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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**16 girls can complete a project in ‘x’ days. 22 boys can complete the same project in (x+2) days. 12 girls can complete the same project in ‘y’ days and 18 boys can complete the same project in ‘y+1’ days. Find the value of ‘x’?**Correct**Answer: 3) 13**

Explanation:

16 girls can complete the project in ‘x’ days

One girl can complete the project in 16x days

12 girls can complete the same project in ‘y’ days

One girl can complete the same project in 12y days

Since, the project is same

16x = 12 y

4x = 3y

y = 4x/3

22 boys can complete the same project in (x+2) days.

One boy can complete the same project in 22*(x+2) days

Also, 18 boys can complete the same project in (y+1) days

One boy can complete the same project in 18*(y+1) days

Again since the project is same

22*(x+2) = 18*(y+1)

11*(x+2) = 9*(y+1)

Now put y = 4x/3

11*(x+2) = 9*(4x/3 +1)

11x +22 = 12x + 9

x = 13Incorrect**Answer: 3) 13**

Explanation:

16 girls can complete the project in ‘x’ days

One girl can complete the project in 16x days

12 girls can complete the same project in ‘y’ days

One girl can complete the same project in 12y days

Since, the project is same

16x = 12 y

4x = 3y

y = 4x/3

22 boys can complete the same project in (x+2) days.

One boy can complete the same project in 22*(x+2) days

Also, 18 boys can complete the same project in (y+1) days

One boy can complete the same project in 18*(y+1) days

Again since the project is same

22*(x+2) = 18*(y+1)

11*(x+2) = 9*(y+1)

Now put y = 4x/3

11*(x+2) = 9*(4x/3 +1)

11x +22 = 12x + 9

x = 13 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**30% of the males are above 40 years of age and 70% of the males are less than or equal to 60 years of age. 40% of all males play handball. If 40% of the males who are above the age of 60 play handball, what percent of players are less than or equal to 60 years?**Correct**Answer: 4) 70%**

Explanation:

Let the number of males = 100x

Total players = 40% of 100x = 40x

Number of males less than or equal to 60 years of age = 70% of 100x = 70x

Number of males above the age of 60 years = 100x – 70x = 30x

Players above the age of 60 = 40% of 30x = 12x

Therefore, players equal to or below the age of 60 = (40x-12x) = 28x

Required percentage = (28x/40x)*100 = 70%Incorrect**Answer: 4) 70%**

Explanation:

Let the number of males = 100x

Total players = 40% of 100x = 40x

Number of males less than or equal to 60 years of age = 70% of 100x = 70x

Number of males above the age of 60 years = 100x – 70x = 30x

Players above the age of 60 = 40% of 30x = 12x

Therefore, players equal to or below the age of 60 = (40x-12x) = 28x

Required percentage = (28x/40x)*100 = 70% - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**A train crosses a pole in 40 sec. The second train of the same length crosses a platform in 60 sec with a speed 25% less than the first train. Find out the ratio of the length of the train and length of the platform.**Correct**Answer: 1) 8:1**

Explanation:

Let the length of the trains = x meter

And length of the platform = p

Speed of first train = 10s

Speed of second train = 75% of 10s = 7.5s

For first train

(x/10s) = 40

For second train

(x+p)/7.5s = 60

(x+p)/7.5s = (3/2)*40 ……………(1)

Put (x/10s) = 40 In equation (1)

(x+p)/7.5s = (3/2)*(x/10s)

(x+p)/3 = (3/2)*(x/4)

(x+p)/3 = (3x/8)

8x+8p = 9x

8p = x

x/p = 8/1

x:p = 8:1Incorrect**Answer: 1) 8:1**

Explanation:

Let the length of the trains = x meter

And length of the platform = p

Speed of first train = 10s

Speed of second train = 75% of 10s = 7.5s

For first train

(x/10s) = 40

For second train

(x+p)/7.5s = 60

(x+p)/7.5s = (3/2)*40 ……………(1)

Put (x/10s) = 40 In equation (1)

(x+p)/7.5s = (3/2)*(x/10s)

(x+p)/3 = (3/2)*(x/4)

(x+p)/3 = (3x/8)

8x+8p = 9x

8p = x

x/p = 8/1

x:p = 8:1 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**Ravi went shopping to buy a shoe with some money. He selected a shoe, which is marked Rs. 600 higher price than the money he had. But shopkeeper gave two successive discounts of 5% and 10% respectively on the marked price of the shoe. Then he could buy that shoe and also another shoe worth Rs. 800 with all the money he had. Then what is the approximate marked price on the first shoe?**Correct**Answer: 1) Rs. 9655**

