Hello Aspirants
Welcome to Online Quant Test in AffairsCloud.com. We are starting Cumulus Course for SBI Clerk 2019 Prelims Exam and we are creating sample questions in Quant section, this type of Question will be asked in SBI Clerk 2019!!!
Click Here to View Cumulus Course: SBI Clerk 2019 Prelims
SBI Clerk 2019 Prelims: Reasoning Test – 7.30 PM Every Day
SBI Clerk 2019 Prelims: Quant Test – 8.30 PM Every Day
SBI Clerk 2019 Prelims: English Test – 9.30 PM Every Day
Help: Share Our Cumulus Course for SBI Clerk 2019 Exam Course page to your Friends & FB Groups
_______________________
Quizsummary
0 of 10 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
Information
All the Best
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 10 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
 Quantitative Aptitude 0%
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 Answered
 Review

Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections (12): What value should come in place of (?) in the following questions.
√(3249 ) + √2809 + √(? ) = 125Correct
Answer: 3) 225
Explanation:
√(3249 ) + √2809 + √(? ) = 125
57 + 53 + √(? ) = 125
110 + √(? ) = 125
√(? ) = 15
?= 225Incorrect
Answer: 3) 225
Explanation:
√(3249 ) + √2809 + √(? ) = 125
57 + 53 + √(? ) = 125
110 + √(? ) = 125
√(? ) = 15
?= 225 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections (12): What value should come in place of (?) in the following questions.
?= 20% of √(24×10+7×6×5+175)Correct
Answer: 1) 5
Explanation:
20% of √(24×10+7×6×5+175)
20% of √(240+210+175)
20% of √625
20% of 25
20/100* 25 =5Incorrect
Answer: 1) 5
Explanation:
20% of √(24×10+7×6×5+175)
20% of √(240+210+175)
20% of √625
20% of 25
20/100* 25 =5 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections (34): What value should come in the place of (?) in the following number series?
5, 45, 82, 113, 135, (?)
Correct
Incorrect

Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections (34): What value should come in the place of (?) in the following number series?
1000, 24, 232, (?), 184, 180
Correct
Answer: 4. 168
Explanation:
1000 – 4^{5} = 24
24 + 4^{4} = 232
232 – 4^{3} = 168 (answer)
168 + 4^{2} = 184
184 – 4^{1 }= 180Incorrect
Answer: 4. 168
Explanation:
1000 – 4^{5} = 24
24 + 4^{4} = 232
232 – 4^{3} = 168 (answer)
168 + 4^{2} = 184
184 – 4^{1 }= 180 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections (56): Following questions contains two equations as 1 and 2. You have to solve both equations and determine the relationship between them and give answer as,
x^{2}+30x+225 = 0
y^{2}+4x –165 = 0Correct
Answer: 5. x ≤ y
Explanation:
x^{2}+30x+225 = 0
x^{2}+15x + 15x +225 = 0
x(x+15) +15(x+15) = 0
x = 15, 15y^{2}+4x – 165 = 0
y^{2}+ 15x11x – 165 = 0
y(y+15) 11(y+15) = 0
y =11, 15Incorrect
Answer: 5. x ≤ y
Explanation:
x^{2}+30x+225 = 0
x^{2}+15x + 15x +225 = 0
x(x+15) +15(x+15) = 0
x = 15, 15y^{2}+4x – 165 = 0
y^{2}+ 15x11x – 165 = 0
y(y+15) 11(y+15) = 0
y =11, 15 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (56): Following questions contains two equations as 1 and 2. You have to solve both equations and determine the relationship between them and give answer as,
3x^{2}20x+25 = 0
5y^{2} – 32x + 35 = 0Correct
Answer: 3. x = y or relationship can’t be determined.
Explanation:
3x^{2}20x+25 = 0
3x^{2}15x5x+25 = 0
3x(x5) 5(x5) = 0
x = 5/3, 55y^{2} – 32y + 35 = 0
5y^{2} – 25y7y+ 35 = 0
5y(y5) 7(y5) = 0
y =7/5, 5Incorrect
Answer: 3. x = y or relationship can’t be determined.
