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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.15) Refer to the graph and answer the given questions
Data related to number of read complaints and unread complaints by 5 customer care executives(A, B, C, D and E) on Tuesday.
Note I: Number of received complaints = Number of read complaints + Number of unread complaints
Note II: No pending complaints from previous days to be considered for calculation. Data is related to number of complaints received on Tuesday Only.
The number of complaints read by B is what percent more than that read by D?Correct
Answer – 2. 32%
Explanation:
80/250 * 100 = 32%Incorrect
Answer – 2. 32%
Explanation:
80/250 * 100 = 32% 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.15) Refer to the graph and answer the given questions
Data related to number of read complaints and unread complaints by 5 customer care executives(A, B, C, D and E) on Tuesday.
Note I: Number of received complaints = Number of read complaints + Number of unread complaints
Note II: No pending complaints from previous days to be considered for calculation. Data is related to number of complaints received on Tuesday Only.
Out of the complaints read by B, 60% are from male customers, The number of unread complaints from female customers is 51 less than that of read complaints from female customers, what is the number of unread complaints from male customers?Correct
Answer – 5. 129
Explanation:
Complaints read by B = 330
Read complaints from female customers = 40% of 330 = 132
Unread complaints from female customers = 132 51 = 81
The number of unread complaints from male customers = 210 – 89 = 129Incorrect
Answer – 5. 129
Explanation:
Complaints read by B = 330
Read complaints from female customers = 40% of 330 = 132
Unread complaints from female customers = 132 51 = 81
The number of unread complaints from male customers = 210 – 89 = 129 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.15) Refer to the graph and answer the given questions
Data related to number of read complaints and unread complaints by 5 customer care executives(A, B, C, D and E) on Tuesday.
Note I: Number of received complaints = Number of read complaints + Number of unread complaints
Note II: No pending complaints from previous days to be considered for calculation. Data is related to number of complaints received on Tuesday Only.
Percentage of read complaints(out of received complaints each of them) were equal for A and G. If the number of complaints received by G is 360, how many complaints were unread by G?Correct
Answer – 2. 225
Explanation:
For A and G: Percentage of read complaints(out of received complaints)
Required % = 180/480 * 100 = 75/2
Read Complaints – x
[Read Complaints/Received Complaints] * 100 = 75/2
[x/360] * 100 = 75/2
x = 135
Unread complaints = 360 – 135 = 225Incorrect
Answer – 2. 225
Explanation:
For A and G: Percentage of read complaints(out of received complaints)
Required % = 180/480 * 100 = 75/2
Read Complaints – x
[Read Complaints/Received Complaints] * 100 = 75/2
[x/360] * 100 = 75/2
x = 135
Unread complaints = 360 – 135 = 225 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.15) Refer to the graph and answer the given questions
Data related to number of read complaints and unread complaints by 5 customer care executives(A, B, C, D and E) on Tuesday.
Note I: Number of received complaints = Number of read complaints + Number of unread complaints
Note II: No pending complaints from previous days to be considered for calculation. Data is related to number of complaints received on Tuesday Only.
What is the average number of all complaints(read complaints + unread complaints) by all the customer care executives?Correct
Answer – 3. 476
Explanation:
Sum of complaints by all the customer care executives = [480 + 540 + 300 + 640 + 420] = 2380
Average = 2380/5 = 476Incorrect
Answer – 3. 476
Explanation:
Sum of complaints by all the customer care executives = [480 + 540 + 300 + 640 + 420] = 2380
Average = 2380/5 = 476 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.15) Refer to the graph and answer the given questions
Data related to number of read complaints and unread complaints by 5 customer care executives(A, B, C, D and E) on Tuesday.
Note I: Number of received complaints = Number of read complaints + Number of unread complaints
Note II: No pending complaints from previous days to be considered for calculation. Data is related to number of complaints received on Tuesday Only.
