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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA and B can complete a work in 7 days and 8 days respectively. They undertook to do a job for Rs 1400. Now with the help of C they did in 3 days. What will C get as his share?
Correct
Explanation:
1/7 + 1/8 + 1/x = 1/3
So x = 168/11 days, C can do in 168/11 days
So money will be shared in ratio 1/7 : 1/8 : 11/168 = 24 : 21 : 11
So C wil get = 11/56 * 1400Incorrect
Explanation:
1/7 + 1/8 + 1/x = 1/3
So x = 168/11 days, C can do in 168/11 days
So money will be shared in ratio 1/7 : 1/8 : 11/168 = 24 : 21 : 11
So C wil get = 11/56 * 1400 -
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeStation A and B are 160 km apart. First train started from A at 7 AM at speed of 50 km/hr. Second train started from B at 8 AM at speed of 60 km/hr. At what time will both meet?
Correct
Explanation:
After 1 hr, i.e at 8 AM, first train has covered 50 km
So now distance between both trains = 160-50 = 110km
So time of meeting will be 8 AM + 110/(50+60) = 8 AM + 1hr = 9AMIncorrect
Explanation:
After 1 hr, i.e at 8 AM, first train has covered 50 km
So now distance between both trains = 160-50 = 110km
So time of meeting will be 8 AM + 110/(50+60) = 8 AM + 1hr = 9AM -
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA circle of area equal to 9ᴨ cm sq. is inscribed in a square. What will be the area of square?
Correct
Explanation:
r2 = 9ᴨ
so r = 3 cm
so diameter = 6 cm = side of square
so area of square = 6*6Incorrect
Explanation:
r2 = 9ᴨ
so r = 3 cm
so diameter = 6 cm = side of square
so area of square = 6*6 -
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeWhat must be added to 1/x to make it equal to x?
Correct
Explanation:
Let y must be added to 1/x
So y + (1/x) = x
So y = x – 1/x = (x^2-1)/xIncorrect
Explanation:
Let y must be added to 1/x
So y + (1/x) = x
So y = x – 1/x = (x^2-1)/x -
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeSelling price of an article is set at Rs 27,500. If it was sold at 10% less, then also there would have a profit of 10%. What is the actual cost price of the article?
Correct
Explanation:
SP = (90/100)*27500 = 24750
So CP = (100/110)* 24750Incorrect
Explanation:
SP = (90/100)*27500 = 24750
So CP = (100/110)* 24750 -
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA and B invested Rs 400 and Rs 550. After 4 months, A added Rs 200 and B withdrawn Rs 100. If after a year a total profit of Rs 3050 is made, what is the share of A in the profit?
Correct
Explanation:
400*4 + 600*8 : 550*4 + 450*8
32 : 29
So A’s profit = 32/61 * 3,050 = 1600Incorrect
Explanation:
400*4 + 600*8 : 550*4 + 450*8
32 : 29
So A’s profit = 32/61 * 3,050 = 1600 -
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThere are 900 boys and 800 girls in a school. 60% of the boys and 80% of the girls passed in an examination. What is the approximate percentage of students who did not pass that exam?
Correct
Explanation:
Boys who dint pass = (40/100)*900 = 360
Girls who dint pass = (20/100)*800 = 160
Total who dint pass = 360+160 = 520 out of total 900+800 = 1700 students
So required % = (520/1700)*100Incorrect
Explanation:
Boys who dint pass = (40/100)*900 = 360
Girls who dint pass = (20/100)*800 = 160
Total who dint pass = 360+160 = 520 out of total 900+800 = 1700 students
So required % = (520/1700)*100 -
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeIn 2014, number of students in a school increased by 20% than the previous year. If the number of students in 2013 and 2015 are equal, what is the percentage decrease in the number of students in 2015 than the previous year?
Correct
Explanation:
Shortcut:
There is increase of 20%, and now we have to make again the same value as before increase, so (20/(100+20)] * 100 = 20/120 * 100 = 50/3%
OR
In 2013 = x, in 2014 = (120/100)*x = 6x/5
In 2015 = x
So percentage decrease in 2015 = [(6x/5 – x)/ (6x/5)] * 100 = 50/3%Incorrect
Explanation:
Shortcut:
There is increase of 20%, and now we have to make again the same value as before increase, so (20/(100+20)] * 100 = 20/120 * 100 = 50/3%
OR
In 2013 = x, in 2014 = (120/100)*x = 6x/5
In 2015 = x
So percentage decrease in 2015 = [(6x/5 – x)/ (6x/5)] * 100 = 50/3% -
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeThe cost of material is divides in its raw materials, labour cost and transportation in the ratio 3 : 6 : 4. If the labour cost on the making of material was Rs 4800, what is the cost of material?
Correct
Explanation:
3 : 6 : 4
So 6/(3+6+4) * x = 4800
So, x = 10400Incorrect
Explanation:
3 : 6 : 4
So 6/(3+6+4) * x = 4800
So, x = 10400 -
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeIf 3x + 5y = 35 and 5x + 2y = 33, then 4x + 7y equals
Correct
Explanation:
Solve 3x + 5y = 35 and 5x + 2y = 33 gives, x = 5, y = 4
So 4x + 7y = 4*5 + 7*4Incorrect
Explanation:
Solve 3x + 5y = 35 and 5x + 2y = 33 gives, x = 5, y = 4
So 4x + 7y = 4*5 + 7*4
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