Explanation:
3x^{2}20x+25 = 0
3x^{2}15x5x+25 = 0
3x(x5) 5(x5) = 0
x = 5/3, 55y^{2} – 32y + 35 = 0
5y^{2} – 25y7y+ 35 = 0
5y(y5) 7(y5) = 0
y =7/5, 5 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeIn a team of 6 batsmen and 5 allrounders, each batsman scored runs that are 250% of the total number of batsmen and each allrounder scored runs that are 80% of the total number of allrounders. How many runs were scored by all?
Correct
Answer: 2. 110
Explanation:
250% of the total number of batsmen = 250% of 6 = 15
And 80% of the total number of allrounders = 80% of 5 = 4
Total runs scored by batsmen = 6*15 = 90
Total runs scored by allrounders = 5*4 = 20
Total = 110 runsIncorrect
Answer: 2. 110
Explanation:
250% of the total number of batsmen = 250% of 6 = 15
And 80% of the total number of allrounders = 80% of 5 = 4
Total runs scored by batsmen = 6*15 = 90
Total runs scored by allrounders = 5*4 = 20
Total = 110 runs 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative Aptitude5 years ago, Satyam’s age was 4/5 times of that of Ravi. 6 years hence, Satyam’s age will be 5/6 times that of Ravi. What is the present age of Ravi?
Correct
Answer: 2. 60 years
Explanation:
5 years ago, let the age of Ravi was 5x, age of Satyam = 4/5*5x = 4x
6 years hence, there age will be 5x+11 and 4x+11
According to question,
(4x+11) = 5/6* (5x+11)
24x +66 = 25x +55
X = 11
Present age of Ravi = 5x + 5 = 5*11 +5 = 60 yearsIncorrect
Answer: 2. 60 years
Explanation:
5 years ago, let the age of Ravi was 5x, age of Satyam = 4/5*5x = 4x
6 years hence, there age will be 5x+11 and 4x+11
According to question,
(4x+11) = 5/6* (5x+11)
24x +66 = 25x +55
X = 11
Present age of Ravi = 5x + 5 = 5*11 +5 = 60 years 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA container contains 200 litres of wine. Some quantity of wine is taken out and 1/4th of that quantity of wine, water is added in the container. Now the ratio of wine to water in the container becomes 4:1. What is the quantity of water added in it?
Correct
Answer: 2) 25 litres
Explanation:
Let the quantity of wine taken out = 4x
Quantity of water added = 1/4 * 4x = x
According to question,
(2004x)/x = 4/1
200 – 4x = 4x
8x = 200
X = 25 litresIncorrect
Answer: 2) 25 litres
Explanation:
Let the quantity of wine taken out = 4x
Quantity of water added = 1/4 * 4x = x
According to question,
(2004x)/x = 4/1
200 – 4x = 4x
8x = 200
X = 25 litres 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA boat travels 36 km upstream in 8 hours and 24 km downstream in 3 hours then, what is the speed of boat in still water and speed of current respectively?
Correct
Answer: 4) 6.25km/h and 1.75km/h
Explanation:
Let speed of boat in still water is x and speed of current is y
Speed of boat in upstream (x y) = 36/8 = 4.5km/h
Speed of boat in downstream( x + y ) = 24/3 = 8km/h
Speed of boat in still water = (Upstream speed + Downstream speed ) / 2 = (4.5 + 8 ) / 2 = 6.25km/h
Speed of current = (downstream speed – upstream speed) / 2 = (8 – 4.5)/2 = 1.75km/hIncorrect
Answer: 4) 6.25km/h and 1.75km/h
Explanation:
Let speed of boat in still water is x and speed of current is y
Speed of boat in upstream (x y) = 36/8 = 4.5km/h
Speed of boat in downstream( x + y ) = 24/3 = 8km/h
Speed of boat in still water = (Upstream speed + Downstream speed ) / 2 = (4.5 + 8 ) / 2 = 6.25km/h
Speed of current = (downstream speed – upstream speed) / 2 = (8 – 4.5)/2 = 1.75km/h
________________________
 Click view Questions button to view Explanation
 Note: We are providing unique questions for you to practice well, have a try !!
 Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
 If you find any mistake, please tell us in the comment section.