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Question 1 of 10
1. Question
1 pointsCategory: Quantitative Aptitude16 girls can complete a project in ‘x’ days. 22 boys can complete the same project in (x+2) days. 12 girls can complete the same project in ‘y’ days and 18 boys can complete the same project in ‘y+1’ days. Find the value of ‘x’?
Correct
Answer: 3) 13
Explanation:
16 girls can complete the project in ‘x’ days
One girl can complete the project in 16x days
12 girls can complete the same project in ‘y’ days
One girl can complete the same project in 12y days
Since, the project is same
16x = 12 y
4x = 3y
y = 4x/3
22 boys can complete the same project in (x+2) days.
One boy can complete the same project in 22*(x+2) days
Also, 18 boys can complete the same project in (y+1) days
One boy can complete the same project in 18*(y+1) days
Again since the project is same
22*(x+2) = 18*(y+1)
11*(x+2) = 9*(y+1)
Now put y = 4x/3
11*(x+2) = 9*(4x/3 +1)
11x +22 = 12x + 9
x = 13Incorrect
Answer: 3) 13
Explanation:
16 girls can complete the project in ‘x’ days
One girl can complete the project in 16x days
12 girls can complete the same project in ‘y’ days
One girl can complete the same project in 12y days
Since, the project is same
16x = 12 y
4x = 3y
y = 4x/3
22 boys can complete the same project in (x+2) days.
One boy can complete the same project in 22*(x+2) days
Also, 18 boys can complete the same project in (y+1) days
One boy can complete the same project in 18*(y+1) days
Again since the project is same
22*(x+2) = 18*(y+1)
11*(x+2) = 9*(y+1)
Now put y = 4x/3
11*(x+2) = 9*(4x/3 +1)
11x +22 = 12x + 9
x = 13 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude30% of the males are above 40 years of age and 70% of the males are less than or equal to 60 years of age. 40% of all males play handball. If 40% of the males who are above the age of 60 play handball, what percent of players are less than or equal to 60 years?
Correct
Answer: 4) 70%
Explanation:
Let the number of males = 100x
Total players = 40% of 100x = 40x
Number of males less than or equal to 60 years of age = 70% of 100x = 70x
Number of males above the age of 60 years = 100x – 70x = 30x
Players above the age of 60 = 40% of 30x = 12x
Therefore, players equal to or below the age of 60 = (40x12x) = 28x
Required percentage = (28x/40x)*100 = 70%Incorrect
Answer: 4) 70%
Explanation:
Let the number of males = 100x
Total players = 40% of 100x = 40x
Number of males less than or equal to 60 years of age = 70% of 100x = 70x
Number of males above the age of 60 years = 100x – 70x = 30x
Players above the age of 60 = 40% of 30x = 12x
Therefore, players equal to or below the age of 60 = (40x12x) = 28x
Required percentage = (28x/40x)*100 = 70% 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA train crosses a pole in 40 sec. The second train of the same length crosses a platform in 60 sec with a speed 25% less than the first train. Find out the ratio of the length of the train and length of the platform.
Correct
Answer: 1) 8:1
Explanation:
Let the length of the trains = x meter
And length of the platform = p
Speed of first train = 10s
Speed of second train = 75% of 10s = 7.5s
For first train
(x/10s) = 40
For second train
(x+p)/7.5s = 60
(x+p)/7.5s = (3/2)*40 ……………(1)
Put (x/10s) = 40 In equation (1)
(x+p)/7.5s = (3/2)*(x/10s)
(x+p)/3 = (3/2)*(x/4)
(x+p)/3 = (3x/8)
8x+8p = 9x
8p = x
x/p = 8/1
x:p = 8:1Incorrect
Answer: 1) 8:1
Explanation:
Let the length of the trains = x meter
And length of the platform = p
Speed of first train = 10s
Speed of second train = 75% of 10s = 7.5s
For first train
(x/10s) = 40
For second train
(x+p)/7.5s = 60
(x+p)/7.5s = (3/2)*40 ……………(1)
Put (x/10s) = 40 In equation (1)
(x+p)/7.5s = (3/2)*(x/10s)
(x+p)/3 = (3/2)*(x/4)
(x+p)/3 = (3x/8)
8x+8p = 9x
8p = x
x/p = 8/1
x:p = 8:1 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeRavi went shopping to buy a shoe with some money. He selected a shoe, which is marked Rs. 600 higher price than the money he had. But shopkeeper gave two successive discounts of 5% and 10% respectively on the marked price of the shoe. Then he could buy that shoe and also another shoe worth Rs. 800 with all the money he had. Then what is the approximate marked price on the first shoe?