If the number of complaints received by F was 38% more than that by C and number of complaints read by F was 25% more than that unread by him, how many complaints were read by F?Correct
Answer – 1. 230
Explanation:
138/100 * 300 = 414
From options, If we choose 230 then
414 – 230 = 184
184*125/100 = 230Incorrect
Answer – 1. 230
Explanation:
138/100 * 300 = 414
From options, If we choose 230 then
414 – 230 = 184
184*125/100 = 230 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeOut of his monthly salary, Ramesh invested 30% in Chit funds. From his remaining salary, he paid 20% towards EMI and the respective ratio between the expenses towards EMI, food and shopping was 7 : 12 : 8. If Ramesh was left with Rs 4800. What was his monthly salary?(in Rs)
Correct
Answer – 4. 30000
Explanation:
Let Ramesh’s monthly salary be Rs 100
Investment in Chit fund = Rs 30
Expenditure on EMI = (70 *20)/100= Rs 14
Expenditure on food = Rs 24
Expenditure on shopping =Rs 16
Savings = 100(30+14+24+16) =Rs (10084)= Rs 16
When saving is Rs 16, monthly salary = Rs 100
When savings is Rs 4800, monthly salary = Rs (100*4800)/16= Rs 30000Incorrect
Answer – 4. 30000
Explanation:
Let Ramesh’s monthly salary be Rs 100
Investment in Chit fund = Rs 30
Expenditure on EMI = (70 *20)/100= Rs 14
Expenditure on food = Rs 24
Expenditure on shopping =Rs 16
Savings = 100(30+14+24+16) =Rs (10084)= Rs 16
When saving is Rs 16, monthly salary = Rs 100
When savings is Rs 4800, monthly salary = Rs (100*4800)/16= Rs 30000 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeA watercraft travels 65 km downstream in 6 hours 30 minutes when it is travelling in a stream (X1). If this watercraft travels in another stream (X2) whose speed is 10% more than that of (X1). It covers 58 km upstream in 10 hours. What is the speed of (X2)?(in kmph)(assume the watercraft’s speed in still water in both streams remains the same)
Correct
Answer – 1. 2.2 kmph
Explanation:
Speed of current (X1) = b kmph
Speed of watercraft in still water = a kmph
Rate downstream = a+b= 65/(13/2) =10kmph
Speed of current (X2)=11b/10 kmph
Rate of upstream = a – 11b/10=5.8 kmph
b = 2 kmph
Speed of current (X2) = (11*2)/10 = 2.2 kmphIncorrect
Answer – 1. 2.2 kmph
Explanation:
Speed of current (X1) = b kmph
Speed of watercraft in still water = a kmph
Rate downstream = a+b= 65/(13/2) =10kmph
Speed of current (X2)=11b/10 kmph
Rate of upstream = a – 11b/10=5.8 kmph
b = 2 kmph
Speed of current (X2) = (11*2)/10 = 2.2 kmph 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.810) Find out the wrong number in the series
106, 107, 162, 326, 817, 2455.5
Correct
Answer – 4. 817
Explanation :
106 * 1 + 1 = 107
107 * 1.5 + 1.5= 162
162 * 2 + 2 = 326
326 * 2.5 + 2.5 = 817.5
817.5 * 3 + 3 = 2455.5Incorrect
Answer – 4. 817
Explanation :
106 * 1 + 1 = 107
107 * 1.5 + 1.5= 162
162 * 2 + 2 = 326
326 * 2.5 + 2.5 = 817.5
817.5 * 3 + 3 = 2455.5 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.810) Find out the wrong number in the series
102, 104, 160, 326, 823, 2439
Correct
Answer – 5.2439
Explanation :
102 * 1 + 2 = 104
104* 1.5 + 4 = 160
160 * 2 + 6 = 326
326 * 2.5 + 8 = 823
823 * 3 + 10 = 2479Incorrect
Answer – 5.2439
Explanation :
102 * 1 + 2 = 104
104* 1.5 + 4 = 160
160 * 2 + 6 = 326
326 * 2.5 + 8 = 823
823 * 3 + 10 = 2479 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.810) Find out the wrong number in the series113, 112, 120, 145, 217, 332
113, 112, 120, 145, 217, 332
Correct
Answer – 3.120
Explanation :
113 + 1³ – 2 = 112
112 + 2³ + 4 = 124
124 + 3³ – 6 = 145
145 + 4³ + 8 = 217
217 + 5³ – 10 =332Incorrect
Answer – 3.120
Explanation :
113 + 1³ – 2 = 112
112 + 2³ + 4 = 124
124 + 3³ – 6 = 145
145 + 4³ + 8 = 217
217 + 5³ – 10 =332
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