# SBI PO 2018 Main Exam: Quants Test Day 2

Hello Aspirants

Welcome to Online **Quants Test** in AffairsCloud.com. We are starting **Cumulus Course for SBI PO 2018 Main Exam** and we are creating sample questions in Quants section, this type of Question will be asked in SBI PO 2018!!!

**Click Here to View Cumulus Course : SBI PO 2018 Main Exam**

**SBI PO 2018 Main Exam: Reasoning Test**– 7.30 PM Every Day

**SBI PO 2018 Main Exam: Quants Test**– 8.30 PM Every Day

**SBI PO 2018 Main Exam: English Test**– 9.30 PM Every Day

**Help:- **Share Our Cumulus Course for SBI PO 2018 Exam Course page to your Friends & FB Groups

________________________

#### Quiz-summary

0 of 10 questions completed

Questions:

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10

#### Information

All the Best

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

#### Results

0 of 10 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

#### Categories

- Quantitative Aptitude 0%

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10

- Answered
- Review

- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions for question (1 – 5): Study the following table to answer the questions that follow. Some values are missing. Study the table carefully and answer the questions based on data in table and particular questions.**

Distance upstream = Distance downstream (if not stated)

Total time taken = Downstream time + Upstream time

**On 1st day, if difference between the time taken by the boat to go upstream and the time taken by the boat to go downstream is 20 hours, find the total time taken by the boat to go upstream and downstream.**CorrectAnswer :

**3. 60**

Explanation-

Given: 320/(a-4) – 320/(a+4) = 20

Solve, a = 12 km/hr = speed of boat

So total time = 320/(12-4) + 320/(12+4) = 40 + 20 = 60 hoursIncorrectAnswer :

**3. 60**

Explanation-

Given: 320/(a-4) – 320/(a+4) = 20

Solve, a = 12 km/hr = speed of boat

So total time = 320/(12-4) + 320/(12+4) = 40 + 20 = 60 hours - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions for question (1 – 5): Study the following table to answer the questions that follow. Some values are missing. Study the table carefully and answer the questions based on data in table and particular questions.**

Distance upstream = Distance downstream (if not stated)

Total time taken = Downstream time + Upstream time

**On 2nd day, if difference between the time taken by the boat to go upstream and the time taken by the boat to go downstream is 45 hours, find the total distance covered by the boat to go upstream and downstream. Downstream speed is 24 km/hr.**CorrectAnswer :

**4. 720**

Explanation-

Let downstream x and upstream y

x+y=75

x-y=45

solving x=15 and y=60, ‘APQ’ DOWN DISTANCE = UP DISTANCE

15*24(SPEED)=360*2=720IncorrectAnswer :

**4. 720**

Explanation-

Let downstream x and upstream y

x+y=75

x-y=45

solving x=15 and y=60, ‘APQ’ DOWN DISTANCE = UP DISTANCE

15*24(SPEED)=360*2=720 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions for question (1 – 5): Study the following table to answer the questions that follow. Some values are missing. Study the table carefully and answer the questions based on data in table and particular questions.**

Distance upstream = Distance downstream (if not stated)

Total time taken = Downstream time + Upstream time

**On 3rd day, if the boat covered half distance upstream with usual speed and other half with double its speed, then it takes 33 3/4 hours less time than usual time to go upstream. Find the total time taken by the boat to go upstream and downstream.**CorrectAnswer :

**2. 108**

Explanation-

Let speed of boat = a km/hr

So 270/(a-6) – [135/(a-6) + 135/(2a-6)] = 33.75

270/(a-6) – 135/(a-6) – 135/(2a-6) = 33.75

135/(a-6) – 135/(2a-6) = 33.75

1/(a-6) – 1/(2a-6) = 1/4

Solve, a = 9 and 2

Speed of stream = 6 km/hr, so speed of boat = 9 km/hr (speed of boat remains greater than speed of stream) So total time = 270/(9-6) + 270/(9+6) = 90 + 18 = 108 hoursIncorrectAnswer :

**2. 108**

Explanation-

Let speed of boat = a km/hr

So 270/(a-6) – [135/(a-6) + 135/(2a-6)] = 33.75

270/(a-6) – 135/(a-6) – 135/(2a-6) = 33.75

135/(a-6) – 135/(2a-6) = 33.75

1/(a-6) – 1/(2a-6) = 1/4

Solve, a = 9 and 2

Speed of stream = 6 km/hr, so speed of boat = 9 km/hr (speed of boat remains greater than speed of stream) So total time = 270/(9-6) + 270/(9+6) = 90 + 18 = 108 hours - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

Distance upstream = Distance downstream (if not stated)

Total time taken = Downstream time + Upstream time

**On 4th day, difference between time taken by the boat to cover ‘X’ km upstream and (X+120) km downstream is 26 hours. Had the boat covered same distance upstream as downstream, what would be the difference in time taken then?**CorrectAnswer :