Correct
Answer: 1) Rs. 9655
Explanation:
Let Ravi had Rs. x
Let the marked price of the shoe is x + 600
Two successive discount
(5+10 – 5*10/100)
14.5%
ATQ,
x – (10014.5) % of (x+600) = 800
x – 85.5% of (x+600) = 800
x – (855/1000)*(x+600) = 800
1000x – 855x – 855*600 = 800000
145x – 513000 = 80000
x = 9055.17
Marked price on the shoe = 9055.17 + 600 = 9655 (approx)Incorrect
Answer: 1) Rs. 9655
Explanation:
Let Ravi had Rs. x
Let the marked price of the shoe is x + 600
Two successive discount
(5+10 – 5*10/100)
14.5%
ATQ,
x – (10014.5) % of (x+600) = 800
x – 85.5% of (x+600) = 800
x – (855/1000)*(x+600) = 800
1000x – 855x – 855*600 = 800000
145x – 513000 = 80000
x = 9055.17
Marked price on the shoe = 9055.17 + 600 = 9655 (approx) 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeRaja borrowed a sum of 3 lakh from Anand at the rate of 6% for 3 years. He then removed some more money from the borrowed sum and lent it to Suraj at the rate of 8% of simple interest for the same time. If Raja lost Rs. 5000 in the whole transaction, then what sum (approximate integer value) did he lend to Suraj?
Correct
Answer: 1) Rs. 204170
Explanation:
The amount Raja has to pay the Anand after 3 years
= 300000 + (6*3) % of 300000
= 300000 + 18 % of 300000
= 354000
Let the amount Raja removed from Rs. 300000 is Rs x
Amount lent to Suraj = (300000x)
Money received from Suraj
= (300000x) + (8*3) % of (300000x)
= (300000x) + (24) % of (300000x)
= (300000x) + (24/100) *(300000x)
= (300000x) + (72000 – 6x/25)
= (300000x) + (72000 – 6x/25)
= 372000 – 31x/25
And the removed money he has = Rs. x
ATQ,
354000 {(372000 – 31x/25) + x} = 5000
18000+ (31x/25)x = 5000
6x/25 = 23000
x = 95833.33
Amount lend to Suraj = (30000095833.33)
= 204166.67
= 204170 (approx)Incorrect
Answer: 1) Rs. 204170
Explanation:
The amount Raja has to pay the Anand after 3 years
= 300000 + (6*3) % of 300000
= 300000 + 18 % of 300000
= 354000
Let the amount Raja removed from Rs. 300000 is Rs x
Amount lent to Suraj = (300000x)
Money received from Suraj
= (300000x) + (8*3) % of (300000x)
= (300000x) + (24) % of (300000x)
= (300000x) + (24/100) *(300000x)
= (300000x) + (72000 – 6x/25)
= (300000x) + (72000 – 6x/25)
= 372000 – 31x/25
And the removed money he has = Rs. x
ATQ,
354000 {(372000 – 31x/25) + x} = 5000
18000+ (31x/25)x = 5000
6x/25 = 23000
x = 95833.33
Amount lend to Suraj = (30000095833.33)
= 204166.67
= 204170 (approx) 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Three friends Vicky, Kishan, and Meet are travelling by their boats in three different rivers in which the speeds of the streams are different. The downstream distances covered by Vicky, Kishan, and Meet are 240km, 180 km, and 300 km respectively, while the upstream distances covered by Vicky, Kishan and Meet are 90km, 120 km, and 200 km respectively. The speeds of the boat of Vicky, Kishan and Meet in still water were 10 km/hr, x km/hr and 6 km/h respectively. The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance. The ratio of the speed of the boat in still water for Vicky and speed of the stream for Kishan is 5:1 and the speed of stream for Vicky is 4 km/hr.
If the speed of stream for Kishan is half of the speed stream for Meet. Find the sum of time taken by Kishan and Meet to cover their upstream distances.
