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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Directions (Q1-5). A farmer harvests six types of crops and vegetables in a square field with side 50 m. The pie chart below shows the percentage area covered by each.

The area covered by Wheat is by what percent more than that of by Mustard?

Directions (Q1-5). A farmer harvests six types of crops and vegetables in a square field with side 50 m. The pie chart below shows the percentage area covered by each.

What is the difference between the area covered by potatoes and that of by onions?

Correct

Answer- 1) 350 m^{2} Explanation- Total area of the square field = (50)^{2} = 2500 m^{2}
Required difference = (23 – 9) % of 2500 = 14% of 2500 = 350 m^{2}

Incorrect

Answer- 1) 350 m^{2} Explanation- Total area of the square field = (50)^{2} = 2500 m^{2}
Required difference = (23 – 9) % of 2500 = 14% of 2500 = 350 m^{2}

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Directions (Q1-5). A farmer harvests six types of crops and vegetables in a square field with side 50 m. The pie chart below shows the percentage area covered by each.

What is the total area covered by wheat, maize and onions together?

Correct

Answer- 5) 1175 m^{2} Explanation- Total area covered by wheat, maize and onions together = (27 + 11 + 9) % of 2500 = 47% of 2500 = 1175 m^{2}

Incorrect

Answer- 5) 1175 m^{2} Explanation- Total area covered by wheat, maize and onions together = (27 + 11 + 9) % of 2500 = 47% of 2500 = 1175 m^{2}

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Directions (Q1-5). A farmer harvests six types of crops and vegetables in a square field with side 50 m. The pie chart below shows the percentage area covered by each.

Farmer’s land is in fact in the form of a circle and square is in the circle with each vertical on the circumference of the circle. The rest of the land is wasteland. The area of the wasteland is how much more than the area covered by maize?

Correct

Answer- 2) 1153.57 m^{2} Explanation- length of the diagonal of the square = √2 × side = 50√2 m
Since the square is inside the square
Radius of the circle = 50√2/2 = 50/√2 m
Area of the circle = ∏r^{2} = 22/7 (50/√2)^{2} = 27500/7 m^{2}
Area of the wasteland = 27500/7 – 2500 = 10000/7 m^{2}
Area covered by maize = 11% of 2500 = 275 m^{2}

Answer- 2) 1153.57 m^{2} Explanation- length of the diagonal of the square = √2 × side = 50√2 m
Since the square is inside the square
Radius of the circle = 50√2/2 = 50/√2 m
Area of the circle = ∏r^{2} = 22/7 (50/√2)^{2} = 27500/7 m^{2}
Area of the wasteland = 27500/7 – 2500 = 10000/7 m^{2}
Area covered by maize = 11% of 2500 = 275 m^{2}

Directions (Q1-5). A farmer harvests six types of crops and vegetables in a square field with side 50 m. The pie chart below shows the percentage area covered by each.

What is the ratio of area covered by wheat and to that of by onion?

Correct

Answer- 3) 3:1
Explanation- Required ratio = 27:9 = 3:1

Incorrect

Answer- 3) 3:1
Explanation- Required ratio = 27:9 = 3:1

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Directions (Q6 and 7). The following questions are accompanied by two statements (l) and (ll). You have to determine which statement (s) is/are sufficient to answer the questions.

What is the difference between cost prize for B and the cost prize for D?
(l) A sells the article to B at a profit of 20% and B sells it to C at a profit of 30%. C sells it to D for Rs 1092.
(ll) The ratio of cost prize for A to the cost prize for B is 5:6 and the ratio of cost prize for C to the cost prize for D is 5:7.

Correct

Answer-4) Both (l) and (ll) together.
Explanation- By using statement (l) alone we can’t calculate the difference because we don’t know the profit or loss percent for which C sold the article to D.
Also by using statement (ll) alone we can’t calculate the difference because we don’t know even single cost prize.
By using both statements together, we have,
Profit percent for which C sells the article to D = (7 – 5)/5 × 100 = 40%
Cost prize for C = 1092/140 × 100 = Rs 780
Cost prize for B = 780/130 × 100 = Rs 600
Required difference = 1092 – 600 = Rs 492

Incorrect

Answer-4) Both (l) and (ll) together.
Explanation- By using statement (l) alone we can’t calculate the difference because we don’t know the profit or loss percent for which C sold the article to D.
Also by using statement (ll) alone we can’t calculate the difference because we don’t know even single cost prize.
By using both statements together, we have,
Profit percent for which C sells the article to D = (7 – 5)/5 × 100 = 40%
Cost prize for C = 1092/140 × 100 = Rs 780
Cost prize for B = 780/130 × 100 = Rs 600
Required difference = 1092 – 600 = Rs 492

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Directions (Q6 and 7). The following questions are accompanied by two statements (l) and (ll). You have to determine which statement (s) is/are sufficient to answer the questions.