**4. 56**

Explanation-

Downstream speed = 11+7 = 18 km/hr

Upstream speed = 11-7 = 4 km/hr

X/4 – (X+120)/18 = 26

Solve, X = 168 km = Upstream distance

Downstream distance = 168+120 = 288 km

Required time now = 288/4 – 288/18 = 56 hoursIncorrectAnswer :

**4. 56**

Explanation-

Downstream speed = 11+7 = 18 km/hr

Upstream speed = 11-7 = 4 km/hr

X/4 – (X+120)/18 = 26

Solve, X = 168 km = Upstream distance

Downstream distance = 168+120 = 288 km

Required time now = 288/4 – 288/18 = 56 hours - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

Distance upstream = Distance downstream (if not stated)

Total time taken = Downstream time + Upstream time

**On 5th day, if ratio of speed of boat to speed of stream is 2 : 1, what is the difference between the time taken by the boat to go upstream and the time taken by the boat to go downstream?**CorrectAnswer :

**1. 36 hours**

Explanation-

Speeds = 2a, a

So 324/(2a+a) + 324/(2a-a) = 72

Solve, a = 6.So speed of stream is 6 km/hr and speed of boat is 12 km/hr

So difference in time = 324/(12-6) – 324/(12+6) = 54 – 18 = 36 hoursIncorrectAnswer :

**1. 36 hours**

Explanation-

Speeds = 2a, a

So 324/(2a+a) + 324/(2a-a) = 72

Solve, a = 6.So speed of stream is 6 km/hr and speed of boat is 12 km/hr

So difference in time = 324/(12-6) – 324/(12+6) = 54 – 18 = 36 hours - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Q. (6-10) Study the following table and answer the questions given below it. Production of different types of Scooters in a company (in thousands)**

**In which of the following pairs of years was the total production of E-type scooter two lakhs?**CorrectAnswer :

**5. None of these**

Explanation-

By checking all optionIncorrectAnswer :

**5. None of these**

Explanation-

By checking all option - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Q. (6-10) Study the following table and answer the questions given below it. Production of different types of Scooters in a company (in thousands)**

**In which of the given years the total production of all types of scooters was minimum?**CorrectAnswer :

**1. 1994**

ExplanationIn 1992 = 180 +60 +84 + 100 +76=500

In 1993 = 210+90+32+80+48= 460

In 1994 = 135+30+44+95+85=389

In 1995 = 190+85+69+125+115= 584

In 1996 = 260+95+120+ 80+120 = 605

In 1997 = 240+140+161+90+185 = 816

So, the year 1994 has the minimum number of ProductionIncorrectAnswer :

**1. 1994**

ExplanationIn 1992 = 180 +60 +84 + 100 +76=500

In 1993 = 210+90+32+80+48= 460

In 1994 = 135+30+44+95+85=389

In 1995 = 190+85+69+125+115= 584

In 1996 = 260+95+120+ 80+120 = 605

In 1997 = 240+140+161+90+185 = 816

So, the year 1994 has the minimum number of Production - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Q. (6-10) Study the following table and answer the questions given below it. Production of different types of Scooters in a company (in thousands)**

**In which of the given years was the production of B-type scooter close to its average production over given years?**CorrectAnswer :

**1. 1995**

Explanation

Average Production of Scooter ‘B’=60+90+30+85+95+140 = 500/6=83.3

Average value is 83.3 is close to year 1995IncorrectAnswer :

**1. 1995**

Explanation

Average Production of Scooter ‘B’=60+90+30+85+95+140 = 500/6=83.3

Average value is 83.3 is close to year 1995 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude

**In which year the production of D-type scooters was maximum?**CorrectAnswer :

**3. 1995**

Explanation

D type scooter Production in the year 1992 = 100

D type scooter production in the year 1993 = 80

D type scooter production in the year 1994 = 95

D type scooter production in the year 1995 = 125

D type scooter production in the year 1996 = 80

D type scooter production in the year 1997 = 90

Year 1995 has the maximum number of productionIncorrectAnswer :

**3. 1995**

Explanation

D type scooter Production in the year 1992 = 100

D type scooter production in the year 1993 = 80

D type scooter production in the year 1994 = 95

D type scooter production in the year 1995 = 125

D type scooter production in the year 1996 = 80

D type scooter production in the year 1997 = 90

Year 1995 has the maximum number of production - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude

**What was the average production of A-type scooter in all the years?**CorrectAnswer :

**1. 202.5**

Explanation

Total Production of Scooter A in all the year = 180+210+135+190+260+240= 1215

Average Production of scooter A = 1215/6= 202.5IncorrectAnswer :

**1. 202.5**

Explanation

Total Production of Scooter A in all the year = 180+210+135+190+260+240= 1215

Average Production of scooter A = 1215/6= 202.5

**Click view Questions button to view Explanation****Note:-**We are providing unique questions for you to practice well, have a try !!- Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
- If you find any mistake, please tell us in the comment section.