Correct
Answer: 4) 115 hours
Explanation:
The speed of stream for Kishan = 2 km/h
Speed of stream for Meet = 2*2 = 4 km/h
The upstream distance covered by Kishan = 120 km
The upstream distance covered by Meet = 200 km
Upstream speed of Kishan = (102) = 8 km/h
Upstream speed of Meet = (64) = 2 km/h
Sum of time taken = (120/8) + (200/2) = 15 + 100 = 115 hoursOverall Explanation:
The downstream distance covered by Vicky =240 km
The downstream distance covered by Kishan =180 km
The downstream distance covered by Meet =300 km
The upstream distance covered by Vickey = 90 km
The upstream distance covered by Kishan = 120 km
The upstream distance covered by Meet = 200 km
Speed in still water (Vicky) = 10 km/h
Speed in still water (Kishan) = x km/h
Speed in still water (Meet) = 6 km/h
ATQ,
Ratio of speed of boat in still water for Vicky and speed of the stream for Kishan is 5:1
Let the speed of stream for Kishan is sK
(10/sK) = 5/1
sK = 2 km/h
Also, the speed of stream for Vicky is 4 km/hr
Downstream speed of Kishan = (x+2)
Upstream speed of Vicky = (104) = 6km
Again, ATQ
The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance
{180/(x+2)} = 90/6
{180/(x+2)} = 15
x = 10 km/hIncorrect
Answer: 4) 115 hours
Explanation:
The speed of stream for Kishan = 2 km/h
Speed of stream for Meet = 2*2 = 4 km/h
The upstream distance covered by Kishan = 120 km
The upstream distance covered by Meet = 200 km
Upstream speed of Kishan = (102) = 8 km/h
Upstream speed of Meet = (64) = 2 km/h
Sum of time taken = (120/8) + (200/2) = 15 + 100 = 115 hoursOverall Explanation:
The downstream distance covered by Vicky =240 km
The downstream distance covered by Kishan =180 km
The downstream distance covered by Meet =300 km
The upstream distance covered by Vickey = 90 km
The upstream distance covered by Kishan = 120 km
The upstream distance covered by Meet = 200 km
Speed in still water (Vicky) = 10 km/h
Speed in still water (Kishan) = x km/h
Speed in still water (Meet) = 6 km/h
ATQ,
Ratio of speed of boat in still water for Vicky and speed of the stream for Kishan is 5:1
Let the speed of stream for Kishan is sK
(10/sK) = 5/1
sK = 2 km/h
Also, the speed of stream for Vicky is 4 km/hr
Downstream speed of Kishan = (x+2)
Upstream speed of Vicky = (104) = 6km
Again, ATQ
The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance
{180/(x+2)} = 90/6
{180/(x+2)} = 15
x = 10 km/h 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Three friends Vicky, Kishan, and Meet are travelling by their boats in three different rivers in which the speeds of the streams are different. The downstream distances covered by Vicky, Kishan, and Meet are 240km, 180 km, and 300 km respectively, while the upstream distances covered by Vicky, Kishan and Meet are 90km, 120 km, and 200 km respectively. The speeds of the boat of Vicky, Kishan and Meet in still water were 10 km/hr, x km/hr and 6 km/h respectively. The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance. The ratio of the speed of the boat in still water for Vicky and speed of the stream for Kishan is 5:1 and the speed of stream for Vicky is 4 km/hr.
Find the average of upstream speeds of the boat of Vicky, Kishan, and Meet. The speed of stream for everyone is 2 km/h.
Correct
Answer: 2) 20/3
Explanation:
Speed in still water (Vicky) = 10 km/h
Speed in still water (Kishan) = 10 km/h
Speed in still water (Meet) = 6 km/h
The speed of stream for everyone is 2 km/h.
Downstream speed are (102), (102) and (62)
Downstream speed are (8), (8) and (4)
Average of downstream speeds = (8+8+4)/3 = 20/3Incorrect
Answer: 2) 20/3
Explanation:
Speed in still water (Vicky) = 10 km/h
Speed in still water (Kishan) = 10 km/h
Speed in still water (Meet) = 6 km/h
The speed of stream for everyone is 2 km/h.
Downstream speed are (102), (102) and (62)
Downstream speed are (8), (8) and (4)
Average of downstream speeds = (8+8+4)/3 = 20/3 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Three friends Vicky, Kishan, and Meet are travelling by their boats in three different rivers in which the speeds of the streams are different. The downstream distances covered by Vicky, Kishan, and Meet are 240km, 180 km, and 300 km respectively, while the upstream distances covered by Vicky, Kishan and Meet are 90km, 120 km, and 200 km respectively. The speeds of the boat of Vicky, Kishan and Meet in still water were 10 km/hr, x km/hr and 6 km/h respectively. The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance. The ratio of the speed of the boat in still water for Vicky and speed of the stream for Kishan is 5:1 and the speed of stream for Vicky is 4 km/hr.