Explanation:

Let Ravi had Rs. x

Let the marked price of the shoe is x + 600

Two successive discount

(5+10 – 5*10/100)

14.5%

ATQ,

x – (100-14.5) % of (x+600) = 800

x – 85.5% of (x+600) = 800

x – (855/1000)*(x+600) = 800

1000x – 855x – 855*600 = 800000

145x – 513000 = 80000

x = 9055.17

Marked price on the shoe = 9055.17 + 600 = 9655 (approx)Incorrect**Answer: 1) Rs. 9655**

Explanation:

Let Ravi had Rs. x

Let the marked price of the shoe is x + 600

Two successive discount

(5+10 – 5*10/100)

14.5%

ATQ,

x – (100-14.5) % of (x+600) = 800

x – 85.5% of (x+600) = 800

x – (855/1000)*(x+600) = 800

1000x – 855x – 855*600 = 800000

145x – 513000 = 80000

x = 9055.17

Marked price on the shoe = 9055.17 + 600 = 9655 (approx) - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**Raja borrowed a sum of 3 lakh from Anand at the rate of 6% for 3 years. He then removed some more money from the borrowed sum and lent it to Suraj at the rate of 8% of simple interest for the same time. If Raja lost Rs. 5000 in the whole transaction, then what sum (approximate integer value) did he lend to Suraj?**Correct**Answer: 1) Rs. 204170**

Explanation:

The amount Raja has to pay the Anand after 3 years

= 300000 + (6*3) % of 300000

= 300000 + 18 % of 300000

= 354000

Let the amount Raja removed from Rs. 300000 is Rs x

Amount lent to Suraj = (300000-x)

Money received from Suraj

= (300000-x) + (8*3) % of (300000-x)

= (300000-x) + (24) % of (300000-x)

= (300000-x) + (24/100) *(300000-x)

= (300000-x) + (72000 – 6x/25)

= (300000-x) + (72000 – 6x/25)

= 372000 – 31x/25

And the removed money he has = Rs. x

ATQ,

354000- {(372000 – 31x/25) + x} = 5000

-18000+ (31x/25)-x = 5000

6x/25 = 23000

x = 95833.33

Amount lend to Suraj = (300000-95833.33)

= 204166.67

= 204170 (approx)Incorrect**Answer: 1) Rs. 204170**

Explanation:

The amount Raja has to pay the Anand after 3 years

= 300000 + (6*3) % of 300000

= 300000 + 18 % of 300000

= 354000

Let the amount Raja removed from Rs. 300000 is Rs x

Amount lent to Suraj = (300000-x)

Money received from Suraj

= (300000-x) + (8*3) % of (300000-x)

= (300000-x) + (24) % of (300000-x)

= (300000-x) + (24/100) *(300000-x)

= (300000-x) + (72000 – 6x/25)

= (300000-x) + (72000 – 6x/25)

= 372000 – 31x/25

And the removed money he has = Rs. x

ATQ,

354000- {(372000 – 31x/25) + x} = 5000

-18000+ (31x/25)-x = 5000

6x/25 = 23000

x = 95833.33

Amount lend to Suraj = (300000-95833.33)

= 204166.67

= 204170 (approx) - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10):**Three friends Vicky, Kishan, and Meet are travelling by their boats in three different rivers in which the speeds of the streams are different. The downstream distances covered by Vicky, Kishan, and Meet are 240km, 180 km, and 300 km respectively, while the upstream distances covered by Vicky, Kishan and Meet are 90km, 120 km, and 200 km respectively. The speeds of the boat of Vicky, Kishan and Meet in still water were 10 km/hr, x km/hr and 6 km/h respectively. The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance. The ratio of the speed of the boat in still water for Vicky and speed of the stream for Kishan is 5:1 and the speed of stream for Vicky is 4 km/hr.**If the speed of stream for Kishan is half of the speed stream for Meet. Find the sum of time taken by Kishan and Meet to cover their upstream distances.**Correct**Answer: 4) 115 hours**

Explanation:

The speed of stream for Kishan = 2 km/h

Speed of stream for Meet = 2*2 = 4 km/h

The upstream distance covered by Kishan = 120 km

The upstream distance covered by Meet = 200 km

Upstream speed of Kishan = (10-2) = 8 km/h

Upstream speed of Meet = (6-4) = 2 km/h

Sum of time taken = (120/8) + (200/2) = 15 + 100 = 115 hours**Overall Explanation:**

