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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA can complete 3/5th of a piece of work in 12 days and B can complete 2/3rd of the same work in 20 days. If both A and B work together, they can do 1/6th of that work in how many days?
Correct
Explanation:
A can do 3/5th of the work in 12 days, so whole work in 5/3 * 12 = 20 days.
B can do 2/3th of the work in 20 days, so whole work in 3/2 * 20 = 30 days.
A and B together can complete whole work in 20*30/(20+30) = 12 days.
So 1/6th work in 1/6 * 12 = 2 daysIncorrect
Explanation:
A can do 3/5th of the work in 12 days, so whole work in 5/3 * 12 = 20 days.
B can do 2/3th of the work in 20 days, so whole work in 3/2 * 20 = 30 days.
A and B together can complete whole work in 20*30/(20+30) = 12 days.
So 1/6th work in 1/6 * 12 = 2 days 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeA person invested Rs 1,600 with rate of interest at 10% pa. Find the total interest earned at the end of two years if for the first year the interest was compounded half yearly and for the second year it was compounded yearly?
Correct
Explanation:
For 1st year – time = 2, r% = 10/2 = 5%.
So Amount after 1st year = 1,600 [(1+5/100)]^{2} = Rs 1764
Amount after 2nd year = 1,764 [(1+10/100)]^{1} = Rs 1940.4
So CI = 1940.0 – 1600Incorrect
Explanation:
For 1st year – time = 2, r% = 10/2 = 5%.
So Amount after 1st year = 1,600 [(1+5/100)]^{2} = Rs 1764
Amount after 2nd year = 1,764 [(1+10/100)]^{1} = Rs 1940.4
So CI = 1940.0 – 1600 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA and B started a business by investing Rs 1200 and Rs 1500 respectively. After 4 months, A added Rs 200 an B added Rs 100 to their investments for 8 and 6 months respectively. After a year from the start of business, they got a total profit of Rs 11,850. What is the share of A in the profit?
Correct
Explanation:
A : B
1200*4 + 1400*8 : 1500*4 + 1600*6
12*4 + 14*8 : 15*4 + 16*6
12 + 14*2 : 15 + 8*3
40 : 39
So A got 40/79 * 11850 = 6000Incorrect
Explanation:
A : B
1200*4 + 1400*8 : 1500*4 + 1600*6
12*4 + 14*8 : 15*4 + 16*6
12 + 14*2 : 15 + 8*3
40 : 39
So A got 40/79 * 11850 = 6000 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeThe amount that A and B earns is in the ratio 6 : 5. After a year there is an equal percentage increase in their incomes and the difference in their incomes become Rs 14300. If difference in the old income of A and new income of B is Rs 6500, what is the % increase in incomes?
Correct
Explanation:
6x and 5x
Suppose, y% increased
So (100+y)/100 * 6x – (100+y)/100 *5x = 14300
This gives (100+y)*x = 14,30,000
Now also given
6x – [(100+y)/100 * 5x] = 6500
Solve, x(20y) = 1,30,000
Divide both equations
(100+y)/(20y) = 11
Solve, y = 10Incorrect
Explanation:
6x and 5x
Suppose, y% increased
So (100+y)/100 * 6x – (100+y)/100 *5x = 14300
This gives (100+y)*x = 14,30,000
Now also given
6x – [(100+y)/100 * 5x] = 6500
Solve, x(20y) = 1,30,000
Divide both equations
(100+y)/(20y) = 11
Solve, y = 10 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeThere is a loss of 10% on an article when it is sold at 3/5 of its Marked Price. How much percent less is Cost Price than Marked Price?
Correct
Explanation:
Let MP = x
Then SP = 3/5 * x = 3x/5
Loss is 10%, so CP = [100/(10010)] * 3x/5 = 2x/3
So required % = [(x – 2x/3)/(x)] * 100Incorrect
Explanation:
Let MP = x
Then SP = 3/5 * x = 3x/5
Loss is 10%, so CP = [100/(10010)] * 3x/5 = 2x/3
So required % = [(x – 2x/3)/(x)] * 100 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe sum of the ages of A and B is 45 yrs. Also 4 yrs ago, the B’s age was 11 less than twice the age of A that time. What is the present age of the A?
Correct
Explanation:
A+B = 45
(B4) = 2(A4) – 11
Solve both equations, A = 20Incorrect
Explanation:
A+B = 45
(B4) = 2(A4) – 11
Solve both equations, A = 20 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeA sum became thrice when invested for 4 years at simple interest, how many times will it become in 7 years?
Correct
Explanation:
Amount is thrice of principal, so interest is 2P
So 2P = P*r*4/100
Solve, r = 50%
So in 7 yrs interest = P*50*7/100 = 3.5P, so amount = P+ 3.5P = 4.5PIncorrect
Explanation:
Amount is thrice of principal, so interest is 2P
So 2P = P*r*4/100
Solve, r = 50%
So in 7 yrs interest = P*50*7/100 = 3.5P, so amount = P+ 3.5P = 4.5P 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDistance between point P and Q is 240 km. A train starts from point P at 6:00 AM with 60 km/hr towards Q. Another train starts from point Q towards P at 7:00 AM with 30 km/kr. At what time the trains will meet?
Correct
Explanation:
When 2nd train starts i.e. at 7 AM (1 hr after 6 AM), distance covered by first train is 60 km (i.e. in 1 hr).
Now 2nd train also starts and distance between them is now (24060) = 180 km
Both coming in opposite direction, so relative speed = (60+30) = 90 km/hr
So time = 7:00 AM + (180/90) = 7:00 AM +2 hrs = 9:00 AMIncorrect
Explanation:
When 2nd train starts i.e. at 7 AM (1 hr after 6 AM), distance covered by first train is 60 km (i.e. in 1 hr).
Now 2nd train also starts and distance between them is now (24060) = 180 km
Both coming in opposite direction, so relative speed = (60+30) = 90 km/hr
So time = 7:00 AM + (180/90) = 7:00 AM +2 hrs = 9:00 AM 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeHow many 4 letter words starting with vowel can be formed by the letters of word ACTIVE such that no letter repeats?
Correct
Explanation:
There are 3 vowels, so we gave 3 choices for the first letter
There are total 6 letters in ACTIVE, and one of them has occupied first place, so 5 choices for second, 4 choices for third, and 3 choices for fourth
So 3*5*4*3 = 180Incorrect
Explanation:
There are 3 vowels, so we gave 3 choices for the first letter
There are total 6 letters in ACTIVE, and one of them has occupied first place, so 5 choices for second, 4 choices for third, and 3 choices for fourth
So 3*5*4*3 = 180 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeWhich is the least fraction out of 2/5, 4/7, 3/8 and 1/4?
Correct
Explanation:
Do by finding their decimal values
OR
Compare each
First – 2/5 and 4/7
2*7 = 14 and 4*5 = 20
So 2/5 is small than 4/7
Next – 2/5 and 3/8
2*8 = 16 and 3*5 = 15
So 3/8 is small than 2/5
Next – 3/8 and 1/4
3*4 = 14 and 1*8 = 8
So 1/4 is smallestIncorrect
Explanation:
Do by finding their decimal values
OR
Compare each
First – 2/5 and 4/7
2*7 = 14 and 4*5 = 20
So 2/5 is small than 4/7
Next – 2/5 and 3/8
2*8 = 16 and 3*5 = 15
So 3/8 is small than 2/5
Next – 3/8 and 1/4
3*4 = 14 and 1*8 = 8
So 1/4 is smallest
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