616 – 4680 = 936
So rate = (100*936/4680*1) = 20
So P (1 + 20/100)^{2} = 4680
Solve, P = 3250 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Study the pie chart below which gives the distribution of the expenditure on different items. Answer the questions that follow.
Which of the following combination of items contribute to 50% of the total expenditure?
Correct
Explanation:
A, B, F = 36^{o}+72^{o}+18^{o} = 126^{o}
B, C, F = 72^{o}+72^{o}+18^{o} = 162^{o}
A, B, C = 36^{o}+72^{o}+72^{o} = 180^{o}
C, D, E = 72^{o}+18^{o}+45^{o} = 135^{o}
180^{o} is the half of complete 360^{o}, so items A, B, and C contribute to 50% of total.Incorrect
Explanation:
A, B, F = 36^{o}+72^{o}+18^{o} = 126^{o}
B, C, F = 72^{o}+72^{o}+18^{o} = 162^{o}
A, B, C = 36^{o}+72^{o}+72^{o} = 180^{o}
C, D, E = 72^{o}+18^{o}+45^{o} = 135^{o}
180^{o} is the half of complete 360^{o}, so items A, B, and C contribute to 50% of total. 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Study the pie chart below which gives the distribution of the expenditure on different items. Answer the questions that follow.
If Rs 1440 is spent on item A, then what is the amount spent on item G?
Correct
Explanation:
Let total money spent is x
So (36/360) * x = 1440
This gives x = 14400
So spent on G = (99/360) * 14400 = 3960Incorrect
Explanation:
Let total money spent is x
So (36/360) * x = 1440
This gives x = 14400
So spent on G = (99/360) * 14400 = 3960 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Study the pie chart below which gives the distribution of the expenditure on different items. Answer the questions that follow.
If the amount spent on item B is 50% more than that spent on item A, then amount spent on A is what percent less than that spent on B?
Correct
Explanation:
There is no need to see the pie chart to answer this question
Required % = 100/(100+50) * 100Incorrect
Explanation:
There is no need to see the pie chart to answer this question
Required % = 100/(100+50) * 100 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Study the pie chart below which gives the distribution of the expenditure on different items. Answer the questions that follow.
Find the amount spent on items A, B and E together.
Correct
Explanation:
Amount spent on A = 36/360 * (total amount spent)
Since we are not given the total amount spent, we cannot determine the individual amounts spent.Incorrect
Explanation:
Amount spent on A = 36/360 * (total amount spent)
Since we are not given the total amount spent, we cannot determine the individual amounts spent. 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Study the pie chart below which gives the distribution of the expenditure on different items. Answer the questions that follow.
If the total expenditure increases by 50% and expenditure on item A increase by 20%, then what will be the angle for item A in the new piechart?
Correct
Explanation:
Let total expenditure is Rs ‘s’. After increase by 50%, new expenditure = 150/100 * s = 3s/2
Angle for item A is 36^{o}, so exp. on A = 36/360 * s = s/10. It increased by 20%, so new amount spent on A = 120/100 * s/10 = 6s/50
So new angle for A = [(6s/50)/(3s/2)] * 360 = 28.8^{o}Incorrect
Explanation:
Let total expenditure is Rs ‘s’. After increase by 50%, new expenditure = 150/100 * s = 3s/2
Angle for item A is 36^{o}, so exp. on A = 36/360 * s = s/10. It increased by 20%, so new amount spent on A = 120/100 * s/10 = 6s/50
So new angle for A = [(6s/50)/(3s/2)] * 360 = 28.8^{o}
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