The downstream distance covered by Vicky =240 km

The downstream distance covered by Kishan =180 km

The downstream distance covered by Meet =300 km

The upstream distance covered by Vickey = 90 km

The upstream distance covered by Kishan = 120 km

The upstream distance covered by Meet = 200 km

Speed in still water (Vicky) = 10 km/h

Speed in still water (Kishan) = x km/h

Speed in still water (Meet) = 6 km/h

ATQ,

Ratio of speed of boat in still water for Vicky and speed of the stream for Kishan is 5:1

Let the speed of stream for Kishan is sK

(10/sK) = 5/1

sK = 2 km/h

Also, the speed of stream for Vicky is 4 km/hr

Downstream speed of Kishan = (x+2)

Upstream speed of Vicky = (10-4) = 6km

Again, ATQ

The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance

{180/(x+2)} = 90/6

{180/(x+2)} = 15

x = 10 km/hIncorrect**Answer: 4) 115 hours**

Explanation:

The speed of stream for Kishan = 2 km/h

Speed of stream for Meet = 2*2 = 4 km/h

The upstream distance covered by Kishan = 120 km

The upstream distance covered by Meet = 200 km

Upstream speed of Kishan = (10-2) = 8 km/h

Upstream speed of Meet = (6-4) = 2 km/h

Sum of time taken = (120/8) + (200/2) = 15 + 100 = 115 hours**Overall Explanation:**

The downstream distance covered by Vicky =240 km

The downstream distance covered by Kishan =180 km

The downstream distance covered by Meet =300 km

The upstream distance covered by Vickey = 90 km

The upstream distance covered by Kishan = 120 km

The upstream distance covered by Meet = 200 km

Speed in still water (Vicky) = 10 km/h

Speed in still water (Kishan) = x km/h

Speed in still water (Meet) = 6 km/h

ATQ,

Ratio of speed of boat in still water for Vicky and speed of the stream for Kishan is 5:1

Let the speed of stream for Kishan is sK

(10/sK) = 5/1

sK = 2 km/h

Also, the speed of stream for Vicky is 4 km/hr

Downstream speed of Kishan = (x+2)

Upstream speed of Vicky = (10-4) = 6km

Again, ATQ

The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance

{180/(x+2)} = 90/6

{180/(x+2)} = 15

x = 10 km/h - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10):**Three friends Vicky, Kishan, and Meet are travelling by their boats in three different rivers in which the speeds of the streams are different. The downstream distances covered by Vicky, Kishan, and Meet are 240km, 180 km, and 300 km respectively, while the upstream distances covered by Vicky, Kishan and Meet are 90km, 120 km, and 200 km respectively. The speeds of the boat of Vicky, Kishan and Meet in still water were 10 km/hr, x km/hr and 6 km/h respectively. The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance. The ratio of the speed of the boat in still water for Vicky and speed of the stream for Kishan is 5:1 and the speed of stream for Vicky is 4 km/hr.**Find the average of upstream speeds of the boat of Vicky, Kishan, and Meet. The speed of stream for everyone is 2 km/h.**Correct**Answer: 2) 20/3**

Explanation:

Speed in still water (Vicky) = 10 km/h

Speed in still water (Kishan) = 10 km/h

Speed in still water (Meet) = 6 km/h

The speed of stream for everyone is 2 km/h.

Downstream speed are (10-2), (10-2) and (6-2)

Downstream speed are (8), (8) and (4)

Average of downstream speeds = (8+8+4)/3 = 20/3Incorrect**Answer: 2) 20/3**

Explanation:

Speed in still water (Vicky) = 10 km/h

Speed in still water (Kishan) = 10 km/h

Speed in still water (Meet) = 6 km/h

The speed of stream for everyone is 2 km/h.

Downstream speed are (10-2), (10-2) and (6-2)

Downstream speed are (8), (8) and (4)

Average of downstream speeds = (8+8+4)/3 = 20/3 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10):**Three friends Vicky, Kishan, and Meet are travelling by their boats in three different rivers in which the speeds of the streams are different. The downstream distances covered by Vicky, Kishan, and Meet are 240km, 180 km, and 300 km respectively, while the upstream distances covered by Vicky, Kishan and Meet are 90km, 120 km, and 200 km respectively. The speeds of the boat of Vicky, Kishan and Meet in still water were 10 km/hr, x km/hr and 6 km/h respectively. The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance. The ratio of the speed of the boat in still water for Vicky and speed of the stream for Kishan is 5:1 and the speed of stream for Vicky is 4 km/hr.**Find the sum of time taken by Vicky and Meet to cover their downstream distances. The speed of stream for Vicky is 100% of the speed of stream for Kishan and speed of stream for Meet is 200% of the speed of stream for Kishan.**Correct**Answer: 4) 50 hours**

Explanation:

The downstream distance covered by Vicky =240 km

The downstream distance covered by Meet =300 km

The speed of stream for Vicky is 100% of speed of stream for Kishan and speed of stream for Meet is 200% of the speed of stream for Kishan.

