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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). A farmer harvests six types of crops and vegetables in a square field with side 50 m. The pie chart below shows the percentage area covered by each.**

**The area covered by Wheat is by what percent more than that of by Mustard?**Correct**Answer- 4) 50%**Required percentage = (27 – 18)/18 × 100 = 50%

Explanation-Incorrect**Answer- 4) 50%**Required percentage = (27 – 18)/18 × 100 = 50%

Explanation- - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). A farmer harvests six types of crops and vegetables in a square field with side 50 m. The pie chart below shows the percentage area covered by each.**

**What is the difference between the area covered by potatoes and that of by onions?**Correct**Answer- 1) 350 m**^{2}

**Explanation-**Total area of the square field = (50)^{2}= 2500 m^{2}

Required difference = (23 – 9) % of 2500 = 14% of 2500 = 350 m^{2}Incorrect**Answer- 1) 350 m**^{2}

**Explanation-**Total area of the square field = (50)^{2}= 2500 m^{2}

Required difference = (23 – 9) % of 2500 = 14% of 2500 = 350 m^{2} - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). A farmer harvests six types of crops and vegetables in a square field with side 50 m. The pie chart below shows the percentage area covered by each.**

**What is the total area covered by wheat, maize and onions together?**Correct**Answer- 5) 1175 m**^{2}

**Explanation-**Total area covered by wheat, maize and onions together = (27 + 11 + 9) % of 2500 = 47% of 2500 = 1175 m^{2}Incorrect**Answer- 5) 1175 m**^{2}

**Explanation-**Total area covered by wheat, maize and onions together = (27 + 11 + 9) % of 2500 = 47% of 2500 = 1175 m^{2} - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

**Farmer’s land is in fact in the form of a circle and square is in the circle with each vertical on the circumference of the circle. The rest of the land is wasteland. The area of the wasteland is how much more than the area covered by maize?**Correct**Answer- 2) 1153.57 m**^{2}

**Explanation-**length of the diagonal of the square = √2 × side = 50√2 m

Since the square is inside the square

Radius of the circle = 50√2/2 = 50/√2 m

Area of the circle = ∏r^{2}= 22/7 (50/√2)^{2}= 27500/7 m^{2}

Area of the wasteland = 27500/7 – 2500 = 10000/7 m^{2}

Area covered by maize = 11% of 2500 = 275 m^{2}Required difference = 10000/7 – 275 = 8075/7 m

^{2}= 1153.57 m^{2}(approx.)Incorrect**Answer- 2) 1153.57 m**^{2}

**Explanation-**length of the diagonal of the square = √2 × side = 50√2 m

Since the square is inside the square

Radius of the circle = 50√2/2 = 50/√2 m

Area of the circle = ∏r^{2}= 22/7 (50/√2)^{2}= 27500/7 m^{2}

Area of the wasteland = 27500/7 – 2500 = 10000/7 m^{2}

Area covered by maize = 11% of 2500 = 275 m^{2}Required difference = 10000/7 – 275 = 8075/7 m

^{2}= 1153.57 m^{2}(approx.) - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

**What is the ratio of area covered by wheat and to that of by onion?**Correct**Answer- 3) 3:1**Required ratio = 27:9 = 3:1

Explanation-Incorrect**Answer- 3) 3:1**Required ratio = 27:9 = 3:1

Explanation- - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6 and 7). The following questions are accompanied by two statements (l) and (ll). You have to determine which statement (s) is/are sufficient to answer the questions.****What is the difference between cost prize for B and the cost prize for D?**

(l) A sells the article to B at a profit of 20% and B sells it to C at a profit of 30%. C sells it to D for Rs 1092.

(ll) The ratio of cost prize for A to the cost prize for B is 5:6 and the ratio of cost prize for C to the cost prize for D is 5:7.Correct**Answer-4) Both (l) and (ll) together.**By using statement (l) alone we can’t calculate the difference because we don’t know the profit or loss percent for which C sold the article to D.

Explanation-

Also by using statement (ll) alone we can’t calculate the difference because we don’t know even single cost prize.

By using both statements together, we have,

Profit percent for which C sells the article to D = (7 – 5)/5 × 100 = 40%

Cost prize for C = 1092/140 × 100 = Rs 780

Cost prize for B = 780/130 × 100 = Rs 600

Required difference = 1092 – 600 = Rs 492Incorrect**Answer-4) Both (l) and (ll) together.**By using statement (l) alone we can’t calculate the difference because we don’t know the profit or loss percent for which C sold the article to D.