The floor of a room is in the form of a square with each side equal to 8m. What is the area of four walls of the room?
(l) The total surface area of the room is 448 m2
(ll) The height of the room is 10 m.

Correct

Answer- 2) Either (l) or (ll) Explanation- the perimeter of the floor = 4 × 8 = 32 m
By using statement (l),
Let the height of the room is h. Then,
Total surface area of the room = 32 × h + 2 × (8)^{2} = 448
By solving we have, h = 10 m
Area of four walls = perimeter × height = 32 × 10 = 320 m^{2}
By using statement (ll)
Height is already given. So we can easily calculate the area of walls by using this statement alone.

Incorrect

Answer- 2) Either (l) or (ll) Explanation- the perimeter of the floor = 4 × 8 = 32 m
By using statement (l),
Let the height of the room is h. Then,
Total surface area of the room = 32 × h + 2 × (8)^{2} = 448
By solving we have, h = 10 m
Area of four walls = perimeter × height = 32 × 10 = 320 m^{2}
By using statement (ll)
Height is already given. So we can easily calculate the area of walls by using this statement alone.

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Compare the numerical values of the quantities given below and choose the correct option.

Quantity 1- No of days taken by B to complete the work. A and B together can complete the work in 16/3 days, B and C together can complete the work in 80/7 days and A and C together can complete the work in 20/3 days.

Quantity 2- Value of x if x^{2} – 32x + 256 = 0

Correct

Answer- 5) Quantity 1 = quantity 2
Explanation- We have,

A + B = 15
B + C = 7
C + A = 12
By solving, we have, B = 5
No of days taken by B to complete the work = 80/5 = 16 days = quantity 1
We have, x^{2} – 32x + 256 = 0 or x^{2} – 16x – 16x + 256 = 0
Therefore, (x – 16)(x – 16) = 0,
So, x = 16 = quantity 2
Therefore, both the quantities are equal.

Incorrect

Answer- 5) Quantity 1 = quantity 2
Explanation- We have,

A + B = 15
B + C = 7
C + A = 12
By solving, we have, B = 5
No of days taken by B to complete the work = 80/5 = 16 days = quantity 1
We have, x^{2} – 32x + 256 = 0 or x^{2} – 16x – 16x + 256 = 0
Therefore, (x – 16)(x – 16) = 0,
So, x = 16 = quantity 2
Therefore, both the quantities are equal.

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

A car travels one third of the distance with a speed of 30 km/h, the next one third with a speed of 50 km/h and the last one third with a speed of 60 km/h. Average speed of the car for the whole journey is:

Correct

Answer- 2) 300/7 km/h
Explanation- Average speed of the car = 3xyz/(xy + yz + xz) = 3 × 30 × 50 × 60/(30 × 50 + 50 × 60 + 60 × 30) = 270000/6300 = 300/7 km/h

Incorrect

Answer- 2) 300/7 km/h
Explanation- Average speed of the car = 3xyz/(xy + yz + xz) = 3 × 30 × 50 × 60/(30 × 50 + 50 × 60 + 60 × 30) = 270000/6300 = 300/7 km/h

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

The interest rate of a bank is 9% per annum compounded annually. A person deposits Rs 25000 in that bank. After how many years the deposit will become Rs 32375.725?

Correct

Answer- 2) 3 years
Explanation- percentage increase in the deposit after 3 years = (32375.725 – 25000)/25000 × 100 = 737572.5/25000 = 29.5029 %
Since 9 × 3 = 27 and 29.5029 is little more than 27, 3 years is the only answer possible.

Incorrect

Answer- 2) 3 years
Explanation- percentage increase in the deposit after 3 years = (32375.725 – 25000)/25000 × 100 = 737572.5/25000 = 29.5029 %
Since 9 × 3 = 27 and 29.5029 is little more than 27, 3 years is the only answer possible.

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