The speed of stream for Kishan is 2 km/h

Speed of stream for Vicky = 100% of 2 = 2 km/h

Speed of stream for Meet = 200% of 2 = 4 km/h

Downstream speed of Vicky = (10+2) = 12 km/h

Downstream speed of Meet = (6+4) = 10

Total time taken = (240/12) + (300/10) = (20 + 30) hours = 50 hoursIncorrect**Answer: 4) 50 hours**

Explanation:

The downstream distance covered by Vicky =240 km

The downstream distance covered by Meet =300 km

The speed of stream for Vicky is 100% of speed of stream for Kishan and speed of stream for Meet is 200% of the speed of stream for Kishan.

The speed of stream for Kishan is 2 km/h

Speed of stream for Vicky = 100% of 2 = 2 km/h

Speed of stream for Meet = 200% of 2 = 4 km/h

Downstream speed of Vicky = (10+2) = 12 km/h

Downstream speed of Meet = (6+4) = 10

Total time taken = (240/12) + (300/10) = (20 + 30) hours = 50 hours - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10):**Three friends Vicky, Kishan, and Meet are travelling by their boats in three different rivers in which the speeds of the streams are different. The downstream distances covered by Vicky, Kishan, and Meet are 240km, 180 km, and 300 km respectively, while the upstream distances covered by Vicky, Kishan and Meet are 90km, 120 km, and 200 km respectively. The speeds of the boat of Vicky, Kishan and Meet in still water were 10 km/hr, x km/hr and 6 km/h respectively. The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance. The ratio of the speed of the boat in still water for Vicky and speed of the stream for Kishan is 5:1 and the speed of stream for Vicky is 4 km/hr.**Find the ratio of the upstream speed of Vicky to the downstream speed of Kishan?**Correct**Answer: 2) 1:2**

Explanation:

The speed of stream for Vicky is 4 km/hr

Downstream speed of Kishan = (x+2) = 10+2 = 12 km/h

Upstream speed of Vicky = (10-4) = 6km

Required Ratio = (6/12) = (1/2) = 1:2Incorrect**Answer: 2) 1:2**

Explanation:

The speed of stream for Vicky is 4 km/hr

Downstream speed of Kishan = (x+2) = 10+2 = 12 km/h

Upstream speed of Vicky = (10-4) = 6km

Required Ratio = (6/12) = (1/2) = 1:2 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10):**Three friends Vicky, Kishan, and Meet are travelling by their boats in three different rivers in which the speeds of the streams are different. The downstream distances covered by Vicky, Kishan, and Meet are 240km, 180 km, and 300 km respectively, while the upstream distances covered by Vicky, Kishan and Meet are 90km, 120 km, and 200 km respectively. The speeds of the boat of Vicky, Kishan and Meet in still water were 10 km/hr, x km/hr and 6 km/h respectively. The time taken by Kishan to cover the downstream distance is equal to the time taken by Vicky to cover the upstream distance. The ratio of the speed of the boat in still water for Vicky and speed of the stream for Kishan is 5:1 and the speed of stream for Vicky is 4 km/hr.**Find the difference in time taken by Kishan to cover Upstream distance and Downstream distance.**Correct**Answer: 5) 0 hour**

Explanation:

The downstream distance covered by Kishan =180 km

The upstream distance covered by Kishan = 120 km

Speed in still water (Kishan) = 10 km/h

Downstream speed = (10 + 2) = 12km/h

Upstream speed = (10-2) = 8 km/h

Time taken in upstream = (120/8) = 15 hours

Time taken in Downstream = (180/12) = 15 hours

Required difference = (15 – 15) hours = 0 hoursIncorrect**Answer: 5) 0 hour**

Explanation:

The downstream distance covered by Kishan =180 km

The upstream distance covered by Kishan = 120 km

Speed in still water (Kishan) = 10 km/h

Downstream speed = (10 + 2) = 12km/h

Upstream speed = (10-2) = 8 km/h

Time taken in upstream = (120/8) = 15 hours

Time taken in Downstream = (180/12) = 15 hours

Required difference = (15 – 15) hours = 0 hours

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