Find the sum of time taken by Vicky and Meet to cover their downstream distances. The speed of stream for Vicky is 100% of the speed of stream for Kishan and speed of stream for Meet is 200% of the speed of stream for Kishan.
Correct
Answer: 4) 50 hours
Explanation:
The downstream distance covered by Vicky =240 km
The downstream distance covered by Meet =300 km
The speed of stream for Vicky is 100% of speed of stream for Kishan and speed of stream for Meet is 200% of the speed of stream for Kishan.
The speed of stream for Kishan is 2 km/h
Speed of stream for Vicky = 100% of 2 = 2 km/h
Speed of stream for Meet = 200% of 2 = 4 km/h
Downstream speed of Vicky = (10+2) = 12 km/h
Downstream speed of Meet = (6+4) = 10
Total time taken = (240/12) + (300/10) = (20 + 30) hours = 50 hoursIncorrect
Answer: 4) 50 hours
Explanation:
The downstream distance covered by Vicky =240 km
The downstream distance covered by Meet =300 km
The speed of stream for Vicky is 100% of speed of stream for Kishan and speed of stream for Meet is 200% of the speed of stream for Kishan.
The speed of stream for Kishan is 2 km/h
Speed of stream for Vicky = 100% of 2 = 2 km/h
Speed of stream for Meet = 200% of 2 = 4 km/h
Downstream speed of Vicky = (10+2) = 12 km/h
Downstream speed of Meet = (6+4) = 10
Total time taken = (240/12) + (300/10) = (20 + 30) hours = 50 hours 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Three friends Vicky, Kishan, and Meet are travelling by their boats in three different rivers in which the speeds of the streams are different. The downstream distances covered by Vicky, Kishan, and Meet are 240km, 180 km, and 300 km respectively, while the upstream distances covered by Vicky, Kishan and Meet are 90km, 120 km, and 200 km respectively. The speeds of the boat of Vicky, Kishan and Meet in still water were 10 km/hr, x km/hr and 6 km/h respectively. The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance. The ratio of the speed of the boat in still water for Vicky and speed of the stream for Kishan is 5:1 and the speed of stream for Vicky is 4 km/hr.
Find the ratio of the upstream speed of Vicky to the downstream speed of Kishan?
Correct
Answer: 2) 1:2
Explanation:
The speed of stream for Vicky is 4 km/hr
Downstream speed of Kishan = (x+2) = 10+2 = 12 km/h
Upstream speed of Vicky = (104) = 6km
Required Ratio = (6/12) = (1/2) = 1:2Incorrect
Answer: 2) 1:2
Explanation:
The speed of stream for Vicky is 4 km/hr
Downstream speed of Kishan = (x+2) = 10+2 = 12 km/h
Upstream speed of Vicky = (104) = 6km
Required Ratio = (6/12) = (1/2) = 1:2 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections (610): Three friends Vicky, Kishan, and Meet are travelling by their boats in three different rivers in which the speeds of the streams are different. The downstream distances covered by Vicky, Kishan, and Meet are 240km, 180 km, and 300 km respectively, while the upstream distances covered by Vicky, Kishan and Meet are 90km, 120 km, and 200 km respectively. The speeds of the boat of Vicky, Kishan and Meet in still water were 10 km/hr, x km/hr and 6 km/h respectively. The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance. The ratio of the speed of the boat in still water for Vicky and speed of the stream for Kishan is 5:1 and the speed of stream for Vicky is 4 km/hr.
Find the difference in time taken by Kishan to cover Upstream distance and Downstream distance.
Correct
Answer: 5) 0 hour
Explanation:
The downstream distance covered by Kishan =180 km
The upstream distance covered by Kishan = 120 km
Speed in still water (Kishan) = 10 km/h
Downstream speed = (10 + 2) = 12km/h
Upstream speed = (102) = 8 km/h
Time taken in upstream = (120/8) = 15 hours
Time taken in Downstream = (180/12) = 15 hours
Required difference = (15 – 15) hours = 0 hoursIncorrect
Answer: 5) 0 hour
Explanation:
The downstream distance covered by Kishan =180 km
The upstream distance covered by Kishan = 120 km
Speed in still water (Kishan) = 10 km/h
Downstream speed = (10 + 2) = 12km/h
Upstream speed = (102) = 8 km/h
Time taken in upstream = (120/8) = 15 hours
Time taken in Downstream = (180/12) = 15 hours
Required difference = (15 – 15) hours = 0 hours
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