Explanation-

Also by using statement (ll) alone we can’t calculate the difference because we don’t know even single cost prize.

By using both statements together, we have,

Profit percent for which C sells the article to D = (7 – 5)/5 × 100 = 40%

Cost prize for C = 1092/140 × 100 = Rs 780

Cost prize for B = 780/130 × 100 = Rs 600

Required difference = 1092 – 600 = Rs 492 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6 and 7). The following questions are accompanied by two statements (l) and (ll). You have to determine which statement (s) is/are sufficient to answer the questions.****The floor of a room is in the form of a square with each side equal to 8m. What is the area of four walls of the room?**

(l) The total surface area of the room is 448 m2

(ll) The height of the room is 10 m.Correct**Answer- 2) Either (l) or (ll)**

**Explanation-**the perimeter of the floor = 4 × 8 = 32 m

By using statement (l),

Let the height of the room is h. Then,

Total surface area of the room = 32 × h + 2 × (8)^{2}= 448

By solving we have, h = 10 m

Area of four walls = perimeter × height = 32 × 10 = 320 m^{2}

By using statement (ll)

Height is already given. So we can easily calculate the area of walls by using this statement alone.Incorrect**Answer- 2) Either (l) or (ll)**

**Explanation-**the perimeter of the floor = 4 × 8 = 32 m

By using statement (l),

Let the height of the room is h. Then,

Total surface area of the room = 32 × h + 2 × (8)^{2}= 448

By solving we have, h = 10 m

Area of four walls = perimeter × height = 32 × 10 = 320 m^{2}

By using statement (ll)

Height is already given. So we can easily calculate the area of walls by using this statement alone. - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Compare the numerical values of the quantities given below and choose the correct option.****Quantity 1- No of days taken by B to complete the work. A and B together can complete the work in 16/3 days, B and C together can complete the work in 80/7 days and A and C together can complete the work in 20/3 days.****Quantity 2- Value of x if x**^{2}– 32x + 256 = 0Correct**Answer- 5) Quantity 1 = quantity 2**We have,

Explanation-

A + B = 15

B + C = 7

C + A = 12

By solving, we have, B = 5

No of days taken by B to complete the work = 80/5 = 16 days = quantity 1

We have, x^{2}– 32x + 256 = 0 or x^{2}– 16x – 16x + 256 = 0

Therefore, (x – 16)(x – 16) = 0,

So, x = 16 = quantity 2

Therefore, both the quantities are equal.Incorrect**Answer- 5) Quantity 1 = quantity 2**We have,

Explanation-

A + B = 15

B + C = 7

C + A = 12

By solving, we have, B = 5

No of days taken by B to complete the work = 80/5 = 16 days = quantity 1

We have, x^{2}– 32x + 256 = 0 or x^{2}– 16x – 16x + 256 = 0

Therefore, (x – 16)(x – 16) = 0,

So, x = 16 = quantity 2

Therefore, both the quantities are equal. - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**A car travels one third of the distance with a speed of 30 km/h, the next one third with a speed of 50 km/h and the last one third with a speed of 60 km/h. Average speed of the car for the whole journey is:**Correct**Answer- 2) 300/7 km/h**Average speed of the car = 3xyz/(xy + yz + xz) = 3 × 30 × 50 × 60/(30 × 50 + 50 × 60 + 60 × 30) = 270000/6300 = 300/7 km/h

Explanation-Incorrect**Answer- 2) 300/7 km/h**Average speed of the car = 3xyz/(xy + yz + xz) = 3 × 30 × 50 × 60/(30 × 50 + 50 × 60 + 60 × 30) = 270000/6300 = 300/7 km/h

Explanation- - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**The interest rate of a bank is 9% per annum compounded annually. A person deposits Rs 25000 in that bank. After how many years the deposit will become Rs 32375.725?**Correct**Answer- 2) 3 years**percentage increase in the deposit after 3 years = (32375.725 – 25000)/25000 × 100 = 737572.5/25000 = 29.5029 %

Explanation-

Since 9 × 3 = 27 and 29.5029 is little more than 27, 3 years is the only answer possible.Incorrect**Answer- 2) 3 years**percentage increase in the deposit after 3 years = (32375.725 – 25000)/25000 × 100 = 737572.5/25000 = 29.5029 %

Explanation-

Since 9 × 3 = 27 and 29.5029 is little more than 27, 3 years is the only answer possible.

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